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  • 1 Penerbitan Pelangi Sdn. Bhd.

    Paper 1

    1. y = x + 1 is a linear function with y-intercept = 1 and gradient 0.Answer: A

    2. y = x2 + 2 is a quadratic function with y-intercept = 2. Its shape is .

    Answer: C

    3. y = x2 + 1 is a quadratic function with y-intercept = 1. Its shape is .Answer: A

    4. y = x3 is a cubic function with y-intercept = 0.Answer: A

    5. y = 1x is a reciprocal function.Answer: D

    6. The shaded region is above the line y = x. Hence, the shaded region is represented by y x.Answer: C

    7. The shaded region is below the line x + y = 2. Hence, the shaded region is represented by x + y 2.Answer: C

    8. x 2 means that the shaded region is to the right of the line x = 2.Answer: B

    9. y 1 means that the shaded region is below the dashed line y = 1.Answer: A

    Paper 2

    1. (a) y = 3x 2 When x = 3, y = 3(3) 2 = 7

    x 3y 7

    (b)

    012

    4

    6

    8

    1 2

    2

    4

    6

    8

    y = 3x 2

    x

    y

    32

    2. (a) y = 2x2 x 8 When x = 3, y = 2(3)2 (3) 8 = 13 When x = 1, y = 2(1) (1) 8 = 7

    x 3 1y 13 7

    CHAPTER

    22 Graphs of Functions IICHAPTER

  • 2 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    (b)

    0 15

    5.5

    3.65 2 3 44 3 2 1

    5

    10

    15

    20

    25

    30

    10

    x

    y = 2x2 x 8

    y

    (c) (i) y = 5.5 (ii) x = 3.65

    3. (a) y = x3 3x + 6 When x = 2, y = (2)3 3(2) + 6 = 4 When x = 1.5, y = (1.5)3 3(1.5) + 6 = 4.875

    x 2 1.5y 4 4.9

    (b)

    0123 321

    5

    10

    1517.5

    2.1

    15

    10

    5

    20

    25

    x

    y

    y = x3 3x + 6

    (c) (i) y = 17.5 (ii) x = 2.1

    4. (a) y = 2x 3 When x = 0, y = 2(0) 3 = 3 When y = 0, 0 = 2x 3 x = 32

    y = 2x 3y

    x0

    3

    32

    (b) y = 4x + 1 When x = 0, y = 4(0) + 1 = 1 When y = 0, 0 = 4x + 1 x = 14

    y = 4x + 1

    y

    x0

    1

    14

    (c) y = x2 3 When x = 0, y = 0 3 = 3 When y = 0, 0 = x2 3 x2 = 3 x = 3 or 3

    y = x 2 3

    y

    x0 333

    (d) y = 4 x2 When x = 0, y = 4 0 = 4 When y = 0, 0 = 4 x2 x2 = 4 x = 2 or 2

  • 3 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    y = 4 x2

    y

    x02 2

    4

    5. (a) y = 2x3 1 When x = 0, y = 2(0) 1 = 1

    y = 2x3 1y

    x01

    (b) y = x3 + 2 When x = 0, y = 0 + 2 = 2

    y = x3 + 2

    y

    x0

    2

    (c)

    y =

    y

    x

    x

    0

    5

    (d)

    y =

    y

    x

    x

    0

    8

    6. y = 2x2 x 8 ...................1 0 = 2x2 x 22 ..................21 2: y = 8 (22) y = 14The suitable straight line is y = 14.

    7. The suitable straight line is y = 3x + 2.

    8. y = x3 3x + 6 ...................1 0 = x3 6x + 3 ...................21 2: y = 3x + 3The suitable straight line is y = 3x + 3.

    9. y x 6 Region above the line y = x 6x 6 Region to the left of the dashed line x = 6

    y

    xy = x 6

    x = 6

    0

    6

    6

    10. y x Region above the line y = xx + y 4 Region above the line x + y = 4

    y

    x0

    x + y = 4

    y = x

    11. y x + 3 Region below the line y = x + 3y 3 Region above the dashed line y = 3x 5 Region to the left of the line x = 5

    1

    0 1 2 3 4 5 6 7

    23456789

    10

    y

    x

    y = x +

    3

    x = 5

    y = 3

  • 4 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    Paper 1

    1. y = x2 + x 6 is a quadratic function. Its shape is .When y = 0, x2 + x 6 = 0 (x + 3)(x 2) = 0 x = 3, x = 2The x-intercepts are 3 and 2.Answer: B

    2. y = 3 x2 = x2 + 3y = 3 x2 is a quadratic function with y-intercept = 3. Its shape is .Answer: C

    3. The graph is a reciprocal function with an equation y = 2x = 2x 1.Hence, m = 2 and n = 1Answer: B

    4. The graph is a cubic function, y = ax3 + 16, with a , 0.Substitute x = 2 into y = 2x3 + 16. 0 = 2(2)3 + 16Hence, x = 2 satisfies the equation y = 2x3 + 16.Therefore, the graph is y = 2x3 + 16.Answer: C

    5. y = x2 9 is a quadratic function with y-intercept = 9. Its shape is .Answer: C

    6. y = 4 + x3 is a cubic function with y-intercept = 4.a . 0 (a = 1), its shape is .Answer: D

    7. y = 5 2x3 is a cubic function with y-intercept = 5. Answer: A

    Paper 2

    1. y 2x + 6 Region below the line y = 2x + 6y 12 x Region above the line y =

    12 xy 6 Region below the dashed line y = 6

    y = 2x + 6

    y = 6

    y

    x0

    1y = x 2

    2. (a) y = 8x

    When x = 1, y = 8(1) = 8 When x = 2, y = 82 = 4

    x 1 2y 8 4

    (b)

    x

    y = 4x 5

    y

    01 2 3 44 3 2

    2.10.6

    0.9

    1

    5

    10

    15

    20

    20

    15

    10

    5 8y = x

  • 5 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    (c) (i) y = 10 (ii) x = 0.6

    (d) 8x = 4x + 5 8x = 4x 5 The suitable straight line is y = 4x 5. The values of x which satisfy 8x = 4x + 5 are

    x = 2.1 and x = 0.9.

    3. (a) y = x3 4x + 8 When x = 3, m = (3)3 4(3) + 8 = 7 When x = 2, n = (2)3 4(2) + 8 = 8(b)

    x

    y = 9x + 18

    y = x3 4x + 8

    y

    0 1 2 3 44

    3.15 0.8

    19

    3 2 1

    20

    10

    30

    40

    50

    30

    20

    10

    (c) (i) y = 19 (ii) x = 2.65

    (d) y = x3 4x + 8 ............1 0 = x3 13x 10 .........2 1 2: y = 9x + 18 The suitable straight line is y = 9x + 18. The values of x which satisfy x3 13x 10 = 0

    are x = 3.15 and x = 0.8.

    4. (a) y = 3x2 + 2x 10 When x = 3, y = 3(3)2 +2(3) 10 = 11 When x = 2, y = 3(2)2 + 2(2) 10 = 6

    x 3 2y 11 6

    (b) y

    x0 1 2 312345

    10

    20

    30

    40

    50

    60

    3.8

    12

    2.5

    y = 9x + 26y = 3x2 + 2x 10

    10

    (c) (i) y = 12 (ii) x = 3.8(d) y = 3x2 + 2x 10 ...............1 3x2 7x = 36 0 = 3x2 7x 36 ...............2 1 2: y = 9x + 26 The suitable straight line is y = 9x + 26. The value of x which satisfies 3x2 7x = 36 is

    x = 2.5.

  • 6 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    5. (a) y = 5 x 2x2 When x = 2, y = 5 (2) 2(2)2 = 1 When x = 3, y = 5 (3) 2(3)2 = 16

    x 2 3y 1 16

    (b)

    x

    y = 5 x 2x 2

    y

    0123 21 43 5

    57

    2.45 2.7 3.6

    35

    20

    25

    10

    15

    5

    10

    30

    3y = x 8 2

    (c) (i) y = 7 (ii) x = 3.6(d) y = 5 x 2x2 ...................1 0 = 13 + 12 x 2x

    2 ............2

    1 2: y = 8 32 x

    The suitable straight line is y = 8 32 x.

    The values of x which satisfy 13 + 12 x 2x2

    = 0 are x = 2.45 and x = 2.7.

    6. (a) y = x3 6x + 7 When x = 3, y = (3)3 6(3) + 7 = 2 When x = 2, y = (2)3 6(2) + 7 = 3

    x 3 2y 2 3

    (b)

    x

    y

    y = x3 6x + 7y = 2x + 11

    4

    30

    25

    20

    15

    10

    5

    5

    0

    10

    15

    33.05

    12

    0.552.553.2

    211234

    (c) (i) y = 12 (ii) x = 3.2(d) y = x3 6x + 7 ..........1 x3 = 8x + 4 ..................2 1 + 2: y + x3 = x3 + 2x + 11 y = 2x + 11 The suitable straight line is y = 2x + 11. The values of x which satisfy x3 = 8x + 4 are

    x = 2.55, 0.55, 3.05.

    7. y 8 2x Region above the line y = 8 2xy 8 Region below the line y = 8x 4 Region to the left of the dashed line x = 4

    y = 8y

    x0 4 y = 8 2x

    x = 4

  • 7 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    8. (a) y = 2x2 2x 5 When x = 1, y = 2(1)2 2(1) 5 = 1 When x = 3, y = 2(3)2 2(3) 5 = 7

    x 1 3y 1 7

    (b)

    x

    y

    0 1 2 3 4

    4.2 4.35

    5

    5

    12

    5

    10

    15

    20

    25

    30

    35

    10

    y = 2x2 2x 5

    y = 2x + 13

    (c) (i) y = 10 (ii) x = 4.35(d) y = 2x2 2x 5 ...............1 18 = 2x2 4x ......................2 1 2: y 18 = 2x 5 y = 2x + 13 The suitable straight line is y = 2x + 13. The value of x which satisfies 2x2 4x = 18 is

    x = 4.2.

    9. (a) y = 18x When x = 3, y = 183 = 6

    When x = 0.5, y = 180.5 = 36

    x 3 0.5y 6 36

    (b)

    x

    y

    1 1 2 3 45

    2.55 1.65 1.8

    7

    5

    10

    15

    20

    25

    30

    35

    40

    10

    15

    20

    234

    y = 4x + 3

    18xy =

    0

    (c) (i) y = 7 (ii) x = 1.65(d) 4x2 + 3x = 18 4x + 3 = 18x The suitable straight line is y = 4x + 3. The values of x which satisfy 4x2 + 3x = 18 are

    x = 2.55 and x = 1.8.

  • 8 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    Paper 1

    1. y = 2x 3 is a linear function with y-intercept = 3 and gradient 0. Answer: B

    2. y = x2 2 is a quadratic function with y-intercept = 2. Its shape is .Answer: A

    3. y = 2x is a reciprocal function.Answer: D

    4. y = 2x3 is a cubic function with y-intercept = 0. Its shape is .

    Answer: C

    5. y = x3 4 is a cubic function with y-intercept = 4.Its shape is .Answer: A

    6. y = x(3 x) = 3x x2 It is a quadratic function with x-intercepts = 0 and 3. Its shape is .Answer: B

    7. y = 4x is a reciprocal function.Answer: D

    8. y = 2x2 + 1 is a quadratic function with y-intercept = 1. Its shape is .Answer: C

    9. y = 4 xn is a cubic function. Hence, n = 3.Answer: C

    10. y = 9 xn is a quadratic function. Hence, n = 2.Answer: A

    11. y = 2xn is a reciprocal function. Hence, n = 1.Answer: D

    12. y = xm + p is a quadratic function with y-intercept = 3. Hence, m = 2 and p = 3.Answer: D

    13. y = 2xn + k is a cubic function with y-intercept = 4. Hence, n = 3 and k = 4.Answer: D

    14. The graph is a quadratic function with y-intercept = 3.Answer: A

    15. The graph is a cubic function with y-intercept = 2.Answer: C

    16. The graph is a quadratic function with y-intercept = 5.Answer: B

    17. x 0 Region to the right of the y-axis 2y x Region above the dashed line 2y = xy 2 x Region below the line y = 2 x

    y

    x0

    2y = x

    y = 2 x

    Answer: D

    18. y 8 2x Region above the line y = 8 2xy 2x Region above the line y = 2xy 8 Region below the dashed line y = 8

    y = 2xy

    x0

    8

    y = 8 2x

    Answer: C

  • 9 Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    19. Region to the right of the y-axis x 0 Region to the left of the line x = 6 x 6Region above the x-axis y 0Region below the dashed line 2y x = 1 2y x 1Answer: B

    20. Region below the line x + y = 6 x + y 6Region above the dashed line 2x + y = 6 2x + y 6Region above the line y = 3 y 3Answer: B

    Paper 2

    1. (a) y = 24 + 3x 2x2 When x = 1, y = 24 + 3(1) 2(1)2 = 19 When x = 4, y = 24 + 3(4) 2(4)2 = 4

    x 1 4y 19 4

    (b)

    y

    y = 10

    x

    5

    0 1 2 33 2 1 4

    5

    10

    15

    20

    25

    3.50.7

    19

    2

    y = 24 + 3x 2x 2

    (c) (i) x = 0.7 (ii) y = 19(d) y = 24 + 3x 2x2 .....................1 0 = 2x2 3x 14 .....................2 1 + 2: y = 10 The suitable straight line is y = 10. The values of x which satisfy 2x2 3x 14 = 0

    are x = 2 and x = 3.5.

    2. (a) y = 4 x x2 When x = 4, y = 4 ( 4) ( 4)2 = 8 When x = 2, y = 4 (2) (2)2 = 2

    x 4 2y 8 2

    (b)

    0 1

    10

    2 3 44 3 2 1

    8

    6

    4

    2

    22.8

    3.32.73.7

    4

    6

    12

    x

    y = 6

    y = 4 x x2

    y

    (c) (i) y = 2.8 (ii) x = 3.3(d) 4 x x2 = 6 The suitable straight line is y = 6. The values of x which satisfy 4 x x2 = 6 are

    x = 3.7 and x = 2.7.

  • 10

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    3. (a) y = x2

    2 2x

    When x = 1, y = (1)2

    2 2(1) = 2.5 When x = 3, y = (3)

    22 2(3)

    = 1.5x 1 3y 2.5 1.5

    (b)

    y

    x2y = 2x 2

    x

    1

    0 1 2 31 4 5 6

    1

    2

    2

    3

    xy = 2 2

    4

    5

    6

    0.6

    1.65

    3.4

    y = 1

    (c) (i) y = 1.65 (ii) x = 0.6 or x = 3.4

    (d) x2

    2 2x = 2 x2

    The suitable straight line is y = 2 x2 .

    The values of x which satisfy x2

    2 2x = 2 x2

    are x = 1 and x = 4.

    4. (a) y = 12 x2(3 x)

    When x = 1, y = 12 (1)2[3 (1)]

    = 2 When x = 1.5, y = 12 (1.5)

    2[3 (1.5)] = 1.7

    x 1 1.5y 2 1.7

    (b) y

    x

    1

    0

    1y = x 2(3 x) 2

    1 2 312 4

    1

    2

    3

    2

    3

    4

    5

    6

    2.71

    .2

    0.7

    5

    y = 1

    (c) x = 1.2(d) x2(3 x) = 2 12 x

    2(3 x) = 1 The suitable straight line is y = 1. The values of x which satisfy x2(3 x) = 2 are

    x = 0.75, x = 1 and x = 2.7.

  • 11

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    5. (a) y = x(x2 4) When x = 1.5, y = 1.5[(1.5)2 4] = 2.6 When x = 0.5, y = 0.5[(0.5)2 4] = 1.9

    x 1.5 0.5y 2.6 1.9

    (b)

    y

    x

    2

    0 1 2 3123

    2

    4

    4

    6

    8

    10

    12

    14

    16

    y = x 2

    2.4

    2.35 0.45

    y = x (x 2 4)

    (c) x = 2.35(d) x(x2 4) = x 2 The suitable straight line is y = x 2. The values of x which satisfy x(x2 4) = x 2

    are x = 2.4, x = 0.45 and x = 2.

    6. (a) y = x2 3x + 10 When x = 4, y = ( 4)2 3( 4) + 10 = 38 When x = 2, y = (2)2 3(2) + 10 = 8

    x 4 2y 38 8

    (b)

    0 1 2 3 4 54 3 23.3 0.7 3.7 4.3

    26

    1

    15

    20

    5

    10

    25

    30

    35

    40

    x

    y = x 2 3x + 10

    y = 2x + 24

    y

    (c) (i) y = 26 (ii) x = 0.7 or x = 3.7(d) y = x2 3x + 10 ........................1 0 = x2 x 14 ..........................2 1 2: y = 2x + 24 The suitable straight line is y = 2x + 24. The values of x which satisfy x2 x 14 = 0 are

    x = 3.3 and x = 4.3.

  • 12

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    7. (a) y = x3 5x 8 When x = 2, y = (2)3 5(2) 8 = 6 When x = 1, y = (1)3 5(1) 8 = 12

    x 2 1y 6 12

    (b)

    01

    5

    5

    10

    10

    15

    20

    15

    20

    25

    30

    35

    2 33 2 1 4x

    y = 9

    y = x3 5x 8

    y = 15 5x

    y

    2.35 0.2 2.1x = 2.85

    (c) x = 2.1, x = 0.2 or x = 2.35(d) y = x3 5x 8 .........................1 0 = x3 23 ...............................2 1 2: y = 5x + 15 The suitable straight line is y = 5x + 15. The value of x which satisfies x3 23 = 0 is

    x = 2.85.

    8. (a) y = x3 13x + 18 When x = 3, y = (3)3 13(3) + 18 = 30 When x = 2, y = (2)3 13(2) + 18 = 0

    x 3 2y 30 0

    (b)

    x

    y = 2x + 20

    y = x 3 13x + 18y

    0 1

    5

    10

    15

    20

    25

    30

    35

    2 3

    3.44

    0.2

    0.9

    3.0

    5

    3.2

    44 3 2 1

    y = 29

    (c) (i) y = 4 (ii) x = 3.05 or x = 0.9(d) y = x3 13x + 18 .....................1 0 = x3 11x 2 ........................2 1 2: y = 2x + 20 The suitable straight line is y = 2x + 20. The values of x which satisfy x3 11x 2 = 0 are

    x = 3.2, x = 0.2 and x = 3.4.

  • 13

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    9. (a) y = 20x 2x2 When x = 2, y = 20(2) 2(2)2 = 32 When x = 5, y = 20(5) 2(5)2 = 50

    x 2 5y 32 50

    (b)

    5

    10

    15

    20

    25

    30

    35

    40

    45

    50

    y

    x0 1 2 3 4 5 6 7 8 9

    y = 28

    y = 4x + 25y = 20x 2x2

    1.7

    2.15

    5.9

    8.3

    (c) (i) y = 50 (ii) x = 1.7 or x = 8.3(d) y = 20x 2x2 ...........................1 0 = 16x 2x2 25 ....................2 1 2: y = 4x + 25 The suitable straight line is y = 4x + 25. The values of x which satisfy 16x 2x2 25 = 0

    are x = 2.15 and x = 5.9.

    10. (a) y = 14 + 11x 3x2 When x = 1, y = 14 + 11(1) 3(1)2 = 0 When x = 5, y = 14 + 11(5) 3(5)2 = 6

    x 1 5y 0 6

    (b)

    5

    10

    15

    20

    25

    25

    20

    15

    10

    50 11 2 3 4 5 6 7

    x

    y

    y = 5

    y = 2x + 10

    y = 14 + 11x 3x 2

    0.7

    0.4 3.

    4

    4.35

    (c) x = 0.7 or x = 4.35(d) y = 14 + 11x 3x2 ....................1 0 = 4 + 9x 3x2 ........................2 1 2: y = 10 + 2x The suitable straight line is y = 10 + 2x. The values of x which satisfy 4 + 9x 3x2 = 0

    are x = 0.4 and x = 3.4.

  • 14

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    11. (a) y = 2x2 + x 5 When x = 3, y = 2(3)2 + (3) 5 = 10 When x = 2, y = 2(2)2 + (2) 5 = 5

    x 3 2y 10 5

    (b)

    0 1 2 3 44 3 2

    2.4 1.92.51

    5

    5

    10

    15

    20

    25

    30

    35

    y

    y = 4

    y = 2x 2 + x 5

    x

    (c) y = 10(d) y = 2x2 + x 5 ....................1 9 = 2x2 + x ..........................2 1 2: y 9 = 5 y = 4 The suitable straight line is y = 4. The values of x which satisfy 2x2 + x = 9 are

    x = 2.4 and x = 1.9.

    12. (a) y = 4x When x = 4, y = 4( 4) = 1 When x = 0.8, y = 40.8 = 5

    x 4 0.8y 1 5

    (b)

    2

    2

    4

    6

    8

    10

    4

    0.85

    2.9

    6

    8

    10

    0 1 2 3 445 3 2 1 5

    y

    x

    y = x

    4y = x

    4y = x

    (c) (i) y = 2.9 (ii) x = 0.85(d) The equation of the straight line is y = x. The values of x are x = 2 and x = 2.

  • 15

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    13. (a) y = 6x When x = 2, y = 6(2) = 3

    When x = 2.5, y = 62.5 = 2.4

    x 2 2.5y 3 2.4

    (b)

    x

    y

    y = 2x

    0 1

    2

    45

    0.85 1.751.75

    6

    8

    10

    12

    12

    10

    8

    6

    4

    2 3 4 54 3 2 12

    6y = x

    (c) (i) y = 5 (ii) x = 0.85(d) The equation of the straight line is y = 2x. The values of x are x = 1.75 and x = 1.75.

    14. (a) y = x3 4x 9 When x = 2, y = (2)3 4(2) 9 = 9 When x = 3, y = (3)3 4(3) 9 = 6

    x 2 3y 9 6

    (b)

    x

    30

    40

    50

    60

    20

    10

    10

    20

    30

    40

    1 1 2 3 4234 0

    y

    y = 10

    y = x 3 4x 9

    0.2 1.9 3.32.1

    (c) (i) y = 20 (ii) x = 3.3(d) y = x3 4x 9 .........................1 0 = x3 4x + 1.........................2 1 2: y = 10 The suitable straight line is y = 10. The values of x which satisfy x3 4x + 1 = 0 are

    x = 2.1, x = 0.2 and x = 1.9.

  • 16

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    15. (a) y = 2x2 + 3x + 7 When x = 1.5, y = 2(1.5)2 + 3(1.5) + 7 = 2 When x = 1, y = 2(1)2 + 3(1) + 7 = 8 When x = 4, y = 2(4)2 + 3(4) + 7 = 13

    x 1.5 1 4y 2 8 13

    (b)

    5

    5

    10

    10

    15

    20

    25

    30

    0 1 2 33 2 1 4 5

    3.35

    y

    x

    y = 6x 25

    y = 2x2+ 3x + 7

    (c) (i) y = 5 (ii) 2x2 3x = 7 2x2 + 3x + 7 = 0 When y = 0, x = 1.25 or x = 2.75. The

    values of x which satisfy 2x2 3x = 7 are x = 1.25 or x = 2.75.

    (d) y = 2x2 + 3x + 7 .....................1 0 = 2x2 3x + 32 ...................2 1 2: y = 6x 25 The suitable straight line is y = 6x 25. The value of x which satisfies 2x2 3x + 32 = 0

    is x = 3.35.

    16. (a) y = 2 + 9x 2x2 When x = 2, y = 2 + 9(2) 2(2)2 = 24 When x = 4, y = 2 + 9(4) 2(4)2 = 6

    x 2 4y 24 6

    (b)

    01

    5

    10

    15

    15

    10

    25

    20

    2 21 43 655

    x

    y = 4x 5

    y = 2 + 9x 2x 2

    y

    3.51.6

    (c) (i) x = 1.6 (ii) y = 10(d) y = 2 + 9x 2x2.......................1 0 = 2x2 5x 7 .......................2 1 + 2: y = 4x 5 The suitable straight line is y = 4x 5. The values of x which satisfy 2x2 5x 7 = 0 are

    x = 1 and x = 3.5.

    17. y 2x Region below the line y = 2xy 8 2x Region above the line y = 8 2xx 4 Region to the left of the dashed line x = 4

    y

    x0

    y = 8 2x

    y = 2xx = 4

    8

    4

  • 17

    Mathematics SPM Chapter 22

    Penerbitan Pelangi Sdn. Bhd.

    18. y 4x Region below the line y = 4x3y x Region above the line 3y = xx 2 Region to the left of the dashed line x = 2

    y

    x03y = x

    y = 4xx = 2

    2

    19. x + y 8 Region above the line x + y = 83y 2x Region above the line 3y = 2xy 8 Region below the dashed line y = 8

    y

    x0

    3y = 2x

    y = 8

    x + y = 8

    20. y x 4 Region above the line y = x 42y 12 3x Region below the line 2y = 12 3xx 2 Region to the right of the dashed line x = 2

    y

    x0

    6

    4

    4

    2y = 12 3x

    y = x 4x = 2

    21. y 3x + 9 Region above the line y = 3x + 9x 3 Region to the left of the dashed line x = 3y 9 Region below the line y = 9

    y

    x0 3

    y = 3x + 9

    x = 39 y = 9

    22. y 2x 5 Region below the line y = 2x 5y x 5 Region above the line y = x 5y 4 Region below the dashed line y = 4

    y

    x0

    4

    5

    y = 2x 5

    y = x 5

    y = 4

    23. x 0 Region to the right of the y-axis2y x Region above the line 2y = x2x + 3y 6 Region above the line 2x + 3y = 6x + y 6 Region below the line x + y = 6

    1

    0 1 2 3 4 5 6 7

    234567

    y

    x2x + 3y = 6

    x + y = 62y = x