1.6 angle pair relationships. which angles are adjacent? 1 3 2 4

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Linear Pair (of angles) 2 adjacent angles whose non-common sides are opposite rays. 1 2

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Page 1: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

1.6 Angle Pair Relationships

Page 2: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Which angles are adjacent?

1 32

4

<1&<2, <2&<3, <3&<4, <4&<1

Vertical Angles – 2 angles that share a common vertex & whose sides form 2 pairs of opposite rays.

<1&<3, <2&<4

Then what do we call <1&<3?

Page 3: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Linear Pair (of angles)

• 2 adjacent angles whose non-common sides are opposite rays.

1 2

Page 4: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Example• Vertical angles?

<1 & <4• Adjacent angles?

<1&<2, <2&<3, <3&<4, <4&<5, <5&<1• Linear pair?

<5&<4, <1&<5• Adjacent angles not a linear pair?

<1&<2, <2&<3, <3&<4

1 3

2

5 4

Page 5: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Important Facts

• Vertical Angles are congruent.

• The sum of the measures of the angles in a linear pair is 180o.

Page 6: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Example:

• If m<5=130o, findm<3m<6m<4

5 3

4

6

=130o

=50o

=50o

Page 7: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Example:• Find x

ym<ABEm<ABDm<DBCm<EBC

3x+5o y+20ox+15o 4y-15o

x=40

y=35

m<ABE=125o

m<ABD=55o

m<DBC=125o

m<EBC=55o

A

B

C

D

E

Page 8: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Complementary Angles

• 2 angles whose sum is 90o

1

2

35o

A

55o

B<1 & <2 are complementary

<A & <B are complementary

Page 9: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Supplementary Angles• 2 angles whose sum is 180o

1 2

130o 50o

X Y

<1 & <2 are supplementary.

<X & <Y are supplementary.

Page 10: 1.6 Angle Pair Relationships. Which angles are adjacent? 1 3 2 4

Ex: <A & <B are supplementary. m<A is 5 times m<B. Find m<A & m<B.

m<A + m<B = 180o

m<A = 5(m<B)Now substitute!

5(m<B) + m<B = 180o

6(m<B)=180o

m<B=30o

m<A=150o