1.15 using solubility rules to predict precipitate formation pp. 54 - 60
TRANSCRIPT
1.15 Using Solubility Rules to Predict Precipitate Formation
pp. 54 - 60
Chemical Reactions in Solution• A solution is a homogeneous mixture in which
a solute – substance in lesser quantity – is dissolved in a solvent – substance in greater quantity.
• An aqueous solution is a solution in which water is the solvent. – The subscript (aq) denotes an aqueous solution
• A solid that is formed as a result of the chemical reaction of two aqueous solutions is called a precipitate.
Solubililty• Solubility is a measure of the amount of a
substance that dissolves in water at a given temperature and pressure.
• A substance with low solubility will remain solid when mixed with water or precipitate out of the solution.– This is denoted with a subscript (s) for solid.
• Table 1 on p. 54 tells us which ionic compounds are soluble and which has low solubility.
Practice___ AgNO3(aq) + ___ CaCl2(aq)
___ NaOH(aq) + ___ Ca(NO3)2(aq)
• If both products are soluble, there is no reaction – write NR after the arrow
NaNO3(aq) + KCl(aq)
Total & Net Ionic Equations
• A total ionic equation depicts the separation of soluble ionic compounds into their respective ions– Re-write an each aqueous ionic compound as two
ions. If not aqueous just re-write the chemical.– e.g. Na2SO4(aq) = 2Na+
(aq) + SO42-
(aq)
– e.g. CaSO4(s) = CaSO4(s)
• Write the total ionic equation for the following reaction:– Na2SO4(aq) + CaCl2(aq) CaSO4(s) + 2NaCl(aq)
Total & Net Ionic Equations• 2Na+
(aq) + SO42-
(aq) + Ca2+(aq) + 2Cl-
(aq) CaSO4(s) + 2Na+
(aq) + 2Cl-(aq)
• If an ion exists on both sides of an equation it means it does not participate in the reaction and so it is called a spectator ion.
• A net ionic equation depicts only the ions that are involved in a chemical reaction.– Cross out the spectator ions in the total ionic
equation and re-write what’s left.
Net Ionic Equation
• Write the net ionic equation for the above reaction:
• 2Na+(aq) + SO4
2-(aq) + Ca2+
(aq) + 2Cl-(aq) CaSO4(s) + 2Na+
(aq) + 2Cl-(aq)
• After crossing out the spectator ions we are left with:
• SO42-
(aq) + Ca2+(aq) CaSO4(s)