1 modeling matter at nanoscales 4. introduction to quantum treatments 4.02. the variational method
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1
MODELING MATTER AT NANOSCALES
4. Introduction to quantum treatments4.02. The variational method
Schrödinger Equation
The solution of the Schrödinger equation gives the exact wave function of a system by means of the Hamiltonian operator that comes from the total energy of a system in classical mechanics:
where the “spectrum” of the operator is the set of eigenvalues Ek of all the K states of the system.
kkk EH ˆ
Schrödinger Equation
However, exact solutions for a Hamiltonian are scarce, although very relevant, and were mostly obtained for ideal conditions.
The variational theorem
The minimal energy as a criterion of accuracy
A wave function is more accurate or near to the exact eigenfunction when the expectation values of energy are minimal:
where yarb is an arbitrary wave function and y0 would be the eigenfunction (exact wave function) of the system.
00*0* ˆˆ EdHdH arbarb
Variational Theorem
Any expectation value of energy corresponding to a test wave function is equal or the upper limit to the lowest exact value of the system
Variational Theorem
Optionally, the variational theorem expresses that the best approximate wave function is that minimizing the expression:
where the denominator is a normalizing factor.This expression must depend on parameters to minimize energy with respect to them.
d
dHE
arbarb
arbarb
*
* ˆ
Variational Theorem
Optionally, the variational theorem expresses that the best approximate wave function is that minimizing the expression:
where the denominator is a normalizing factor.This expression must depend on parameters to minimize energy with respect to them.
d
dHE
arbarb
arbarb
*
* ˆ
Variational Theorem
To this purpose, the arbitrary function can be developed in terms of fm possible states of the system that must be linearly independent, although not necesarily eigenfunctions of the operator:
where cm are coefficients of participation in the linear combination and can be considered as parameters serving to optimize the function.
cccarb ...2211
A simple case
A typical simple case where the arbitrary function depends on two states f1 and f2:
2211 ccarb
A simple case
This example could be referred to the electronic component of hydrogen molecule. The wave function is to be represented as a linear combination of functions describing the behavior of each electron as f1 and f2 .
+
=
1 2 arb
H2
A simple case
The variational function of the system can be written as:
and the conditions to yield the minimal energy with respect to coefficients would be:
dcccc
dccHccE
2211*22
*11
2211*22
*11
ˆ
02
1
cc
E0
12
cc
E
A simple case
The energy expression in terms of the previous linear combination is then:
dHcHccHccHcE
dHcHccHccHc
2*2
221
*2122
*1211
*1
21
2*2
221
*2122
*1211
*1
21
ˆˆˆˆ
ˆˆˆˆ
A simple caseDefining the term or matrix element:
expressing the energy of interaction between fm and fn local functions, and:
meaning the overlap between both functions in the space defined by t coordinates, we can write:
dHH ˆ*
A simple caseDefining the term or matrix element:
expressing the energy of interaction between fm and fn local functions, and:
meaning the overlap between both functions in the space defined by t coordinates, we can write:
dHH ˆ*
dS *
A simple caseDefining the term or matrix element:
expressing the energy of interaction between fm and fn local functions, and:
meaning the overlap between both functions in the space defined by t coordinates, we can write:
dHH ˆ*
dS *
22222112122111
21
22222112122111
21
ScSccSccScE
HcHccHccHc
A simple caseReordering, and deriving with respect to c1 and c2, we are ready to obtain their values for a minimal energy:
where the unknown are cm´s that will approach the exact energy according the variational principle.It must be observed that (Hmn – SmnE) terms are the coefficients of the cm variables.
0
0
2222221211
1212211111
ESHcESHc
ESHcESHc
A simple caseReordering, and deriving with respect to c1 and c2, we are ready to obtain their values for a minimal energy:
where the unknown are cm´s that will approach the exact energy according the variational principle.It must be observed that (Hmn – SmnE) terms are the coefficients of the cm variables.
0
0
2222221211
1212211111
ESHcESHc
ESHcESHc
A simple caseIn matrix terms, it means:
or(H – SE)C = 0
HC – SEC = 0
HC = SEC
0
0
2
1
22222121
12121111
c
c
ESHESH
ESHESH
A simple caseIn matrix terms, it means:
or(H – SE)C = 0
HC – SEC = 0
HC = SEC
0
0
2
1
22222121
12121111
c
c
ESHESH
ESHESH
A simple caseThe only non – trivial solution of this system, that is, the necessary and sufficient condition for the solution, is that the determinant of coefficients Hmn – SmnE must vanish:
or|H – SE| = 0
It is an equation of nth degree (in this case second degree) with n solutions for E.
022222121
12121111
ESHESH
ESHESH
A simple caseThe only non – trivial solution of this system, that is, the necessary and sufficient condition for the solution, is that the determinant of coefficients Hmn – SmnE must vanish:
or|H – SE| = 0
It is an equation of nth degree (in this case second degree) with n solutions for E.
022222121
12121111
ESHESH
ESHESH
A simple caseDeveloping the determinant:
If we substitute some terms to H11= H22 = W, H21= H12=w and the wave functions are normalized (S11=S22=1), the equation simplifies to a simple second degree equation in E:
0
22112122121122112
22211112222112211
2121121222221111
ESSESHESHHH
ESSESHESHHH
ESHESHESHESH
A simple caseDeveloping the determinant:
If we substitute some terms to H11= H22 = W, H21= H12=w and the wave functions are normalized (S11=S22=1), the equation simplifies to a simple second degree equation in E:
0
22112122121122112
22211112222112211
2121121222221111
ESSESHESHHH
ESSESHESHHH
ESHESHESHESH
021 2212
2212 ESES
A simple caseSolutions must be:
and therefore the energy only depends on parameters W, w and S12. It must be remembered that these solutions were deduced under the condition that the energy was minimal with respect to coefficients cm, not being them explicitly there.
2
12
22212
21212
2
212
22212
21212
1
12
122
12
122
21
21
S
SSSE
S
SSSE
A simple caseSolutions must be:
and therefore the energy only depends on parameters W, w and S12. It must be remembered that these solutions were deduced under the condition that the energy was minimal with respect to coefficients cm, not being them explicitly there.
2
12
22212
21212
2
212
22212
21212
1
12
122
12
122
21
21
S
SSSE
S
SSSE
The variational wave function
Solving these equations, the spectrum of eigenvalues (energies) of the system’s Hamiltonian is obtained. They must correspond to the corresponding Ek different states.
The variational optimal wave function must also be deduced after finding cm’s.
The variational wave function
Solving these equations, the spectrum of eigenvalues (energies) of the system’s Hamiltonian is obtained. They must correspond to the corresponding Ek different states.
The variational optimal wave function must also be deduced after finding cm’s.
The variational wave function
If the values of S12, W and w were considered known since the initial steps and we found values for E1 and E2, then c m values can be also calculated:
However, it is easy to realize that this system is unable to provide solutions different from 0 for c1 and c2 if other condition is not applied.
0
0
222211
112211
EcESc
EScEc
The variational wave function
If the values of S12, W and w were considered known since the initial steps and we found values for E1 and E2, then c m values can be also calculated:
However, it is easy to realize that this system is unable to provide solutions different from 0 for c1 and c2 if other condition is not applied.
0
0
222211
112211
EcESc
EScEc
The variational wave function
The solution of this problem can only be achieved if the state wave functions are also mutually orthogonal, giving:
wheredmn = 1 when m = n
dmn = 0 when m ≠ n
1...22
*
cc
dS
The variational wave function
Then:
And consequently, solving the system:
1
0
0
22
21
221
211
cc
Ecc
cEc
The variational wave function
Then:
And consequently, solving the system:
1
0
0
22
21
221
211
cc
Ecc
cEc
21
2
2
2
1 1
E
c
21
2
1
2
2 1
E
c
The variational solutionIn our case of interest
the variational wave function is then:
+
=
1 2 arb
H2
22
1
2
12
2
2
2211
21
21
2
11
EE
ccarbH
Notes and Conclusions
To obtain a reliable variational wave function it is also necessary to select appropriate f1 and f2 basis functions.For the variational method to obtain a wave function of a system approaching the exact it is necessary to find an appropriate parameter dependence of the basis reference functionsAs much appropriate parameters can be considered, providing accountable details of the object system, the resulting variational wave functions will be more reliable and near to the exact solution.
Notes and Conclusions
To obtain a reliable variational wave function it is also necessary to select appropriate f1 and f2 basis functions.For the variational method to obtain a wave function of a system approaching the exact it is necessary to find an appropriate parameter dependence of the basis reference functionsAs much appropriate parameters can be considered, providing accountable details of the object system, the resulting variational wave functions will be more reliable and near to the exact solution.
Notes and Conclusions
To obtain a reliable variational wave function it is also necessary to select appropriate functional forms for the f1 and f2 basis.
For approaching the exact wave function of a system by the variational method holds that as much appropriate parameters can be considered, the resulting variational wave functions will be more reliable and near to the exact solution.It works if such parameters can account energy relevant details of the object system.
Notes and Conclusions
To obtain a reliable variational wave function it is also necessary to select appropriate functional forms for the f1 and f2 basis.
For approaching the exact wave function of a system by the variational method holds that as much appropriate parameters can be considered, the resulting variational wave functions will be more reliable and near to the exact solution.It works if such parameters can account energy relevant details of the object system.
Notes and Conclusions
To obtain a reliable variational wave function it is also necessary to select appropriate functional forms for the f1 and f2 basis.
For approaching the exact wave function of a system by the variational method holds that as much appropriate parameters can be considered, the resulting variational wave functions will be more reliable and near to the exact solution.It works if such parameters can account energy relevant details of the object system.