2 stories house calculation report

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  • 8/16/2019 2 stories house calculation report

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    (Purlin)

    (Length ,L) 1 m.(Spacing, @) 0.33 m.

    (Slope of Roof) 30 degree

    (Live Load) 30 kg/m. 2 (Dead Load)

    (Roof Material) 50 kg/m. 2 (Purlin) 5 kg/m. 2 ( , ) 15 kg/m. 3

    Dead Load 70 kg/m. 2

    0-10 m. 50 kg/m. 2(Wind Load)= (2Psinθ/1+sin^2θ) 40.00 kg/m. 2

    Load Casekg/m.

    Case 1 DL= x DL= 23.1 kg/m.

    Case 2 DL+LL = x(DL+LL )= 33 kg/m.

    Case 3 0.75(DL+LL+WL) x = 34.65 kg/m.

    W = 35 kg/m.Wx = Wsin q = 17.5 kg/m.Wy = Wcos q = 30.31 kg/m.

    = 3.03 kg.m.

    S x = 0.21 cm. cm.

    25x 25x2 mm. @ 0.33 m.

    S x = 1.19 cm. Ix = 1.48 cm.

    0.13 cm L/240 = 0.42 cm O.K.

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    (Length ,L) 2 m. 0.33 m.

    1 m. (Slope of Roof) 30 degree

    (Live Load) 30 kg/m. 2 (Dead Load)

    7 kg/m. 2 (Roof Material) 50 kg/m. 2 (Purlin) 5 kg/m. 2 ( , ) 15 kg/m. 3

    Dead Load 77 kg/m. 2

    0-10 m. 50 kg/m. 2 (Wind Load) 40.00 kg/m. 2

    W = 110 kg/m. w = W/cosθ = 127.02 kg/m.

    = 80.00 kg.m.

    S x = 5.56 cm.

    100 x 50 x 20 x 3.2

    S x = 21.3 cm. Ix = 107 cm.

    0.07 cm.

    0.56 cm. O.K.

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    Project : Engineer :Location : Date :Owner : Time :

    1.1.End Moment(M 1) kg.-m. 2.1.Use Steel Grade

    1.2.Middle Moment 300.00 kg.-m. 2.2.Modulus Of Elastic 2,100,000 ksc.

    1.3.End Moment(M 2) 2.3.Yield Strength 2,400 ksc.

    1.4.Max. Shear(V.) 450.00 kg. 2.4.Ultimate Strength 4,100 ksc.

    1.5.Deflection( ) kg.-m.3

    2.5.All. Bend. Stress 1,440 ksc.

    1.6.Max. Length(L.) 1.50 m. 2.6.All. Deflextion= L 240

    1.7.Lateral Support(L b) 1.50 m.

    1.8.Coefficient of C b 1.00 4.1.Real Laterally Sup. ***** m.

    4.2.Min. Laterall Sup. 1.30 m.

    3

    kg.-m.

    [ I.Datas For Design ] [ II.Properties Of Steel For DesignFe-24

    ddbcb

    30- . .-2015

    10:57:41 PM

    Design For Flexible Members :

    [ IV.Check Laterally Supported ]

    [ III.Result Of Calculate ]3.1.Required (S x-x) 20.83 cm. 4.3.Max. Laterall Sup. 2.50 m.

    3.2.Type Of Section 2 Lip. Chan. C3.3.Trial Section No. 8 2 Double

    3.4.Size Of Section 150*50*20 mm. 5.1.Laterally Supported Is Sufficiently3.5.Thick. Web(t , t w) 3.20 mm. = *****

    3.6.Thick. Flange(t f ) 3.20 mm. = *****

    3.7.Section Area(A s) 8.61 cm.2

    = *****

    3.8.Weight Of Section 6.76 kg./m. All.Bending Stress(Fb) ***** ksc.

    3.9.Sect. Modulus(S x-x) 37.40 cm.3

    3.10.M. Of In.(I x-x) 280.00 cm.4

    5.2.Laterally Supported Is Non-Sufficiently

    3.11.Rad. Of Gyr.(r min.) 1.81 cm. = 75.66

    = 54.66

    = 122.22

    1.Actual Bending Stress 401 ksc. OK.! All.Bending Stress(Fb) 1,440.00 ksc.

    2.Actual Shear Stress 102.50 ksc. OK.!

    3.Actual Deflextion 6.1.Max. Allowable 0.63 cm.

    [ Recheck Allowable Stress On Section ]2C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    [ VI.Allowable Deflextion( < (L/240) ]

    Select To Use Section : 2C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    >

    [ V.Allowable Bending Stress(Fb) ]

    >

    7 1 7 1 0 4* * Cb

    F y

    4 3 7 7.

    F y

    b f

    t f 2 *

    7 9 6 5.

    F y

    L

    r t

    3 5 8 5 1 0 4* * C b

    F y

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    Project : Engineer :Location : Date :Owner : Time :

    1.1.End Moment(M 1) kg.-m. 2.1.Use Steel Grade

    1.2.Middle Moment 30.00 kg.-m. 2.2.Modulus Of Elastic 2,100,000 ksc.

    1.3.End Moment(M 2) 2.3.Yield Strength 2,400 ksc.

    1.4.Max. Shear(V.) 200.00 kg. 2.4.Ultimate Strength 4,100 ksc.

    1.5.Deflection( ) kg.-m.3

    2.5.All. Bend. Stress 1,440 ksc.

    1.6.Max. Length(L.) 1.50 m. 2.6.All. Deflextion= L 240

    1.7.Lateral Support(L b) 1.50 m.

    1.8.Coefficient of C b 1.00 4.1.Real Laterally Sup. ***** m.

    4.2.Min. Laterall Sup. 1.30 m.

    3

    kg.-m.

    [ I.Datas For Design ] [ II.Properties Of Steel For DesignFe-24

    ddbcb

    30- . .-2015

    10:52:49 PM

    Design For Flexible Members :

    [ IV.Check Laterally Supported ]

    [ III.Result Of Calculate ]3.1.Required (S x-x) 2.08 cm. 4.3.Max. Laterall Sup. 2.50 m.

    3.2.Type Of Section 2 Lip. Chan. C3.3.Trial Section No. 8 2 Double

    3.4.Size Of Section 150*50*20 mm. 5.1.Laterally Supported Is Sufficiently3.5.Thick. Web(t , t w) 3.20 mm. = *****

    3.6.Thick. Flange(t f ) 3.20 mm. = *****

    3.7.Section Area(A s) 8.61 cm.2

    = *****

    3.8.Weight Of Section 6.76 kg./m. All.Bending Stress(Fb) ***** ksc.

    3.9.Sect. Modulus(S x-x) 37.40 cm.3

    3.10.M. Of In.(I x-x) 280.00 cm.4

    5.2.Laterally Supported Is Non-Sufficiently

    3.11.Rad. Of Gyr.(r min.) 1.81 cm. = 75.66

    = 54.66

    = 122.22

    1.Actual Bending Stress 40 ksc. OK.! All.Bending Stress(Fb) 1,440.00 ksc.

    2.Actual Shear Stress 45.55 ksc. OK.!

    3.Actual Deflextion 6.1.Max. Allowable 0.63 cm.

    [ Recheck Allowable Stress On Section ]2C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    [ VI.Allowable Deflextion( < (L/240) ]

    Select To Use Section : 2C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    >

    [ V.Allowable Bending Stress(Fb) ]

    >

    7 1 7 1 0 4* * Cb

    F y

    4 3 7 7.

    F y

    b f

    t f 2 *

    7 9 6 5.

    F y

    L

    r t

    3 5 8 5 1 0 4* * C b

    F y

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    Project : Engineer :Location : Date :Owner : Time :

    1.1.Design Load(P) 300 kg. 2.1.Use Steel Grade

    1.2.Length(Lx-x) 1.10 m. 2.2.Modulus Of Elastic. 2,100,000 ksc.

    1.3.Length(Ly-y) 1.10 m. 2.3.Yield Strength 2,400 ksc.

    1.4.Max. Length 1.10 m. 2.4.Ultimate Strength 4,100 ksc.

    1.5.Min. Value Of k 0.65 2.5.All. Comp. Stress 1,440 ksc.

    1.6.Use Value Of k 1.20 2.6.Use Allowable KL/r 200 For Main.

    3.1.Req. Min. Area 0.21 cm.2

    4.1.Type Of Section 2 Lip. Chan.

    ****

    [ IV.Select Type & Section Of Steel ]

    Fe-24

    [ III.Result Of Calculate ]

    ddbcb

    Design For Axially Compression Members :

    24- . .-2546

    11:00:57 PM

    [ I.Datas For Design ] [ II.Properties Of Steel For Desig

    [fixed-fixed]

    . . c . . . .

    3.3.Value Of ( ) (kL/r) 72.93 OK.! 4.3.Size Of Section 150*50*20 mm.

    3.5.Allowable Compressive Stress : F a 4.4.Thick. Web(t , tw) 3.20 mm.

    4.5.Thick. Flange(tf) 3.20 mm.

    Fai = 1,095.54 ksc. 4.6.Section Area(As) 8.61 cm.2

    4.7.Weight Of Section 6.76 kg./m.

    Fae = 0.00 ksc. 4.8.Sect. Modulus(Sx-x) 37.40 cm.3

    4.9.Moment Of In.(Ix-x) 280.00 cm.4

    4.10.Rad. Of Gyr.(rmin. 1.81 cm.

    5.1.Status Of Sect. Area 5.4.Actual Stress 34.86 ksc. OK.!

    5.2.Load Resist By Sect. 9,429 kg. OK.! 5.5.Slenderness Ratio 72.93 < 200 OK.!

    5.3.Safty Load 31.43 times

    2.)Elastic Range :

    : This Section OK.!

    Select To Use Section : C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    1.)Inelastic Range :

    [ V.Recheck Design Section ]C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    cr k l /

    cr k l /

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    Project : Engineer :Location : Date :Owner : Time :

    1.1.End Moment(M 1) kg.-m. 2.1.Use Steel Grade

    1.2.Middle Moment 202.00 kg.-m. 2.2.Modulus Of Elastic 2,100,000 ksc.

    1.3.End Moment(M 2) 2.3.Yield Strength 2,400 ksc.

    1.4.Max. Shear(V.) 120.00 kg. 2.4.Ultimate Strength 4,100 ksc.

    1.5.Deflection( ) kg.-m.3

    2.5.All. Bend. Stress 1,440 ksc.

    1.6.Max. Length(L.) 1.50 m. 2.6.All. Deflextion= L 240

    1.7.Lateral Support(L b) 1.50 m.

    1.8.Coefficient of C b 1.00 4.1.Real Laterally Sup. ***** m.

    4.2.Min. Laterall Sup. 1.30 m.

    3

    kg.-m.

    [ I.Datas For Design ] [ II.Properties Of Steel For DesignFe-24

    ddbcb

    30- . .-2015

    10:56:00 PM

    Design For Flexible Members :

    [ IV.Check Laterally Supported ]

    [ III.Result Of Calculate ]3.1.Required (S x-x) 14.03 cm. 4.3.Max. Laterall Sup. 3.75 m.

    3.2.Type Of Section 2 Lip. Chan. C3.3.Trial Section No. 4 2 Double

    3.4.Size Of Section 100*50*20 mm. 5.1.Laterally Supported Is Sufficiently3.5.Thick. Web(t , t w) 3.20 mm. = *****

    3.6.Thick. Flange(t f ) 3.20 mm. = *****

    3.7.Section Area(A s) 7.01 cm.2

    = *****

    3.8.Weight Of Section 5.50 kg./m. All.Bending Stress(Fb) ***** ksc.

    3.9.Sect. Modulus(S x-x) 21.30 cm.3

    3.10.M. Of In.(I x-x) 107.00 cm.4

    5.2.Laterally Supported Is Non-Sufficiently

    3.11.Rad. Of Gyr.(r min.) 1.87 cm. = 79.80

    = 54.66

    = 122.22

    1.Actual Bending Stress 474 ksc. OK.! All.Bending Stress(Fb) 1,440.00 ksc.

    2.Actual Shear Stress 43.00 ksc. OK.!

    3.Actual Deflextion 6.1.Max. Allowable 0.63 cm.

    [ Recheck Allowable Stress On Section ]2C - 100*50*20*3.2 mm.( = 5.5 kg./m.)

    [ VI.Allowable Deflextion( < (L/240) ]

    Select To Use Section : 2C - 100*50*20*3.2 mm.( = 5.5 kg./m.)

    >

    [ V.Allowable Bending Stress(Fb) ]

    >

    7 1 7 1 0 4* * Cb

    F y

    4 3 7 7.

    F y

    b f

    t f 2 *

    7 9 6 5.

    F y

    L

    r t

    3 5 8 5 1 0 4* * C b

    F y

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    Project : Engineer :Location : Date :Owner : Time :

    1.1.End Moment(M 1) kg.-m. 2.1.Use Steel Grade

    1.2.Middle Moment 828.00 kg.-m. 2.2.Modulus Of Elastic 2,100,000 ksc.

    1.3.End Moment(M 2) 2.3.Yield Strength 2,400 ksc.

    1.4.Max. Shear(V.) 730.00 kg. 2.4.Ultimate Strength 4,100 ksc.

    1.5.Deflection( ) kg.-m.3

    2.5.All. Bend. Stress 1,440 ksc.

    1.6.Max. Length(L.) 1.50 m. 2.6.All. Deflextion= L 240

    1.7.Lateral Support(L b) 1.50 m.

    1.8.Coefficient of C b 1.00 4.1.Real Laterally Sup. ***** m.

    4.2.Min. Laterall Sup. 1.30 m.

    3

    kg.-m.

    [ I.Datas For Design ] [ II.Properties Of Steel For DesignFe-24

    ddbcb

    30- . .-2015

    10:54:19 PM

    Design For Flexible Members :

    [ IV.Check Laterally Supported ]

    [ III.Result Of Calculate ]3.1.Required (S x-x) 57.50 cm. 4.3.Max. Laterall Sup. 2.50 m.

    3.2.Type Of Section 2 Lip. Chan. C3.3.Trial Section No. 8 2 Double

    3.4.Size Of Section 150*50*20 mm. 5.1.Laterally Supported Is Sufficiently3.5.Thick. Web(t , t w) 3.20 mm. = *****

    3.6.Thick. Flange(t f ) 3.20 mm. = *****

    3.7.Section Area(A s) 8.61 cm.2

    = *****

    3.8.Weight Of Section 6.76 kg./m. All.Bending Stress(Fb) ***** ksc.

    3.9.Sect. Modulus(S x-x) 37.40 cm.3

    3.10.M. Of In.(I x-x) 280.00 cm.4

    5.2.Laterally Supported Is Non-Sufficiently

    3.11.Rad. Of Gyr.(r min.) 1.81 cm. = 75.66

    = 54.66

    = 122.22

    1.Actual Bending Stress 1,107 ksc. OK.! All.Bending Stress(Fb) 1,440.00 ksc.

    2.Actual Shear Stress 166.27 ksc. OK.!

    3.Actual Deflextion 6.1.Max. Allowable 0.63 cm.

    [ Recheck Allowable Stress On Section ]2C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    [ VI.Allowable Deflextion( < (L/240) ]

    Select To Use Section : 2C - 150*50*20*3.2 mm.( = 6.76 kg./m.)

    >

    [ V.Allowable Bending Stress(Fb) ]

    >

    7 1 7 1 0 4* * Cb

    F y

    4 3 7 7.

    F y

    b f

    t f 2 *

    7 9 6 5.

    F y

    L

    r t

    3 5 8 5 1 0 4* * C b

    F y

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    S-1

    (S) 1.40 m. m = S/L = 0.35 (L) 4.00 m.

    D= S/20 7.00 cm. 10.00 cm.

    3 cm. (d) 7.00 cm.

    (w) Dead Load 240kg/m2Live Load 150kg/m2Finishing Load 50kg/m2

    (w) 440 kg/m2

    Mmax =( ws2) /8 = 107.80 kg.m < M = R.b.d2= 630.81 kg.m. O.K.

    (As) = = 1.47 cm2

    RB 9 mm. @ 0.20 m. As = 3.18 cm2

    Rb M

    d j fs M

    ..

    (As t)= 0.0025 x b x h= 2.5cm2 RB 9 mm. @ 0.20 m.

    As= 3.18cm2 O.K.

    (d)= = 2.89 cm. < 7.00 cm. O.K.

    . 11482

    Rb M

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    S2

    (S) 1.10 m. m = S/L = 0.55 (L) 2.00 m.

    D= (2S+2L)/180 3.44 cm. 10.00 cm.

    2.5 cm. (d) 7.50 cm.

    (w) Dead Load 240kg/m2Live Load 150kg/m2Finishing Load 50kg/m2

    (w) 440 kg/m2Cmax = 0.083

    Mmax = 44.19 kg.m

    (As) = = 0.56 cm2

    RB 9 mm.@ 0.20 m. As = 3.18cm2( 2 )

    d j fs M

    ..

    (d)= = 2.09 cm. < 7.50 cm. O.K.

    . 11482

    Rb

    M

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    ST-1

    (L) 4.00 m.

    D= L/25 16.00 cm. 15.00 cm.

    2.5 cm. (d) 12.50 cm.

    (w) Dead Load 700 kg/mLive Load 200 kg/mFinishing Load 30 kg/m ( ) 20 kg/m(w) 950 kg/m

    Mmax =( ws2)

    /8 = 1900.00 kg.m(w.L/2) = 1900 kg. (As) = = 11.47 cm2

    DB 12 mm. @ 0.10 m. As = 11.30cm2 2

    Rb

    M

    d j fs M

    ..

    = . x x . = . cm RB 9 mm. @ 0.15 m. As = 4.24cm2

    (d)= = 11.68 cm. < 12.50 cm. O.K.

    . 11482

    Rb

    M

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    ST-2

    (L) 1.05 m.

    D= L/25 4.20 cm. 10.00 cm.

    2.5 cm. (d) 7.50 cm.

    (w) Dead Load 630 kg/mLive Load 200 kg/mFinishing Load 50 kg/m ( ) 20 kg/m(w) 900 kg/m

    Mmax =( ws2)

    /8 = 124.03 kg.m(w.L/2) = 472.5 kg. (As) = = 1.25 cm2

    RB 9 mm. @ 0.20 m. As = 3.18cm2 2

    Rb

    M

    d j fs M

    ..

    = . x x . = . cm RB 9 mm. @ 0.2 m. As = 3.18cm2

    (d)= = 2.98 cm. < 7.50 cm. O.K.

    . 11482

    Rb

    M

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    B1

    0.20 m.0.40 m.0.03 m.

    d = 0.358 m.

    d' = 0.042 m.

    Dead Load B1 192 kg/m.

    M+ 1,600 kg-m.V 4,800 kg

    Mc =Rbd 2= 3,571.90 kg-m. > M +

    As 1 = M+/fs.jd= 3.37 cm

    ( ) 3 DB 12 mm As = 3.39 cm 20 DB 12 mm As = 0.00 cm 2

    3.39 cm

    ( ) 3 DB 12 mm As = 3.39 cm 2

    V 4,800 kg Vc = 0.29fc'^0.5(b.d) = 3216.75 kg

    V' = V -Vc= 1583.25 kg RB 6 mm. Av = 0.57 cm 2

    s = Av.fv.d/(V') = 15.34 cm. 0.20 m. 0.179 m.

    RB 6 mm @ 0.15 m.

    3 DB 12 mm

    RB 6 mm@ 0.15 m.

    3 DB 12 mm

    .11482

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    B4

    0.20 m.0.50 m.0.03 m.

    d = 0.456 m.

    d' = 0.044 m.

    Dead Load B4 240 kg/m.

    M+ 7,000 kg-m.V 7,100 kg

    Mc =Rbd 2= 5,795.13 kg-m. < M +

    M' = M + - Mc 1,205 kg-m. As 1 = Mc/fs.jd= 9.59 cm

    As 2 = M'/fs(d-d')= 1.95 cm

    As = As 1+As 2 = 11.54 . . ( ) 3 DB 16 mm As = 6.03 cm

    3 DB 16 mm As = 6.03 cm 2

    12.06 cm 2

    As' = 0.5As 2((1-k)/k-(d'/d))= 2.49 . . 3 DB 16 mm As = 6.03 cm 2

    0 DB 0 mm As = 0.00 cm 2

    6.03 cm 2

    V 7100 kg Vc = 0.29fc'^0.5(b.d) = 4097.31 kg

    V' = V -Vc= 3002.69 kg RB 6 mm. Av = 0.57 cm 2

    s = Av.fv.d/(V') = 10.30 cm. 0.20 m. 0.228 m

    RB 6 mm @ 0.10 m.

    3 DB 16 mm

    RB 6 mm@ 0.10 m.

    6 DB 16 mm

    .11482

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    B3

    0.20 m.0.50 m.0.03 m.

    d = 0.456 m.

    d' = 0.044 m.

    Dead Load B3 240 kg/m.

    M+ 4,500 kg-m.V 6,000 kg

    Mc =Rbd 2= 5,795.13 kg-m. > M +

    As 1 = M+/fs.jd= 7.45 cm

    ( ) 2 DB 16 mm As = 4.02 cm 22 DB 16 mm As = 4.02 cm 2

    8.04 cm

    ( ) 2 DB 16 mm As = 4.02 cm 2

    V 6,000 kg Vc = 0.29fc'^0.5(b.d) = 4097.31 kg

    V' = V -Vc= 1902.69 kg RB 6 mm. Av = 0.57 cm 2

    s = Av.fv.d/(V') = 16.25 cm. 0.20 m. 0.228 m.

    RB 6 mm @ 0.15 m.

    2 DB 16 mm

    RB 6 mm@ 0.15 m.

    4 DB 16 mm

    .11482

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    B2

    0.20 m.0.40 m.0.03 m.

    d = 0.358 m.

    d' = 0.042 m.

    Dead Load B2 192 kg/m.

    M+ 2,700 kg-m.V 4,800 kg

    Mc =Rbd 2= 3,571.90 kg-m. > M +

    As 1 = M+/fs.jd= 5.69 cm

    ( ) 3 DB 12 mm As = 3.39 cm 22 DB 12 mm As = 2.26 cm 2

    5.65 cm

    ( ) 3 DB 12 mm As = 3.39 cm 2

    V 4,800 kg Vc = 0.29fc'^0.5(b.d) = 3216.75 kg

    V' = V -Vc= 1583.25 kg RB 6 mm. Av = 0.57 cm 2

    s = Av.fv.d/(V') = 15.34 cm. 0.20 m. 0.179 m.

    RB 6 mm @ 0.15 m.

    3 DB 12 mm

    RB 6 mm@ 0.15 m.

    5 DB 12 mm

    .11482

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    C-2

    25,000 kg Y 25 cm X 25 cm

    Ag= 625 SD 30 4 DB 16 mm

    As = 8.05fc' = 240 ksc fy= 3000 ksc

    fs= 1200 ksc pg= 0.013 (0.01-0.08) OK

    P= 40,082 kg > 25,000 kg OK RB 6 mm

    0.26 m

    0.29 m0.25 m

    2.40 cm 4 cm4 DB 16 mm

    RB 6 mm @ 0.15 m25 cm

    25 cm

    4 DB 16 mm RB 6 @ 0.15 m.

    .11482

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    C-1

    15,000 kg Y 20 cm X 20 cm

    Ag= 400 SD 30 4 DB 12 mm

    As = 4.53fc' = 240 ksc fy= 3000 ksc

    fs= 1200 ksc pg= 0.011 (0.01-0.08) OK

    P= 25,016 kg > 15,000 kg OK RB 6 mm

    0.19 m

    0.29 m0.20 m

    1.80 cm 4 cm4 DB 12 mm

    RB 6 mm @ 0.15 m20 cm

    20 cm

    4 DB 12 mm RB 6 @ 0.15 m.

    .11482

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    Project : 2 Engineering ByLocation :

    . . . ; F5 = . .

    : ( x - direction : a ) =

    : ( y - direction : b) =

    = . ./ . . .

    . . = . .

    = . .

    =

    =

    : ( t ) =

    : ( d ) =

    : (Total Load ) = . .

    : ( q ) = . ./ . . . < : OK

    M = WL2 / 2 = . . - .

    d req. = sqrt ( M / Rb) = . < Effective depth :OK

    ; Beam Shear

    vb = 0.29 x sqrt ( fc' ) = ./ . . .

    Vb = V / ( B x d ) = ./ . . . < vb : OK

    ; Punching Shear vp = 0.53 x sqrt ( fc' ) = ./ . . .

    Vp = V / ( b x d ) = ./ . . . < vp : OK

    As = M / f s / j / d As = . . .

    Use 5 DB 12 mm m. As = . . . > As req. : OK

    S 0 = . .

    uall = 3.23 x sqrt(fc') / D = . ./ . . . . (Use 35 / . .)

    S 0 = V / Uall x j x d =

    = . . OK

    $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    REINFORCED CONCRETE DESIGN$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    3500

    Date : 29/11/2015 14:18

    0.20

    0.20

    8000

    7863

    0.30

    0.23

    0.04

    0.09

    350

    3850

    3853

    245.72

    0.69

    0.70

    @ 0.15

    1.95

    35.4

    0.81

    3.81

    6.97

    0.64

    18.85

    5.65

    1376.03 / 35 x 0.898 x 22

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    Ground level

    5 - DB12@ 0.15 m.

    DB 12 mm.

    1: 3 : 5

    8000 ./ . .

    F5

    0 . 2

    5

    0

    0 . 2

    5 0

    0 . 2

    0

    0.70

    0 . 7

    0

    0.250 0.2500.20

    0.20

    0 . 2

    0

    PLAN VIEW

    SECTION VIEW ;

    0.100.10

    0.230.30

    1.50

  • 8/16/2019 2 stories house calculation report

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    Project : 2 Engineering ByLocation :

    . . . ; F4 = . .

    : ( x - direction : a ) =

    : ( y - direction : b) =

    = . ./ . . .

    . . = . .

    = . .

    =

    =

    : ( t ) =

    : ( d ) =

    : (Total Load ) = . .

    : ( q ) = . ./ . . . < : OK

    M = WL2 / 2 = . . - .

    d req. = sqrt ( M / Rb) = . < Effective depth :OK

    ; Beam Shear

    vb = 0.29 x sqrt ( fc' ) = ./ . . .

    Vb = V / ( B x d ) = ./ . . . < vb : OK

    ; Punching Shear vp = 0.53 x sqrt ( fc' ) = ./ . . .

    Vp = V / ( b x d ) = ./ . . . < vp : OK

    As = M / f s / j / d As = . . .

    Use 6 DB 12 mm m. As = . . . > As req. : OK

    S 0 = . .

    uall = 3.23 x sqrt(fc') / D = . ./ . . . . (Use 35 / . .)

    S 0 = V / Uall x j x d =

    = . . OK

    $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    REINFORCED CONCRETE DESIGN$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    6000

    Date : 29/11/2015 14:11

    0.20

    0.20

    8000

    6720

    0.30

    0.23

    0.06

    0.52

    600

    6600

    6720

    537.60

    0.91

    1.00

    @ 0.18

    3.80

    35.4

    1.77

    3.81

    6.97

    1.44

    22.62

    6.79

    2688 / 35 x 0.898 x 22.5

  • 8/16/2019 2 stories house calculation report

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    Ground level

    6 - DB12@ 0.18 m.

    DB 12 mm.

    1: 3 : 5

    8000 ./ . .

    F4

    0 . 4

    0

    0

    0 . 4

    0 0

    0 . 2

    0

    1.00

    1 . 0

    0

    0.400 0.4000.20

    0.20

    0 . 2

    0

    PLAN VIEW

    SECTION VIEW ;

    0.100.10

    0.230.30

    1.50

  • 8/16/2019 2 stories house calculation report

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    Project : 2 Engineering ByLocation :

    . . . ; F3 = . .

    : ( x - direction : a ) =

    : ( y - direction : b) =

    = . ./ . . .

    . . = . .

    = . .

    =

    =

    : ( t ) =

    : ( d ) =

    : (Total Load ) = . .

    : ( q ) = . ./ . . . < : OK

    M = WL2 / 2 = . . - .

    d req. = sqrt ( M / Rb) = . < Effective depth :OK

    ; Beam Shear

    vb = 0.29 x sqrt ( fc' ) = ./ . . .

    Vb = V / ( B x d ) = ./ . . . < vb : OK

    ; Punching Shear vp = 0.53 x sqrt ( fc' ) = ./ . . .

    Vp = V / ( b x d ) = ./ . . . < vp : OK

    As = M / f s / j / d As = . . .

    Use 7 DB 12 mm m. As = . . . > As req. : OK

    S 0 = . .

    uall = 3.23 x sqrt(fc') / D = . ./ . . . . (Use 35 / . .)

    S 0 = V / Uall x j x d =

    = . . OK

    $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    REINFORCED CONCRETE DESIGN$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    12000

    Date : 29/11/2015 14:05

    0.20

    0.20

    8000

    7821

    0.30

    0.23

    0.09

    1.13

    1200

    13200

    13217

    1182.93

    1.28

    1.30

    @ 0.2

    7.91

    35.4

    3.90

    3.81

    6.97

    3.09

    26.39

    7.92

    5592.02 / 35 x 0.898 x 22

  • 8/16/2019 2 stories house calculation report

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    Ground level

    7 - DB12@ 0.2 m.

    DB 12 mm.

    1: 3 : 5

    8000 ./ . .

    F3

    0 . 5

    5

    0

    0 . 5

    5 0

    0 . 2

    0

    1.30

    1 . 3

    0

    0.550 0.5500.20

    0.20

    0 . 2

    0

    PLAN VIEW

    SECTION VIEW ;

    0.100.10

    0.230.30

    1.50

  • 8/16/2019 2 stories house calculation report

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    Project : 2 Engineering ByLocation :

    . . . ; F2 = . .

    : ( x - direction : a ) =

    : ( y - direction : b) =

    = . ./ . . .

    . . = . .

    = . .

    =

    =

    : ( t ) =

    : ( d ) =

    : (Total Load ) = . .

    : ( q ) = . ./ . . . < : OK

    M = WL2 / 2 = . . - .

    d req. = sqrt ( M / Rb) = . < Effective depth :OK

    ; Beam Shear

    vb = 0.29 x sqrt ( fc' ) = ./ . . .

    Vb = V / ( B x d ) = ./ . . . < vb : OK

    ; Punching Shear vp = 0.53 x sqrt ( fc' ) = ./ . . .

    Vp = V / ( b x d ) = ./ . . . < vp : OK

    As = M / f s / j / d As = . . .

    Use 8 DB 16 mm m. As = . . . > As req. : OK

    S 0 = . .

    uall = 3.23 x sqrt(fc') / D = . ./ . . . . (Bonding Pass ; OK)

    S 0 = V / Uall x j x d =

    = . . OK

    $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    REINFORCED CONCRETE DESIGN$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    18000

    Date : 29/11/2015 10:48

    0.20

    0.20

    8000

    7752

    0.30

    0.23

    0.12

    1.64

    1800

    19800

    19844

    1899.24

    1.57

    1.60

    @ 0.21

    12.28

    26.55

    6.27

    3.81

    6.97

    4.82

    40.21

    16.08

    8682.24 / 26.55 x 0.898

  • 8/16/2019 2 stories house calculation report

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    Ground level

    8 - DB16@ 0.21 m.

    DB 12 mm.

    1: 3 : 5

    8000 ./ . .

    F2

    0 . 7

    0

    0

    0 . 7

    0 0

    0 . 2

    0

    1.60

    1 . 6

    0

    0.700 0.7000.20

    0.20

    0 . 2

    0

    PLAN VIEW

    SECTION VIEW ;

    0.100.10

    0.230.30

    1.50

  • 8/16/2019 2 stories house calculation report

    26/27

    Project : 2 Engineering ByLocation :

    . . . ; F1 = . .

    : ( x - direction : a ) =

    : ( y - direction : b) =

    = . ./ . . .

    . . = . .

    = . .

    =

    =

    : ( t ) =

    : ( d ) =

    : (Total Load ) = . .

    : ( q ) = . ./ . . . < : OK

    M = WL2 / 2 = . . - .

    d req. = sqrt ( M / Rb) = . < Effective depth :OK

    ; Beam Shear

    vb = 0.29 x sqrt ( fc' ) = ./ . . .

    Vb = V / ( B x d ) = ./ . . . < vb : OK

    ; Punching Shear vp = 0.53 x sqrt ( fc' ) = ./ . . .

    Vp = V / ( b x d ) = ./ . . . < vp : OK

    As = M / f s / j / d As = . . .

    Use 10 DB 16 mm m. As = . . . > As req. : OK

    S 0 = . .

    uall = 3.23 x sqrt(fc') / D = . ./ . . . . (Bonding Pass ; OK)

    S 0 = V / Uall x j x d =

    = . . OK

    $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    REINFORCED CONCRETE DESIGN$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    25000

    Date : 29/11/2015 10:43

    0.25

    0.25

    8000

    7090

    0.35

    0.28

    0.14

    1.55

    2500

    27500

    28360

    2714.14

    1.85

    2.00

    @ 0.21

    14.36

    26.55

    7.33

    3.81

    6.97

    4.57

    50.27

    20.11

    12407.5 / 26.55 x 0.898

  • 8/16/2019 2 stories house calculation report

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    Ground level

    10 - DB16@ 0.21 m.

    DB 12 mm.

    1: 3 : 5

    8000 ./ . .

    F1

    0 . 8

    7

    5

    0 . 8

    7 5

    0 . 2

    5

    2.00

    2 . 0

    0

    0.875 0.8750.25

    0.25

    0 . 2

    5

    PLAN VIEW

    SECTION VIEW ;

    0.100.10

    0.280.35

    1.50