1 diffraction. 2 diffraction theory (10.4 hecht) we will first develop a formalism that will...
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1
Diffraction
2
Diffraction theory (10.4 Hecht)
We will first develop a formalism that will describe the propagation of a wave – that is develop a mathematical description of Huygen’s principle
We know this
Wavefront UU
What is UU here?
3
Diffraction theory Consider two well behaved functions U1’, U2’ that
are solutions of the wave equation. Let U1’ = U1e-it ; U2’ = U2e-it
Thus U1 , U2 are the spatial part of the functions and since,
we have,
0
10'1
'
22
22
12
12
2
22
2
2
22
UkUUkU
eUv
Ut
U
vU ti
4
Green’s theorem
Consider the product U1 grad U2 = U1U2
Using Gauss’ Theorem
Where S = surface enclosing V
Thus,
SV
SdUUdVUU
2121
dSn
USdU
22
normaloutwardndSnSd ˆˆ
5
Green’s Theorem Now expand left hand side,
Do the same for U2U1 and subtract from (2), gives Green’s theorem
V S
dSn
UUdVUUUU 2212
2121
V S
dSn
UU
n
UUdVUUUU 31
22
112
222
1
6
Green’s theorem
Now for functions satisfying the wave equation (1), i.e.
Consequently,
since the LHS of (3) = 0
12
12
22
22 UkUUkU
4012
21
dSn
UU
n
UU
S
7
Green’s theorem applied to spherical wave propagation Let the disturbance at t=0 be,
where r is measured from point P in V and U1 = “Green’s function”
Since there is a singularity at the point P, draw a small sphere P, of radius , around P (with P at centre)
Then integrate over +P, and take limit as 0
r
eUU
ikr
o11
8
Spherical Wave propagation
522
2
22
dr
e
rU
r
U
r
e
dSr
e
nU
n
U
r
e
P r
ikrikr
ikrikr
n̂
P
n̂
Thus (4) can be written,Thus (4) can be written,
9
Spherical Wave propagation
In (5), an element of area on P is defined in terms of solid angle
and we have used
Now consider first term on RHS of (5)
dddS
d sin2
rn
1022
0 limlim Idr
Ue
r
ik
10
Kirchoff’s Integral Theorem
Now U2 = continuous function and thus the derivative is bounded (assume)
Its maximum value in V = C Then since eik 1 as 0 we have,
The second term on the RHS of (5)
rU
2
0limlim 010 CdI
dr
e
rUI
r
ikr2
2020 limlim
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Kirchoff’s Integral Theorem
dUikU
deik
U
dr
e
rUI
ik
r
ikr
220
2220
22020
lim
1lim
limlim
Now as 0 U2(r) UP (its value at P)
and, PPP UdUdU 4
Now designate the disturbance U as an electric field E
12
Kirchoff integral theorem
64 dSn
E
r
e
r
e
nEE
ikrikr
P
This gives the value of disturbance at P in terms of values on surface enclosing P.
It represents the basic equation of It represents the basic equation of scalar diffraction scalar diffraction theorytheory
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Geometry of single slit
n̂
n̂
R
S P
’
Have infinite screen with aperture A
Radiation from source, S, arrives at aperture with amplitude
'
'
r
eEE
ikr
o
Let the hemisphere (radius R) and screen with aperture comprise the surface () enclosing P.
Since R
E=0 on .
Also, E = 0 on side of screen facing V.
r’r
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Fresnel-Kirchoff Formula Thus E=0 everywhere on surface except the
portion that is the aperture. Thus from (6)
dSr
e
nr
e
r
e
nr
eE
ikrikrikrikr
P
''
4''
)7(1
ˆˆ
ˆˆ
..
,'
'ˆˆ'ˆˆˆˆ
2ikr
ikrikr
err
ikrn
r
e
rrn
r
e
nge
Thusr
rnnn
andr
rnnn
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Fresnel-Kirchoff Formula
Now assume r, r’ >> ; then k/r >> 1/r2
Then the second term in (7) drops out and we are left with,
'coscos2
1'ˆˆˆˆ
2
1
'
,
'ˆˆˆˆ'
4
'
'
rnrnF
dSFrr
eiEE
or
dSrnrnikrr
eEE
aperture
rriko
P
aperture
rrik
oP
Fresnel Kirchoff Fresnel Kirchoff diffraction formuladiffraction formula
16
Obliquity factor
Since we usually have ’ = - or n.r’=-1, the obliquity factor
F() = ½ [1+cos ] Also in most applications we will also
assume that cos 1 ; and F() = 1 For now however, keep F()
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Huygen’s principle
Amplitude at aperture due to source S is,
Now suppose each element of area dA gives rise to a spherical wavelet with amplitude dE = EAdA
Then at P,
Then equation (6) says that the total disturbance at P is just proportional to the sum of all the wavelets weighted by the obliquity factor F()
This is just a mathematical statement of Huygen’s principle.
'
'
r
eEE
ikr
oA
r
edAEdE
ikr
AP
FdEP
18
Fraunhofer vs. Fresnel diffraction
In Fraunhofer diffraction, both incident and diffracted waves may be considered to be plane (i.e. both S and P are a large distance away)
If either S or P are close enough that wavefront curvature is not negligible, then we have Fresnel diffraction
P
S
Hecht 10.2Hecht 10.2 Hecht 10.3Hecht 10.3
19
Fraunhofer vs. Fresnel Diffraction
S
P
d’
d
’
hh’
r’ r
20
Fraunhofer Vs. Fresnel Diffraction
2
2222
22222222
'
11
2
1
'
'
2
11
'
'
2
11'
2
11
'
'
2
11'
'''
ddd
h
d
h
d
hd
d
hd
d
hd
d
hd
hdhdhdhd
Now calculate variation in (r+r’) in going from one side of aperture to the other. Call it
21
Fraunhofer diffraction limit
Now, first term = path difference for plane waves
’
sinsin’
sin’≈ h’/d’
sin ≈ h/d
sin’ + sin = ( h’/d + h/d )
Second term = measure of curvature of wavefront
Fraunhofer Diffraction
21
'
1
2
1
dd
22
Fraunhofer diffraction limit
If aperture is a square - X The same relation holds in azimuthal plane and 2
~ measure of the area of the aperture Then we have the Fraunhofer diffraction if,
apertureofaread
or
d
,
2
Fraunhofer or far field limit
23
Fraunhofer, Fresnel limits
The near field, or Fresnel, limit is
See 10.1.2 of text
2
d
24
Fraunhofer diffraction Typical arrangement (or use laser as a
source of plane waves) Plane waves in, plane waves out
S
f1 f2
screen
25
Fraunhofer diffraction
1. Obliquity factorAssume S on axis, so Assume small ( < 30o), so
2. Assume uniform illumination over aperture
r’ >> so is constant over the aperture
3. Dimensions of aperture << rr will not vary much in denominator for calculation of amplitude at any point Pconsider r = constant in denominator
1'ˆˆ rn1ˆˆ rn
'
'
r
eikr
26
Fraunhofer diffraction
Then the magnitude of the electric field at P is,
aperture
ikrikr
oP dSe
rr
eikEE
'2
'
27
Single slit Fraunhofer diffraction
y = b
y
dy
P
ro
r
r = ro - ysin
dA = L dy
where L ( very long slit)
28
Single slit Fraunhofer diffraction
'2sin
2
,
sin
_______________
'
sin
rr
eikEC
kb
where
ebCeE
dyeeCE
dAeCE
ikro
iikrP
ikyb
o
ikrP
ikrP
o
o
2
2sin
oII
Fraunhofer single slit diffraction pattern
2bCIo