1-41-6_abs_value_intro_teacher [autosaved]

Upload: ricky-proctor

Post on 08-Apr-2018

216 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    1/36

    ABSOLUTE VALUEEQUALITIES and

    INEQUALITIES

    Candace Moraczewski and Greg Fisher

    April, 2004

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    2/36

    3 x !

    -3 3

    This absolute value equation represents thenumbers on the number line whose distance from 0is equal to 3.

    0

    3 units 3 units

    Two numbers satisfy this equation . Both 3 and -3 are3 units from 0 .

    Look at the number line and notice the distance from 0

    of -3

    and3.

    An absolute value equation is an equation that containsa variable inside the absolute value sign .

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    3/36

    The absolute value of a number is its distance

    from 0 on a number line.

    -5 0

    5 5- ! because -5 is 5 units from 0

    -3

    3 3- ! because -3 is 3 units from 0

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    4/36

    0-5 -3

    R emember though, on a number line if anumber is to the left of another number it isless than that number .

    -5 < -3 even though 3- 5- "

    R emember absolute value means distancefrom 0

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    5/36

    0 53

    Notice that for numbers to the right of 0 thefollowing is true .

    5 > 3 and also 3 5 "

    R emember absolute value means distancefrom 0

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    6/36

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    7/36

    Solve | x +2 | = 7

    x +2 = 7 or x+2 =-7-7 70

    X+2

    {5 ,-9 }x=

    5 or x =

    -9

    Exactly 7units of -2

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    8/36

    Solve 4|x 3 | + 2 = 104| x 3 | = 8

    | x 3 | = 2x 3 = 2 or x-3 = -2

    x = 5 or x= 1{1,5 }

    Exactly 2units of + 3

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    9/36

    Solve -2|2x + 1| -3 = 9

    -2| 2x + 1| = 12

    | 2x + 1| = -6

    NO SOLUTION BecauseAbs . value cannot be negative

    0

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    10/36

    -3 30

    x

    If a number x is between -3 and 3 then this translates to:

    Inequality notation : -3 < x < 3 (a double inequality)

    Absolute value notation : 3 x

    because -3 is to the left of x and x is to the left of 3

    because all of the numbers between -3 and 3 have adistance from 0 less than 3

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    11/36

    -3 30

    x

    If a number x is between -3 and 3 , including the -3 and 3 ,

    then this translates to:

    Inequality notation :-3

    x3

    (a double inequality)

    Absolute value notation : 3 x e

    e e

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    12/36

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    13/36

    -3 30

    x

    If a number x is to the left of -3 or to the right of 3 , includingthe -3 and 3 , then this translates to:

    Inequality notation : x -3 or x 3 (a compound or inequality)

    Absolute value notation : 3 x u

    x

    e u

    - g

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    14/36

    2 xThis absolute value inequality represents all of thenumbers on a number line whose distance from 0 isless than 2 . See the red shaded line below .

    0-2 2

    Inequality notation : -2 < x < 2

    x

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    15/36

    2 x e

    0-2 2

    This absolute value inequality represents all of thenumbers on the number line whose distance from 0is less than or equal to 2 . Notice that both -2 and 2are included on this interval .

    Inequality notation : 2x2 ee

    x

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    16/36

    2 x "

    0-2 2

    This absolute value inequality represents all of thenumbers on the number line whose distance from 0is more than 2 . Notice that the intervals satisfyingthis inequality are going in opposite directions .

    Inequality notation : x < -2 or x > 2

    x x

    g- g

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    17/36

    2 x u

    0-2 2

    This absolute value inequality represents all of thenumbers on the number line whose distance from 0is more than or equal to 2 . Notice that the intervalssatisfying this inequality are going in oppositedirections and that 2 and -2 are included on theintervals .

    Inequality notation : 2or x - 2x ue

    xx

    g- g

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    18/36

    W ord Problems Although I am endorsing this behavior,pretend that you are allowed to go within 9 of the speed limit of 55 mph without getting

    a ticket.

    Write an absolute value inequalitythat models this situation .

    |x 65 | < 9

    D esired amount Acceptable R ange

    Check Answer: x -65 < 9 AND x-65 > -9

    x 56 56

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    19/36

    W ord Problems

    If a bag of chips is within .4 oz of 6 oz thenit is allowed to go on the market . W rite aninequality that models this situation .

    |x 6 | < .4

    D esired amount Acceptable R ange

    Check Answer: x 6 < .4 AN D x 6 > -. 4

    x < 6. 4 AN D x > 5.6 5.6 < x < 6. 4

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    20/36

    In a poll of 100 people, Mistys approvalrating as a dog is 78% with a 3 % of error . ticket . W rite an absolute value inequalitythat models this situation .

    |x 78 | -3

    x7 5 75

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    21/36

    TO SOLVE A MO R E COMPLICATE D ABSOLUTE VALUEINEQUALITY, FOLLO W THESE STEPS ASILLUST R ATE D IN THE FOLLO W ING EXAMPLES

    1. D raw a number line and identify theinterval(s) which satisfy the inequality

    2. W rite the expression in the absolute valuesign over the designated interval(s)3. Translate this to either a double inequality or two inequalities going in opposite directionsconnected with the word or

    4. R emember to include the endpoint if theinequality also has an equal to symbol

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    22/36

    S olve 4 1 -x2

    0-4 4

    2x - 1

    4 1-2 x4

    Now solve the double inequality

    1 . Draw a number line and identify the interval(s) which

    satisfy the inequality :

    2 . Write the expression in the absolute value signover the designated interval(s)

    3. Translate this to either a double inequality or twoinequalities going in opposite directions

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    23/36

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    24/36

    S olve 8 2 3x e

    0-8 8

    3 x + 2

    8 2 3x8 ee

    Now solve the double inequality

    3. Translate this to either a double inequality or two inequalities going in opposite directions

    1 . Draw a number line and identify the interval(s)

    which satisfy the inequality

    2 .. Write the expression in the absolute value sign over the designated interval(s)

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    25/36

    8 2 3x8 ee

    D ivide every position by 3

    2 x310 ee

    -2

    -2

    -2________________ 6 3x10 ee

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    26/36

    S olve 5 2 x u

    0-5 5

    x + 2

    5 2 or x5- 2 x ue

    Now solve the or compound inequality

    x + 2

    1 . Draw a number line and identify the interval(s) which

    satisfy the inequality

    2 . Write the expression in the absolute value signover the designated interval(s)

    3. Translate this to either a double inequality or twoinequalities going in opposite directions

    g- g

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    27/36

    5 2 or x5- 2 x ue-2 -2 -2 -2

    3 or x7- x ue

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    28/36

    S olve 2 3x- 4 "

    0-2 2

    4 3 x

    2 3x4or 2- 3x- 4 "

    Now solve the or compound inequality

    4 3 x

    1 . Draw a number line and identify the interval(s) which

    satisfy the inequality

    2 . Write the expression in the absolute value signover the designated interval(s)3. Translate this to either a double inequality or twoinequalities going in opposite directions

    g- g

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    29/36

    -4 -4 -4 -4

    2- 3x-or 6- 3x- "

    2 3x4or 2- 3x- 4 "

    D ivide both inequalities by -3 . R emember to change

    the sense of the inequality signs because of divisionby a negative .

    3

    2 or x2 x "

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    30/36

    TRY THE FOLLOWING P R OBLEM S. TO S EE THEANS WE R, CLICK ON THE A RR OW TO THE R IGHTOF THE P R OBLEM .

    2 3x- 4 .6

    1 1 2 x.51 2 x- 7- .4

    5 3x- 2- .3

    4 3 -x.2

    5 3 - 2 .1

    u

    u

    u

    ex

    Solve the following absolute value inequalities . W rite answer using both inequality notation and interval notation .

    Click here to takethe post quiz

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    31/36

    ANS WE RS:

    ] 4 1,- [ , 4 x1- .1 ee

    Click here to returnto the problem set

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    32/36

    ) [7, 1]- ,- ( , 7 or x1- x2 . ggue

    ANS WE RS:

    Click here to returnto the problem set

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    33/36

    ) 1 , 37- ( , 1 x

    37- 3.

    ANS WE RS: Click here to returnto the problem set

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    34/36

    ) 3,- [ 4]- ,- ( , 3- or x4- x4. ggue

    ANS WE RS:

    Click here to returnto the problem set

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    35/36

    0) 1,- ( , 0 x1- 5 .

    ANS WE RS:Click here to returnto the problem set

  • 8/7/2019 1-41-6_Abs_Value_Intro_Teacher [Autosaved]

    36/36

    ) 2 , [ ] 32 ,- ( , 2 or x

    32 x6. ggue

    ANS WE RS:

    Click here to returnto the problem set