hitting a golf ball out of a sand trap: jye jye the path of the
TRANSCRIPT
Hitting a golf ball out of a sand trap: https://
www.youtube.com/watch?v=FLR4V_lXJYE The path of the ball can be approximated
by:◦ y = -x2 + 5x◦ x is the horizontal distance travelled by the ball in
meters◦ y is the height of the ball in meters
3.2 Properties of Graphs of Quadratic Relations
What is the greatest height achieved by the ball?
Table of Values
2 Ways to Solve – Table & Graph
x 0 1 2 3 4 5
y 0 4 6 6 4 0
NOTICE:x values are all
positive, since ball moves forward,
not backward and a y-value of 0 is where the ball stops (ground
level)• So the maximum height is y = 6m,
and it occurs for 2 seconds• Wait, how can the maximum height
occur for more than an instant?• Perhaps there’s a more accurate
way to see the maximum height
Graph
2 Ways to Solve – Table & Graph
• Using the graph, we can see the 2 points where maximum height of 6m occurs
• The maximum height actually occurs between these points, at x = 2.5, which is y = 6.25
• A table of values is also correct, but you need more data points to have more accuracy
Sketch the graph of the relation y = x2 – 6x. Determine the equation of the axis of symmetry, the coordinates of the vertex, the y-intercept and the x-intercepts. Relationship is quadratic since highest
degree is 2 a = 1(parabola opens upward), b = -6, c = 0 In order to sketch the graph, create a table
of values and then plot the points
Example #2
x y
-1 7
0 0
1 -5
2 -8
3 -9
4 -8
5 -5
6 0
7 7
Example #2 - y = x2 – 6xOnce you make your table of values, plot the points on a set of axes.
Axis of Symmetry
Equation of Axis of Symmetry: x = 3
VertexCoordinates of Vertex: (3, -9)
x y
-1 7
0 0
1 -5
2 -8
3 -9
4 -8
5 -5
6 0
7 7
Example #2 - y = x2 – 6xLocating the x and y intercepts.
x-intercepts: when y = 0(0,0) and (6,0)
y-intercept: when x = 0(0,0)
You can either read this off the table of values, or see it
from the graph.
Pied Kingfisher catching fish in a split second
https://www.youtube.com/watch?v=6YRM0sy3xIYThe underwater path of the bird is described by a parabola with the equation y = 0.5x2 – 3x, where x is the horizontal position of the bird relative to its entry point, and y is the depth of the bird underwater (both in meters).
Quadratic Relations in Nature
The vertex of a parabola has the:◦ Min y-value if parabola opens up◦ Max y-value if parabola opens down
A parabola is symmetric with respect to a vertical line through its vertex
x-intercept is when y=0 y-intercept is when x=0
In Summary…