lsamathwilson.weebly.com...round to the nearest hundredth. 62/87,21 first find the total amount...

22
Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years SOLUTION: The simple interest is $567. 2. $240 at 8% for 9 months SOLUTION: 9 months is equivalent to of a year. The simple interest is $14.40. 3. $725 at 3.25% for 5 years SOLUTION: The simple interest is $117.81. 4. $3750 at 5.75% for 42 months SOLUTION: 42 months is equivalent to years. The simple interest is $754.69. 5. Mateos sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what eSolutions Manual - Powered by Cognero Page 1 6-6 Simple and Compound Interest

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Page 1: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 1

6-6 Simple and Compound Interest

Page 2: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 2

6-6 Simple and Compound Interest

Page 3: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 3

6-6 Simple and Compound Interest

Page 4: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 4

6-6 Simple and Compound Interest

Page 5: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 5

6-6 Simple and Compound Interest

Page 6: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 6

6-6 Simple and Compound Interest

Page 7: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 7

6-6 Simple and Compound Interest

Page 8: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 8

6-6 Simple and Compound Interest

Page 9: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 9

6-6 Simple and Compound Interest

Page 10: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 10

6-6 Simple and Compound Interest

Page 11: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 11

6-6 Simple and Compound Interest

Page 12: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 12

6-6 Simple and Compound Interest

Page 13: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 13

6-6 Simple and Compound Interest

Page 14: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

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6-6 Simple and Compound Interest

Page 15: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 15

6-6 Simple and Compound Interest

Page 16: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 16

6-6 Simple and Compound Interest

Page 17: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 17

6-6 Simple and Compound Interest

Page 18: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 18

6-6 Simple and Compound Interest

Page 19: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 19

6-6 Simple and Compound Interest

Page 20: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 20

6-6 Simple and Compound Interest

Page 21: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

eSolutions Manual - Powered by Cognero Page 21

6-6 Simple and Compound Interest

Page 22: lsamathwilson.weebly.com...Round to the nearest hundredth. 62/87,21 First find the total amount Mateo ¶s sister will pay. Mateo ¶s sister made payments of $152.35 each month for

Find the simple interest. Round to the nearest cent, if necessary. 1. $1350 at 6% for 7 years

SOLUTION:  

The simple interest is $567.

2. $240 at 8% for 9 months

SOLUTION:  

9 months is equivalent to of a year.

The simple interest is $14.40.

3. $725 at 3.25% for 5 years

SOLUTION:  

The simple interest is $117.81.

4. $3750 at 5.75% for 42 months

SOLUTION:  

42 months is equivalent to  years.

The simple interest is $754.69.

5. Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was her simple interest rate for her loan? Round to the nearest hundredth.

SOLUTION:  First find the total amount Mateo’s sister will pay. Mateo’s sister made payments of $152.35 each month for 3 years, or 36 months. The total amount she will pay over the length of the loan is 36 • 152.35 = $5484.60. Next, subtract the principal to find out how much interest she paid. 5484 – 5000 = $484. Use the simple interest formula to find the interest rate.

The simple interest rate for her loan was 3.23%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.6. $480 at 5% for 3 years

SOLUTION:  

 

Year Principal Interest Amount at end of year

1 $480 480 + 24 = $504

2 $504 504 + 25.20 = $529.20

3 $529.20 529.20 + 26.46 = $555.66

7. $515 at 11.8% for 2 years

SOLUTION:  

 

Year Principal InterestAmount at end of year

1 $515515 + 60.77 = $575.77

2 $575.77575.77 + 67.94 = $643.71

8. $6525 at 6.25% for 4 years

SOLUTION:  

 

Year Principal InterestAmount atend of year

1  $65256525 +

407.81 = $6932.81

2 $6932.816932.81 + 433.30 = $7366.11

3 $7366.117366.11 + 460.38 = $7826.49

4 $7826.497826.49 + 489.16 = $8315.65

9. $2750 at 8.5% for 3 years

SOLUTION:  

 

Year Principal InterestAmount at

end of year

1 $27502750 +

233.75 = $2983.75

2 $2983.752983.75 + 253.62 = $3237.37

3 $3237.373237.37 + 275.18 = $3512.55

Find the simple interest. Round to the nearest cent, if necessary.10. $275 at 7.5% for 4 years

SOLUTION:  

The simple interest is $82.50.

11. $620 at 6.25% for 5 years

SOLUTION:  

The simple interest is $193.75.

12. $734 at 12% for 3 months

SOLUTION:  

The simple interest is $22.02.

13. $2020 at 8% for 18 months

SOLUTION:  

The simple interest is $242.40.

14. $1200 at 6% for 36 months

SOLUTION:  

The simple interest is $216.

15. $4380 at 10.5% for 2 years

SOLUTION:  

The simple interest is $919.80.

16. Thomas borrowed $4800 to buy a new car. He will be paying $96 each month for the next 60 months. Find the simple interest rate for his car loan.

SOLUTION:  First find the total amount Thomas will pay. Thomas will make payments of $96 each month for 60 months. The total amount he will pay over the length of the loan is 60 • 96 = $5760. Next, subtract the principal to find out how much interest he will pay. 5760 – 4800 = $960. Use the simple interest formula to find the interest rate.

The simple interest rate for his loan is 4%.

Find the total amount in each account to the nearest cent if the interest is compounded annually.17. $3850 at 5.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at

end of year 1 $3850

3850 +

202.125 =

$4052.125

2 $4052.13

4052.125 +

212.7365625

≈ $4264.86

18. $4025 at 6.8% for 6 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $4025 4025 +

273.70 = $4298.70

2 $4298.70 4298.70 + 292.31

= $4591.01

3 $4591.01 4591.01 + 312.19

= $4903.20

4 $4903.20 4903.20 + 333.42

= $5236.62

5 $5236.62 5236.62 + 356.09

= $5592.71

6 $5592.71 5592.71 + 380.30

= $5973.01

19. $595 at 4.75% for 3 years

SOLUTION:  

 

Year Principal Interest Amount

at

end

of

year 1 $595

595

+

28.2625

=

$623.26 2 $623.26

623.26+

29.60

=

$652.86

3 $652.86

652.87+

31.01

≈ $683.88

20. $840 at 7% for 4 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $840 840 +

58.80 = $898.80

2 $898.80 898.80 + 62.92 = $961.72

3 $961.72 961.72 + 67.32 =

$1029.04

4 $1029.04 1029.04 + 72.03

= $1101.07

21. $12,000 at 6.95% for 4 years

SOLUTION:   

 

Year Principal InterestAmount at

end of year

1 $12,000

12,000 +

834 =

$12,834

2 $12,834

12,834 +

891.963 =

$13,725.96

3 $13,725.96

13,725.96

+ 953.95  =$14,679.91

4 $14,679.91

14,679.92+

1020.25 ≈ $15,700.17

22. $8750 at 12.25% for 2 years

SOLUTION:  

 

Year Principal Interest Amount at end of

year 1 $8750

8750 + 1071.875

= $9821.875

2 $9821.88

9821.875 +

1203.1803 ≈ 

$11,025.06

23. Denise has a car loan of $8000. Over the course of the loan, she paid a total of $1680 in interest at a simple interest rate of 6%. How many months was the loan?

SOLUTION:  Use the simple interest formula.

The length of the loan was 3.5 years or 42 months.

24. A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period,how much was invested?

SOLUTION:  Use the simple interest formula.

$1800 was invested.

25. Financial Literacy A bank offers the options shown for interest rates on their savings accounts. Which option will yield more money after 3 years with an initial deposit of $1500? Explain.

SOLUTION:  For option A, the rate 0.625 for simple interest with $1500 invested.

The interest earned with option A is $281.25. For option B, the rate is 0.0575 compounded annually for 3 years with $1500 invested.

The interest earned for option B is 1773.91 – 1500 = $273.91. Since $281.25 > $273.91, option A is better.

Year Principal Interest Amount at end of year

1 $1500

1500 + 86.25 = $1586.25

2 $1586.25

1586.25 + 91.21

= $1677.46

3 $1677.46

1677.46 + 96.45

= $1773.91

Find the total amount in each account to the nearest cent if the interest is compounded twice a year.26. $2500 at 6.75% for 1 year

SOLUTION:  

 

Period Principal Interest Amount

at end

of year 1 $2500

2500 +

84.38 =

$2584.38

2 $2584.38

2584.38

+ 87.22

=

$2671.60

27. $14,750 at 5% for 1 year

SOLUTION:  

 

Period Principal Interest Amount at

end of year 1 $14,750

14,750 +

368.75 =

$15,118.75

2 $15,118.75

15,118.75

+ 377.97 =

$15,496.72

28. $3750 at 10.25% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at end of

year 1 $3750

3750 + 192.19 = $3942.19

2 $3942.19

3942.19 + 202.04

= $4144.23

3 $4144.23

4144.23 + 212.39

= $4356.62

4 $4356.62

4356.62 + 223.28

= $4579.90

29. $975 at 7.2% for 2 years

SOLUTION:  

 

Period Principal Interest Amount at

end of

year 1 $975

975 +

35.10 =

$1010.10 2 $1010.10

1010.10 +

36.36 =

$1046.46 3 $1046.46

1046.46 +

37.67 =

$1084.13 4 $1084.13

1084.13 +

39.03 =

$1123.16

30. Mrs. Glover placed $15,000 in a certificate of deposit for 18 months for her children’s college funds. Each month shemakes $56.50 in interest. Find the annual simple interest rate for the certificate of deposit.

SOLUTION:  Mrs. Glover earns $56.50 • 18 = $1017 in interest over the entire period of the certificate of deposit. Use the simple interest formula to find the rate.

The interest rate is 4.52%.

31. Jameson received his first credit card bill for a total of $325.42. Each month he makes a $50 payment and the remaining balance is charged an interest rate of 1.5%. The table below shows his first three monthly bills. If he does not make any more charges, what will be the amount of the fifth bill? the seventh bill?

SOLUTION:  

The amount of the 5th

bill is $137.77.

The amount of the 7th

bill is $39.68.

Bill Bill Amount Payment New

Balance 1 $325.42 50.00 $275.42 2 50.00 $229.55 3 50.00 $182.99 4 50.00 $135.73 5 50.00 $87.77 6 50.00 $39.09 7 $39.68 $0

32. Multiple Representations In this problem, you will compare simple and compound interest. Consider the followingsituation. Ben deposits $550 at a 6% simple interest rate and Anica deposits $550 at a 6% interest rate that is compounded annually. a.      Table Copy and complete the table.

  b. Graph Graph the data on the coordinate plane. Show the time in years on the x-axis and the total interest earned in dollars on the y-axis. Plot Ben’s interest balance in blue and Anica’s interest in red. Then connect the points. c. Analyze Compare the graphs of the two functions.

SOLUTION:  a. Ben deposits $550 at a 6% simple interest rate.

Anica deposits $550 at a 6% interest rate compounded annually.

  b.

    c. Sample answer: The graph of Ben’s interest is in a straight line. The graph of Anica’s interest is increasing at a faster rate and is not in a straight line.

Years Ben 2

4

6

8

10

Year Principal Interest Amount

at

end

of

year

Total

Interest

Earned

1 $550

550

+ 33

=

$583

$33

2 $583

583

+

34.98

=

$617.98

33 +

34.98 =

$67.98

3 $617.98

617.98

+

37.08

=

$655.06

67.98

+

37.08

=

$105.06 4 $655.06

655.06

+

39.30

=

$694.36

105.06

+

39.30

= $144.36

5 $694.36

694.36

+

41.66

=

$736.02

144.36

+

41.66

=

$186.02 6 $736.02

736.02

+

44.16

=

$780.18

186.02

+

44.16

=

$230.18 7 $780.18

780.18

+

46.81

=

$826.99

230.18

+

46.81

=

$276.99 8 $826.99

826.99

+

49.62

=

$876.61

276.99

+

49.62

=  326.61

9 $876.61

876.61

+

52.60

=

$929.21

326.61

+

52.60

=

$379.21 10 $929.21

929.21

+

55.75

=

$984.96

379.21

+

55.75

=

$434.96

33. Model with Mathematics Give a principal and interest rate where the amount of simple interest earned in four years would be $80. Justify your answer.

SOLUTION:  Use the simple interest formula.

In order to earn $80 in four years, the principal investment times the rate must equal 20. One example of this is the principal is $2000 and the rate is 1% or 0.01, since 0.01 • 20000 = 20. Then I = $2000 • 0.01 • 4 or $80.

34. Justify Conclusions Kai-Yo deposits $500 into an account that earns 2% simple interest. Marcos deposits $250 into an account that earns 4% simple interest. How much money does each have after 10 years? Who will have more money over the long run? Explain your reasoning.

SOLUTION:  Kai-Yo deposits $500 in an account with 2% simple interest.

Kai-Yo will have 500 + 100 = $600 after 10 years. Marcos deposits $250 in an account with 4% simple interest.

Marcos will have 250 + 100 = $350 after 10 years. Even though Kai-Yo and Marcos earn the same amount of interest after every year, Kai-Yo will always have $250 more than Marcos because that was the difference in the initial deposit.

35. Find the Error Sabino is finding the simple interest on a $2500 investment at a simple interest rate of 5.75% for 18 months. Find his mistake and correct it.

SOLUTION:  

Sabino did not convert the time to years.

36. Persevere with Problems Determine the length of time it will take to double a principal of $100 if deposited into anaccount that earns 10% simple annual interest.

SOLUTION:  When the principal doubles, the interest earned will be $100.

It will take 10 years for the principal to double.

37. Building on the Essential Question Compare simple and compound interest.

SOLUTION:  Sample Answer: With simple interest, the amount of money earned will be the same each year because it is always applied to the initial amount. With compound interest, the amount of interest will increase each year because it is being applied to the new total after the interest is added each year.

38. A $500 certificate of deposit has a simple interest rate of 7.25%. What is the value of the certificate after 8 years?

 

A  $290B  $500C  $790D  $2900

SOLUTION:  

The simple interest earned is $290. The value of the certificate will be 500 + 290 = $790 after 8 years. Choice C is the correct answer.

39. Beatriz borrowed $1500 for student loans. She will make 30 equal payments of $62.50 to pay off the loan. What is the simple interest rate for the loan?

 

F  4%G  7%H  8.5%J  10%

SOLUTION:  Beatriz will make 30 equal payments of $62.50 to pay off her loan. The total amount she will pay is 30 • 62.50 = $1875. She will pay 1875 – 1500 = $375 in interest. Her loan is for 30 months, or 2.5 years.

The simple interest rate is 10%. Choice J is the correct answer.

40. A savings account with $2250 has an interest rate of 5%. If the interest is compounded annually, how much will be in the account after 2 years?

 

A  $230.63B  $337.50C  $2480.63D  $2587.50

SOLUTION:  

There will be $2480.63 in the account after 2 years. Choice C is the correct answer.

Year Principal Interest Amount at end of year 1 $2250 2250 + 112.50 = $2362.50

2 $2362.50 2362.50 + 118.13 = $2480.63

41. Short Response Which of the following plans will produce the greater earnings for an investment of $500 over 5 years? How much more will that plan earn?

SOLUTION:  For plan A, the simple interest rate is 0.0675 for $500 invested over 5 years.

The interest for Plan A is $168.75. For Plan B, the interest is compounded annually.

  For plan B the amount of interest earned is 685.04 – 500 = $185.04. Since $185.04 > $168.75, plan B produces the greater investment. Plan B earns $185.04 – $168.75 or $16.29 more than plan A.

Year Principal Interest Amount at end of year

1 $500 500 + 32.50 = $532.50

2 $532.50 532.50 + 34.61

= $567.11

3 $567.11 567.11 + 36.86

= $603.97

4 $603.97 603.97 + 39.26

= $643.23

5 $643.23 643.23 + 41.81

= $685.04

42. In 2000, there were 356 endangered species. Nine years later, 360 species were considered endangered. What was the percent of change? Round to the nearest tenth.

SOLUTION:  Use the percent of change formula.

The percent of change was about 1.1%.

Solve each problem using the percent equation.43. 12 is what percent of 400?

SOLUTION:  The part is 12 and the whole is 400. Let p represent the percent.

So, 12 is 3% of 400.

44. 30 is 60% of what number?

SOLUTION:  The percent is 60% and the part is 30. Let b represent the whole.

So, 30 is 60% of 50.

45. In a recent year, the number of $1 bills in circulation in the United States was about 7 billion. a. Suppose the number of $5 bills in circulation was 25% of the number of $1 bills. About how many $5 bills were in circulation? b. If the number of $10 bills was 20% of the number of $1 bills, about how many $10 bills were in circulation?

SOLUTION:  

a. × 7 or 1.75 billion

b. × 7 or 1.4 billion

Find each product. Write in simplest form.

46. 

SOLUTION:  

47. 

SOLUTION:  

48. 

SOLUTION:  

49. The table shows the amount of time Craig spends jogging every day. He increases the time he jogs every day.

a. Write an equation to show the number of minutes spent jogging m for each day d. b. How many minutes will Craig jog during day 9?

SOLUTION:  a. 

The equation is m = 8d – 1. b.

Craig will jog 71 minutes during day 9.

Day Time Jogging 1 8(1) – 1 = 7 2 8(2) –1 = 15 3 8(3) –1 = 23 4 8(4) – 1 = 31 5 8(5) – 1 = 39 d 8d – 1

Solve each problem.50. Find 66% of 90.

SOLUTION:  

59.4 is 66% of 90.

51. What is 0.2% of 735?

SOLUTION:  

147 is 0.2% of 735.

52. Find 250% of 7000.

SOLUTION:  

53. A meteorologist predicted that the downtown area would get 16 inches of snow in a snowstorm. The downtown areaended up getting 13 inches of snow. What was the percent error of the prediction?

SOLUTION:  Find the amount of error. 16 – 13 = 3 Find the percent error.

Rounded to the nearest tenth, the percent error is 23.1%.

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6-6 Simple and Compound Interest