• 1. A ship displaces 7,000 tons while 1. A ship displaces 7,000 tons while floating in fresh water. Find the floating in fresh water. Find the displacement of the ship when displacement of the ship when floating floating at the same draft in water of density at the same draft in water of density 1,015 kgs/m1,015 kgs/m³³

• A. 7,105 tons

• B. 7,135 tons

• C. 7,125 tons

• D. 7,115 tons

• 1. Solution:1. Solution:

• New Δ New Density

• Old Δ Old Density

• New Δ 1,015 Kgs/m³

• 7,000 t 1,000 Kgs/m³

• New Δ = 7,000 tons x 1,015 Kgs/m³

• 1,000 Kgs/m³

• New Δ = 7,105,000

• 1,000

• New Δ = 7,105 Tons

• 2. The words pipe, butt, tun and 2. The words pipe, butt, tun and puncheon all refer to __________.puncheon all refer to __________.

• A. structural shape used in construction

• B. various length of timber

• C. the sizes of cask

• D. viscosities of liquid cargoes

• Tun can be:• An old British measurement of liquid. • A large cask for liquids, especially wine. • A measure of liquid capacity, particularly one

equivalent to around 252 wine gallons (954 litres). • A large cask, particularly one holding a volume

equivalent to 2 butts, or 252 gallons. • Puncheon, in the United States also called pon for

brevity, is an old English unit of wine casks, holding about 318 litres. It is also known as tertian (from the Latin word for third), because three of it make a tun, and as the (wine) firkin.

STAVESTAVE

STAVE JOINTSTAVE JOINT

BUNG HOLEBUNG HOLEBILGEBILGE

BILGE HOOPBILGE HOOPQUARTER HOOPQUARTER HOOP

HEAD HOOPHEAD HOOP

RIVETRIVET

CANTCANTHEADHEAD

CHIMECHIMECROSECROSE

PARTS OFPARTS OFA CASKA CASK

• 3. The 3. The curvature of the deckcurvature of the deck in a in a transverse directiontransverse direction. It is measured . It is measured between the deck height at the center and between the deck height at the center and the deck height at the side.the deck height at the side.

• A. sheer

• B. base line

• C. camber

• D. moulded breadth

SHIP CONSTRUCTION

D

E

A

B

C

waterline

A= CamberB = Tumble Home

C = FreeboardD = BeamE = Dead rise

• 4. Your vessel is at a dock where the 4. Your vessel is at a dock where the density is 1,012. To what draft will she density is 1,012. To what draft will she be loaded so as to draw 23’ 06” when be loaded so as to draw 23’ 06” when she gets to sea where the density is she gets to sea where the density is 1,026?1,026?

• A. 23’ 06”

• B. 23’ 02”

• C. 23’ 10”

• D. 24’ 02”

• 4. Solution:

• New Draft Old Density

• Old Draft New Density

• New Draft 1,026 Kgs/m³

• 23‘ 06” 1,012 Kgs/m³

• New Draft = (23.5’) x 1,026 Kgs/m³

• 1,012 Kgs/m³

• New Draft = 23.82’ or 23’ 10”

• 5. A device that can tighten rigging by 5. A device that can tighten rigging by means of screw threadsmeans of screw threads..

• A. pelican hook

• B. stretcher

• C. rottmear releasing gear

• D. turnbuckle

TurnbucklesTurnbuckles Pelican HookPelican Hook

• 6. One of the 6. One of the principal dangersprincipal dangers inherent inherent in in liquefied petroleum gasliquefied petroleum gas is ______. is ______.

• A. The strong odor it produces

• B. The way it reacts with seawater

• C. As it warms up it becomes heavier than

air

• D. It’s low temperature causes frostbite or

freezing

• 7. 7. For package freightFor package freight, an average , an average

allowance for “broken stowage” is.allowance for “broken stowage” is.

• A. 15%

• B. 30%

• C. 60%

• D. 5%

8. Sweat damage in a hatch full of canned 8. Sweat damage in a hatch full of canned goods and cartons will occur when the.goods and cartons will occur when the.

• A. Air temperature is higher than the

temperature of the cargo

• B. Dew point is lower than the temperature

of the cargo

• C. Dew point is higher than the temperature

of the cargo

• D. Air temperature is lower than the

temperature of the cargo

• 9. The difference between the initial trim 9. The difference between the initial trim and the trim after a loading change is and the trim after a loading change is known as.known as.

• A. final trim

• B. change of trim

• C. trim

• D. change of draft

10. What is the size of 24-strand wire 10. What is the size of 24-strand wire necessary to lift 18 tons with a 3-fold necessary to lift 18 tons with a 3-fold purchase?purchase?

• A. 2 inches

• B. 4 inches

• C. 3 inches

• D. 6 inches

• GEAR M.A. (Mechanical Adv. )

Single Whip/Purchase 1

Gun Tackle 2

Luff Tackle/ Handy Billy 3

Watch Tackle

Double Purchase 4

Double Luff 5

Three Fold Purchase 6

10. Solution:

• S = Wt. x ( 1 + 10% N.O.S. )

• M.A.

• S = 18 tons x 1.6

• 6

• S = 4.8 Tons

• SWL = 2C² / 6

• C = √SWL x 6

• 2

• C = √ 4.8 x 6

• 2

• C = 3.8 inches

• 11. Foam extinguishes fire by:

• A. chemical action

• B. inerting the air

• C. cooling

• D. smothering

• 12. In regards to the 12. In regards to the center of buoyancycenter of buoyancy, , which of the following statement is which of the following statement is correct?correct?

• A. It moves toward the low side of an

inclined vessel

• B. It is the measure of metacentric height

• C. It caused the displacement to increase

• D. It moves toward the high side of an

inclined vessel

• 13. No vessel may use or carry an oil 13. No vessel may use or carry an oil transfer hose larger than 3 inches unless transfer hose larger than 3 inches unless it meets all of the following requirements it meets all of the following requirements EXCEPT:EXCEPT:

• A. Have a bursting pressure greater than

600 psi

• B. Have a working pressure greater than

150 psi

• C. Have a metallic reinforcement

• D. Have identification markings

14. You are making a heavy lift with the 14. You are making a heavy lift with the jumbo boom. Your vessel displaces 18,000 jumbo boom. Your vessel displaces 18,000 tons. The 50-ton weight is on the pier, and tons. The 50-ton weight is on the pier, and its center is 75 ft. to starboard of the its center is 75 ft. to starboard of the centerline. The head of the boom is 112 ft. centerline. The head of the boom is 112 ft. above the baseline, and the center of the above the baseline, and the center of the gravity of the lift when stowed on deck will gravity of the lift when stowed on deck will be 56 ft. above the baseline. As the jumbo be 56 ft. above the baseline. As the jumbo takes the strain, the ship lists 3.5takes the strain, the ship lists 3.5º.º. What is What is the GM when the cargo is stowed?the GM when the cargo is stowed?

• A. 3.24 ft.• B. 3.19 ft.• C. 3.40 ft.• D. 3.56 ft.

• Given: Δ = 18,000 tons, Weight = 50 tons

• KG = 75 ft (Stbd.) Centerline

• Head of Boom= 112 ft. from Baseline

• KG of cargo = 56 ft. (from baseline

• when stowed on deck ), List = 3.5º

• Find: GM when Cargo was Stowed

• Solution:

• Using the Inclining Experiment

• Tan List = Wt. x Dist.

• Δ x GM

• GM = Wt x Dist.• Δ x Tan List• GM = 50 t x 75 ft.• 18,000 t x Tan 3.5º• GM = 3.40 ft. ( When Lifting )• GG’ = Wt. x Dist.• Δ• GG’ = 50 t x 56 ft.• 18,050 t• GG’ = 0.16 ft.• GM = 3.40 ft. (-)• GM = 3.24 ft. ( When Stowed on Deck )

• 15. The KG of a vessel is found by 15. The KG of a vessel is found by dividing the displacement into the:dividing the displacement into the:

• A. Sum of the free surface moments of the

vessel

• B. Height of the center of gravity of the

vessel

• C. Sum of the longitudinal moments of the

vessel

• D. Sum of the vertical moments of the vessel

• 16. A ship is loading in dock water of 16. A ship is loading in dock water of density 1,010 kgs/mdensity 1,010 kgs/m³,³, F.W.A.150 mms. F.W.A.150 mms. Find the change in draft on entering salt Find the change in draft on entering salt water?water?

• A. 60 mms

• B. 90 mms

• C. 30 mms

• D. 100 mms

Allowable Increase = FWA x (Change in Dens)

• 25

• = 150 mms. x (1025 – 1010)

• 25

• = 150 mms. X 15

• 25

• Allowable Increase = 90 mms.

• 17. What is the Safe working load of 4-17. What is the Safe working load of 4-inch Manila rope?inch Manila rope?

• A. 2.2 tons

• B. 3.4 tons

• C. 1.8 tons

• D. 1.3 tons

17. Solution:

• SWL = C² (Occasional Lift)

7

• SWL = 4²

7

• SWL = 16/7

• SWL = 2.28 tons

• 18. Form the 18. Form the foundation for the decksfoundation for the decks, , they are situated athwartship from the they are situated athwartship from the side to side of the vessel.side to side of the vessel.

• A. girders

• B. garboard strake

• C. pillars

• D. deck beams

• 19. You have a quantity of bagged cargo 19. You have a quantity of bagged cargo to stow in #3 UTD. Which method of stow to stow in #3 UTD. Which method of stow will provide minimum block stability?will provide minimum block stability?

• A. Bag on bag stow

• B. Alternate layer directions

• C. Half bag stow

• D. Bilge and cantline

• Method of Stowing Bagged CargoMethod of Stowing Bagged Cargo

• 1. Full Bag Method = provide maximum

ventilation.

• 2. Alternate Layer Direction = provide

• maximum Block Stability .

• 3. Half Bag or Brick Method = provides

minimum Broken Space.

•

• 20. The 20. The purpose of setting the freeboardpurpose of setting the freeboard requirement is primarily to ensure that the requirement is primarily to ensure that the ship has.ship has.

• A. adequate load during voyage at sea

• B. reserve of buoyancy

• C. enough watertight doors and openings

• D. enough freeboard after loading

• 21.You are going to load bales of wool 21.You are going to load bales of wool having a stowage factor of 100 in #3 having a stowage factor of 100 in #3 lower hold which had a bale cubic of lower hold which had a bale cubic of 62,000. How many tons of wool can be 62,000. How many tons of wool can be stowed in the compartment, assuming stowed in the compartment, assuming 10% broken stowage?10% broken stowage?

• A. 520

• B. 654

• C. 620

• D. 558

• 21. Solution:

• Allowance = 100% - B.S

100

• Allowance = 100% - 10%

100

• Allowance = 90%

100

• Allowance = 0.9

21. Solution:21. Solution:

• Weight = Volume x Allowance

• Stowage Factor

• Weight = 62,000 ft³ x 0.9

• 100 ft³/ton

• Weight = 55,800 ft³

• 100 ft³/ton

• Weight = 558 Tons

• 22. On the fully containerized ship, 22. On the fully containerized ship, approximately one third or more of the approximately one third or more of the cargo is on deck above the rolling center. cargo is on deck above the rolling center. Top stowed containers are subject to.Top stowed containers are subject to.

• A. accelerations greater than on

conventional vessels

• B. accelerations the same as on

conventional vessels

• C. accelerations less than on conventional

vessels

• D. no accelerations

• 23. When loading bulk liquid cargo, what 23. When loading bulk liquid cargo, what is the first action you should take if a is the first action you should take if a cargo valve is jammed open?cargo valve is jammed open?

• A. Order the dock man to shutdown

• B. Call the owner, operator, or terminal

supervisor

• C. Trip the pump relieve valve

• D. Run out the vessel’s or terminal’s fire

hose

• 24. If additional weight is added above 24. If additional weight is added above the center of gravity, the vessel will:the center of gravity, the vessel will:

• A. reduce righting moments

• B. all of these

• C. reduce reserve buoyancy

• D. increase GM

• 25. Name one 25. Name one major advantagemajor advantage of of transporting transporting gas under refrigerationgas under refrigeration..

• A. less product per volume

• B. it reduces its volume

• C. it increases its volume

• D. none of these

• 26. Which of the following is classified 26. Which of the following is classified as a combustible liquid?as a combustible liquid?

• A. Tetraethylene alcohol

• B. Carbon tetrachloride

• C. Ethyl alcohol

• D. Acetaldehyde

• Grades of Petroleum ProductsGrades of Petroleum Products

• Grade Flash Pt. Reid Vapor

• A. Flammable 80º F or 14 psi or

• below above

• B. Flammable 80º F or more than 8.5

• below less than 14 psi

• C. Flammable 80º F or 8.5 psi or below

• below

• D. Combustible above 80º F but ----

• below 150º F

• E. Combustible 150º F or above -----

• 27. If a vessel is loaded in such manner 27. If a vessel is loaded in such manner that she is to be sagging, what kind of that she is to be sagging, what kind of stress is placed on the sheer strake?stress is placed on the sheer strake?

• A. Tension

• B. Thrust

• C. Compression

• D. Racking

• 28. The 28. The upward slope of a ship bottomupward slope of a ship bottom from the keel to the bilge is known as ___.from the keel to the bilge is known as ___.

• A. slope

• B. dead rise

• C. camber

• D. keel height

• 29. Which product is 29. Which product is MOST likely to MOST likely to accumulate static electricityaccumulate static electricity??

• A. Hard asphalt

• B. Lubricating oil

• C. Crude oil

• D. Residual fuel oil

• 30. What is the 30. What is the minimum distanceminimum distance from any shoreline that from any shoreline that oily wastes oily wastes may be pump out over the sidemay be pump out over the side??

• A. 25 miles

• B. 50 miles

• C. 75 miles

• D. 100 miles

• 31. Liquefied flammable gas is defined 31. Liquefied flammable gas is defined as any flammable gas having a Reid as any flammable gas having a Reid vapor pressure exceeding __________ vapor pressure exceeding __________ poundspounds..

• A. 30

• B. 40

• C. 14

• D. 50

• 32. The normal tendency for a loaded 32. The normal tendency for a loaded tanker is to:tanker is to:

• A. sag

• B. hog

• C. very tender

• D. permanent list

• 33. A box-shaped barge 16 m x 6 m 5 m is 33. A box-shaped barge 16 m x 6 m 5 m is floating alongside a ship in fresh water at floating alongside a ship in fresh water at a mean draft of 3.5 m. The barge is to be a mean draft of 3.5 m. The barge is to be lifted out of the water and loaded on to the lifted out of the water and loaded on to the ship with a heavy lift derrick. Find the load ship with a heavy lift derrick. Find the load in tons borne by the purchase when the in tons borne by the purchase when the draft of the barge is reduced to 2 m.draft of the barge is reduced to 2 m.

• A. 144 tons

• B. 166 tons

• C. 155 tons

• D. None of these

• 33. Solution: 33. Solution:

• Weight = L x W x (Depth - Draft) x Rel. Den.

• Weight = 16m x 6m x (5m – 3.5m) x 1.000

• Weight = 16m x 6m x 1.5m x 1.000 kgs/m³

• Weight = 144 tons

• 34. A vessel is at a dock where the water 34. A vessel is at a dock where the water density is 1,000. She draws 36’ 04”. What density is 1,000. She draws 36’ 04”. What would she draw in salt water having would she draw in salt water having density of 1,026?density of 1,026?

• A. 36’ 04”

• B. 34’ 06”

• C. 37’ 03”

• D. 35’ 05”

• 34. Solution:34. Solution:

• New Draft x Old Density

Old Draft New Density

• New Draft x 1,000 kgs./m³

36’ 04” 1,026 kgs./m³

• New Draft = 36’ 04”(36.33) x 1,000 kgs./m³

1,026 kgs./m³

• New Draft = 35’ 05”

• 35. It is compose of steel plate, not of 35. It is compose of steel plate, not of these are rectangles in shape. Arrange in these are rectangles in shape. Arrange in longitudinal manner on the ship and longitudinal manner on the ship and placed one after the other from the stem placed one after the other from the stem to stern.to stern.

• A. shell plating

• B. stringers

• C. strake

• D. frames

• 36. Which is 36. Which is NOT a safety precaution to NOT a safety precaution to be observed during the loading of LNGbe observed during the loading of LNG??

• A. Ascertain that the hoses to be used are in

good order

• B. Report any leakage of cargo

• C. Make sure the rake ends of the barge are

completely dry and mopped

• D. Be on the lookout for work being

accomplished ashore in the vicinity of the

barges

• 37. A vessel that displaces 28,500 tons 37. A vessel that displaces 28,500 tons has a KG of 30 ft., 1,550 tons are has a KG of 30 ft., 1,550 tons are discharged with a center of gravity of 12 discharged with a center of gravity of 12 ft. above the keel. What would be the new ft. above the keel. What would be the new center of gravity?center of gravity?

• A. 31 ft.

• B. 30 ft.

• C. 29 ft.

• D. 32 ft.

• 37.37. Solution:

• Weight KG Moments

• Δ = 28,500 t x 30 ft. 855,000

• Disch. = 1,550 t x 12 ft. 18,600 (-)

• 26,950 t 836,400

• NKG = Total Moments

• Total Weight

• NKG = 836,400 ft./tons

• 26,959 tons

• NKG = 31 ft.

• 38. Determine the free surface constant 38. Determine the free surface constant for a tank that is 70 ft. long by 35 feet for a tank that is 70 ft. long by 35 feet wide by 25 ft. deep. The specific gravity of wide by 25 ft. deep. The specific gravity of the liquid in the tank is 0.78 and the ship the liquid in the tank is 0.78 and the ship is floating in salt water having a density is floating in salt water having a density of 1.026.of 1.026.

• A. 4,800.2

• B. 5,430.8

• C. 8,770.8

• D. 5,573.0

• 38. Solution:

• FSK = r x l x b³

420

• r = S.G. of Liquid inside the Tank

S.G. of where the vsl. Is floating

• r = 0.78

1.026

• r = 0.76

• 38. Solution:38. Solution:

• FSK = r x l x b³

420

• FSK = 0.76 x 70 ft. x 35 ft.³

420

• FSK = 5,430.8

• 39. Your vessel is taking on fuel when a 39. Your vessel is taking on fuel when a small leak develops in the hose. You order small leak develops in the hose. You order the pumping stopped. Before you resume the pumping stopped. Before you resume pumping, you should.pumping, you should.

• A. repair the hose with a patch

• B. place a large drip pan under the leak and

plug the scuppers

• C. notify the terminal superintendent

• D. replace the hose

• 40. A vessel in the form of a triangular 40. A vessel in the form of a triangular prism 32 m long, 8 m wide, at the top, and prism 32 m long, 8 m wide, at the top, and 5 m deep, KG 3.7 m. Find the initial 5 m deep, KG 3.7 m. Find the initial metacentric height when floating on even metacentric height when floating on even keel at 4 m. draft F and A? keel at 4 m. draft F and A?

• A. + 0.68 m

• B. + 0.48 m

• C. + 0.58 m

• D. + 0.78 m

• 40. Solution:

8 m

5 m 4 m

W L

WIDEWIDE

K K

BBGG

MM X

DEEPDEEP DRAFTDRAFT

Let x be the half breadth at the waterline

Using Ratio and Proportion

Then: X x Draft of Vsl.

Other Half Depth of Vsl.

X x 4 m

4 m 5 m

X = 16 m / 5 m

X = 3.2 m

x 2

6.4 m Breadth of Vsl. At Waterline

• KB = 2/3 x Draft

• KB = 2/3 x 4 m

• KB = 2.67 m

• BM = B² / 6 x Draft B² = Breadth of WL

• = 6.4 m x 6.4 m

• 6m x 4 m

• BM = 40.96

• 24

• BM = 1.71 m

• KB = 2.67 m

• BM = 1.71 m ( + )

• KM = 4.38 m

• KG = 3.70 m ( - )

• GM = 0.68 m

• 41. The most inherent danger in LPG is.41. The most inherent danger in LPG is.

• A. react to seawater

• B. strong odor is produced

• C. low temperature causes frostbites of

freezing

• D. when warmed becomes heavier than air

• 42. To shore up the main deck for the stowage of deck means to.

• A. distribute the weight of the cargo by

placing fore and aft planks on the main

deck

• B. weld pad eyes on deck in proper position

to secure the cargo

• C. strengthen the main deck by placing

pillars underneath it

• D. package the cargo in wooden crates so it

will damage the deck

• 43. Name one major advantage of 43. Name one major advantage of transporting gas under refrigerationtransporting gas under refrigeration..

• A. less product per volume

• B. it increase its volume

• C. it reduces its volume

• D. none of these

• 44. How many tons of cotton with a 44. How many tons of cotton with a stowage factor of 90 can you stow in a stowage factor of 90 can you stow in a hold with a bale of cubic of 66,000?hold with a bale of cubic of 66,000?

• A. 749 tons

• B. 779 tons

• C. 733 tons

• D. 795 tons

• 44. Solution:

• Weight = Volume

• S.F.

• Weight = 66,000 ft³

• 90 ft³/ton

• Weight = 733 Tons

• 45. The internal volume of a cargo hold 45. The internal volume of a cargo hold measured from the measured from the inside of the side inside of the side shell, the underside of the deck, and the shell, the underside of the deck, and the tank toptank top is known as the ________. is known as the ________.

• A. Gross tonnage

• B. Measured space

• C. Deadweight space

• D. Grain cubic

• 46. A tank will hold 153 tons when full of 46. A tank will hold 153 tons when full of fresh water. Find how many tons of oil of fresh water. Find how many tons of oil of relative density 0.8 it will hold allowing relative density 0.8 it will hold allowing 2% of the oil loaded for expansion.2% of the oil loaded for expansion.

• A. 130 tons

• B. 115 tons

• C. 120 tons

• D. 110 tons

• 46. Solution:46. Solution:

• Cap. Of Oil = Cap. of FW x Cap. For Exp.

• = 153 t x 0.98

• Cap of Oil = 149.94 tons

• Weight of Oil = Cap. of Oil x R.D. of Oil

R. D. of FW

• Weight of Oil = 149.94 t x 0.8

1.0

• Weight of Oil = 119.952 Tons

• 47.The term “oil” as used in the oil 47.The term “oil” as used in the oil pollution regulations meanspollution regulations means..

• A. sludge

• B. fuel oil

• C. oil refuse

• D. all of these

• 48. Why are most break bulk vessels built 48. Why are most break bulk vessels built with the transverse framing system rather with the transverse framing system rather than the longitudinal system?than the longitudinal system?

• A. The transverse system is more resistant to hog and sag stress

• B. The numerous longitudinal frames cause excessive broken stowage

• C. The transverse system provides better support to the varying cargo densities on the break bulk vessel.

• D. The deep web frames interfere with the stowage of break bulk cargo

• 49. A “barrel” is a unit of liquid measure equivalent to:

• A. 43 U.S. gallons at 65 F• B. 40 U.S. gallons at 50 F• C. 45 U.S. gallons at 75 F• D. 42 U.S. gallons at 60 F

• 50. Pollution regulations requires that 50. Pollution regulations requires that each scupper on deck must be equipped each scupper on deck must be equipped with:with:

• A. Two-piece soft patch

• B. Soft rubber plug

• C. Wooden plug

• D. Mechanical means of closing

MECHANICAL MEANS OF CLOSING SCUPPER

• 51. Which material should not be used to 51. Which material should not be used to secure cargo on deck for a voyage?secure cargo on deck for a voyage?

• A. Steel strapping

• B. Steel chain

• C. Wire rope

• D. Fiber rope

• 52. A ship is floating upright on an even 52. A ship is floating upright on an even keel at 6.0 m draft F and A. The areas of keel at 6.0 m draft F and A. The areas of the water-plane are as follows:the water-plane are as follows:

• Draft (m)0 1 2 3 4 5 6

• Area (sq.m.) 5000 5600 6020

6025 6025 6020 6000

• Find the ship’s KB at this draft?

• A. 3.6 meters

• B. 3.06 meters

• C. 4.16 meters

• D. 3.56 meters

• Given: Draft F & A = 6.0 m Find = Ship’s KB

• Solution:

K0

1

2

3

4

5

6 A

B C

D

E

F

G

B

WP Area SM Prod of Levers Prod of

Volume Moments

A 6,000 x 1 6,000 x 6h 36,000h

B 6,020 x 4 24,080 x 5h 120,400h

C 6.025 x 2 12,050 x 4h 48,200h

D 6,025 x 4 24,100 x 3h 72,300h

E 6,020 x 2 12,040 x 2h 24,080h

F 5,600 x 4 22,400 x 1H 22,400h

G 5,000 x 1 5,000 x 0 0h

105,670 323, 380h

• KB = Moments About Keel

• Prod. Of Volume of Δ

• KB = 323,380h

• 105,670

• KB = 3.06 m

• 53. The making of the load lines are 53. The making of the load lines are painted in __________ in a dark groundpainted in __________ in a dark ground..

• A. white

• B. yellow

• C. red

• D. black

54. Backstays are _________.54. Backstays are _________.

• A. Running rigging leading forward from the

masts

• B. Running rigging leading aft from the masts

• C. Standing rigging leading aft from the

masts

• D. Standing rigging from the crosstree to the

mast head

BACKSTAYSBACKSTAYS

• 55. Which of the following describes a 55. Which of the following describes a STIFF vessel?STIFF vessel?

• A. Pitches heavily

• B. Has an unusually high center of buoyancy

• C. Small GM

• D. Short rolling period

• 56. When loading a cargo of taconite, 56. When loading a cargo of taconite, proper sequencing of loading by hatch proper sequencing of loading by hatch number is necessary to:number is necessary to:

• A. Prevent negative stability from developing

• B. Prevent excessive longitudinal stresses

• C. Provide proper trim

• D. Control list

TACONITE a low-grade siliceous ironlow-grade siliceous iron formation in Minnesota, U.S., from which high-grade iron ore is derived. The iron formation consists of fine-grained silica with variable ratios of hematite and magnetite totaling less than 30 percent iron. Recovery of the iron requires fine grinding and concentration of iron-bearing phases, which in turn are formed into pellets suitable for taconite

• 57. A hold, which is ready to receive 57. A hold, which is ready to receive cargo, should becargo, should be::

• A. free from any odor

• B. well ventilated

• C. clean and dry

• D. all of these

• 58. To avoid excessive surge pressure 58. To avoid excessive surge pressure when ballasting, you should.when ballasting, you should.

• A. bunker at a nominal rate

• B. close valves slowly

• C. shut valves before topping off

• D. check for kinks in hose

• 59. How do you consider a hold 59. How do you consider a hold compartment where the spaces under compartment where the spaces under the hatch covers and lids are NOT the hatch covers and lids are NOT completely filled?completely filled?

• A. A compartment without free surface

• B. A partially full compartment

• C. An empty compartment

• D. A full compartment

• 60. Before loading bulk grain, bilge wells must be covered to:

• A. add strength to the bilge well strainer

• B. permit rapid flow of water to the bilge

wells

• C. prevent oil, water or other liquid from

reaching the cargo

• D. prevent cargo shifting into the bilge wells

• 61. Concerning a stiff ship, which of the 61. Concerning a stiff ship, which of the following is NOT true?following is NOT true?

• A. There is a small metacentric height

• B. The weight is concentrated low in the

vessel

• C. The height of the metacenter height is

great

• D. There is a danger of cargo breaking loose

• 62. The description of a “Stiff” vessel is.

• A. period of roll is large due to large

metacentric height

• B. she will have an unusually high center of

gravity

• C. she will pitch heavily

• D. she will have a large metacentric height

63.The accidental release of LPG cargo 63.The accidental release of LPG cargo carried at a very low temperature presents carried at a very low temperature presents an unusual risk because ____.an unusual risk because ____.

• A. of its toxic vapor

• B. it can cause a brittle fracture of the ship’s

mild steel structure members.

• C. of the possibility of explosion if it mixes

with seawater

• D. of its vigorous chemical reaction with steel

• 64. A vessel displacing 18,000 short tons 64. A vessel displacing 18,000 short tons and has a VCG of 70 ft. You dump 100 and has a VCG of 70 ft. You dump 100 short tons of water, which had a VCG of short tons of water, which had a VCG of 88 ft., what is the new KG?88 ft., what is the new KG?

• A. 30 ft.

• B. 89.9 ft.

• C. 69.9 ft.

• D. 31 ft.

• 64. Solution:

• Weight KG Moments

• Δ 18,000 70 ft. 1,260,000

• Disch. 100 88 ft. 8,800 ( - )

• 17,900 1,251,200

• NKG = Total Moments

• Total Weights

• NKG = 1,251,200 / 17,900

• NKG = 69.9 ft.

• 65. The heaviest type of pallet is the65. The heaviest type of pallet is the..

• A. shipping pallet

• B. stevedoring pallet

• C. factory pallet

• D. warehouse pallet

• 66. When stowing bagged cargo, you wish to 66. When stowing bagged cargo, you wish to maintain a vertical wall or bulkhead as the stow maintain a vertical wall or bulkhead as the stow progresses. The bulkheads extend from one progresses. The bulkheads extend from one side of the vessel to the other and extend one side of the vessel to the other and extend one section forward to the square, from the lower section forward to the square, from the lower hold up to the tween-deck. Stability of the hold up to the tween-deck. Stability of the bulkhead will best be maintained by ___.bulkhead will best be maintained by ___.

• A. Alternating the stow with on tier fore and aft the

next tier athwarships• B. Stowing the bags athwarships• C. Stowing the bags fore-and-aft• D. Stowing the bags on edge along the bulkhead

being built

• 67. Vessel displacing 740 tons and 67. Vessel displacing 740 tons and measures 141 ft. long, breadth 34 ft. What measures 141 ft. long, breadth 34 ft. What is the reduction in GM due to free surface is the reduction in GM due to free surface if the hold below measuring 41 ft. long, 30 if the hold below measuring 41 ft. long, 30 ft. wide, and 9 ft. deep is filled 2.5 ft. of ft. wide, and 9 ft. deep is filled 2.5 ft. of water each foot of water weights 35.1 water each foot of water weights 35.1 tons.tons.

• A. 1.75 ft.

• B. 3.18 ft.

• C. 2.14 ft.

• D. 2,96 ft.

67. Solution:

• Weight of Water in hold = 35.1 x 2.5 ft.

• Wt. of Water = 87.75 tons

• Old Δ = 740.00 tons ( + )

• New Δ = 827.75 tons

FSC = L x B³ 420 x Δ FSC = 41 x 30³ 420 x 827.75 FSC = 3.18 ft.

• 68. Which of the following statement is 68. Which of the following statement is TRUE concerning repairs on the hull of a TRUE concerning repairs on the hull of a vessel, which is to be riveted and welded?vessel, which is to be riveted and welded?

• A. Riveting and welding should be done

alternately at equal intervals

• B. Riveting must be completed before

welding begins

• C. Welding must be completed before

riveting begins

• D. It does not matter in what order the

operations are done

69. How long is the standard container 69. How long is the standard container used to measure equivalent units?used to measure equivalent units?

• A. 20 ft.

• B. 10 ft.

• C. 35 ft.

• D. 40 ft.

• 70. When fruit is carried as refrigerated 70. When fruit is carried as refrigerated cargo, the most frequent cause of its cargo, the most frequent cause of its being infected at the discharge port is.being infected at the discharge port is.

• A. being carried at the wrong temperature

• B. improper cleaning of the cargo spaces

• C. leaks in the ship’s refrigeration system

• D. improper handling prior to stowage

• 71. Causes of shipboard fracture are 71. Causes of shipboard fracture are primarily:primarily:

• A. notches and notch sensitive steel

• B. heavy weather

• C. low temperature

• D. unusually high bending moments

• 72. Your vessel is loaded with non-72. Your vessel is loaded with non-hygroscopic cargoes and is proceeding hygroscopic cargoes and is proceeding from a cold climate to a warm climate, from a cold climate to a warm climate, you should.you should.

• A. energize the exhaust blowers

• B. energize the intake blowers

• C. ventilate the cargo holds

• D. do not ventilate the cargo holds

• 73. Which precaution should be used 73. Which precaution should be used when taking petroleum samples?when taking petroleum samples?

• A. After filling containers with liquid, they

should be sealed with paraffin.

• B. Samples should be left open for about

one hour before capping.

• C. No lint or fibrous material should be in

the containers.

• D. All of these

• 74. On your vessel, a wire rope for the 74. On your vessel, a wire rope for the cargo gear shows signs of excessive cargo gear shows signs of excessive wear and must be replaced. In ordering a wear and must be replaced. In ordering a new wire for this 10-ton boom, what new wire for this 10-ton boom, what safety factor should you use?safety factor should you use?

• A. Six

• B. Five

• C. Three

• D. Seven

• 75. What descriptive term indicates that 75. What descriptive term indicates that the dimension is measured from the inner the dimension is measured from the inner face of the shell or deck plating?face of the shell or deck plating?

• A. Molded

• B. Effective

• C. Tonnage

• D. Register

• 76. The assigned minimum summer 76. The assigned minimum summer freeboard of any vessel may not be less freeboard of any vessel may not be less than:than:

• A. 50 mm

• B. 100 mm

• C. 250 mm

• D. 450 mm

• 77. Chlorine gas can be fatal if exposed 77. Chlorine gas can be fatal if exposed too severely. Chlorine gas is primarily a.too severely. Chlorine gas is primarily a.

• A. skin burning agent

• B. respiratory irritant

• C. blood poisoning agent

• D. nerve paralyzing agent

• 78. A weight of 250 T is loaded 95 ft. 78. A weight of 250 T is loaded 95 ft. forward the tipping center. The vessel’s forward the tipping center. The vessel’s MTI is 1000 ft. tons. What will be the MTI is 1000 ft. tons. What will be the change of trim?change of trim?

• A. 18.75 inches

• B. 11.90 inches

• C. 23.75 inches

• D. 38.01 inches

• 78. Solution:

• C.O.T. = W x D

MTI

• C.O.T. = 250 t x 95 ft.

1,000 ft/tons

• C.O.T. = 23,750

1,000

• C.O.T. = 23.75 inches

• 79. When vessel is stationary and in a 79. When vessel is stationary and in a hogging condition the main deck is under hogging condition the main deck is under __________.__________.

• A. compression stress

• B. racking stress

• C. tension stress

• D. shear stress

• 80. The mean load draft of a vessel is 24 80. The mean load draft of a vessel is 24 ft. 5 inches in salt water. What should be ft. 5 inches in salt water. What should be her draft when loading in dock water her draft when loading in dock water density of 1,005?density of 1,005?

• A. 26 ft. 4 inches

• B. 23 ft. 6.2 inches

• C. 25 ft. 9.4 inches

• D. 24 ft. 10.8 inches

• 80. Solution:

• New Draft Old Density

Old Draft New Density

• New Draft 1,025 kgs/m³

24.417 ft. 1,005 kgs/m³

• New Draft = 24.417 ft x 1,025 kgs/m³

1,005 kgs/m³

• New Draft = 24.9 ft or 24’ 10.8”

• 81. A floating vessel will behave as if all 81. A floating vessel will behave as if all of its weight is acting downward through of its weight is acting downward through the:the:

• A. center of buoyancy

• B. center of floatation

• C. center of gravity

• D. metacenter

• 82. If reefer spaces are not properly 82. If reefer spaces are not properly cleaned prior to loading cargo. It will likely cleaned prior to loading cargo. It will likely cause _______.cause _______.

• A. malfunction of the refrigeration equipment

• B. contamination of the insulation in the

space

• C. mold to develop on commodities

• D. any of these

• 83. Ship’s officers should check every 83. Ship’s officers should check every cargo compartment after it has been filled cargo compartment after it has been filled with bulk grain to ensure.with bulk grain to ensure.

• A. all void spaces are filled

• B. all lighting circuits are energized

• C. the heaviest grade is the lower hold

• D. the correct grade of cargo has been

loaded

• 84. Sugar is a cargo, which demands 84. Sugar is a cargo, which demands absolute freedom from dampness and absolute freedom from dampness and avoidance of contact with iron becauseavoidance of contact with iron because.

• A. wet sugar in contact with iron will cause

corrosion

• B. dry sugar and wet sugar will stick to each

other when damp

• C. iron will contaminate sugar

• D. green sugar is more highly refined than

dry sugar

• 85. If a cargo hose joint is leaking badly 85. If a cargo hose joint is leaking badly after you tighten up on it, you shouldafter you tighten up on it, you should..

• A. reduce pressure

• B. notify terminal operator

• C. put a drip pan under it

• D. shut down and renew gasket

86. A small quantity of ethyl marcaptan is 86. A small quantity of ethyl marcaptan is added to LPG to give it a characteristic:added to LPG to give it a characteristic:

• A. color

• B. pressure

• C. warning odor

• D. density

• 87. Find the density of fuel oil whose 87. Find the density of fuel oil whose relative density is 0.92relative density is 0.92..

• A. 910 kgs/m³

• B. 920 kgs/m³

• C. 930 kgs/m³.

• D. 900 kgs/m³

• 88. If you notice oil in the vicinity of the 88. If you notice oil in the vicinity of the vessel with bunkering, you shouldvessel with bunkering, you should..

• A. ascertain if oil is coming from your vessel

• B. stop bunkering

• C. notify the master

• D. notify terminal superintendent

• 89. What term indicates a transverse 89. What term indicates a transverse curvature of the deck?curvature of the deck?

• A. Camber

• B. Freeboard

• C. Dead rise

• D. Flare

• 90. When reading the draft marks you 90. When reading the draft marks you note that the water level is at the top of note that the water level is at the top of number 8. What is the draft?number 8. What is the draft?

• A. 8’ 03”

• B. 8’ 00”

• C. 7’ 09”

• D. 8’ 06”

• 91. Your vessel is excessively stiff. Which 91. Your vessel is excessively stiff. Which of the following would you consider in of the following would you consider in order to give her an easier ride?order to give her an easier ride?

• A. Deballast deep tanks and double bottoms

• B. Pump out wings tanks

• C. Ballast deep tanks and double bottoms

• D. Cradle the booms

• 92. What is the proper first aid for LPG 92. What is the proper first aid for LPG in the eyes?in the eyes?

• A. Apply an ice pack to the eye

• B. Flash the eye with plenty of water

• C. Keep the eyelid closed

• D. Rub the eye area clean

• 93. When a weight is shifted down, which 93. When a weight is shifted down, which of the following takes place?of the following takes place?

• A. The height of CG increases

• B. Metacentric height increases

• C. The height of CB decreases

• D. The height of metacenter increases

• 94. Which of the following is (are) correct 94. Which of the following is (are) correct concerning the function of deck beams?concerning the function of deck beams?

• I. Support the vertical deck.

• II. To act as the tie to keep the side of

the ship in place.

• A. I only

• B. Both I and II

• C. II only

• D. None of these

• 95. Saw dust is very useful dunnage 95. Saw dust is very useful dunnage for the following cargo.for the following cargo.

• A. creosoted goods

• B. camphor oil

• C. linseed oil

• D. vegetable oil

• 96. Concerning oil spill which statement is 96. Concerning oil spill which statement is CORRECT?CORRECT?

• A. They usually stay in small area.

• B. A small spill is not dangerous to marine

life.

• C. They usually disappear quickly.

• D. They may cause serious pollution as the

effect tends to be cumulative.

97. Which of the following cargoes 97. Which of the following cargoes require strips of common building lathe require strips of common building lathe as dunnage in order to carry away heat as dunnage in order to carry away heat generated by the cargo?generated by the cargo?

• A. Cardboard cartons of shoes

• B. Canned soups packaged in crakes

• C. Paper products packaged in rolls

• D. Refrigerated fruit that is ripening

• 98. What is the first step to clean a hold 98. What is the first step to clean a hold from which a coal cargo has just been from which a coal cargo has just been discharged?discharged?

• A. Open the bilge suction and rose boxes

• B. Wash down with salt water

• C. Sweep down the residue

• D. Close down ventilation

• 99. Cargo with a stowage factor of 10 can be stowed.

• I. No more than 2 or 3 feet high in a

tween-deck area.

• II. About 7 feet high in the lower hold.

• A. I and II

• B. I only

• C. None of these

• D. II only

• 100. The heel block is located ______.100. The heel block is located ______.

• A. at the base of the boom

• B. At the cargo hook

• C. near the amidships guy

• D. near the spider band