1_ higrotermic _rezist camp curent

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    II. Thermal insulation design for the envelop elements( Proiectarea higrotermic a anvelopei cldirii)

    The equation used for the thermal resistance estimation in the hypothesis of one direction thermal flux is:

    ek

    k

    i

    ekiefo

    dRRRR

    11, ++=++= [m2K/W] (1)

    Atentie:

    Dincondiiadeeconomiedeenergie:

    R0,ef Rmin

    Incare:

    Rmin rezistentatermicaminimanormata,

    Rmin=(1,21,3)Rmin

    cu Rminvaloareaminim normat a rezistenei termicemedii corectateantreguluielementdeconstruciedinanvelop,peansamblulcldirii.

    Observatii:Deoarece intabeleledemaijossedauvalorileminimealerezistentelormediicorectatepetipuride

    elemente si ansamblul cldirii, pentru predimensionarea termoizolaiei vom considera ca punile

    termiceaferenteelementelordeconstruciereducrezistenetermicadincmpcurentcu20%...30%.

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    Thermal characteristics of the materials used in the construction of the envelope:

    Nr. Material

    Density

    Thermalconductivity

    Thermalreceptivity

    Sm

    Vapourpermeabilityresistance

    1/KDKg/m W/(mk) W/(m

    2k) -

    0 1 2 3 4 51 Reinforced concrete 2500 1,74 16,25 21,632 Reinforced concrete 2400 1,62 15,36 21,33 Cement/lime plaster 1700 0,87 4,47 8,54 Plaster over insulation 1200 0.52 3.15 4.75 Mineral wool 100/130 0,048 0,50 1,36 Polystyrene 20 0,044 0,29 30,07 Cardboard plaster 700 0,23 3,13 3,48 Sand infilling 1600 0,58 7,50 3,910 Gravel infilling 1800 0,70 8,74 2,411 Aerated concrete (b.c.a.)

    masonry with slim joints

    675 0,27 3,38 3,8

    12 Aerated concrete strips 625 0,25 3,13 3,713 Fir timber 550 0,17 4,12 10,414 Oak and beech timber 800 0,23 5,78 11,315 PFL board 300 0,07 1,95 2,716 Bituminous cardboard 600 0,17 3,28 -

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    REZISTENTELE TERMI CE ALE STRATURILOR DE AER

    NEVENTILATE

    Grosimea

    stratului de aer

    Directia si sensul fluxului termic

    OrizontalVertical

    Ascendent descendent

    0 0,00 0,00 0,00

    5 0,11 0,11 0,11

    7 0,13 0,13 0,13

    10 0,15 0,15 0,15

    15 0,17 0,16 0,17

    25 0,18 0,16 0,19

    50 0,18 0,16 0,21100 0,18 0,16 0,22

    300 0,18 0,16 0,23

    OBSERVATIE:Pentruvaloriintermediareseinterpoleaz liniar

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    1. External walls type I (cross shear wall):

    ek

    k

    i

    ekiefo

    dRRRR

    11, ++=++=

    i=8, e=23

    Nr. MaterialLayer

    ThicknessTherm.conduct.

    Therm.asim.factor

    Heatloss resist.

    Vapourconductiv.

    d Sm R 1/KD(m) (W/mK) (W/m2K) (m2K/W) -

    1/i

    1Internal Cement / limeplaster

    2 Reinforced concrete

    3Polystyrene / mineralwool/ polyurethane X

    4 External plaster

    1/e

    Total on element R=

    External walls: type II

    Nr. MaterialLayer

    ThicknessTherm.conduct.

    Therm.asim.factor

    Heatloss

    resist.

    Vapourconductiv.

    d Sm R 1/KD(m) (W/mK) (W/m2K) (m2K/W) -

    1/i

    1Internal Cement / limeplaster

    2 Brick masonry

    3Polystyrene / mineralwool/ polyurethane X

    4 External plaster

    1/e

    Total on element R=

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    2. Top floor (terrace roof) :

    1- waterproof membraneprotection (mortar 3 cm+gravel or concreteboards);2 waterproof

    membrane;3 diffusive layer;4 waterproofmembrane support(mortar 3 cm);5 plistyrene termo-insulation 20 cm;6 vapor barrier;7 diffusion layer;8 sloping layer (b.c.a.)8 cm;9 reinforced concretefloor slab 1215 cm;10 ceiling plaster - 1,5cm;

    3. Floor over the basement:

    floor over basement:

    1- ceiling plaster - 1,5 cm;2- thermal insulation of mineralwool 10 cm;3- reinforced concrete floor slab 1215 cm;

    4- mortar bead 3 cm5 Ceramic floor tile 1.2 cm

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