2011-2012 chem 21 mide exam answers

6

Click here to load reader

Upload: kristine-benitez-wong

Post on 30-Sep-2015

219 views

Category:

Documents


4 download

DESCRIPTION

chemistry

TRANSCRIPT

ME Ans1a1b1c1d34(712.2dm + 12.60m - 1234mm)/pi[(6.51 x 102g - 8.14 x 103g) /(78.55g/mol)]xANCommercially available concentrated hydrochloric acid is 37.0% w/w HCl. Its density is 1.18 g/mL. Using this information calculate the molarity of concentrated HCl8.923pH-log[H+]1. Exactly 750.0 mL of a solution that contained 480.4 ppm of Ba(NO3)2 were mixed with 200.0 mL of a solution that was 0.03090 M in Al2(S04)3%C2H5OH, 0.084, 0.089, 0.079, 0.080, 0.080, 0.083, 0.086, and 0.0786.02E+23atoms/mol0.0000000012[H+]a. Write the balanced reaction./xi-mean/712.2dm71.22m1.203E-06ppm H+b. What mass of solid BaS04 was formed?0.0840.001625mean0.0824Column112.60m12.60m0.06510gc.What was the molarity of the unreacted reagent Al2(S04)3 or Ba(NO3)2? 0.0890.006625median0.08151234mm1.234m0.00814gppmmg/L0.0790.003375range0.0110Mean0.08237582.586m0.056964.37E+2037.0g HClMmol/LH1.0079Ba137.331137.330.0800.002375ssd0.00381Standard Error0.001348775926.29m78.55g/mol100g solnCl35.453N14.007228.0140.0800.002375var1.46E-051.46E-05Median0.08156.02E+23atoms/mol1.18g/mLMM HCl36.4609O15.999695.9940.0830.000625avedev0.003130.003125Mode0.08mol HCl1.0147857019molmLmol/Lmg/Lgmol261.3380.0860.003625%re2.97Standard Deviation0.0038149143L soln0.0847457627LBa(NO3)2750480.40.36030.00137867443limiting0.00045955810.0780.004375Sample Variance1.46E-05M12.0MAl2(S04)32000.03090.0061801xs0.005720min0.078Kurtosis-0.5845802251(5.0420.013)/(2.9980.005)M xs0.0060215178max0.089Skewness0.6654540784Range0.0115.0420.0130.0139283883Ba137.331137.33Minimum0.0782.9980.005S32.065132.065Maximum0.0894.020.0123443016O15.999463.996Sum0.659233.391Count80.3218gAl26.982253.964S32.065396.195O15.99912191.988342.147100C212F