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Page 1: 1 Econ 240A Power 17. 2 Outline Review Projects 3 Review: Big Picture 1 #1 Descriptive Statistics –Numerical central tendency: mean, median, mode dispersion:

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Econ 240AEcon 240A

Power 17Power 17

Page 2: 1 Econ 240A Power 17. 2 Outline Review Projects 3 Review: Big Picture 1 #1 Descriptive Statistics –Numerical central tendency: mean, median, mode dispersion:

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OutlineOutline

• Review

• Projects

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Review: Big Picture 1Review: Big Picture 1• #1 Descriptive Statistics

– Numericalcentral tendency: mean, median, modedispersion: std. dev., IQR, max-minskewnesskurtosis

– Graphical• Bar plots• Histograms• Scatter plots: y vs. x• Plots of a series against time (traces)

Question: Is (are) the variable (s) normal?

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Review: Big Picture 2Review: Big Picture 2

• # 2 Exploratory Data Analysis– Graphical

• Stem and leaf diagrams• Box plots• 3-D plots

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Review: Big Picture 3Review: Big Picture 3• #3 Inferential statistics

– Random variables– Probability– Distributions

• Discrete: Equi-probable (uniform), binomial, Poisson– Probability density, Cumulative Distribution Function

• Continuous: normal, uniform, exponential– Density, CDF

• Standardized Normal, z~N(0,1)– Density and CDF are tabulated

• Bivariate normal– Joint density, marginal distributions, conditional distributions– Pearson correlation coefficient, iso-probability contours

– Applications: sample proportions from polls

),(~:,//ˆ npBxwherenxnsuccessesp

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Review: Big Picture 4Review: Big Picture 4• Inferential Statistics, Cont.

– The distribution of the sample mean is different than the distribution of the random variable

• Central limit theorem

– Confidence intervals for the unknown population mean

nxxExz x //][/][

95.0]/96.1/96.1[ nxnxp

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Review: Big Picture 5Review: Big Picture 5• Inferential Statistics

– If population variance is unknown, use sample standard deviation s, and Student’s t-distribution

– Hypothesis tests

– Decision theory: minimize the expected costs of errors• Type I error, Type II error

– Non-parametric statistics• techniques of inference if variable is not normally distributed

95.0]//[ 025.0025.0 nstxnstxp

)//(][,0:,0:0 nsxExtHH A

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Review: Big Picture 6Review: Big Picture 6• Regression, Bivariate and Multivariate

– Time series• Linear trend: y(t) = a + b*t +e(t)• Exponential trend: ln y(t) = a +b*t +e(t)• Quadratic trend: y(t) = a + b*t +c*t2 + e(t)• Elasticity estimation: lny(t) = a + b*lnx(t) +e(t)

• Returns Generating Process: ri(t) = c + rM(t) + e(t)

• Problem: autocorrelation– Diagnostic: Durbin-Watson statistic

– Diagnostic: inertial pattern in plot(trace) of residual

– Fix-up: Cochran-Orcutt

– Fix-up: First difference equation

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Review: Big Picture 7Review: Big Picture 7• Regression, Bivariate and Multivariate

– Cross-section• Linear: y(i) = a + b*x(i) + e(i), i=1,n ; b=dy/dx• Elasticity or log-log: lny(i) = a + b*lnx(i) + e(i); b=(dy/dx)/(y/x)• Linear probability model: y=1 for yes, y=0 for no; y =a + b*x +e• Probit or Logit probability model• Problem: heteroskedasticity• Diagnostic: pattern of residual(or residual squared) with y and/or x• Diagnostic: White heteroskedasticity test• Fix-up: transform equation, for example, divide by x

– Table of ANOVA• Source of variation: explained, unexplained, total• Sum of squares, degrees of freedom, mean square, F test

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Review: Big Picture 8Review: Big Picture 8• Questions: quantitative dependent, qualitative

explanatory variables– Null: No difference in means between two or more

populations (groups), One Factor• Graph• Table of ANOVA• Regression Using Dummies

– Null: No difference in means between two or more populations (groups), Two Factors

• Graph• Table of ANOVA• Comparing Regressions Using Dummies

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Review: Big Picture 9Review: Big Picture 9

• Cross-classification: nominal categories, e.g. male or female, ordinal categories e.g. better or worse, or quantitative intervals e.g. 13-19, 20-29– Two Factors mxn; (m-1)x(n-1) degrees of freedom– Null: independence between factors; expected

number in cell (i,j) = p(i)*p(j)*n– Pearson Chi- square statistic = sum over all i, j of

[observed(i, j) – expected(i, j)]2 /expected(i, j)

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SummarySummary

• Is there any relationship between 2 or more variables– quantitative y and x: graphs and regression– Qualitative binary y and quantitative x:

probability model, linear or non-linear– Quantitative y and qualitative x: graphs and

Tables of ANOVA, and regressions with indicator variables

– Qualitative y and x: Contingency Tables

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ProjectsProjects

• Learning by doing

• Learning from one another

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Control of Social ProblemsControl of Social Problems

• HIV/AIDS

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HIV/AIDS HIV/AIDS What can we do to What can we do to

prevent it?!prevent it?!Group 4:Group 4:

Pinar SahinPinar SahinDarren EganDarren EganDavid WhiteDavid WhiteYuan YuanYuan Yuan

Miguel Delgado HelleseterMiguel Delgado HelleseterDavid RhodesDavid Rhodes

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable

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Is there a relationship?Is there a relationship?

#of HIV vs CDC expenditure

y = -78.53x + 104053

R2 = 0.610

10000

20000

30000

40000

50000

60000

70000

80000

500 600 700 800 900 1000

CDC expenditure ($million)

num

ber o

f mor

bidi

ty

regression of HIV infection and CDC expenditureDependent Variable: INFECTMethod: Least SquaresDate: 11/21/03 Time: 17:10Sample: 1 9Included observations: 9

Variable Coefficient Std. Error t-Statistic Prob.

CDCMONEY -78.5302 23.73235 -3.3089951 0.012959C 104053.4 17180.64 6.05643533 0.000513

R-squared 0.610016 Mean dependent var 48122.44Adjusted R-squared 0.554304 S.D. dependent var 13830.59S.E. of regression 9233.366 Akaike info criterion 21.29216Sum squared resid 5.97E+08 Schwarz criterion 21.33599Log likelihood -93.8147 F-statistic 10.94945Durbin-Watson stat 0.822936 Prob(F-statistic) 0.012959

both of t and F statistic are significant. R-squared is 0.61, which is also fine.

• Both the t and F statistics are significant• R^2 is .61, which is decent Group 4

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HIV/AIDS cases vs. per capita HIV/AIDS cases vs. per capita funding per statefunding per state

Dependent Variable: INFECTMethod: Least SquaresDate: 11/21/03 Time: 18:07Sample: 1 50Included observations: 50

Variable Coefficient Std. Error t-Statistic Prob.

PERCAPFUND 5.605922 2.044885 2.74143582 0.008568C 4.614507 2.447325 1.88553113 0.065418

R-squared 0.135376 Mean dependent var 10.518Adjusted R-squared 0.117363 S.D. dependent var 8.751926S.E. of regression 8.222325 Akaike info criterion 7.090761Sum squared resid 3245.118 Schwarz criterion 7.167242Log likelihood -175.269 F-statistic 7.51547Durbin-Watson stat 1.952071 Prob(F-statistic) 0.008568

# of cases VS per Capital funding per state

0

20

40

60

80

100

120

140

160

0 2 4 6 8 10 12

per Capita funding per state

# o

f cas

es p

er 1

00,0

00

peo

ple

Group 4

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Controlling Social ProblemsControlling Social Problems

• This same analytical framework works for various social ills– Morbidity per capita– Offenses per capita– Pollution per capita

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable

Offenses Per Capita

PollutionPer Capita

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Source: Report to the Nation on Crime and Justice

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Source: Report to the Nation on Crime and Justice

control

Causalfactors

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Not Controllable

Controllability is an empiricalquestion that we want to answer

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Optimizing BehaviorOptimizing Behavior

• Cost Curve: – Cost = Damages from Morbidity + Abatement

Expenditures– C = p*M + Exp

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Cost CurveCost Curve

Abatement Exp

Morbidity M

C = p*M + Exp

Exp=0, M=C/p

M=0, Exp=C

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Family of Cost CurvesFamily of Cost Curves

Abatement Exp

Morbidity M

Higher Cost

Lower Cost

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Not Controllable: Don’t Throw Money At It

Higher Cost

Lowest Cost

Optimum: ZeroAbatement

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Optimum Expenditures

Lowest Attainable Cost

Optimum

Higher Cost Curve

Page 29: 1 Econ 240A Power 17. 2 Outline Review Projects 3 Review: Big Picture 1 #1 Descriptive Statistics –Numerical central tendency: mean, median, mode dispersion:

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Optimum Expenditures

Lowest Attainable Cost

Optimum

Higher Cost Curve

Spend too MuchBut Morbidity Is Low

Page 30: 1 Econ 240A Power 17. 2 Outline Review Projects 3 Review: Big Picture 1 #1 Descriptive Statistics –Numerical central tendency: mean, median, mode dispersion:

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Optimum Expenditures

Lowest Attainable Cost

Optimum

Higher Cost Curve

Spend Too Little, Morbidity Is Too High

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Economic ParadigmEconomic Paradigm

• Step One: Describe the feasible alternatives

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable

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Economic ParadigmEconomic Paradigm

• Step One: Describe the feasible alternatives

• Step Two: Value the alternatives

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Cost CurveCost Curve

Abatement Exp

Morbidity M

C = p*M + Exp

Exp=0, M=C/p

M=0, Exp=C

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Economic ParadigmEconomic Paradigm

• Step One: Describe the feasible alternatives

• Step Two: Value the alternatives

• Step Three: Optimize, pick the lowest cost alternative

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Optimum Expenditures

Lowest Attainable Cost

Optimum

Higher Cost Curve

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Family of Control Curves

Control CurveAnother TimeOr Another Place

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Behind the Control CurveBehind the Control Curve

• Morbidity Generation– M = f(sex-ed, risky behavior)– M = f(sex-ed, RB)

• Producing Morbidity Abatement– Sex-ed = g(labor)– Sex-ed = g(L)

• Abatement Expendtiture– Exp = wage*labor = w*L

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Morbidity GenerationMorbidity Generation

Morbidity, M

Sex-ed

M = f(Sex-ed, RB)

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Morbidity GenerationMorbidity Generation

Morbidity, M

Sex-ed

M = f(Sex-ed, RB)

Riskier behavior

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Production FunctionProduction Function

Sex-ed

Labor, L

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Expenditure On Wage Bill Expenditure On Wage Bill (Abatement)(Abatement)

Labor, L

Exp

Exp = w*L

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Control CurveControl Curve

Labor,L

Exp

Exp = w*L

Sex-ed

Sex-ed = g(L)

Morbidity, M

M = f(Sex-ed, RB)

ExpenditurefunctionProduction function

Morbidity Generation

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Control CurveControl Curve

Labor,L

Exp

Exp = w*L

Sex-ed

Sex-ed = g(L)

Morbidity, M

M = f(Sex-ed, RB)

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Control CurveControl Curve

Labor,L

Exp

Exp = w*L

Sex-ed

Sex-ed = g(L)

Morbidity, M

M = f(Sex-ed, RB)

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Control CurveControl Curve

Labor,L

Exp

Exp = w*L

Sex-ed

Sex-ed = g(L)

Morbidity, M

M = f(Sex-ed, RB)

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Control CurveControl Curve

Labor,L

Exp

Exp = w*L

Sex-ed

Sex-ed = g(L)

Morbidity, M

M = f(Sex-ed, RB)

Higher Risky Behavior

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ExerciseExercise

• Derive the control curve for the jurisdiction with more risky behavior

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Expansion PathExpansion Path

• Assume the family of control curves is nested, i.e. have the same slope along any ray from the origin

• Assume all jurisdictions place the same value, p, on morbidity

• Assume all jurisdictions are optimizing

• Then the expansion path is a ray from the origin

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Family of Control Curves

Control CurveAnother TimeOr Another Place

Expansion path

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Family of Control Curves

Control CurveAnother TimeOr Another Place

Expansion path

M

Exp

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Econometric IssuesEconometric Issues

• Two Relationships– Control curve: M = h(exp, RB)– Expansion path: M/EXP = k

• Variation in risky behavior from one jurisdiction to the next shifts the control curve and traces out (identifies) the expansion path

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• Unless price, technology, or optimizing behavior changes from jurisdiction to jurisdiction, there will not be enough movement in the expansion path to trace out(identify) the control curve

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MorbidityPer capita

Abatement ExpenditurePer Capita

Control Curve

The Problem is Controllable: Family of Control Curves

Control CurveAnother TimeOr Another Place

Expansion path

M

Exp

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California Expenditure VS. California Expenditure VS. ImmigrationImmigration

By: Daniel Jiang, Keith Cochran, By: Daniel Jiang, Keith Cochran, Justin Adams, Hung Lam, Steven Justin Adams, Hung Lam, Steven

Carlson, Gregory WiefelCarlson, Gregory Wiefel

Fall 2003Fall 2003

Page 56: 1 Econ 240A Power 17. 2 Outline Review Projects 3 Review: Big Picture 1 #1 Descriptive Statistics –Numerical central tendency: mean, median, mode dispersion:

Immigration VS ExpenditureImmigration VS Expenditure

Immigration VS Expenditure

y = 0.2363x + 814.96

R2 = 0.3733

20000

30000

40000

50000

60000

70000

80000

90000

100000 150000 200000 250000 300000 350000

Immigration

Exp

end

itu

re

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SimultaneitySimultaneity

Immigration

CA EXP

Expenditurefunction

ImmigrationFunction

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Simultaneity ConceptsSimultaneity Concepts• Jointly determined: Morbidity and abatement

expenditure are jointly determined by the control curve and the cost curve

• Morbidity and abatement expenditure are referred to as endogenous variables

• Risky behavior is an exogenous variable• For a 2-equation simultaneous system, at

least one exogenous variable must be excluded from a behavioral (structural) equation to identify it

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TheoryTheory

• Minimize Cost, C = p*M + Exp• Subject to the control curve, M = h(Exp, RB)• Lagrangian, La = p*M + Exp + [M-h(RB, Exp]

• Slope of the control curve = slope of cost curve

pExph

ExphExpLa

pMLa

/1/1/

0/1/

0/

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ModelModel

• Production Function: Cobb-Douglas– Sex-ed = a*Lb *eu b>0

• Abatement Expenditure– Exp = w*L

• Morbidity Abatement– M = d*sex-edm *RBn *ev m<0, n>0

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Model Cont.Model Cont.• Combine production function, expenditure and

morbidity abatement functions to obtain control function– M = d*[a*Lb *eu ]m *RBn *ev

– M = d*[a*(exp/w)b *eu ]m *RBn *ev

– M = d* am * expb*m * w-b*m *RBn *eu*m *ev

– lnM = ln(d*am) + b*m lnexp –b*m lnw + n* lnRB + (u*m + v)

– Or assuming w is constant: y1 = constant1 + b*m y2 + n x + error1

– We would like to show that b*m is negative, i.e. that morbidity is controllable

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Model Cont.Model Cont.

• Expansion Path– M/exp = k*ez

– lnM = -lnexp + lnk + z– Or y1 = constant2 – y2 + error2

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Reduced FormReduced Form• Solve for y1 and y2, the two endogenous

variables• y1 = [constant1 + constant2]/(1-b*m) + n/(1-b*m)

x + (error1 + b*m error2)/(1-b*m)• y2 ={ -[constant1 + constant2]/(1-b*m) +

constant2} - n/(1-b*m) x + {-(error1 + b*m error2)/(1-b*m) + error2}

• There is no way to get from the estimated parameter on x, n/(1 – b*m) to n or b*m, the parameters of interest for the control function

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