10 askeland chap
TRANSCRIPT
![Page 1: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/1.jpg)
111
10Dispersion Strengthening andEutectic Phase Diagrams
10–22 A hypothetical phase diagram is shown in Figure 10–32. (a) Are any intermetalliccompounds present? If so, identify them and determine whether they are stoichio-metric or nonstoichiometric. (b) Identify the solid solutions present in the system. Iseither material A or B allotropic? Explain. (c) Identify the three-phase reactions bywriting down the temperature, the reaction in equation form, the composition ofeach phase in the reaction, and the name of the reaction.
Solution: (a) u � non-stoichiometric intermetallic compound.
(b) a, h, g, and b; material B is allotropic, existing in three different forms atdifferent temperatures
(c)
10–23 The Cu–Zn phase diagram is shown in Figure 10–33. (a) Are any intermetalliccompounds present? If so, identify them and determine whether they are stoichio-metric or nonstoichiometric. (b) Identify the solid solutions present in the system.(c) Identify the three-phase reactions by writing down the temperature, the reactionin equation form, and the name of the reaction.
u: 40% B h: 95% B 300°C: bS u � h; eutectoid; b: 90% B
b: 80% B u: 37% B 600°C: a � bS u; peritectoid; a: 5% B
a: 5% B b: 90% B 680°C: L S a � b; eutectic; L: 60% B
L 2: 50% B a: 5% B 900°C: L1 S L2 � a; monotectic; L1: 28% B
g: 97% B b: 90% B 1100°C: g � L S b; peritectic; L: 82% B
![Page 2: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/2.jpg)
112 The Science and Engineering of Materials Instructor’s Solution Manual
Solution: (a) b, b�, g, d, e: all nonstoichiometric.
(b) a, u
(c)
10–24 A portion of the Al–Cu phase diagram is shown in Figure 10–34. (a) Determine theformula for the u compound. (b) Identify the three-phase reaction by writing downthe temperature, the reaction in equation form, the composition of each phase in thereaction, and the name of the reaction.
Solution: (a)
(b)
10–25 The Al–Li phase diagram is shown in Figure 10–35. (a) Are any intermetallic com-pounds present? If so, identify them and determine whether they are stoichiometricor nonstoichiometric. Determine the formula for each compound. (b) Identify thethree-phase reactions by writing down the temperature, the reaction in equationform, the composition of each phase in the reaction, and the name of the reaction.
Solution: (a) b is non-stoichiometric @ 21 wt% Li:
g, is stoichiometric @ 34 wt% Li:
(b)
10–26 An intermetallic compound is found for 10 wt% Si in the Cu–Si phase diagram.Determine the formula for the compound.
Solution: at% Si �10 g�28.08 g/mol
10�28.08 � 90�63.54� 0.20 or SiCu4
g: 34% Li a 1Li2: 99% Li170°C: L S g � a 1Li2 eutectic L: 98% Li
L: 47% Li g: 34% Li510°C: b � L S g peritectic b: 25% Li
a: 4% Li b: 20.4% Li600°C: L S a � b eutectic L: 9.9% Li
at% Li �34 g�6.94 g/mol
34�6.94 � 66�26.981� 100% � 66.7% Li ∴ AlLi2
at% Li �21 g�6.94 g/mol
21�6.94 � 79�26.981� 100% � 50 at% Li ∴ AlLi
a: 5.65% Cu, u: 52.5% Cu.548°C; L S a � u; eutectic; L: 33.2% Cu,
u at 54% Cu; 54 g�63.54 g/mol
54�63.54 � 46�26.981� 33 at% Cu; CuAl2
250°C: b¿ S a � g; eutectoid
420°C: e � L S u; peritectic
550°C: d S g � e; eutectoid
600°C: d � L S e; peritectic
700°C: g � L S d; peritectic
830°C: b � L S g; peritectic
900°C: a � L S b; peritectic
![Page 3: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/3.jpg)
10–27 Using the phase rule, predict and explain how many solid phases will form in aneutectic reaction in a ternary (three-component) phase diagram, assuming that thepressure is fixed.
Solution: F � C � P � 1
At the eutectic, F � 0, C � 3 0 � 3 � P � 1 or P � 4
Therefore, L S a� b� g and 3 solid phases form.
10–30 Consider a Pb–15% Sn alloy. During solidification, determine (a) the compositionof the first solid to form, (b) the liquidus temperature, solidus temperature, solvustemperature, and freezing range of the alloy, (c) the amounts and compositions ofeach phase at 260°C, (d) the amounts and compositions of each phase at 183°C, and(e) the amounts and compositions of each phase at 25°C.
Solution: (a) 8% Sn
(b) liquidus � 290°C, solidus � 240°C,solvus � 170°C, freezing range � 50°C
(c) L: 30% Sn a: 12% Sn;
(d) a: 15% Sn 100% a
(e) a: 2% Pb b: 100% Sn
10–31 Consider an Al–12% Mg alloy (Figure 10–36). During solidification, determine(a) the composition of the first solid to form, (b) the liquidus temperature, solidustemperature, solvus temperature, and freezing range of the alloy, (c) the amountsand compositions of each phase at 525°C, (d) the amounts and compositions of eachphase at 450°C, and (e) the amounts and compositions of each phase at 25°C.
Solution: (a) 2.5% Mg
(b) liquidus � 600°C, solidus � 470°C,solvus � 400°C, freezing range � 130°C
(c) L: 26% Mg a: 7% Mg;
(d) a: 12% Mg 100% a
(e)
%a �34 � 12
34 � 1� 100% � 67% %b � 33%
a: 1% Mg b: 34% Mg
%a �26 � 12
26 � 7� 100% � 74% %L � 26%
%a �100 � 15
100 � 2� 100 � 87% %b � 13%
%L �15 � 12
30 � 12� 100% � 17% %a � 83%
CHAPTER 10 Dispersion Strengthening and Eutectic Phase Diagrams 113
![Page 4: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/4.jpg)
114 The Science and Engineering of Materials Instructor’s Solution Manual
10–32 Consider a Pb–35% Sn alloy. Determine (a) if the alloy is hypoeutectic or hypereu-tectic, (b) the composition of the first solid to form during solidification, (c) theamounts and compositions of each phase at 184°C, (d) the amounts and composi-tions of each phase at 182°C, (e) the amounts and compositions of each microcon-stituent at 182°C, and (f) the amounts and compositions of each phase at 25°C.
Solution: (a) hypoeutectic (b) 14% Sn
(c)
(d)
(e) primary a: 19% Sn %primary a � 63%eutectic: 61.9% Sn %eutectic � 37%
(f)
10–33 Consider a Pb–70% Sn alloy. Determine (a) if the alloy is hypoeutectic or hypereu-tectic, (b) the composition of the first solid to form during solidification, (c) theamounts and compositions of each phase at 184°C, (d) the amounts and composi-tions of each phase at 182°C, (e) the amounts and compositions of each microcon-stituent at 182°C, and (f) the amounts and compositions of each phase at 25°C.
Solution: (a) hypereutectic (b) 98% Sn
(c)
(d)
(e) primary b: 97.5% Sn %primary b� 22.8%eutectic: 61.9% Sn %eutectic � 77.2%
(f)
10–34 Calculate the total % b and the % eutectic microconstituent at room temperature forthe following lead-tin alloys: 10% Sn, 20% Sn, 50% Sn, 60% Sn, 80% Sn, and 95%Sn. Using Figure 10–22, plot the strength of the alloys versus the % b and the % eutectic and explain your graphs.
%a �100 � 70
100 � 2� 100% � 30% %b � 70%
a: 2% Sn b: 100% Sn
%a �97.5 � 70
97.5 � 19� 100% � 35% %b � 65%
a: 19% Sn b: 97.5% Sn
%b �70 � 61.9
97.5 � 61.9� 100% � 22.8% %L � 77.2%
b: 97.5% Sn L: 61.9% Sn
%a �100 � 35
100 � 2� 100% � 66% %b � 34%
a: 2% Sn b: 100% Sn
%a �97.5 � 35
97.5 � 19� 100% � 80% %b � 20%
a: 19% Sn b: 97.5% Sn
%a �61.9 � 35
61.9 � 19� 100% � 63% %L � 37%
a: 19% Sn L: 61.9% Sn
![Page 5: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/5.jpg)
Solution: %b %eutectic
10% Sn 0%
20% Sn
50% Sn
60% Sn
80% Sn
95% Sn 97.5 � 95
97.5 � 61.9� 7.0%
95 � 2
99 � 2� 95.9%
97.5 � 80
97.5 � 61.9� 49.2%
80 � 2
99 � 2� 80.4%
60 � 19
61.9 � 19� 95.6%
60 � 2
99 � 2� 59.8%
50 � 19
61.9 � 19� 72.3%
50 � 2
99 � 2� 49.5%
20 � 19
61.9 � 19� 2.3%
20 � 2
99 � 2� 18.6%
10 � 2
99 � 2� 8.2%
CHAPTER 10 Dispersion Strengthening and Eutectic Phase Diagrams 115
10–35 Consider an Al–4% Si alloy. (See Figure 10–23.) Determine (a) if the alloy ishypoeutectic or hypereutectic, (b) the composition of the first solid to form duringsolidification, (c) the amounts and compositions of each phase at 578°C, (d) theamounts and compositions of each phase at 576°C, the amounts and compositionsof each microconstituent at 576°C, and (e) the amounts and compositions of eachphase at 25°C.
Solution: (a) hypoeutectic
(b) 1% Si
(c)
(d)
%a �99.83 � 4
99.83 � 1.65� 97.6% %b � 2.4%
a: 1.65% Si b: 99.83% Si
%a �12.6 � 4
12.6 � 1.65� 78.5% %L � 21.5%
a: 1.65% Si L: 12.6% Si
20 40 60 80 1004000
5000
6000
7000
8000
% β
Tens
ile s
tren
gth
(psi
)
20 40 60 80
5000
6000
7000
8000
% eutectic
Hypo-
Hyper-
Tens
ile s
tren
gth
(psi
)
![Page 6: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/6.jpg)
116 The Science and Engineering of Materials Instructor’s Solution Manual
(e) primary a: 1.65% Si %primary a� 78.5%eutectic: 12.6% Si %eutectic � 21.5%
10–36 Consider a Al–25% Si alloy. (See Figure 10–23.) Determine (a) if the alloy ishypoeutectic or hypereutectic, (b) the composition of the first solid to form duringsolidification, (c) the amounts and compositions of each phase at 578°C, (d) theamounts and compositions of each phase at 576°C, (e) the amounts and composi-tions of each microconstituent at 576°C, and (f) the amounts and compositions ofeach phase at 25°C.
Solution: (a) hypereutectic
(b) 100% Si
(c)
(d)
(e) primary b: 99.83% Si %primary b� 14.2%eutectic: 12.6% Si %eutectic � 85.8%
(f)
10–37 A Pb–Sn alloy contains 45% a and 55% b at 100°C. Determine the composition ofthe alloy. Is the alloy hypoeutectic or hypereutectic?
Solution:
10–38 An Al–Si alloy contains 85% a and 15% b at 500°C. Determine the composition ofthe alloy. Is the alloy hypoeutectic or hypereutectic?
Solution:
10–39 A Pb–Sn alloy contains 23% primary a and 77% eutectic microconstituent.Determine the composition of the alloy.
Solution:
10–40 An Al–Si alloy contains 15% primary b and 85% eutectic microconstituent.Determine the composition of the alloy.
%primary a � 23 �61.9 � x
61.9 � 19� 100 or x � 52% Sn
%a � 85 �100 � x
100 � 1� 100 or x � 15.85% Si Hypereutectic
%a � 45 �98.0 � x
98.0 � 5� 100 or x � 56.15% Sn Hypoeutectic
a: 0% Si b: 100% Si %a �100 � 25
100 � 0� 75% %b � 25%
%a �99.83 � 25
99.83 � 1.65� 76.2% %b � 23.8%
a: 1.65% Si b: 99.83% Si
%L �99.83 � 25
99.83 � 12.6� 85.8% %b � 14.2%
b: 99.83% Si L: 12.6% Si
a: 0% Si b: 100% Si %a �100 � 4
100 � 0� 96% %b � 4%
![Page 7: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/7.jpg)
Solution:
10–41 Determine the maximum solubility for the following cases.
(a) lithium in aluminum (Figure 10–35),(b) aluminum in magnesium (Figure 10–37),(c) copper in zinc (Figure 10–33), and(d) carbon in g-iron (Figure 10–38)
Solution: (a) 4% Li dissolves in aluminum
(b) 12.7% Al dissolves in magnesium
(c) 3% Cu dissolves in zinc
(d) 2.11% C dissolves in g-iron
10–42 Determine the maximum solubility for the following cases.
(a) magnesium in aluminum (Figure 10–36),(b) zinc in copper (Figure 10–33),(c) beryllium in copper (Figure 10–33), and(d) Al2O3 in MgO (Figure 10–39)
Solution: (a) 14.9% Mg dissolves in aluminum
(b) 40% Zn dissolves in copper
(c) 2.5% Be dissolves in copper
(d) 18% Al2O3 dissolves in MgO
10–43 Observation of a microstructure shows that there is 28% eutectic and 72% primaryb in an Al–Li alloy (Figure 10–35). (a) Determine the composition of the alloy andwhether it is hypoeutectic or hypereutectic. (b) How much a and b are in the eutec-tic microconstituent?
Solution: (a)
(b)
10–44 Write the eutectic reaction that occurs, including the compositions of the threephases in equilibrium, and calculate the amount of a and b in the eutectic microcon-stituent in the Mg–Al system, (Figure 10–36).
Solution:
∴ %aEut �40.2 � 32.3
40.2 � 12.7� 100% � 28.7% and %gEut � 71.3%
L32.3 S a12.7 � g40.2
%aEut �20.4 � 9.9
20.4 � 4� 100% � 64% and %bEut � 36%
28 �20.4 � x
20.4 � 9.9� 100 or x � 17.46% Li Hypereutectic
%eutectic � 85 �100 � x
100 � 12.6� 100 or x � 25.71% Si
CHAPTER 10 Dispersion Strengthening and Eutectic Phase Diagrams 117
![Page 8: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/8.jpg)
118 The Science and Engineering of Materials Instructor’s Solution Manual
10–45 Calculate the total amount of a and b and the amount of each microconstituent in aPb–50% Sn alloy at 182°C. What fraction of the total a in the alloy is contained inthe eutectic microconstituent?
Solution:
10–46 Figure 10–40 shows a cooling curve for a Pb–Sn alloy. Determine (a) the pouringtemperature, (b) the superheat, (c) the liquidus temperature, (d) the eutectic tempera-ture, (e) the freezing range, (f ) the local solidification time, (g) the total solidifica-tion time, and (h) the composition of the alloy.
Solution: (a)
(b)
(c)
(d)
(e)
(f)
(g)
(h) approximately 32% Sn
10–47 Figure 10–41 shows a cooling curve for an Al–Si alloy. Determine (a) the pouringtemperature, (b) the superheat, (c) the liquidus temperature, (d) the eutectic tempera-ture, (e) the freezing range, (f) the local solidification time, (g) the total solidifica-tion time, and (h) the composition of the alloy.
Solution: (a)
(b)
(c)
(d)
(e)
(f)
(g)
(h) approximately 45% Si
total solidification time � 11.5 min
local solidification time � 11.5 � 1 � 10.5 min
freezing range � 1000 � 577 � 423°C
eutectic temperature � 577°C
liquidus temperature � 1000°C
superheat � 1150 � 1000 � 150°C
pouring temperature � 1150°C
total solidification time � 600 s
local solidification time � 600 � 110 � 490 s
freezing range � 250 � 183 � 67°C
eutectic temperature � 183°C
liquidus temperature � 250°C
superheat � 360 � 250 � 110°C
pouring temperature � 360°C
f � 32.8�60.5 � 0.54
ain eutectic � 60.5 � 27.7 � 32.8%
aPrimary �61.9 � 50
61.9 � 19� 100% � 27.7% Eutectic � 72.3%
atotal �97.5 � 50
97.5 � 19� 100% � 60.5% bTotal � 39.5%
![Page 9: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/9.jpg)
10–48 Draw the cooling curves, including appropriate temperatures, expected for thefollowing Al–Si alloys.
(a) Al–4% Si (b) Al–12.6% Si (c) Al–25% Si (d) Al–65% Si
Solution:
CHAPTER 10 Dispersion Strengthening and Eutectic Phase Diagrams 119
10–49 Based on the following observations, construct a phase diagram. Element A melts at850°C and element B melts at 1200°C. Element B has a maximum solubility of 5%in element A, and element A has a maximum solubility of 15% in element B. Thenumber of degrees of freedom from the phase rule is zero when the temperature is725°C and there is 35% B present. At room temperature 1% B is soluble in A and7% A is soluble in B.
Solution:
T
tAl – 4% Si
630°577°
T
tAl – 12.6% Si
577°T
tAl – 25% Si
780°
577° T
tAl – 65% Si
1200°
577°
b + L
b
L
a + b
A B205 40 60 80 85% B
200
400
600
800
1000
1200
Tem
pera
ture
(°C
)
a + La
![Page 10: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/10.jpg)
120 The Science and Engineering of Materials Instructor’s Solution Manual
10–50 Cooling curves are obtained for a series of Cu–Ag alloys, (Figure 10–42). Use thisdata to produce the Cu–Ag phase diagram. The maximum solubility of Ag in Cu is7.9% and the maximum solubility of Cu in Ag is 8.8%. The solubilities at roomtemperature are near zero.
Solution: Tliq Tsol
0% Ag S 1085°C8% Ag S 1030°C 950°C20% Ag S 975°C 780°C50% Ag S 860°C 780°C71.9% Ag S 780°C 780°C90% Ag S 870°C 780°C100% Ag S 961°C
10–51 The SiO2–Al2O3 phase diagram is included in Figure 10–27(b). A refractory isrequired to contain molten metal at 1900°C. (a) Will pure Al2O3 be a potential can-didate? Explain. (b) Will Al2O3 contaminated with 1% SiO2 be a candidate? Explain.
Solution: (a) Yes. Tm � 2040°C � 1900°C No liquid will form.
(b) No. Some liquid will form.
This liquid will weaken the refractory.
%L �100 � 99
100 � 80� 100% � 5% L
700
800
900
1000
1100
Cu 29 40 60 80 Ag
Tem
pera
ture
(°C
)
L
%Ag
aa + L
b + L
a + bb
![Page 11: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/11.jpg)
10–66 Consider the ternary phase diagram shown in Figures 10–30 and 10–31. Determinethe liquidus temperature, the first solid to form, and the phases present at room tem-perature for the following compositions.
(a) 30% B–20% C, balance A (b) 10% B–25% C, balance A(c) 60% B–10% C, balance A
Solution: (a)
(b)
(c)
10–67 Consider the ternary phase diagram shown in Figures 10–30 and 10–31. Determinethe liquidus temperature, the first solid to form, and the phases present at room tem-perature for the following compositions.
(a) 5% B–80% C, balance A (b) 50% B–5% C, balance A(c) 30% B–35% C, balance A
Solution: (a)
(b)
(c)
10–68 Consider the liquidus plot in Figure 10–30. (a) For a constant 20% B, draw a graphshowing how the liquidus temperature changes from 20% B–0% C, balance A to20% B–80% C, balance A, (b) What is the composition of the ternary eutectic in thissystem? (c) Estimate the temperature at which the ternary eutectic reaction occurs.
Solution: %A %B %C Tliquidus
80–20–0 390C70–20–10 355°C60–20–20 300°C50–20–30 210°C40–20–40 150°C30–20–50 210°C20–20–60 270°C10–20–70 320°C0–20–80 400°C
TLiq � 290°C; b; a � b � g
TLiq � 330°C; b; a � b
TLiq � 390°C; g; a � g
TLiq � 390°C; b; a � b
TLiq � 330°C; a; a � g
TLiq � 220°C; b; a � g � b
CHAPTER 10 Dispersion Strengthening and Eutectic Phase Diagrams 121
100
200
300
400
0 20 40 60 80
Tem
pera
ture
(°C
)
%C
L
a + L
g + L
B = 20%
![Page 12: 10 Askeland Chap](https://reader037.vdocument.in/reader037/viewer/2022100209/552f67b95503465e378b4588/html5/thumbnails/12.jpg)
122 The Science and Engineering of Materials Instructor’s Solution Manual
(b) The composition of the ternary eutectic is about 40% 20% B–40% C,balance A
(c) The ternary eutectic temperature is about 150°C
10–69 From the liquidus plot in Figure 10–30, prepare a graph of liquidus temperatureversus percent B for a constant ratio of materials A and C (that is, from pure B to50% A–50% C on the liquidus plot). Material B melts at 600°C.
Solution: A B C
50– 0–50 200°C45–10–45 180°C40–20–40 150°C35–30–35 280°C30–40–30 330°C25–50–25 375°C20–60–20 415°C15–70–15 485°C0–100–0 580°C
100
200
300
400
500
600
0 20 40 60 80 100
Tem
pera
ture
(°C
)
% B
L
% A = % C a + L
b + L