12.3 – analyze geometric sequences and series
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12.3 – Analyze Geometric Sequences and Series. Geometric Sequence:. Ratio of any term to the previous term is constant. Common Ratio:. Ratio each term is increasing by. 1. Tell whether the sequence is geometric. 4, 10, 18, 28, 40, …. 5 2. 9 5. 14 9. 10 7. No. - PowerPoint PPT PresentationTRANSCRIPT
12.3 – Analyze Geometric Sequences and Series
Geometric Sequence:
Ratio of any term to the previous term is constant
Common Ratio:
Ratio each term is increasing by
1. Tell whether the sequence is geometric.
4, 10, 18, 28, 40, …
52
95
14 9
10 7
No
2. Tell whether the sequence is geometric.
625, 125, 25, 5, 1, …
15
15
15
15
Yes
3. Tell whether the sequence is geometric.
–4, 8, –16, 32, –64, …
–2
Yes
–2 –2 –2
Rule for a Geometric Sequence:
The nth term of a geometric sequence with first term a1 and common ratio r is given by:
11
nna a r
4. Write a rule for the nth term of the sequence. Then find a7.
4, 20, 100, 500, ….
11
nna a r
a1 = 4
r = 5
14 5
nna
a7 = 4(5)7–1
a7 = 4(5)6
a7 = 4(15625)
a7 = 62500
5. Write a rule for the nth term of the sequence. Then find a7.
152, –76, 38, –19, …
11
nna a r
a1 = 152
r =-1 2
11
1522
n
na
a7 = 152(-1/2)7–1
a7 = 152(-1/2)6
a7 = 152(1/64)
a7 = 19/8
6. Write a rule for the nth term of the geometric sequence, given: a4 = 12, r = 2
11
nna a r
12 = a1(2)4 – 1
12 = a1(2)3
12 = 8a1
3/2 = a1
132
2n
na
7. Write a rule for the nth term of the geometric sequence, given: a6 = –96, r = 2/3
11
nna a r
12
7293
n
na
6 1
12
963
a
5
12
963
a
132
96243
a 243
32
1729 a
8. Write a rule for the nth term of the geometric sequence, given: a3 = –48, a6 = 3072 1
1n
na a r
3 1148 a r
6 113072 a r
2148 a r 5
13072 a r
12
48a
r
52
483072 r
r
r3
33072 48r364 r
4 r
148
16a
13 a
13 4
nna
9. Write a rule for the nth term of the geometric sequence, given: a2 = –12, a4 = –3 1
1n
na a r
2 1112 a r
4 113 a r
112 a r 3
13 a r
112
ar
3123 r
r
r2
23 12r 21
4r
1
2r
112
0.5a
124 a
11
242
n
na
Sum of a Finite Geometric Series:
The sum of the first n terms of a geometric series with common ratio r 1 is:
11
1
n
nr
S ar
11
1
n
nr
S ar
10. Find the sum of the geometric series.
16
1
1
4 3i
i
a1 = 4(3)1-1 =
r = 3
4(1) = 4
n = 16
161 34
1 3nS 1 43046721
41 3nS
4 21523360
86,093,440S
11
1
n
nr
S ar
11. Find the sum of the geometric series.7
0
112
2
i
i
a1 = 12(-1/2)0 =
r = -1/2
12(1) = 12
n = 8
81 0.5
121 0.5nS
1 0.00390625
121.5nS
8512
128
255
32S