1 database security floris geerts. course organization one introductory lecture (this one) then, a...
TRANSCRIPT
Course organization
• One introductory lecture (this one)
• Then, a range of db security topics presented by you
• You will be graded on the quality of presentation, technical depth, critical assessment of the topic and ability to answer questions raised in class
• No exam.2
Course organization• Today, after this lecture:
– Send me an email [email protected]– with your name and at most two partners (in
case we need to assign multiple persons to the same topic)
– A ranked list of the top 10 topics (11 topics)• Then I will assign the topics.• You’ll get time to study and prepare presentations • You send the slides to me, and incorporate
comments3
Topics1. Access control• Getting access
• Access control mechanisms
2. Safety & integrity• Redundancy
• Data integrity
3. Intrusion• DB specific
• Software specific
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Topics4. Cryptography
• Symmetric
• Asymmetric
• Quantum (optional)
4. Privacy & Security• Statistical DB
• Privacy preservation
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Data Security
Dorothy Denning, 1982:
• Data Security is the science and study of methods of protecting data (...) from unauthorized disclosure and modification
• Data Security = Confidentiality + Integrity
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Data Security
• Distinct from systems and network security– Assumes these are already secure
• Tools:– Cryptography, information theory, statistics, …
• Applications:– Everywhere
Topic 1Access methods: “Getting in”
• It is all about passwords and authentication- How are passwords used for authentication in
DBMS?- What kind of password control mechanisms do
DBMS have? (e.g., Oracle,…)- What makes a password good or bad?
- Techniques to check this
- Techniques to generate one
- Alternatives to passwords (e.g., captcha)8
Captcha• CAPTCHA stands for
Completely Automated Public Turing test to tell Computers and Humans Apart
• A.K.A. Reverse Turing Test, Human Interaction Proof
• The challenge: develop a software program that can create and grade challenges most humans can pass but computers cannot
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Topic 2:Access methods: control mechanisms
• How do DBMS control access to different users?
• How do DBMS assure that users can only change/query data to which they have access?
• As an example
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Discretionary Access Control (DAC) in SQL
GRANT privileges ON object TO users [WITH GRANT OPTIONS]
GRANT privileges ON object TO users [WITH GRANT OPTIONS]
privileges = SELECT | INSERT(column-name) | UPDATE(column-name) | DELETE | REFERENCES(column-name)object = table | attribute
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Examples
GRANT INSERT, DELETE ON Customers TO Yuppy WITH GRANT OPTIONS
GRANT INSERT, DELETE ON Customers TO Yuppy WITH GRANT OPTIONS
Queries allowed to Yuppy:
Queries denied to Yuppy:
INSERT INTO Customers(cid, name, address) VALUES(32940, ‘Joe Blow’, ‘Seattle’)
DELETE Customers WHERE LastPurchaseDate < 1995
INSERT INTO Customers(cid, name, address) VALUES(32940, ‘Joe Blow’, ‘Seattle’)
DELETE Customers WHERE LastPurchaseDate < 1995
SELECT Customer.addressFROM CustomerWHERE name = ‘Joe Blow’
SELECT Customer.addressFROM CustomerWHERE name = ‘Joe Blow’
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Examples
GRANT SELECT ON Customers TO MichaelGRANT SELECT ON Customers TO Michael
Now Michael can SELECT, but not INSERT or DELETE
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Examples
GRANT SELECT ON Customers TO Michael WITH GRANT OPTIONS
GRANT SELECT ON Customers TO Michael WITH GRANT OPTIONS
Michael can say this: GRANT SELECT ON Customers TO Yuppi
Now Yuppi can SELECT on Customers
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Examples
GRANT UPDATE (price) ON Product TO LeahGRANT UPDATE (price) ON Product TO Leah
Leah can update, but only Product.price, but not Product.name
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Examples
GRANT REFERENCES (cid) ON Customer TO BillGRANT REFERENCES (cid) ON Customer TO Bill
Customer(cid, name, address, balance)Orders(oid, cid, amount) cid= foreign key
Customer(cid, name, address, balance)Orders(oid, cid, amount) cid= foreign key
Now Bill can INSERT tuples into Orders
Bill has INSERT/UPDATE rights to Orders.BUT HE CAN’T INSERT ! (why ?)
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Views and Security
CREATE VIEW PublicCustomers SELECT Name, Address FROM CustomersGRANT SELECT ON PublicCustomers TO Fred
CREATE VIEW PublicCustomers SELECT Name, Address FROM CustomersGRANT SELECT ON PublicCustomers TO Fred
David says
Name Address Balance
Mary Huston 450.99
Sue Seattle -240
Joan Seattle 333.25
Ann Portland -520
David owns
Customers:Fred is notallowed to
see this
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Views and Security
Name Address Balance
Mary Huston 450.99
Sue Seattle -240
Joan Seattle 333.25
Ann Portland -520
CREATE VIEW BadCreditCustomers SELECT * FROM Customers WHERE Balance > 0GRANT SELECT ON BadCreditCustomers TO John
CREATE VIEW BadCreditCustomers SELECT * FROM Customers WHERE Balance > 0GRANT SELECT ON BadCreditCustomers TO John
David says
David owns
Customers: John isallowed tosee only >0
balances
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Revocation
REVOKE [GRANT OPTION FOR] privileges ON object FROM users { RESTRICT | CASCADE }
REVOKE [GRANT OPTION FOR] privileges ON object FROM users { RESTRICT | CASCADE }
Administrator says:
REVOKE SELECT ON Customers FROM David CASCADEREVOKE SELECT ON Customers FROM David CASCADE
John loses SELECT privileges on BadCreditCustomers
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Revocation
Joe: GRANT [….] TO Art …Art: GRANT [….] TO Bob …Bob: GRANT [….] TO Art …Joe: GRANT [….] TO Cal …Cal: GRANT [….] TO Bob …Joe: REVOKE [….] FROM Art CASCADE
Joe: GRANT [….] TO Art …Art: GRANT [….] TO Bob …Bob: GRANT [….] TO Art …Joe: GRANT [….] TO Cal …Cal: GRANT [….] TO Bob …Joe: REVOKE [….] FROM Art CASCADE
Same privilege,same object,
GRANT OPTION
What happens ??
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Other approaches
Discretionary Access Control (DAC)
Label-based Access Control (LBAC)Role-based Access Control (RBAC)Mandatory Access Control (MAC)
Pro’s and con’s of these control mechanisms?
Topic:Safety & Integrity
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It is about keeping our precious bits safe from harm.
•Disk failure which mostly goes together with data loss• System failure which can cause data inconsistency. (For example a Denial-Of-Service attack can result in system failures because of the exhaustion of system resources.
Topic 3: Recovery
• Mostly solved by redundancy:– having and organizing redundant information
so that the data stored can be recovered in case there is a disk failure.
– Where and how to store? Secondary storage, RAIDs
– How to assure that all the data has a copy somewhere
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Topic 4: Integrity
• How to assure that all data is consistent– The same data in all copies
• How to assure that nothing gets corrupted during transmission– Error correcting codes
• How to keep track of changes and possible unauthorized access– Transaction log/data auditing
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Topic 5: DB intrusion
• Intrusion prevention– detecting ongoing attacks in real time in order
to prevent damage to the database.
• Intrusion detection– Use of database auditing
• Example: SQL injection
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Search claims by:
SQL InjectionYour health insurance company lets you see the claims online:
Now search through the claims :
Dr. Lee
First login: User:
Password:
fred
********
SELECT…FROM…WHERE doctor=‘Dr. Lee’ and patientID=‘fred’SELECT…FROM…WHERE doctor=‘Dr. Lee’ and patientID=‘fred’
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SQL InjectionNow try this:
Search claims by: Dr. Lee’ OR patientID = ‘suciu’; --
Better:
Search claims by: Dr. Lee’ OR 1 = 1; --
…..WHERE doctor=‘Dr. Lee’ OR patientID=‘suciu’; --’ and patientID=‘fred’…..WHERE doctor=‘Dr. Lee’ OR patientID=‘suciu’; --’ and patientID=‘fred’
Topic 6: Software intrusion
• Leveraging Stack and Buffer overflow in programs
• How to prevent/detect such intrusions?
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Topic 7: Cryptography - symmetric
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Commonly used techniques
Same encryption and decryption key
DES, AES
Topic 9: Cryptography - Quantum
• Newest methods based on quantum computing
• You need to ask if you want this – it is a bit math heavy.
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Topic 10: Security in Statistical DBs
Goal:
• Allow arbitrary aggregate SQL queries
• Hide confidential data
• Inference
SELECT count(*)FROM PatientsWHERE age=42 and sex=‘M ’ and diagnostic=‘schizophrenia’
SELECT count(*)FROM PatientsWHERE age=42 and sex=‘M ’ and diagnostic=‘schizophrenia’
OK
SELECT nameFROM PatientWHERE age=42 and sex=‘M ’ and diagnostic=‘schizophrenia’
SELECT nameFROM PatientWHERE age=42 and sex=‘M ’ and diagnostic=‘schizophrenia’
Not OK
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First Last Age Race
Harry Stone 34 Afr-Am
John Reyser 36 Cauc
Beatrice Stone 47 Afr-am
John Ramos 22 Hisp
First Last Age Race
* Stone 30-50 Afr-Am
John R* 20-40 *
* Stone 30-50 Afr-am
John R* 20-40 *
Topic 11: Privacy preservation k-Anonymity/Randomization
Definition: each tuple is equal to at least k-1 others
Anonymizing: