(10) introduction to convection
TRANSCRIPT
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Heat Transfer
Introduction to Convection Heat and Mass
Transfer
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Convection Fundamental Concepts-Convection Transfer
Consider the flow of a fluid past a flat surface.
The local heat flux is:
Where h is the local heat transfer coefficient (W/m2K). q
and h vary along the surface. The total heat transfer rateover the entire surface is:
Lx
q Ts, AsU, T
TThq s
TTAhq ss where L
0
hdxL
1h
Average
convection heat
transfer coefficient
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Results similar to convection heat transfer may be
obtained for convection mass transfer when a fluid with
molar concentration C A, (kmol/m3) or density A,
(kg/m3
) for species A flows over a surface with uniformconcentration C A,sor density A,sfor species A as shown
below:
The molar flux NA (kmol/m2s) and mass flux mA (kg/ m
2
s) are expressed, respectively as:
Lx
NACA,s, As
U, CA,
dx
,As,AmA CChN ,As,AmA hm
Where hm= local convection mass transfer coefficient
A= McCA= density
MA= molecular weight of species A
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Total molar transfer rate NA(kmol/s) and total mass transfer
rate mA(kg/s) are also expressed, respectively, as follows:
Where = average mass transfer coefficient, m/s
Assuming saturated state of species A at surface temperature
Ts, the density A,may be obtained directly from
thermodynamic tables ( for water: table A.6(text))
At the corresponding saturation pressure Psatthe molar
concentration may be obtained from equation of state for anideal gas
,As,AmA CChN ,As,AmA hm
L
0
hdxL
1h
h
s
sats,A
RT
PC Where R = universal gas constant
= 8.314 kJ / kmol K
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Convection boundary layer
Convection can be forced or natural
It is due to the random motion of molecules (diffusion) and
the bulk motion of the fluid particles Convection could be internal or external
ExamplesAirflow over wings, buildings, a bank of heat
exchangers (external)
1. The Velocity boundary Layer Velocity B.L. Region with velocity gradient dU / dy 0
u
x
Free Stream
U
y
(x)
B.L.
U
s Velocity gradient
due to shear
stress,
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is the boundary layer thickness defined as the value of y at
which u = 0.99 U. At y = dU/dy and are negligible.
The local friction coefficient is calculated from:
The surface frictional drag, FD, is calculated using Cf
Assuming a Newtonian fluid, sis calculated from:
Where is the dynamic viscosity of the fluid, and du/dy is the
velocity gradient perpendicular to the wall.
2
UC
2s
f Wall shear .
Kinetic energy of fluid
0ys
y
u
s
2f
ssD A2
UCAF
also
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2. Thermal Boundary Layer
Thermal B.L. Region with temperature gradient dT/dy
tis the thermal boundary layer thickness, defined as the
value of y at which:
x
T
yt
t(x)U
T
Ts
Isothermal Surface
99.0TT
TT
s
s
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The local convective heat transfer coefficient may be
calculated by first finding qs from energy balance at the
surface. Fourier Law (No fluid motion at the surface,
conduction only)
For a constant surface temperature,Ts Ts- T= constant
Since tincreases with x, T/y must decrease with x
Therefore h and q also decrease with x
0ys
y
Tkq
TThq ss
TT
yTk
hs
0yf
also
0yy
T
decreases with xSince
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,As,A
AAB
m CC
y
CD
h
,As,A
AAB
my
D
h
Concentration Boundary Layer
Ficks Law
Where DABor Dv= mass diffusion coefficient, m/s2
Mass diffusivity or mass diffusion coefficient has the same
units as thermal diffusivity, (m/s2)
As with heat transfer, we can write
x
yc
c(x)
U
CA,s
Concentration
Boundary Layer
CA,
CA
CA, Free Stream
Mixtureof A & B
y
CDN AABA
yDm AABA
Heat flux (qx)
Fouriers LawMolar or Mass flux
Ficks Law
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SUMMARY:
Three boundary layers:
Velocity B.L. ()
Velocity distribution (V)
Wall friction ()
Thermal B.L. (t)
Temperature distribution (T)
Convection heat transfer (h, Nu)
Concentration B.L. (c)
Concentration distribution (C)
Convection mass transfer (hm, Sh)
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Problem 6.1
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Laminar & Turbulent Flow & Reynolds Number
Convection transfer rates and surface friction depend on
whether the flow is laminar or turbulent. Laminar orturbulent flow is determined by the value of Re
For internal flow: Reynolds Number (Re)
where ReD,cis the critical Reynolds number
For external flow: Reynolds Number (Re)
where Rex,cis the critical Reynolds number
xU
Rex5c
c,x 105xU
Re
DURe
D
2300Rec,D
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Laminar Ordered fluid motion with identifiable streamlines on which
fluid particles move.
Turbulent Irregular fluid motion with velocity fluctuations which increase
energy, mass, and momentum transfer. Larger twith flatter
velocity, temperature and concentration profiles.
Transition Turbulent
Laminar
xc
U
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Regions in turbulent Boundary Layer
Turbulent regionTransport mainly by
turbulent mixing
Buffer ZoneTransport by diffusion and
turbulent mixing
Viscous or Laminar Sub layerTransport
by diffusion and linear velocity profile
Variation of Velocity B.L.
Thickness () and local heat
transfer coefficient (h) for flowover an isothermal surface
h(x)
(x)
x
h ,
Laminar Transition Turbulent
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Problem 6.14
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Boundary Layer Equations
Consider a steady , 2-D flow of a viscous incompressible
fluid in a Cartesian coordinate as shown below. We wish to
obtain a set of differential equations that governs the
velocity and temperature distributions in the fluid to solve
V, T, C and (force), q (heat transfer), m (mass transfer).
x
T
U
Thermal B.L.
Concentration B.L.
Velocity B.L.
qs
NA,s
T
U
CA,
CA
y
Ts
t
C
CA, s
Mixture of
A & B
dx
dy
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The equations are based on application of conservation
principles on a differential control volume of the fluid as
demonstrated below for conservation of mass over a control
volume: The velocity Boundary Layer
Continuity equation
Conservation of mass over a control volume, inout = 0
u
v
y
x
0yv
xu
0y
v
x
u
dyyvv
dx
x
uu
u
vGu = mass velocity (kg / m2s)
For an incompressible fluid where = constant:
See Appendix E for detailed development of conservation ofmass, momentum, energy and chemical species
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The following differential equations are therefore obtained for
steady, 2-D flow for an incompressible fluid with constant
properties (, , cv, cp, k, etc.)
Continuity Equation: Conservation of Mass
Momentum Equation in x-direction: Velocity B.L.
Momentum Equation in y-direction: Velocity B.L.
0y
v
x
u
Xy
u
x
u
x
P
y
uvx
uu2
2
2
2
Yy
v
x
v
y
P
y
vv
x
vu
2
2
2
2
Where X = Bodyforce in x direction
X=gx
Where Y = Bodyforce in y direction
Y=gy
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Energy Equation: Thermal B.L.
Viscous Energy Dissipation Equation
Species Transfer or Continuity Equation: Species
Concentration B.L.
q
y
T
x
Tk
y
Tv
x
Tuc
2
2
2
2
p
222
y
v
x
u
x
v
y
u
A2
A2
2
A2
AB
AA myx
Dy
vx
u
A2A
2
2A
2
ABAA N
y
C
x
CD
y
Cv
x
Cu
Where = viscous
energy dissipation
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Approximations and Special Conditions
A most common situation is one in which the 2-D boundary
layer can be characterized as Steady (time independent)
Incompressible ( is constant)
Having constant properties (, , k, etc.) with temperature
Having negligible body forces ( X = Y = 0)
Non-reacting (no chemical reaction) without internal heat
generation
In addition, since is very small, the following B.L.
approximations apply:
x
v,y
v,
x
u
y
u
vu Velocity B.L.
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This means that normal stresses in x-direction are negligible,
and the wall shear stress reduces to:
These simplification reduce the B.L. equations to the
following equations.
Continuity Equation:
x
T
y
T
xCor
xyCor
yAAAA
yu
yxxy
0y
v
x
u
Thermal B.L.
Concentration B.L.
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Momentum equationin x-direction, and y-direction
The continuity and momentum equations can be used to solve
for the spatial variations of u and v.
Energy Equation:
Species Continuity Equation
2
2
y
uv
x
P1
y
uv
x
uu
0y
P
2
p2
2
y
u
c
v
y
T
y
Tv
x
Tu
,
This can be used to
solve for the temperature
2A
2
ABAA
yD
yv
xu
2A
2
ABAA
y
CD
y
Cv
x
Cu
This can be used to solve for concentration variation
or
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Boundary Layer Similarity and Normalized
Convection Equations
Examination of the simplified convection equations
repeated below shows a strong similarity between themomentum equation and energy equation:
Similarly, there is a strong similarity between mass transferand momentum and energy equations as indicated below:
2
2
y
uv
x
P1
y
uv
x
uu
2
p2
2
y
u
c
v
y
T
y
Tv
x
Tu
Momentum equation
in x-direction for
velocities u and v
Energy equation for
temperature T
DiffusionAdvection
2A
2
ABAA
y
CD
y
Cv
x
Cu
Mass TransferEquation
Diffusion
Advection
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Similarity Parameters for Boundary Layers
Dimensionless independent variables defined as:
Dependent dimensionless variables are:
The dimensionless independent and dependent variables may besubstituted in to the momentum and energy equations to obtain
dimensionless forms of conservation equations (see table 6.1)
Similarity parameters make it possible to apply results obtained for a
surface experiencing one set of conditions to geometrically similar
surfaces experiencing entirely different conditions.
L
x*x
L
y*y Where L = characteristic
length for the surface
V
u*u
V
v*v
s
s
TT
TT*T
s,A,A
s,AAA
CC
CC*C
2V
P*P
and
, ,
,
Where
V = Upstream velocity
CA= mass concentration
of species A
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Dimensionless groups
1. Reynolds Number (Re)
Is the viscosity (kg / s m)
is the kinematic viscosity (m2/s)
2. Prandtl Number (Pr)
3. Nusselt Number (Nu) = The dimensionless temperature
gradient at the surface.
4. Stanton Number (St)
cc VLVL
Re
k
cPr
p
0*yf
c
*y
*T
k
hL
Nu
pVc
h
PrRe
NuSt
= Inertia Forces
Viscous Forces
= Momentum diffusivity
Thermal diffusivity
(A modified
Nusselt Number)
is the thermal diffusivity (m2/s)
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5. Schmidt Number (Sc)
6. Sherwood Number (Sh) = Dimensionless concentration
gradient at the surface
In terms of dimensionless groups, the complete set of
dimensionless convection equations are therefore:
ABDSc
0*y
A
AB
mL
*y
*C
D
LhSh
= Momentum diffusivity
Mass diffusivity
DAB= mass diffusivity (m2/s)
0*y
*v
*x
*u
2
2
L *y
*u
Re
1
*x
*P
*y
*u*v
*x
*u*u
Velocity (Continuity equation)
Velocity
(Momentum
equation)
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Solution Forms:
2
2
L *y
*T
PrRe
1
*y
*T*v
*x
*T*u
2A2
L
AA
*y
*CScRe1
*y*C*v
*x*C*u
*dx*dp
,Re*,y*,xf*u L1
*dx
*dp,Re*,xf
*y
*uL2
0*y0*y
L2f *y
*u
Re
2
2V
C
*dx
*dpPr,,Re*,y*,xf*T L3
Thermal
(Energy Equation)
Mass Concentration(Mass Diffusion
Equation)
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Nusselt Number:
Convection mass transfer:
0*y
f
0*ys
sf
*y
*T
L
k
*y
*T
TT
TT
L
kh
L,V,,,c,kfh p
0*yf *y
*T
k
hLNu
Pr,Re*,xfNu L4
Pr,Refk
LhNu L5
f
Pr,Re,Nufh L
*dx
*dp,Sc,Re*,y*,xf*C L6A
0*yAAB
0*y
A
,As,A
s,A,AABm
*y
*C
L
D
*y
*C
CC
CC
L
Dh
Where hm= mass transfer coefficient, m/s (convection)
,
,
,
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Sherwood Number:
Physical Significance of the Dimensionless Parameters
Reynolds Number
Inertia forces therefore dominate for large values of Re andviscous forces dominate for small Re values. Viscous forces
dominate in laminar flow but become progressively less
important than inertia forces as Re increases.
0*y
A
AB
m
*y
*C
D
LhSh
Sc,Re*,xfSh L7
Sc,RefD
LhSh L8
AB
m L,V,,,c,DfSc,Re,Shfh pABLm
L2
2
2
1 ReVL
LV
LV
F
F
= Inertia Forces
Viscous Forces
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Prandtl Number, Pr
Large differences in Pr are associated with large variations in the
fluid viscosity, . The spectrum of Prandtl Numbers of fluids isgiven below.
Normally
is the velocity B.L. thickness and tis the thermal B.L.thickness.
k
cPr
p
= Momentum diffusivityThermal diffusivity
10-2 10-1 100 10 102 103
Liquid metals Gases WaterLight Organics
Oils
n
t
Pr
Where n is a positive integer
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For gases,
For liquid metals (very high k, low Pr)
For oils (very high , high Pr)
Mass transfer and Lewis Number, Le
Table 6.2 (text) lists several dimensionless parameters that
are generally relevant in heat and mass transfer
t
t
t
n
c
Sc
Pr
Sc
DLe
AB
n
c
t Le
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Boundary Layer Analogies
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Boundary Layer Analogies
Heat and mass transfer analogy
Heat and mass transfer are analogous
Heat and mass transfer relations are therefore interchangeablefor a particular geometry
For example, it the form of relationship for a convection heat
transfer problem involving x*, Re, and Pr, that is f4(x*, Re, Pr) has
been obtained for a particular surface geometry, the results may
be used for convection mass transfer for the same geometrysimply by replacing Nu with Sh and Pr with Sc
The analogy can also be used to relate two convection
coefficients. By analogy:
nL7L4n Sc
Sh
Re*,xfRe*,xfPr
Nu
nABm
n Sc
DLh
Pr
khL
n1pn
ABm
LecLeD
k
h
h
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Problem 6.46
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Reynolds Analogy
When dP*/dx*= 0 and Pr = Sc = 1, the boundary layer equations
(momentum, energy and mass concentration) are exactly of the
same form. If dP*/dx*= 0 then U= V = upstream fluid velocity, and the
boundary conditions are also of the same form.
Solutions for U*,T*, CA* must also be of the same form.
It follows that:
ShNu2
ReC Lf
pVc
h
PrRe
NutS
V
h
ScRe
ShSt mm
(1)
Modified Nusselt Number
Mass Transfer Stanton Number
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From (1) we have: Reynolds Analogy,
The Reynolds analogy can be used, provided these restrictionsare satisfied
dP*/dx* 0 , Pr 1 , Sc 1
In general application, the modified Reynolds analogy is:
Where jH, and jmare the Colburn j factor for heat and masstransfer
Equations (2) and (3) are approximate for laminar flow, butmore accurate or valid for turbulent flow.
mf StSt2
C If one parameter is known, it can be
used to obtain others.
Hf jPrSt2
C32
mmf jScSt2
C32
For 0.6 < Pr < 60
For 0.6 < Sc < 3000
(2)
(3)
Evaporative Cooling: Simultaneous Heat &
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Evaporative Cooling: Simultaneous Heat &
Mass Transfer
As shown in the figure below, the Evaporative cooling
process of heat and mass transfer occurs when a gasflows over a liquid surface.
There are numerous industrial and environmental
applications of evaporative cooling process.
In the evaporative cooling process the energy required for
evaporation of the liquid comes from the internal energy of
the liquid. As a consequence, the temperature of the liquid
reduces or cooling effect occurs
Liquid Layer (species A)
Gas Layer(species B)
qevap
qadd
qconv
Latent and sensible heat exchange at a gas liquid interface
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Under steady state operation, the latent energy lost by the
liquid must be replenished by energy transfer to the liquid from
its surroundings or by energy addition by other means (e.g.
electrical heating of the fluid By energy conservation on a control surface on the liquid
surface, we have:
Where
qevap = evaporative cooling load
qconv = convection sensible heat transfer from the gas to the
liquid
qadd = heat addition to the liquid
If there is no heat addition we have
Where A,satis the saturated vapor density at the surface
temperature, Ts.
evapaddconv qqq
fgs,s,Amfgaevap hhhmq
s,ss,Afgms ThhTTh
d
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expressed as:
Since by heat and mass transfer analogy, and for exponent n=1/3
With mA
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Solution Methods in Internal and External
Convection Transfer
The primary objective in internal and external convection
transfer is to obtain convection coefficients for different flow
geometries. The convection coefficients are subsequently used
to obtain heat or mass transfer rates.
Solution methods in obtaining convection coefficients include:
Experimental or Empirical Method
Theoretical Method Non-dimensionalized approach is generally followed, and the
local and average convection coefficients are generally
correlated by the following form of equations:
Heat Transfer Mass Transfer
Pr,Re*,xfNu x4x
Pr,RefNu x5x
Sc,Re*,xfSh x7x
Sc,RefSh x8x
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Experimental or Empirical Method
The empirical method involves heat and mass transfer
measurements and data correlation using appropriate
dimensionless parameters For fixed Prandtl numbers for a given fluid, log-log plots of Re
versus Nu generally are straight lines as illustrated below (left).
The straight line plots may be represented by an equation of
the form: nmLL PrReCNu Where C, m, n are independent
constants
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Log-log plot of Re versus the ratio Nu / Prncombine into a
single straight line for all the Pr as illustrated above (right).
The corresponding correlation equation for mass transfer
is of the form:
Where the independent constants C, m, and n are the
same as obtained for heat transfer for similar geometry
nmLL ScReCSh
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Theoretical method
Special case of exact solution to convection transfer equations(example 6.4 in text)
Parallel flow or Couette flow is one of the situations where exactsolutions can be obtained for convection transfer equations. Aspecial case of parallel flow involves stationary and movingplates of infinite extent separated by a distance L with theintervening space filled by an incompressible fluid as shownbelow:
With the assumption of steady state conditions, incompressiblefluid with constant properties, no body forces (I.e. X=0, andY=0), and no internal energy generation the convection transferequations reduce to the following:
Engine oil
Moving Plate
Stationary Plate
LTL
T0 x,uy,v
U
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1. Continuity Equation
For incompressible fluid (= constant) and parallel flow(v = 0) the continuity equation reduces to:
The x velocity component is therefore independent of x, and
the velocity field is said to be fully developed.
2. Momentum Equation With u / v = 0, v = 0 and X = 0, the momentum equation
reduces to:
In parallel flow the pressure gradient P / x = 0, and the x-
momentum equation reduces to:
0xu
0y
u
yx
P0
0y
u2
2
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Finally, the velocity distribution is given by:
3. Energy equation For the 2-D, S.S. condition with y=0, energy generation q=0 and
u/x = 0 for fully developed temperature field, the energy
equation reduces to:
Integrating twice and solving, the temperature distribution is
given by:
0)0(u U)L(u UL
y)y(u
2
2
2
y
u
y
Tk0
L
yTT
L
y
L
yU
k2
TyT 0L
22
o
2
22
bL
y1U
k2TyT
B.C.s
T(0) = ToT(L) = TL
Tb= bearing Temp.
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ME 327(10)Introduction to Convection 50 of 51
4. Surface Heat Fluxes
The surface heat fluxes are obtained from the temperature
distribution by applying the Fouriers Law:
At the bottom and top surfaces, the heat fluxes are respectively
given be:
5. Location of Maximum Temperature
The location of the maximum temperature may be found from
the requirement:
LTT
Ly2
L1U
k2k
dydTkq 0L
22
y
0L2
0 TT
L
k
L2
Uq
0L
2
L TT
L
k
L2
Uq
0L
TT
L
y2
L
1
Uk2dy
dT 0L2
2
L2
1TT
U
ky 0L2max
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The maximum temperature occurs in the fluid and there is heat
transfer to the hot and cold plates. The temperature distribution
is a string function of the velocity of the moving plate.
6. Viscous Energy Dissipation The viscous energy dissipation was defined as:
With v = 0, and du/dx = 0, the viscous energy dissipation
equation reduces to:
For U = 0 there is no viscous dissipation, and the temperature
distribution is linear.
2222
y
v
x
u
3
2
y
v
x
u2
x
v
y
u
2
dy
du