1 analysis and simulation exercises ~dc circuit analysis (1) basic circuit laws (kirchhoff ’ s...
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Analysis and Simulation Exercises ~DC Circuit Analysis (1)
Basic Circuit Laws (Kirchhoff’s Voltage/ Current Law)
Thévenin’s Theorem Norton’s Theorem
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Spice fileBridge Circuit for use with Basic Circuit LawsV 3 0 25vR1 1 2 100R2 1 0 75R3 2 3 50R4 4 0 60R5 2 4 150R6 1 4 200.OP.PRINT DC I(R1) I(R2) I(R3).PRINT DC I(R4) I(R5) I(R6).DC V 25V 25V 25V.OPT nopage.END
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Output file(1)
**** 09/19/02 11:39:09 ************** PSpice Lite (Mar 2000) ***************** Bridge Circuit for use with Basic Circuit Laws **** CIRCUIT DESCRIPTION********************************************V 3 0 25vR1 1 2 100R2 1 0 75R3 2 3 50R4 4 0 60R5 2 4 150R6 1 4 200.OP.PRINT DC I(R1) I(R2) I(R3).PRINT DC I(R4) I(R5) I(R6).DC V 25V 25V 25V.OPT nopage.END
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Output file(2)
**** DC TRANSFER CURVES TEMPERATURE = 27.000 DEG C
V I(R1) I(R2) I(R3) 2.500E+01 -9.704E-02 8.885E-02 -1.726E-01 **** DC TRANSFER CURVES TEMPERATURE = 27.000 DEG C V I(R4) I(R5) I(R6) 2.500E+01 8.379E-02 7.560E-02 8.184E-03
* SMALL SIGNAL BIAS SOLUTION TEMPERATURE =27.000 DEG C
NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE
( 1) 6.6641 ( 2) 16.3680 ( 3) 25.0000 ( 4) 5.0273
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Output file(3)
VOLTAGE SOURCE CURRENTS NAME CURRENT V -1.726E-01
TOTAL POWER DISSIPATION 4.32E+00 WATTS
**** OPERATING POINT INFORMATION TEMPERATURE = 27.000 DEG C
JOB CONCLUDEDTOTAL JOB TIME .07
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Verify Kirchhoff’s Voltage Law Check V12+V23+V30+V01=0 ?? V1= 6.6641 V2=16.3680 V3= 25.0000
V4= 5.0273 V12=V1-V2=-9.7039, V23=V2-V3=-8.632,
V30=V3=25.000, V01=-V1=-6.6641 V12+V23+V30+V01=
-9.7039 -8.632+ 25.000 -6.6641=0
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Verify Kirchhoff’s Current Law Finding the sum of the currents
entering node 1. For node 1, I21+I01+I41=0. I21= -I(R1)= 97.04mA, I01= -I(R2)=-88.85mA, I41= -I(R6)=-8.184mA I21+I01+I41=97.04 - 88.85 - 8.184 = 0.0
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Spice fileThevenin Circuit for spiceV 1 0 75vR1 1 2 100R2 2 3 150R3 2 0 200RL 3 0 1E12.OP.OPT nopage.TF V(3) V.END
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Simulation Output File (Partial)
NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE
( 1) 75.0000 ( 2) 50.0000 ( 3) 50.0000
**** SMALL-SIGNAL CHARACTERISTICS V(3)/V = 6.667E-01 INPUT RESISTANCE AT V = 3.000E+02
OUTPUT RESISTANCE AT V(3) = 2.167E+02
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Spice FileFind the short-current for R4
Norton's Theorem; Find IscV 1 0 48VR1 1 2 20KR2 2 0 20KR3 2 3 5KR4 3 0 0.001.DC V 48V 48V 48V .OP.OPT nopage.PRINT DC I(R4) V(1,2).END
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Simulation Output File**** DC TRANSFER CURVES TEMPERATURE = 27.000 DE
G C V I(R4) V(1,2) 4.800E+01 1.600E-03 4.000E+01
**** SMALL SIGNAL BIAS SOLUTION TEMPERATURE = 27.000 DEG C
NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE
( 1) 48.0000 ( 2) 8.0000 ( 3) 1.600E-06