1 equations and inequalities © 2008 pearson addison-wesley. all rights reserved sections 1.1–1.4

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1 Equations and Inequalities © 2008 Pearson Addison-Wesley. All rights reserved Sections 1.1– 1.4

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1Equations and Inequalities

© 2008 Pearson Addison-Wesley.All rights reserved

Sections 1.1–1.4

1.3 Complex Numbers

1.4 Quadratic Equations

Equations and Inequalities1

Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 1-3

Complex Numbers1.3Basic Concepts of Complex Numbers ▪ Operations on Complex Numbers

Basic Concepts of Complex Numbers

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The set of real numbers is a subset of the overall set of Complex Numbers. In order to extend the set of real numbers to include even roots of negative numbers such as , the number i is defined to have the following property: i2 = -1.1

From this definition, we have the imaginary unit, . Numbers in the form a + bi where a and b are real numbers, are called complex numbers. In the complexNumber a + bi , a is the real part and b is the imaginary part.

1i

Complex Numbers, cont’d

The standard form of a complex number is written as a + bi , with the real and imaginary parts separated.

Now when dealing with negative values under an even radical, the negative sign can be separated as follows, for a > 0:

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1.3 Example 1 Writing √–a as i√a (page 104)

Write as the product of a real number and i.

(a)

(b)

(c)

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1.3 Example 2 Finding Products and Quotients Involving Negative Radicands (page 105)

Multiply or divide. Simplify each answer.

(a)

(b)

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1.3 Example 2 Finding Products and Quotients Involving Negative Radicands (cont.)

Multiply or divide. Simplify each answer.

(c)

(d)

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1.3 Example 3 Simplifying a Quotient Involving a Negative Radicand (page 105)

Write in standard form a + bi.

Factor.

Operations with Complex Numbers

Addition and Subtraction:

Multiplication:

Powers of i :

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idbcadicbia

ibcadbdacdicbia

1 1 1

1 1 1

1284

1173

1062

951

iii

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Complex Conjugates

For a complex number a + bi , its conjugate has the form, a - bi . The pair is referred to as complex conjugates.

For real numbers a and b,

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22 babiabia

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1.3 Example 4 Adding and Subtracting Complex Numbers

(page 106)

Find each sum or difference.

(a) (4 – 5i) + (–5 + 8i)

= –1 + 3i

= [4 + (–5)] + (–5i + 8i)

(b) (–6 + 3i) + (12 – 9i) = 6 – 6i

(c) (–10 + 7i) – (5 – 3i)

= –15 + 10i

(d) (15 – 8i) – (–10 + 4i) = 25 – 12i

= (–10 – 5) + [7i + (3i)]

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1.3 Example 5 Multiplying Complex Numbers (page 107)

Find each product.

(a) (5 + 3i)(2 – 7i)

(b) (4 – 5i)2

= 5(2) + (5)(–7i) + (3i)(2) + (3i)(–7i)

= 10 – 35i + 6i – 21i2

= 10 – 29i – 21(–1)

= 31 – 29i

= 42 – 2(4)(5i) + (5i)2

= 16 – 40i + 25i2

= 16 – 40i + 25(–1)

= –9 – 40i

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1.3 Example 5 Multiplying Complex Numbers (cont.)

Find the product.

(c) (9 – 8i)(9 + 8i) = 92 – (8i)2

= 81 – 64i2

= 81 – 64(–1)

= 81 + 64

= 145 or 145 + 0i

This screen shows how theTI–83/84 Plus displays theresults in this example.

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1.3 Example 6 Simplifying Powers of i (page 107)

Simplify each power of i.

Write the given power as a product involving or .

(a) (b)

(a) (b)

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1.3 Example 7(a) Dividing Complex Numbers (page 108)

Write in standard form a + bi.Multiply the numerator and denominator by the complex conjugate of the denominator.

i2 = –1

Combine terms.

Lowest terms; standard form

Multiply.

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1.3 Example 7(b) Dividing Complex Numbers (page 108)

Write in standard form a + bi.Multiply the numerator and denominator by the complex conjugate of the denominator.

–i2 = 1

Lowest terms; standard form

Multiply.

This screen shows how theTI–83/84 Plus displays theresults in this example.

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Quadratic Equations1.4Solving a Quadratic Equation ▪ Completing the Square ▪The Quadratic Formula ▪ Solving for a Specified Variable ▪ The Discriminant

Solving Quadratic EquationsAn equation that can be written in the form

where a, b, and c are real numbers with a ≠ 0, is a quadratic equation.

The given form is called the standard form.

A quadratic equation is a second-degree equation – that is, an equation with a squared variable term as the highest degree.

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Zero-Factor Property

If a and b are complex numbers with ab = 0, then a = 0 or b = 0 or both.

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1.4 Example 1 Using the Zero-Factor Property (page 111)

Solve .

Factor.

Set each factor equal to 0 and then solve for x.

or

or

or

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1.4 Example 1 Using the Zero-Factor Property (cont.)

Now check.

Solution set:

Solving Quadratic Equations

That is the solution set of the equation includes the postive and the negative values. If k = 0, then there is a double solution.

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Square Root PropertyIf x2 = k, then

kxkx or

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1.4 Example 2 Using the Square Root Property (page 112)

Solve each quadratic equation.

Generalized square root property

(a)

(c)

(b)

Completing the Square

To solve by completing the square:

1. If a ≠ 1, divide both sides of the equation by a.

2. Rewrite the equation so that the constant term is alone on one side of the equality symbol.

3. Square half the coefficient of x, and add this square to both sides of the equation.

4. Factor the resulting trinomial as a perfect square and combine the constant terms on the other side.

5. Use the square root property to complete the solution.

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0 ,02 acbxax

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1.4 Example 3 Using the Method of Completing the Square, a = 1 (page 113)

Solve by completing the square.

Rewrite the equation so that the constant is alone on one side of the equation.

Square half the coefficient of x, and add this square to both sides of the equation.

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1.4 Example 3 Using the Method of Completing the Square, a = 1 (cont.)

Factor the resulting trinomial as a perfect square and combine terms on the other side.

Use the square root property to complete the solution.

Solution set:

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1.4 Example 4 Using the Method of Completing the Square, a ≠ 1 (page 113)

Solve by completing the square.

Rewrite the equation so that the constant is alone on one side of the equation.

Square half the coefficient of x, and add this square to both sides of the equation.

Divide both sides of the equation by a, 4.

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1.4 Example 4 Using the Method of Completing the Square, a ≠ 1 (cont.)

Factor the resulting trinomial as a perfect square and combine terms on the other side.

Use the square root property to complete the solution.

Solution set:

The Quadratic Formula

The method of completing the square can be used to solve any quadratic equation. If this method is applied to the standard form for the quadratic equation, the results is the Quadratic Formula:

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a

acbbx

2

42

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1.4 Example 5 Using the Quadratic Formula (Real Solutions)

(page 115) Solve .

a = 1, b = 6, c = –3

Write the equation in standard form.

Quadratic formula

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1.4 Example 5 Using the Quadratic Formula (Real Solutions)

(cont.)

Solution set:

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1.4 Example 6 Using the Quadratic Formula (Nonreal Complex Solutions) (page 115)

Solve .

a = 4, b = –3, c = 5

Write the equation in standard form.

Quadratic formula

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1.4 Example 6 Using the Quadratic Formula (Nonreal Complex Solutions) (page 115)

Solution set:

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1.4 Example 8(a) Solving for a Quadratic Variable in a Formula (page 116)

Solve for r. Use ± when taking square roots.

Goal: Isolate r.

Multiply by 3.

Divide by πh.

Square root property

Rationalize the denominator.

Simplify.

The Discriminant

Discriminant Number of Solutions Type of Solutions

Positive, perfect square Two Rational

Positive, but not a perfect square

Two Irrational

Zero One (double solution) Rational

Negative Two Nonreal complex

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The discriminant is the quantity under the radical sign in the Quadratic Formula. The value of the discriminant is used to determine the number and type of solutions of a quadratic equation.

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1.4 Example 9(a) Using the Discriminant (page 118)

Determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers.

a = 4, b = –12, c = 9

There is one distinct rational solution.

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1.4 Example 9(b) Using the Discriminant (page 118)

Determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers.

a = 3, b = 1, c = 5

There are two distinct nonreal complex solutions.

Write in standard form.

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1.4 Example 9(c) Using the Discriminant (page 118)

Determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers.

a = 2, b = –6, c = –7

There are two distinct irrational solutions.

Write in standard form.