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2h 2 (g) + o 2 (g) 2h 2 o(g)

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2H 2H 2 2 (g) + O (g) + O 2 2 (g) (g) 2H 2H 2 2 O(g) O(g)

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2H 2 (g) + O 2 (g)  2H 2 O(g). 2H 2 (g) + O 2 (g)  2H 2 O(g). 5[2H 2 (g) + O 2 (g)  2H 2 O(g)] 10H 2 (g) + 5O 2 (g)  10H 2 O(g). 2H 2 (g) + O 2 (g)  2H 2 O(g). 5[2H 2 (g) + O 2 (g)  2H 2 O(g)] 10H 2 (g) + 5O 2 (g)  10H 2 O(g). Reaction Stoichiometry. - PowerPoint PPT Presentation

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Page 1: 2H 2 (g) + O 2 (g) 2H 2 O(g)

2H2H22(g) + O(g) + O22(g) (g) 2H2H22O(g)O(g)

Page 2: 2H 2 (g) + O 2 (g) 2H 2 O(g)

2H2H22(g) + O(g) + O22(g) (g) 2H2H22O(g)O(g)

5[2H2(g) + O2(g) 2H2O(g)]10H2(g) + 5O2(g) 10H2O(g)

Page 3: 2H 2 (g) + O 2 (g) 2H 2 O(g)

2H2H22(g) + O(g) + O22(g) (g) 2H2H22O(g)O(g)

5[2H2(g) + O2(g) 2H2O(g)]10H2(g) + 5O2(g) 10H2O(g)

Page 4: 2H 2 (g) + O 2 (g) 2H 2 O(g)

Reaction StoichiometryReaction Stoichiometry

Limiting Reactant = H2(g)

Excess Reactant = O2(g)

Theoretical Yield = 10 Molecules H2O


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