09.2 integer programming.pdf

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    Solving Combinatorial Optimization Problems: exact

    techniques

    Relaxation If we do not consider one or more constraints of the originalproblem P O, we can transform the problem in another problem that can be

    simpler to solve P R. Considering that the problem is a minimization

    problem, the optimal values of the objective function are related in the

    following way:

    f?PR f?

    PO

    (with less constraints the solution can only improve or stay the same).

    Linear relaxation transform an integer problem in a problem with

    continuous variables by dropping the constraint that the variables must beinteger (or Binary). This allows us to use the Simplex Algorithm instead of

    the more complex, and far more time consuming, tree search.

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    Solving the linear relaxation

    Problem PL0:

    max F = 3x+ 7y

    subject to:

    x 3.55x 4y 10

    4

    7x + 2y 9

    x , y 0Optimal, non integer, solution:

    x= 3.5 and y= 3.5; F = 35

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    Branching in x: x 3

    max F = 3x+ 7y

    subject to:

    x 3.5

    5x 4y 10

    4

    7x + 2y 9

    x , y 0

    x 3

    Solution (non integer):x= 3 and y= 3.6; F = 34.5

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    Branching in x: x 4

    max F = 3x+ 7y

    subject to:

    x 3.5

    5x 4y 10

    4

    7x + 2y 9

    x , y 0

    x 4Without admissible solutions.

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    Branching in y: y 4

    max F = 3x+ 7y

    subject to:

    x 3.5

    5x 4y 104

    7x + 2y 9

    x , y 0

    x 3

    y 4 Solution (non-integer):

    x= 1.7 and y= 4; F = 33.2

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    Branching in x: x 1

    max F = 3x+ 7y

    subject to:

    x 3.5

    5x 4y 10

    47x + 2y 9

    x , y 0

    x 3

    y 4

    x 1

    Solution (non-integer):

    x= 1 and y= 4.2; F = 32.5

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    Branching in x: x 2

    max F = 3x+ 7y

    subject to:

    x 3.5

    5x 4y 10

    47x + 2y 9

    x , y 0

    x 3

    y 4

    x 2 Without feasible solutions.

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    Branching in y: y 4

    max F = 3x+ 7y

    subject to:

    x 3.5

    5x 4y 10

    47x + 2y 9

    x , y 0

    x 3

    y 4

    x 1y 4

    Solution (integer):

    x= 1 and y= 4; F = 31Best integer solution obtained so far!

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    Branching in y: y 5

    max F = 3x+ 7y

    subject to:

    x 3.5

    5x 4y 10

    47x + 2y 9

    x , y 0

    x 3

    y 4

    x 1y 5

    ,

    ,

    -

    I

    h ; 4y I O

    ,

    -,

    /

    /

    -

    ,

    /

    -

    - ;

    4I

    h y

    9

    ,

    /

    /

    ,

    ,

    , , ,

    ,

    ,

    Without admissible solutions.

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    Branch-and-Bound tree

    !"#$

    &'(' )'*+,+-.

    / 0 123

    4 0 123 ! # $%

    !"#$5

    &'(' )'*+,+-.

    / 0 1

    4 0 126 7 0 1823

    !"#$9

    &'( :(;

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    Upper and lower Bounds

    the branch & bound is more efficient because it is possible to cut

    nodes of the search tree without exploring them, because we are surenot to obtain better solutions than the ones we already have;

    allow us to measure the distance, (considering the value of the

    objective function) to the optimal solution.

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    Bounds in a maximization problem:

    alowerlimitLIis given by an

    integer solution that has beenpreviously obtained the opti-

    mal solution F? can never be

    worse (lower) than the integer

    solution that we already have;

    an upperlimit LSis given bythe highest value of the objec-

    tive function within all the no-

    des that are not yet completely

    explored (we hope to find there

    an integer solution that is bet-ter than the one we got).

    Maximization Problem

    F*- LB UB - LB

    F

    Upper Bound UB

    Value of the objective function for themost promising unexplored node

    Optimal integer solution F*(unknown)

    Lower bound LB

    Best integer solution found(highest value of the objective

    function)

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    Bounds example

    Consider a maximization problem where all the variables are integer. The

    tree in figure1is obtained along the resolution process.

    !"#$

    &'(')*'+,-,. /(012('3

    ! # $%%

    !"#4

    &'(')*'+,-,. /(012('3! # &'

    !"#5

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    &'(')*'+,-,. /(012('3! # )$

    !"#:

    &'(')*'+,-,. /(012('3

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