2010amathsprelimp1solution

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Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution No. Solutions 1. Ans: 2a. When and When and b. …………….(I) …….(II) Solving Simultaneously, 3a. 1

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2010AMathsPrelimP1Solution

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Page 1: 2010AMathsPrelimP1Solution

Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution

No. Solutions1.

Ans:

2a.When and

When and

b. …………….(I) …….(II)

Solving Simultaneously,

3a.

3b Let one of the roots be and the other .sum of roots =

1

Page 2: 2010AMathsPrelimP1Solution

Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution

No. Solutions4a.

, when

Gradient of normal = 3,

Eqn of normal:

b.

=

5. , where .

or

or

or (na)

6a.When ,

6b.

Let

2

Page 3: 2010AMathsPrelimP1Solution

Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution

No. Solutions or

The other solution is 7a.

Sub ,

Comparing coeff of ,

Sub ,

7b.dx

= dx

=

= 0.599

8a.

when

cm/s

8b.

3

Page 4: 2010AMathsPrelimP1Solution

Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution

No. Solutions

= 628.3 cm3/s

9a.when initial population

9b.when ,

When ,

= 2457expected no. of snails after 7 yrs = 2460

9c.

no. of years needed = 9 years10a. Let

-------(I)

-------(II)(I) + (II):

sub ,

=

4

Page 5: 2010AMathsPrelimP1Solution

Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution

No. Solutions10b.

2 real and distinct rootsthe number of real roots of the equation = 2

11a.

11b.

Coordinates of stationary pt:

Nature of point: min. turning point

c.

Range of x:

12a. Amplitude = 3

Period =

5

1

Page 6: 2010AMathsPrelimP1Solution

Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution

No. Solutionsb.c.

c.Graph of

d.

No. of solutions = 6

13a.3rd term =

or (rej)13b.

(b)

General term =

=

Let

When , Coeff. Of

= 21840Let

When , Coeff. Of

= 3640

Coeff. Of in

6

5

2

2

4

1

5

45

6

y

x

1)(f xy

6

51

xy

Page 7: 2010AMathsPrelimP1Solution

Tanjong Katong Secondary School A Maths Sec 4 Prelims 2010 Paper 1 Solution

No. Solutions= 21840(3) + 3640(–1)= 61880

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