Prog_2 course- 2014

2 bytes team

Kinan keshkeh

IT Engineering-Damascus University

3rd year

Let’s Remember!!

SomeOf Prog_1

:D

Program 2Bytes_pro;

Uses wincrt;

Var k,x,y,z :integer;

Procedure proc1(a:integer; var b:integer ;)

var i,x: integer;

Begin

i:=10; x:=7; y:=12; a:=2; b:=4;

end;

Begin

x:=3; y:=5; proc1(k,z);

Writeln(„z=„,z);

Writeln(„k=„,k);

Writeln(„x=„,x);

Writeln(„y=„,y);

Writeln(„i=„,i);

End.

+1 +1 +1

+1 +1

{ z=4 }

{Random value often be zero}

{ x=3 }

{ y=12 } { error }

In procedures and functions There are four types of variables :

1. General Variables : are variables that are written at the top of the program befor all procedures and functions and we can see it and deal with it by all procedures and functions in the main program (like : k , x , y , z) .

2. Local Variables : are variables that are declared in the statements part within procedure or function and we can‟t see it and deal with it outside that procedures (like : i , x ) .

3. Formality Variables : are variables that appear in the header of procedure or function and it is formality and is not reserved place for it in memory (like a , b )

we have two types of formality variables

1) input variables : Keeps the value entered by after the completion of the procedural ( like : a)

2) output variables : Keeps the value obtained by the procedure. And we writes before it the reserved word (var) (like : b )

4. Actual Variables : are variables that main program pass it to procedure or function during a summons and it agree formality variables in number and type (like : k , z)

Notes : Local variables have priority from general variables in the same

Field of vision ( يجال انرؤيا ) ( like : x)

Execution always start form (begin) by the main program

in string :

var : name , lname : string ;

begin writeln(„enter the name and lname „);

readln(name , lname);

writeln(name);

writeln(lname);

End.

Ahmed

Ali

Inputs :

Ahmed Ali

X nothing

outputs

readln(name);

readln(lname);

+1

SETS

A П B A B

What is a DiscreteType??

Discrete Data Type:

Integer boolean char Enumerated

Day=(sat,sun,mon,tu,wed,th,fri)

Lik

e..

Definition

The SET is a Data Structure which contain

discrete type elements ..

Doesn‟t have index.!!

<Nameof varible > :Set of < discrete type >

We can‟t define the set as this form :

S : Set of Integer;

Because set can have 256 components at most

and all its component values should be in rang 0

.. 255 .

Ex:

• S1 : Set of 1..100;

• S2 : Set of „a‟..‟z‟;

• S : Set of Days;

• S : Set of 66..256;

• S: set of char ;

{True}

{True}

{True}

{False}

+1 {True}

Set Handling

Var:

s1:set of 0..255;

S2,s3:set of 40..100;

S4:set of „a‟..‟z‟;

S1 := [ 55, 80, 99, 80, 600, 41, 44..55];

Isn‟t added

S1:

41 44..55 80 99

S1 :

S1 := [];

S2 := [200,20];

S2:

40..100

“NO Change”

S4 := [‘B’,’A’,’c’,’a’];

S4:

„a‟ „c‟

S4 := [I,k];

Var I,k:integer;

i:=1; k:=k+1;

+1

S4:

Compile Error !!

S1 := [I,j];

Var I,j:integer;

i:=1; j:=i*9;

+1

S1:

1,9

i, j : integer; i := 1; j := i-1; S1 := [i, j]; S1 := S1 + [i*2];

S1:

0,1,2

+1

S1:=S4;

+1

Error

Ya fahmaneen !! :D

Operation

• To put a value in it , we use [value] .

• The operations on Sets :

⋂ ⇔ *

⋃ ⇔ +

/ ⇔ -

⊆ ⇔ <=

⊇ ⇔ >=

∈ ⇔ in

Program SetsOperator;

Var

A0 : set of 1..15;

A1 : set of 1..10;

A2 : set of 5..15;

i : integer;

Begin

A1 := [1..10];

A2 := [5..15];

A0 := A1*A2; {A0=[5..10]} A0 := A1+A2; {A0=[1..15]} A0 := A1-A2; {A0=[1..4]} A0 := A0-[1]; {A0=[2..4]}

A1 := [2,3]; A2 := [1,2,3,4,5]; if (A1 <= A2) then {or (A2 >= A1)} writeln ('A1 is a subset of A2'); readln (i); if (i in A1) then writeln (i,' is in A1') else writeln (i,' is not in A1'); End;

True statement

A0, A1 : Set of 1..15; A : boolean; A0 := [1, 2]; A1 := [2, 4]; A0 := A0 – [77]; A := A1 >= A0; A := 1 in A0;

Const Sets

Type Digits = set of 0..9; Const HexD : set of '0'..'z‘ = ['0'..'9', 'A'..'F', 'a'..'f']; ED : Digits = [0, 2, 4, 6, 8]; Var d : Digits; Begin d := [8]; d := ED; {d=[0,2,4,6,8]} ED:=ED+[9]; ED:=d; End.

+1

Error ..

Fateh

3eoonk !!

Enum Set

Type Day = (sun,mon,….,sat); Name=(koko,soso,fofo,fifi); Var days: Set of Day; N:set of Name Begin Days:=[sun..sat]; N:=[KOKO,SOSO]; End.

Read & Print Sets :

Program Test(); Type

SInt = Set of 1..150 ; SCh = Set of ‘0’..’z’;

Var S1 : SInt; S2 : SCh; Slen : Integer;

Begin Readln(Slen); ReadsetI(S1 , Slen); ReadsetC(S2 , Slen); PrintsetI(S1 , Slen); PrintsetC(S2 , Slen); Readln;

End.

Read Integer Sets

Procedure ReadsetI (var S:SInt; L:integer) ; var i, x : integer; Begin s:=[];

For i:=1 to L do begin

Read(x); S := S + [x];

end; End;

Read Char Sets

Procedure ReadsetC (var S:SCh; L:integer) ; var i, x : Char; Begin s:=[];

For i:=1 to L do begin

Read(x); S := S + [x];

end; End;

Print Integer Sets Using While Loop:

Procedure PrintsetI (S : SInt) ; var I : Integer; Begin

I := 0; While ( S <> []) do If (I in S) then begin

Writeln(I); S := S – [I];

end; I := I + 1;

End;

Print Integer Sets Using For Loop

Procedure PrintsetI (S : SI) ; var I : Integer; Begin

For I:=1 to 32700 do Begin

If (I in S) then Begin

Writeln(I); S := S – [I]; End; If (S = []) then I := 32700;

End; End;

Exercise : يرى في يؼهذ يا إػطاء دوراخ في يادذي انرياضياخ وانهغح اإلَكهيسيح

يؼطى كم طانة ػُذ ذسجيهه في انًؼهذ رقى فريذ يحصىر تيٍ طانة 50فإرا ػهًد أٌ ػذد انطالب في كم يادج ال يرجاوز 100..1

انًطهىب كراتح ترَايج ػاو تاسرخذاو االجرائياخ وانًجًىػاخ ورنك :نهقياو تانًهاو انرانيح

ذشكيم يجًىػح نطالب انرياضياخ ويجًىػح نطالب انهغح 1. (إدخال ػُاصر انًجًىػح )اإلَكهيسيح

إجراء نطثاػح ػُاصر انًجًىػح 2.

إجراء إلػطاء يجًىػح تأرقاو انطالب انًسجهيٍ تانًادذيٍ 3.

ػذد ٍقررخ إدارج انًؼهذ ذخفيض ػذد انطالب ورنك تاالسرغُاء ػ4.يحذد يُهى يذخم يٍ نىحح انًفاذيح ػهى أٌ يرى اخريار أرقاو

انطالب انًفصىنيٍ تشكم ػشىائي وانًطهىب كراتح إجراء نُقم أرقاو انطالب انًفصىنيٍ إنى يجًىػح جذيذج

وضغ أرقاو انطالب انًفصىنيٍ ضًٍ شؼاع 5.

Program prog2byte_team;

Uses wincrt;

Type students=set of 1..100;

numbers=array[1..50] of 1..100;

Var seng,smath : students;

Procedure inputset(var s : students; m:integer);

Var i,x: integer;

Begin

s:=[ ];

i:=0;

While (i<m) do

begin

writeln(„input students number „);

readln(x);

if (x in s) then

writeln(„ you input this number befor please enter

another number „)

else

begin

i:=i+1;

s:=s+[x];

end;

end;

End;

numbers of

students

Procedure printset(s :students);

Var i:integer;

Begin

i:=1;

While (s<>[ ]) do

begin

if (i in s) then

begin

write(i:5);

s:=s-[ i ];

end;

i:=i+1;

end;

writeln;

End;

Procedure bothsub(s1,s2 : students; var s3: students);

Begin

s3:=s1*s2;

End;

Procedure deletestd(var s,n : students);

Var k,i,x ; integer;

Begin

n:= [ ];

Randomize;

i:=0; Writeln(„enter the number you want to go throw out „);

Readln(x);

While (i<x) do

begin

k:= random(100) + 1;

if ( k in s ) then

begin

s:=s – [ k ];

seng:= seng – [ k ];

smath:=smath – [ k ];

i:=i+1;

n:=n + [ k ];

end;

end;

End;

يجًىػح انطالب

انًفصىنيٍ

يجًىػح انرقاطغ

:Randomize يقىو ترىنيذ

أرقاو ػشىائيح أػرًادا ػهى ساػح انُظاو

:Random(100)=0..99;

Random(100)+1=1..100

Procedure setinArray(s: students; var a: numbers ; var k: integer);

Var i : integer;

Begin

K:=0;

For i:=1 to 100 do

If (i in s) then

begin

k:=k+1;

a[k]:=i;

end;

End;

سرذػاء ايٍ أجم انشؼاع في انثرَايج

انرئيسي

Var nmath,neng,k,i :integer;

Aunaccepted : numbers;

Sunaccepted,sboth : students;

Begin

Writeln(„enter the number of math students „);

Readln(nmath);

Inputset(smath,nmath);

Writeln(„enter the number of English students „);

Readln(neng);

Inputset(seng,neng);

Bothsub(smath , seng , sboth);

Printset(sboth);

Deletestd(sboth,Sunaccepted);

Printset(Sunaccepted);

setinArray(Sunaccepted,Aunaccepted,k);

For i:=1 to k do

Writeln(Aunaccepted[i]:5);

Readln;

End.

Homework:

Creat and read two arrays of student numbers, student numbers in Prog and in English.

-We want to know the students numbers at the two subjects..?!

-what are the student numbers at the Prog and Not at English ??

+10 point

Group : group link

Mobile phone- Kinan : 0994385748

Facebook account : kinan’s account

2 bytes team

Revision Practise

Ques:

write a programme DO:

1-Read An Array 2-Print An Array//Proce

3-function to find the min elem in the array

4-Procedure to find the Sum array(of the tow arrays).

5- Multi array

Write the Main Program..

Programme P-Matrix;

Const nMax=20; mMax=20;

Type Matrix=array[1..nmax,1..mmax] of real;

Var A,B,Add,mult :Matrix;

n1,n2 :1..nmax;

m1,m2 :1..mmax;

min: integer;

Procedure ReadMat(Var: n:1..nmax;var m:1..mmax; var A:matrix);

Var i,j:integer;

begin

writeln(„enter the first Dimention of matrix< ‟ ,nmax);

Readln(n);

writeln(„enter the second Dimention of matrix< ‟ ,mmax);

Readln(m);

for i:=1 to n do

begin

for j:=1 to m do read(A[I,j]); {hint}

readln; {hint}

end;

end;

Procedure WriteMat(Var: n:1..nmax;var m:1..mmax; var

A:matrix);

Var i,j:integer;

begin

for i:=1 to n do

begin

for j:=1 to m do write(A[i,j],‟ ‟);

writeln;

end;

end;

Function MinOfMatrix(n:1..nmax,m:1..mmax;A:matrix):real

Var i,j:integer; min:real;

begin

min:=A[1,1];

For i:=1 to n do

for j:=1 to m do

if (A[i,j]<min) then

min:=A[i,j];

MinOfMatrix:=min;

end;

Procedure Add_Tow_Matrix(n1,n2:1..nmax;

m1,m2:1..mmax; var n3:1..nmax; var m3:1..mmax; var c:Matrix);

Var i,j:integer;

begin

if(n1<>n2)or(m1<>m2) then

writeln(„the addition is impossible‟);

else

begin

n3:=n1; m3:=m1;

for i:=1 to n3 do

for j:=1 to m3 do

C[i.j]:=A[i,j]+B[i,j];

end;

end;

Procedure Mult_Tow_Matrix(n1,n2:1..nmax; m1,m2:1..mmax; var n3:1..nmax; var m3:1..mmax; var c:Matrix);

Var i,j,k:integer;

begin

if(n1<>m2) then

writeln(„the multi is impossible‟);

else

begin

n3:=n2; m3:=m1; { A(m1,n1)*B(m2,n2)=C(m3,n3)}

for i:=1 to n3 do

for j:=1 to m3 do

begin

C[i,j]=0;

for k:=1 to m2

C[i.j]:= C[i.j] +A[i,k]*B[k,j];

end;

end;

end;

Begin

ReadMat(n1,m1,A); WriteMat(n1,m1,A);

ReadMat(n2,m2,B); WriteMat(n2,m2,B);

writeln(„the minimum of the first Mat = ‟);

min:=MinOfMatrix(n1,m1,A); writeln(min);

Add_Tow_Matrix(n1.m1,n2,m2,A,B,n3,m3,Add);

WriteMat(n3,m3,Add);

Mult_Tow_Matrix(n1,n2,m1,m2,A,B, n3,m3,mult);

WriteMat(n3,m3,mult);

End;

Group : group link

Mobile phone- Kinan : 0994385748

Facebook account : kinan’s account

2 bytes team