13468-10-59p
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98988TRANSCRIPT
13468-10-59P AID: 1825 | 05/12/2014
Show the T-s diagram with steam as working fluid for the ideal Rankine cycle as in Figure (1).
Express the specific work input to the cycle.
(1)
Here, pressure at state 1 is , pressure at state 2 is , and specific volume of steam at state 1 is .
Refer to saturated water-pressure table, and interpret the values of , and for a pressure
Substitute for , for , and for in Equation (1).
Express the enthalpy of steam at state 2.
(2)
Here, specific enthalpy of steam at state 1 is , and specific enthalpy of steam at state 2 is .
Substitute for , and for in Equation (2).
Express the quality of steam at the end of heat rejection process.
(3)
Here, specific entropy of saturated liquid is, specific entropy of vaporization is , and specific entropy at state 4 is .
Refer to superheated water table, and interpret the values of and for a pressureand temperature .
Similarly, interpret the values of , and from saturated water-pressure table for a pressure .
Since , substitute for , for , and for in Equation (3).
Therefore, the quality of steam at the exit of turbine is .
Express the specific enthalpy of steam at state 4.
(4)
Refer to saturated steam tables, and interpret the value of for a pressure as .
Substitute for , for , and 0.7934 for in Equation (4).
Express the specific heat input to the Rankine cycle.
(5)
Here, specific heat input to the cycle is , specific enthalpy of steam at state 3 is .
Substitute for , and for in Equation (5).
Express the specific heat output of the Rankine cycle.
(6)
Here, specific heat output of the cycle is .
Substitute for , and for in Equation (6).
Express the exergy destruction for the process.
(7)
Here, entropy at state i is , entropy at state j is , heat transferred during the process is , and temperature of the heat source is , and ambient temperature is .
As processes , and are isentropic processes, the exergy destruction during the process remains constant. Therefore, the exergy destruction during processes , and are .
Process .
Substitute 290 K for , 1,500 K for , for , for , and for in Equation (7).
Therefore, the exergy destruction during process is .
Process .
Substitute 290 K for , 290 K for , for , for , and for in Equation (7).
Therefore, the exergy destruction during process is .