22[a math cd]
DESCRIPTION
mathTRANSCRIPT
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1 Penerbitan Pelangi Sdn. Bhd.
Paper 1
1. y = x + 1 is a linear function with y-intercept = 1 and gradient 0.Answer: A
2. y = x2 + 2 is a quadratic function with y-intercept = 2. Its shape is .
Answer: C
3. y = x2 + 1 is a quadratic function with y-intercept = 1. Its shape is .Answer: A
4. y = x3 is a cubic function with y-intercept = 0.Answer: A
5. y = 1x is a reciprocal function.Answer: D
6. The shaded region is above the line y = x. Hence, the shaded region is represented by y x.Answer: C
7. The shaded region is below the line x + y = 2. Hence, the shaded region is represented by x + y 2.Answer: C
8. x 2 means that the shaded region is to the right of the line x = 2.Answer: B
9. y 1 means that the shaded region is below the dashed line y = 1.Answer: A
Paper 2
1. (a) y = 3x 2 When x = 3, y = 3(3) 2 = 7
x 3y 7
(b)
012
4
6
8
1 2
2
4
6
8
y = 3x 2
x
y
32
2. (a) y = 2x2 x 8 When x = 3, y = 2(3)2 (3) 8 = 13 When x = 1, y = 2(1) (1) 8 = 7
x 3 1y 13 7
CHAPTER
22 Graphs of Functions IICHAPTER
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2 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
(b)
0 15
5.5
3.65 2 3 44 3 2 1
5
10
15
20
25
30
10
x
y = 2x2 x 8
y
(c) (i) y = 5.5 (ii) x = 3.65
3. (a) y = x3 3x + 6 When x = 2, y = (2)3 3(2) + 6 = 4 When x = 1.5, y = (1.5)3 3(1.5) + 6 = 4.875
x 2 1.5y 4 4.9
(b)
0123 321
5
10
1517.5
2.1
15
10
5
20
25
x
y
y = x3 3x + 6
(c) (i) y = 17.5 (ii) x = 2.1
4. (a) y = 2x 3 When x = 0, y = 2(0) 3 = 3 When y = 0, 0 = 2x 3 x = 32
y = 2x 3y
x0
3
32
(b) y = 4x + 1 When x = 0, y = 4(0) + 1 = 1 When y = 0, 0 = 4x + 1 x = 14
y = 4x + 1
y
x0
1
14
(c) y = x2 3 When x = 0, y = 0 3 = 3 When y = 0, 0 = x2 3 x2 = 3 x = 3 or 3
y = x 2 3
y
x0 333
(d) y = 4 x2 When x = 0, y = 4 0 = 4 When y = 0, 0 = 4 x2 x2 = 4 x = 2 or 2
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3 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
y = 4 x2
y
x02 2
4
5. (a) y = 2x3 1 When x = 0, y = 2(0) 1 = 1
y = 2x3 1y
x01
(b) y = x3 + 2 When x = 0, y = 0 + 2 = 2
y = x3 + 2
y
x0
2
(c)
y =
y
x
x
0
5
(d)
y =
y
x
x
0
8
6. y = 2x2 x 8 ...................1 0 = 2x2 x 22 ..................21 2: y = 8 (22) y = 14The suitable straight line is y = 14.
7. The suitable straight line is y = 3x + 2.
8. y = x3 3x + 6 ...................1 0 = x3 6x + 3 ...................21 2: y = 3x + 3The suitable straight line is y = 3x + 3.
9. y x 6 Region above the line y = x 6x 6 Region to the left of the dashed line x = 6
y
xy = x 6
x = 6
0
6
6
10. y x Region above the line y = xx + y 4 Region above the line x + y = 4
y
x0
x + y = 4
y = x
11. y x + 3 Region below the line y = x + 3y 3 Region above the dashed line y = 3x 5 Region to the left of the line x = 5
1
0 1 2 3 4 5 6 7
23456789
10
y
x
y = x +
3
x = 5
y = 3
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4 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
Paper 1
1. y = x2 + x 6 is a quadratic function. Its shape is .When y = 0, x2 + x 6 = 0 (x + 3)(x 2) = 0 x = 3, x = 2The x-intercepts are 3 and 2.Answer: B
2. y = 3 x2 = x2 + 3y = 3 x2 is a quadratic function with y-intercept = 3. Its shape is .Answer: C
3. The graph is a reciprocal function with an equation y = 2x = 2x 1.Hence, m = 2 and n = 1Answer: B
4. The graph is a cubic function, y = ax3 + 16, with a , 0.Substitute x = 2 into y = 2x3 + 16. 0 = 2(2)3 + 16Hence, x = 2 satisfies the equation y = 2x3 + 16.Therefore, the graph is y = 2x3 + 16.Answer: C
5. y = x2 9 is a quadratic function with y-intercept = 9. Its shape is .Answer: C
6. y = 4 + x3 is a cubic function with y-intercept = 4.a . 0 (a = 1), its shape is .Answer: D
7. y = 5 2x3 is a cubic function with y-intercept = 5. Answer: A
Paper 2
1. y 2x + 6 Region below the line y = 2x + 6y 12 x Region above the line y =
12 xy 6 Region below the dashed line y = 6
y = 2x + 6
y = 6
y
x0
1y = x 2
2. (a) y = 8x
When x = 1, y = 8(1) = 8 When x = 2, y = 82 = 4
x 1 2y 8 4
(b)
x
y = 4x 5
y
01 2 3 44 3 2
2.10.6
0.9
1
5
10
15
20
20
15
10
5 8y = x
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5 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
(c) (i) y = 10 (ii) x = 0.6
(d) 8x = 4x + 5 8x = 4x 5 The suitable straight line is y = 4x 5. The values of x which satisfy 8x = 4x + 5 are
x = 2.1 and x = 0.9.
3. (a) y = x3 4x + 8 When x = 3, m = (3)3 4(3) + 8 = 7 When x = 2, n = (2)3 4(2) + 8 = 8(b)
x
y = 9x + 18
y = x3 4x + 8
y
0 1 2 3 44
3.15 0.8
19
3 2 1
20
10
30
40
50
30
20
10
(c) (i) y = 19 (ii) x = 2.65
(d) y = x3 4x + 8 ............1 0 = x3 13x 10 .........2 1 2: y = 9x + 18 The suitable straight line is y = 9x + 18. The values of x which satisfy x3 13x 10 = 0
are x = 3.15 and x = 0.8.
4. (a) y = 3x2 + 2x 10 When x = 3, y = 3(3)2 +2(3) 10 = 11 When x = 2, y = 3(2)2 + 2(2) 10 = 6
x 3 2y 11 6
(b) y
x0 1 2 312345
10
20
30
40
50
60
3.8
12
2.5
y = 9x + 26y = 3x2 + 2x 10
10
(c) (i) y = 12 (ii) x = 3.8(d) y = 3x2 + 2x 10 ...............1 3x2 7x = 36 0 = 3x2 7x 36 ...............2 1 2: y = 9x + 26 The suitable straight line is y = 9x + 26. The value of x which satisfies 3x2 7x = 36 is
x = 2.5.
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6 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
5. (a) y = 5 x 2x2 When x = 2, y = 5 (2) 2(2)2 = 1 When x = 3, y = 5 (3) 2(3)2 = 16
x 2 3y 1 16
(b)
x
y = 5 x 2x 2
y
0123 21 43 5
57
2.45 2.7 3.6
35
20
25
10
15
5
10
30
3y = x 8 2
(c) (i) y = 7 (ii) x = 3.6(d) y = 5 x 2x2 ...................1 0 = 13 + 12 x 2x
2 ............2
1 2: y = 8 32 x
The suitable straight line is y = 8 32 x.
The values of x which satisfy 13 + 12 x 2x2
= 0 are x = 2.45 and x = 2.7.
6. (a) y = x3 6x + 7 When x = 3, y = (3)3 6(3) + 7 = 2 When x = 2, y = (2)3 6(2) + 7 = 3
x 3 2y 2 3
(b)
x
y
y = x3 6x + 7y = 2x + 11
4
30
25
20
15
10
5
5
0
10
15
33.05
12
0.552.553.2
211234
(c) (i) y = 12 (ii) x = 3.2(d) y = x3 6x + 7 ..........1 x3 = 8x + 4 ..................2 1 + 2: y + x3 = x3 + 2x + 11 y = 2x + 11 The suitable straight line is y = 2x + 11. The values of x which satisfy x3 = 8x + 4 are
x = 2.55, 0.55, 3.05.
7. y 8 2x Region above the line y = 8 2xy 8 Region below the line y = 8x 4 Region to the left of the dashed line x = 4
y = 8y
x0 4 y = 8 2x
x = 4
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7 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
8. (a) y = 2x2 2x 5 When x = 1, y = 2(1)2 2(1) 5 = 1 When x = 3, y = 2(3)2 2(3) 5 = 7
x 1 3y 1 7
(b)
x
y
0 1 2 3 4
4.2 4.35
5
5
12
5
10
15
20
25
30
35
10
y = 2x2 2x 5
y = 2x + 13
(c) (i) y = 10 (ii) x = 4.35(d) y = 2x2 2x 5 ...............1 18 = 2x2 4x ......................2 1 2: y 18 = 2x 5 y = 2x + 13 The suitable straight line is y = 2x + 13. The value of x which satisfies 2x2 4x = 18 is
x = 4.2.
9. (a) y = 18x When x = 3, y = 183 = 6
When x = 0.5, y = 180.5 = 36
x 3 0.5y 6 36
(b)
x
y
1 1 2 3 45
2.55 1.65 1.8
7
5
10
15
20
25
30
35
40
10
15
20
234
y = 4x + 3
18xy =
0
(c) (i) y = 7 (ii) x = 1.65(d) 4x2 + 3x = 18 4x + 3 = 18x The suitable straight line is y = 4x + 3. The values of x which satisfy 4x2 + 3x = 18 are
x = 2.55 and x = 1.8.
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8 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
Paper 1
1. y = 2x 3 is a linear function with y-intercept = 3 and gradient 0. Answer: B
2. y = x2 2 is a quadratic function with y-intercept = 2. Its shape is .Answer: A
3. y = 2x is a reciprocal function.Answer: D
4. y = 2x3 is a cubic function with y-intercept = 0. Its shape is .
Answer: C
5. y = x3 4 is a cubic function with y-intercept = 4.Its shape is .Answer: A
6. y = x(3 x) = 3x x2 It is a quadratic function with x-intercepts = 0 and 3. Its shape is .Answer: B
7. y = 4x is a reciprocal function.Answer: D
8. y = 2x2 + 1 is a quadratic function with y-intercept = 1. Its shape is .Answer: C
9. y = 4 xn is a cubic function. Hence, n = 3.Answer: C
10. y = 9 xn is a quadratic function. Hence, n = 2.Answer: A
11. y = 2xn is a reciprocal function. Hence, n = 1.Answer: D
12. y = xm + p is a quadratic function with y-intercept = 3. Hence, m = 2 and p = 3.Answer: D
13. y = 2xn + k is a cubic function with y-intercept = 4. Hence, n = 3 and k = 4.Answer: D
14. The graph is a quadratic function with y-intercept = 3.Answer: A
15. The graph is a cubic function with y-intercept = 2.Answer: C
16. The graph is a quadratic function with y-intercept = 5.Answer: B
17. x 0 Region to the right of the y-axis 2y x Region above the dashed line 2y = xy 2 x Region below the line y = 2 x
y
x0
2y = x
y = 2 x
Answer: D
18. y 8 2x Region above the line y = 8 2xy 2x Region above the line y = 2xy 8 Region below the dashed line y = 8
y = 2xy
x0
8
y = 8 2x
Answer: C
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9 Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
19. Region to the right of the y-axis x 0 Region to the left of the line x = 6 x 6Region above the x-axis y 0Region below the dashed line 2y x = 1 2y x 1Answer: B
20. Region below the line x + y = 6 x + y 6Region above the dashed line 2x + y = 6 2x + y 6Region above the line y = 3 y 3Answer: B
Paper 2
1. (a) y = 24 + 3x 2x2 When x = 1, y = 24 + 3(1) 2(1)2 = 19 When x = 4, y = 24 + 3(4) 2(4)2 = 4
x 1 4y 19 4
(b)
y
y = 10
x
5
0 1 2 33 2 1 4
5
10
15
20
25
3.50.7
19
2
y = 24 + 3x 2x 2
(c) (i) x = 0.7 (ii) y = 19(d) y = 24 + 3x 2x2 .....................1 0 = 2x2 3x 14 .....................2 1 + 2: y = 10 The suitable straight line is y = 10. The values of x which satisfy 2x2 3x 14 = 0
are x = 2 and x = 3.5.
2. (a) y = 4 x x2 When x = 4, y = 4 ( 4) ( 4)2 = 8 When x = 2, y = 4 (2) (2)2 = 2
x 4 2y 8 2
(b)
0 1
10
2 3 44 3 2 1
8
6
4
2
22.8
3.32.73.7
4
6
12
x
y = 6
y = 4 x x2
y
(c) (i) y = 2.8 (ii) x = 3.3(d) 4 x x2 = 6 The suitable straight line is y = 6. The values of x which satisfy 4 x x2 = 6 are
x = 3.7 and x = 2.7.
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10
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
3. (a) y = x2
2 2x
When x = 1, y = (1)2
2 2(1) = 2.5 When x = 3, y = (3)
22 2(3)
= 1.5x 1 3y 2.5 1.5
(b)
y
x2y = 2x 2
x
1
0 1 2 31 4 5 6
1
2
2
3
xy = 2 2
4
5
6
0.6
1.65
3.4
y = 1
(c) (i) y = 1.65 (ii) x = 0.6 or x = 3.4
(d) x2
2 2x = 2 x2
The suitable straight line is y = 2 x2 .
The values of x which satisfy x2
2 2x = 2 x2
are x = 1 and x = 4.
4. (a) y = 12 x2(3 x)
When x = 1, y = 12 (1)2[3 (1)]
= 2 When x = 1.5, y = 12 (1.5)
2[3 (1.5)] = 1.7
x 1 1.5y 2 1.7
(b) y
x
1
0
1y = x 2(3 x) 2
1 2 312 4
1
2
3
2
3
4
5
6
2.71
.2
0.7
5
y = 1
(c) x = 1.2(d) x2(3 x) = 2 12 x
2(3 x) = 1 The suitable straight line is y = 1. The values of x which satisfy x2(3 x) = 2 are
x = 0.75, x = 1 and x = 2.7.
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11
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
5. (a) y = x(x2 4) When x = 1.5, y = 1.5[(1.5)2 4] = 2.6 When x = 0.5, y = 0.5[(0.5)2 4] = 1.9
x 1.5 0.5y 2.6 1.9
(b)
y
x
2
0 1 2 3123
2
4
4
6
8
10
12
14
16
y = x 2
2.4
2.35 0.45
y = x (x 2 4)
(c) x = 2.35(d) x(x2 4) = x 2 The suitable straight line is y = x 2. The values of x which satisfy x(x2 4) = x 2
are x = 2.4, x = 0.45 and x = 2.
6. (a) y = x2 3x + 10 When x = 4, y = ( 4)2 3( 4) + 10 = 38 When x = 2, y = (2)2 3(2) + 10 = 8
x 4 2y 38 8
(b)
0 1 2 3 4 54 3 23.3 0.7 3.7 4.3
26
1
15
20
5
10
25
30
35
40
x
y = x 2 3x + 10
y = 2x + 24
y
(c) (i) y = 26 (ii) x = 0.7 or x = 3.7(d) y = x2 3x + 10 ........................1 0 = x2 x 14 ..........................2 1 2: y = 2x + 24 The suitable straight line is y = 2x + 24. The values of x which satisfy x2 x 14 = 0 are
x = 3.3 and x = 4.3.
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12
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
7. (a) y = x3 5x 8 When x = 2, y = (2)3 5(2) 8 = 6 When x = 1, y = (1)3 5(1) 8 = 12
x 2 1y 6 12
(b)
01
5
5
10
10
15
20
15
20
25
30
35
2 33 2 1 4x
y = 9
y = x3 5x 8
y = 15 5x
y
2.35 0.2 2.1x = 2.85
(c) x = 2.1, x = 0.2 or x = 2.35(d) y = x3 5x 8 .........................1 0 = x3 23 ...............................2 1 2: y = 5x + 15 The suitable straight line is y = 5x + 15. The value of x which satisfies x3 23 = 0 is
x = 2.85.
8. (a) y = x3 13x + 18 When x = 3, y = (3)3 13(3) + 18 = 30 When x = 2, y = (2)3 13(2) + 18 = 0
x 3 2y 30 0
(b)
x
y = 2x + 20
y = x 3 13x + 18y
0 1
5
10
15
20
25
30
35
2 3
3.44
0.2
0.9
3.0
5
3.2
44 3 2 1
y = 29
(c) (i) y = 4 (ii) x = 3.05 or x = 0.9(d) y = x3 13x + 18 .....................1 0 = x3 11x 2 ........................2 1 2: y = 2x + 20 The suitable straight line is y = 2x + 20. The values of x which satisfy x3 11x 2 = 0 are
x = 3.2, x = 0.2 and x = 3.4.
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13
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
9. (a) y = 20x 2x2 When x = 2, y = 20(2) 2(2)2 = 32 When x = 5, y = 20(5) 2(5)2 = 50
x 2 5y 32 50
(b)
5
10
15
20
25
30
35
40
45
50
y
x0 1 2 3 4 5 6 7 8 9
y = 28
y = 4x + 25y = 20x 2x2
1.7
2.15
5.9
8.3
(c) (i) y = 50 (ii) x = 1.7 or x = 8.3(d) y = 20x 2x2 ...........................1 0 = 16x 2x2 25 ....................2 1 2: y = 4x + 25 The suitable straight line is y = 4x + 25. The values of x which satisfy 16x 2x2 25 = 0
are x = 2.15 and x = 5.9.
10. (a) y = 14 + 11x 3x2 When x = 1, y = 14 + 11(1) 3(1)2 = 0 When x = 5, y = 14 + 11(5) 3(5)2 = 6
x 1 5y 0 6
(b)
5
10
15
20
25
25
20
15
10
50 11 2 3 4 5 6 7
x
y
y = 5
y = 2x + 10
y = 14 + 11x 3x 2
0.7
0.4 3.
4
4.35
(c) x = 0.7 or x = 4.35(d) y = 14 + 11x 3x2 ....................1 0 = 4 + 9x 3x2 ........................2 1 2: y = 10 + 2x The suitable straight line is y = 10 + 2x. The values of x which satisfy 4 + 9x 3x2 = 0
are x = 0.4 and x = 3.4.
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14
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
11. (a) y = 2x2 + x 5 When x = 3, y = 2(3)2 + (3) 5 = 10 When x = 2, y = 2(2)2 + (2) 5 = 5
x 3 2y 10 5
(b)
0 1 2 3 44 3 2
2.4 1.92.51
5
5
10
15
20
25
30
35
y
y = 4
y = 2x 2 + x 5
x
(c) y = 10(d) y = 2x2 + x 5 ....................1 9 = 2x2 + x ..........................2 1 2: y 9 = 5 y = 4 The suitable straight line is y = 4. The values of x which satisfy 2x2 + x = 9 are
x = 2.4 and x = 1.9.
12. (a) y = 4x When x = 4, y = 4( 4) = 1 When x = 0.8, y = 40.8 = 5
x 4 0.8y 1 5
(b)
2
2
4
6
8
10
4
0.85
2.9
6
8
10
0 1 2 3 445 3 2 1 5
y
x
y = x
4y = x
4y = x
(c) (i) y = 2.9 (ii) x = 0.85(d) The equation of the straight line is y = x. The values of x are x = 2 and x = 2.
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15
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
13. (a) y = 6x When x = 2, y = 6(2) = 3
When x = 2.5, y = 62.5 = 2.4
x 2 2.5y 3 2.4
(b)
x
y
y = 2x
0 1
2
45
0.85 1.751.75
6
8
10
12
12
10
8
6
4
2 3 4 54 3 2 12
6y = x
(c) (i) y = 5 (ii) x = 0.85(d) The equation of the straight line is y = 2x. The values of x are x = 1.75 and x = 1.75.
14. (a) y = x3 4x 9 When x = 2, y = (2)3 4(2) 9 = 9 When x = 3, y = (3)3 4(3) 9 = 6
x 2 3y 9 6
(b)
x
30
40
50
60
20
10
10
20
30
40
1 1 2 3 4234 0
y
y = 10
y = x 3 4x 9
0.2 1.9 3.32.1
(c) (i) y = 20 (ii) x = 3.3(d) y = x3 4x 9 .........................1 0 = x3 4x + 1.........................2 1 2: y = 10 The suitable straight line is y = 10. The values of x which satisfy x3 4x + 1 = 0 are
x = 2.1, x = 0.2 and x = 1.9.
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16
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
15. (a) y = 2x2 + 3x + 7 When x = 1.5, y = 2(1.5)2 + 3(1.5) + 7 = 2 When x = 1, y = 2(1)2 + 3(1) + 7 = 8 When x = 4, y = 2(4)2 + 3(4) + 7 = 13
x 1.5 1 4y 2 8 13
(b)
5
5
10
10
15
20
25
30
0 1 2 33 2 1 4 5
3.35
y
x
y = 6x 25
y = 2x2+ 3x + 7
(c) (i) y = 5 (ii) 2x2 3x = 7 2x2 + 3x + 7 = 0 When y = 0, x = 1.25 or x = 2.75. The
values of x which satisfy 2x2 3x = 7 are x = 1.25 or x = 2.75.
(d) y = 2x2 + 3x + 7 .....................1 0 = 2x2 3x + 32 ...................2 1 2: y = 6x 25 The suitable straight line is y = 6x 25. The value of x which satisfies 2x2 3x + 32 = 0
is x = 3.35.
16. (a) y = 2 + 9x 2x2 When x = 2, y = 2 + 9(2) 2(2)2 = 24 When x = 4, y = 2 + 9(4) 2(4)2 = 6
x 2 4y 24 6
(b)
01
5
10
15
15
10
25
20
2 21 43 655
x
y = 4x 5
y = 2 + 9x 2x 2
y
3.51.6
(c) (i) x = 1.6 (ii) y = 10(d) y = 2 + 9x 2x2.......................1 0 = 2x2 5x 7 .......................2 1 + 2: y = 4x 5 The suitable straight line is y = 4x 5. The values of x which satisfy 2x2 5x 7 = 0 are
x = 1 and x = 3.5.
17. y 2x Region below the line y = 2xy 8 2x Region above the line y = 8 2xx 4 Region to the left of the dashed line x = 4
y
x0
y = 8 2x
y = 2xx = 4
8
4
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17
Mathematics SPM Chapter 22
Penerbitan Pelangi Sdn. Bhd.
18. y 4x Region below the line y = 4x3y x Region above the line 3y = xx 2 Region to the left of the dashed line x = 2
y
x03y = x
y = 4xx = 2
2
19. x + y 8 Region above the line x + y = 83y 2x Region above the line 3y = 2xy 8 Region below the dashed line y = 8
y
x0
3y = 2x
y = 8
x + y = 8
20. y x 4 Region above the line y = x 42y 12 3x Region below the line 2y = 12 3xx 2 Region to the right of the dashed line x = 2
y
x0
6
4
4
2y = 12 3x
y = x 4x = 2
21. y 3x + 9 Region above the line y = 3x + 9x 3 Region to the left of the dashed line x = 3y 9 Region below the line y = 9
y
x0 3
y = 3x + 9
x = 39 y = 9
22. y 2x 5 Region below the line y = 2x 5y x 5 Region above the line y = x 5y 4 Region below the dashed line y = 4
y
x0
4
5
y = 2x 5
y = x 5
y = 4
23. x 0 Region to the right of the y-axis2y x Region above the line 2y = x2x + 3y 6 Region above the line 2x + 3y = 6x + y 6 Region below the line x + y = 6
1
0 1 2 3 4 5 6 7
234567
y
x2x + 3y = 6
x + y = 62y = x