2.4 complex numbers

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2.4 COMPLEX NUMBERS Copyright © Cengage Learning. All rights reserved.

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Page 1: 2.4 COMPLEX NUMBERS

2.4 COMPLEX NUMBERS

Copyright © Cengage Learning. All rights reserved.

Page 2: 2.4 COMPLEX NUMBERS

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• Use the imaginary unit i to write complex

numbers.

• Add, subtract, and multiply complex numbers.

• Use complex conjugates to write the quotient of

two complex numbers in standard form.

• Find complex solutions of quadratic equations.

What You Should Learn

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The Imaginary Unit i

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The Imaginary Unit i

𝑥2 + 1 = 0 has no real solution

has complex solution

Imaginary unit 𝒊

𝑖 = −1

where 𝑖2 = −1

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The Imaginary Unit i

Complex number in standard form:

𝒂 + 𝒃𝒊

Example:

Complex number −5 + −9

Standard form: −5 + 3𝑖

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The Imaginary Unit i

𝒂 + 𝒃𝒊

Real part imaginary part

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The Imaginary Unit i

𝑎 = 𝑎 + 0𝑖

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The Imaginary Unit i

EXAMPLE:

𝑥 + 4𝑖 = −2 + 𝑏𝑖

⇒ 𝑥 = −24 = 𝑏

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Operations with Complex Numbers

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Operations with Complex Numbers

EXAMPLE:

2 + 5𝑖 − (4 + 7𝑖) 2 + 5𝑥 − (4 + 7𝑥)

Add/Subtract binomials

= 2 − 4 + 5 − 7 𝑥 = 2 − 4 + 5 − 7 𝑖

= −2 + −2 𝑖 = −2 + −2 𝑥

= −2 − 2𝑖 = −2 − 2𝑥

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Operations with Complex Numbers

The additive identity in the complex number system is

zero (the same as in the real number system).

The additive inverse of the complex number a + bi is

–(a + bi) = –a – bi.

(a + bi) + (–a – bi) = 0 + 0i = 0.

Additive inverse

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Example 1 – Adding and Subtracting Complex Numbers

a. (4 + 7i) + (1 – 6i) = 4 + 7i + 1 – 6i

= (4 + 1) + (7i – 6i)

= 5 + i

b. (1 + 2i) – (4 + 2i) = 1 + 2i – 4 – 2i

= (1 – 4) + (2i – 2i)

= –3 + 0

= –3

Remove parentheses.

Group like terms.

Write in standard form.

Remove parentheses.

Group like terms.

Simplify.

Write in standard form.

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Example 1 – Adding and Subtracting Complex Numbers

c. 3i – (–2 + 3i) – (2 + 5i) = 3i + 2 – 3i – 2 – 5i

= (2 – 2) + (3i – 3i – 5i)

= 0 – 5i

= –5i

d. (3 + 2i) + (4 – i) – (7 + i) = 3 + 2i + 4 – i – 7 – i

= (3 + 4 – 7) + (2i – i – i)

= 0 + 0i

= 0

cont’d

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Operations with Complex Numbers

(a + bi)(c + di) = a(c + di) + bi(c + di)

= ac + (ad)i + (bc)i + (bd)i2

= ac + (ad)i + (bc)i + (bd)(–1)

= ac – bd + (ad)i + (bc)i

= (ac – bd) + (ad + bc)i

Distributive Property

Distributive Property

i 2 = –1

Commutative Property

Associative Property

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FOIL

Complex Numbers Binomials

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Complex Conjugates

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Complex Conjugates

The product of two complex numbers can be a real

number.

This occurs with pairs of complex numbers of the form

a + bi and a – bi, called complex conjugates.

(a + bi)(a – bi) = a2 – abi + abi – b2i2

= a2 – b2(–1)

= a2 + b2

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Example 3 – Multiplying Conjugates

Multiply each complex number by its complex conjugate.

a. 1 + i b. 4 – 3i

Solution:

a. The complex conjugate of 1 + i is 1 – i.

(1 + i )(1 – i) = 12 – i2

= 1 – (–1)

= 2

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Example 3 – Solution

b. The complex conjugate of 4 – 3i is 4 + 3i.

(4 – 3i)(4 + 3i) = 42 – (3i)2

= 16 – 9i2

= 16 – 9(–1)

= 25

cont’d

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Complex Conjugates

To write the quotient of a + bi and c + di in standard form,

where c and d are not both zero, multiply the numerator

and denominator by the complex conjugate of the

denominator to obtain

Standard form

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Complex Solutions of Quadratic

Equations

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Complex Solutions of Quadratic Equations

When using the Quadratic Formula to solve a quadratic

equation, you often obtain a result such as , which you

know is not a real number. By factoring out i = , you

can write this number in standard form.

The number i is called the principal square root of –3.

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Example 6 – Complex Solutions of a Quadratic Equation

Solve (a) x2 + 4 = 0 and (b) 3x2 – 2x + 5 = 0.

Solution:

a. x2 + 4 = 0

x2 = –4

x = 2i

b. 3x2 – 2x + 5 = 0

Write original equation.

Subtract 4 from each side.

Extract square roots.

Write original equation.

Quadratic Formula

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Example 6 – Solution

Simplify.

Write in standard form.

Write in standard form.

cont’d