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    Decision Making

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    Sales Price Relationship Analysis

    A workshop making lampshades finds that the number it

    can sell varies depending on selling price.

    It can sell 10 per week if the price is set at Rs. 80, but 50

    per week if the price is reduced to Rs. 40. The cost of

    production is Rs. 20 for each lampshade and there are

    overheads of Rs. 60 per week.

    Assume linear relationship between price and sales.

    What should be the price to maximize his profit.

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    Sales Price Relationship Analysis

    0

    500

    1000

    1500

    2000

    2500

    0 20 40 60 80

    Sales

    R

    upees

    Revenue Cost Profit

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    Inverse Costs

    Maintenance department of a foundry wants to plan itsannual expenditure on equipment maintenance.

    Currently it has a crew of 10 people. It costs the company

    Rs. 20000 per month per crew member.

    If department increases its crew size, it can make

    maintenance operations more efficient. As a result

    breakdown costs will come down.

    Data analysis showed that size of maintenance crew and

    breakdown loss have a inverse relation as follows.

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    Inverse Costs

    Crew size 10 11 12 13 14 15

    Ependiture 2400000 2640000 2880000 3120000 3360000 3600000

    Breakdown loss 12000000 6000000 4000000 3000000 2400000 2000000

    Total cost 14400000 8640000 6880000 6120000 5760000 5600000

    Crew size 16 17 18 19 20

    Ependiture 3840000 4080000 4320000 4560000 4800000

    Breakdown loss 1900000 1800000 1700000 1600000 1500000

    Total cost 5740000 5880000 6020000 6160000 6300000

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    Inverse Costs

    0

    2000000

    4000000

    60000008000000

    10000000

    12000000

    14000000

    16000000

    8 9 10 11 12 13 14 15 16 17 18 19 20 21

    Crew size

    Cost

    Expenditure Breakdown loss Total cost

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    Inventory Costs

    Annualcost

    Lot Size (Q)

    Holding cost (HC)

    Ordering (setup) cost (OC)

    Total cost = HC+ OC

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    Replacement Decisions

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    Depreciation

    Any equipment we use at work reduces in value year by

    year, which is called as depreciation.

    Calculation of depreciation is needed for many decision

    making situations and one of them is replacement

    analysis.

    There are two basic methods of depreciation calculation.

    1. Straight line analysis

    2. Declining Balance method

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    Depreciation and Replacement Analysis

    A machine tool costs Rs. 300,000 when new.

    Lets calculate the written down value after 1,2 and 3 years using

    1. Straight line method with annual depreciation of Rs. 50,000

    2. By declining Balance method with annual depreciation of 20 %

    Approach 1: Straight line method

    Capital cost = 3,00,000

    Annual depreciation = 50,000Value after 1st year = 2,50,000

    Value after 2nd year = 2,00,000

    Value after 3rd year = 1,50,000

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    Depreciation and Replacement Analysis

    A machine tool costs Rs. 300,000 when new.

    Lets calculate the written down value after 1,2 and 3 years using

    1. Straight line method with annual depreciation of Rs. 50,000

    2. By declining Balance method with annual depreciation of 20 %

    Approach 2: Declining balance method

    Capital cost = 3,00,000

    Annual depreciation = 20%Value after 1st year = 30,00,000 - 0.2 x 3,00,000 = 2,40,000

    Value after 2nd year = 2,40,0000.2 x 2,40,000 = 1,92,000

    Value after 3rd year = 1,92,0000.2 x 1,92,000 = 1,53,600

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    Equipment Replacement Decisions

    Suppose a factory has a permanent need for an

    equipment, that wears out over a period of several

    years. In the initial period of use, the depreciation is

    likely to be high but maintenance costs will be low.

    Towards the end of its useful life, the rate of

    depreciation may be slow but maintenance costs will

    be high.

    When will it be better to sell off the existing equipment

    and purchase a new one ?

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    Equipment Replacement Decisions

    When will it be better to sell off the existing equipment

    and purchase a new one ?

    Year Depreciation maintenance

    Cost

    1 50000 6000

    2 45000 75003 40000 12000

    4 35000 20000

    5 30000 34000

    6 25000 50000

    7 20000 700008 15000 90000

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    Equipment Replacement Decisions

    0

    20000

    40000

    60000

    80000

    100000

    120000

    0 2 4 6 8 10

    Year

    Rupees

    Depreciation Maintenence Total Cost

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    Decision making Under Uncertainty

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    A set of quantitative decision-making techniques for

    decision situations where uncertainty exists

    States of nature

    events that may occur in the future

    decision maker is uncertain which state of nature

    will occur

    decision maker has no control over the states of

    nature

    Decision making Under Uncertainty

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    Payoff Table

    A method of organizing & illustrating the payoffs

    from different decisions given various states ofnature

    A payoff is the outcome of the decision

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    Payoff Table

    States Of Nature

    Decision a b1 Payoff 1a Payoff 1b

    2 Payoff 2a Payoff 2b

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    Decision making Criteria

    Maximax criterion (optimistic)

    choose decision with the maximum of the maximum

    payoffs

    Maximin criterion (Pessimist)

    choose decision with the maximum of the minimum

    payoffs

    Minimax regret criterion

    choose decision with the minimum of the maximum

    regrets for each alternative

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    Hurwicz criterion

    choose decision in which decision payoffs are

    weighted by a coefficient of optimism,

    coefficient of optimism () is a measure of a decision

    makers optimism, from 0 (completely pessimistic) to 1

    (completely optimistic)

    Equal likelihood (Laplace) criterion

    choose decision in which each state of nature is

    weighted equally

    Decision making Criteria

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    A B C D

    X 8 0 -10 6

    Y -4 12 18 -2

    Z 14 6 0 8

    Pay-Offs in Thousands of rupeesAlternative

    X -10 8Y -4 18

    Z 0 14

    Alternative Minimum Pay-off Maximum Pay-off

    Decision Making Example

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    A B C D

    X 8 0 -10 6

    Y -4 12 18 -2

    Z 14 6 0 8

    Pay-Offs in Thousands of rupeesAlternative

    X -10 8Y -4 18

    Z 0 14

    Alternative Minimum Pay-off Maximum Pay-off

    Maximin Maximax

    Decision Making Example

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    Minimax Regret Example

    A B C

    S1 700 300 150

    S2 500 450 200

    S3 300 300 100

    Events and Pay-offsStrategic

    Altenatives

    A B C

    S1 0 150 50

    S2 200 0 0

    S3 400 150 100

    Strategic

    Altenatives

    Events and Regrets

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    Minimax Regret Example

    A B C

    S1 700 300 150

    S2 500 450 200

    S3 300 300 100

    Events and Pay-offsStrategic

    Altenatives

    A B C

    S1 0 150 50 150

    S2 200 0 0 200

    S3 400 150 100 400

    Maximum

    Regret

    Strategic

    Altenatives

    Events and Regrets

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    Minimax Regret Example

    A B C

    S1 700 300 150

    S2 500 450 200

    S3 300 300 100

    Events and Pay-offsStrategic

    Altenatives

    A B C

    S1 0 150 50 150

    S2 200 0 0 200

    S3 400 150 100 400

    Maximum

    Regret

    Strategic

    Altenatives

    Events and Regrets

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    Hurwicz Criterion

    Step 1:Choose alfa and (1-alfa)

    Step 2:Determine for each alternative,

    h = (alfa) (max pay off) + (1-alfa) (minimum pay off)

    Step 3:Select the alternative with maximum value of h

    alfa is the coefficient of optimism. It is a measure of a

    decision makers optimism, from 0 to 1 (completelyoptimistic)

    (1-alfa) is the degree of pessimism

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    Hurwicz Criterion Example

    Take degree of optimism as 0.6

    A B C

    S1 8000 4500 2000

    S2 3500 4500 5000

    S3 5000 5000 4000

    Strategic

    Altenativ

    Events and Pay-offs

    For alternative S1,

    h = 0.6(8000)+0.4(2000) = 5600

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    Hurwicz Criterion Example

    Take degree of optimism as 0.6

    A B C

    S1 8000 4500 2000 5600

    S2 3500 4500 5000 4400

    S3 5000 5000 4000 4600

    Strategic

    Altenative

    Events and Pay-offsh

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    Hurwicz Criterion Example

    Take degree of optimism as 0.6

    A B C

    S1 8000 4500 2000 5600

    S2 3500 4500 5000 4400

    S3 5000 5000 4000 4600

    Strategic

    Altenativ

    Events and Pay-offsh

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    Laplace Criterion Example

    In this method we each state of nature is weighted equally.

    In other words, likelihood of occurrence of events is

    considered to be equal.

    Step 1:Assign equal weights to each pay off of an

    alternative or strategy.

    Step 2:Estimate the expected pay off for each alternative

    Step 3:Select the alternative which has the maximum

    expected pay off

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    Laplace Criterion Example

    A B C D

    1 4 0 -5 32 -2 6 9 1

    3 7 3 2 4

    Events and Pay offsAlternative

    Expected Pay off for Alternative 1:

    0.25 (4) + 0.25 (0) +0.25 (-5) + 0.25 (3) = 0.5

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    Laplace Criterion Example

    A B C D

    1 4 0 -5 3 0.52 -2 6 9 1 3.5

    3 7 3 2 4 4.0

    Events and Pay offsAlternative

    Expected

    Pay off

    Expected Pay off for Alternative 1:

    0.25 (4) + 0.25 (0) +0.25 (-5) + 0.25 (3) = 0.5

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    Laplace Criterion Example

    A B C D

    1 4 0 -5 3 0.52 -2 6 9 1 3.5

    3 7 3 2 4 4.0

    Events and Pay offsAlternative

    Expected

    Pay off

    Expected Pay off for Alternative 1:

    0.25 (4) + 0.25 (0) +0.25 (-5) + 0.25 (3) = 0.5

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    Decision making With Probabilities

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    Decision making With Probabilities

    Probabilities need to be assigned to events

    Expected Value is a weighted average of decision

    outcomes.

    EV x p ix ixi

    n

    whereix outcome i

    p ix probability of outco

    ( )

    1

    me i

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    Expected payoff Criterion

    A store keeper stocks a perishable item. Shelf life of thisitem is one month. Store keeper wants to determine the

    number of items he should stock at the beginning of the

    month.

    He buys the item for Rs. 30 and sells at Rs. 50.He analyzes the trend for last two years i.e. 24 months.

    The following table gives the sales during last 24 months.

    Sales 10 11 12 13

    Frequency 3 5 10 6

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    Sales 10 11 12 13

    Frequency 3 5 10 6

    Probability 0.125 0.208 0.417 0.250

    Expected payoff Criterion

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    10 11 12 1310 200 170 140 110

    11 200 220 190 160

    12 200 220 240 210

    13 200 220 240 260

    StockDemand

    Expected payoff Criterion

    Expected Demand is derived from the sales of the past

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    10 11 12 13

    10 25.00 21.25 17.50 13.7511 41.67 45.83 39.58 33.33

    12 83.33 91.67 100.00 87.50

    13 50.00 55.00 60.00 65.00

    EMV 200.00 213.75 217.08 199.58

    Stock and conditional pay offDemand

    Expected payoff Criterion

    EMV = Expected Monetary Value

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    10 11 12 13

    10 25.00 21.25 17.50 13.7511 41.67 45.83 39.58 33.33

    12 83.33 91.67 100.00 87.50

    13 50.00 55.00 60.00 65.00

    EMV 200.00 213.75 217.08 199.58

    Stock and conditional pay offDemand

    Expected payoff Criterion

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    Expected Regret Criterion

    10 11 12 13

    10 0 30 60 90

    11 20 0 30 60

    12 40 20 0 30

    13 60 40 20 0

    Stock and Regret

    Demand

    10 11 12 13

    10 0.00 3.75 7.50 11.25

    11 4.17 0.00 6.25 12.50

    12 16.67 8.33 0.00 12.50

    13 15.00 10.00 5.00 0.00

    ER 35.83 22.08 18.75 36.25

    Stock and Conditional RegretDemand

    D i i T

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    Decision Trees

    Decision Trees

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    Decision Trees

    Bharat Oil Company (BOC) owns a land that may

    contain oil.

    Geologist report shows a 25% chance of oil

    Another company is offering to buy the land for Rs.90 Cr

    If BOC decides to drill, it will earn a profit of Rs. 700

    Cr if oil is found.

    However, it will incur a loss of Rs. 100 Cr if oil is notfound.

    Should BOC drill or sell ?

    Decision Trees

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    Decision Trees

    Oil

    Oil

    Dry

    Dry

    (0.25)

    (0.25)

    (0.75)

    (0.75)

    700 Cr

    -100 Cr

    90 Cr

    90 Cr

    Drill

    Sell

    decision

    Expected

    pay off is

    100 Cr

    Expected

    pay off is

    90 Cr

    Value of Perfect Information

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    Value of Perfect Information

    In many decision making exercises it is possible

    to get more or extra information about the events

    or state of nature.

    But it will cost extra money.

    Question : Is additional information worth the

    cost ?

    Value of Perfect Information

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    Value of Perfect Information

    Continuing with the previous example,

    A sesmic survey can tell whether the land is fairly

    likely or fairly unlikely to have oil.Cost of the survey is Rs. 30 Cr

    Should BOC do the survey ?

    Value of Perfect Information

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    Value of Perfect Information

    Expected pay off with perfect information is

    = 0.25 (700) + 0.75 (90) = 242.5 Cr

    Expected value of perfect information is

    = Expected pay off with perfect information - Expected pay

    off without perfect information

    = 242.5100 = 142.5 Cr.

    If EVPI is less than the cost of survey, then dont do thesurvey. Its not worth it.

    In this case, 142.5 Cr. >> 30 Cr.

    It is worthwhile doing the survey.

    Decision Trees

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    Decision Trees

    A firm is adding a new product line and must build a new plant. Demand

    will either be favourable or unfavourable, with probabilities of 0.6 and 0.4,

    respectively. If a large plant is built and demand is favourable the pay off is

    estimated to be Rs. 1520 Cr. If the demand is unfavourable, the loss with

    larger plant will be Rs. 20 Cr

    If a medium sized plant is built and demand is unfavourable, the pay off is

    Rs. 760 Cr. If the demand proves to be favourable, the firm can maintain the

    medium sized facility or expand it. Maintaining medium sized facility will

    result in to a pay off of Rs. 950 Cr and expanding it will give a pay off of Rs

    570 Cr in the next period.

    Draw a decision tree for this problem

    What should the management do to achieve the highest expected pay off ?

    Decision Trees

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    Decision Trees

    Fav

    Un Fav

    (0.6)

    (0.6)

    (0.4)

    (0.4)

    1520 Cr

    -20 Cr

    760 Cr

    Large

    Small

    decision Fav

    Un Fav

    Expand

    Continue

    570 Cr

    950 Cr

    0.6 (1520) 0.4 (20) = 904 Cr

    0.6 (950) + 0.4 (760) = 874 Cr

    Build a large Plant