(32) radiation fundamentals 1

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    RADIATIVE HEAT TRANSFER

    Prabal Talukdar

    Department of Mechanical Engineering

    IIT Delhi

    E-mail: [email protected]

    MECH/IITD

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    Introduction

    MECH/IITD

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    Thermal Radiation Radiation heat transfer can take lace in a vacuum. It

    does not need a medium unlike conduction/convection Thermal radiation is the stream of electromagnetic

    ra a on em e y a ma er a en y on accoun o s

    finite absolute temperature

    Infrared radiation from a common household radiator or

    electric heater is an example of thermal radiation, as is

    the light emitted by a glowing incandescent light bulb.

    erma ra a on s genera e w en ea rom emovement of electrons within atoms is converted to

    electromagnetic radiation

    MECH/IITD

    Dominant in high temperature applications

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    Spectrum of Electro-magnetic

    MECH/IITD

    Thermal radiation falls in the range of 10-1-102 m of the Electro-magnetic spectrum.

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    Emission Process

    MECH/IITD

    Volumetric Phenomenon Surface phenomenon

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    Emission b a surface

    MECH/IITD

    Gray Diffuse

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    Solid an le

    Plane Angle Solid Angle

    MECH/IITD

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    MECH/IITD

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    Solid an le = 2 = 2 2 =

    MECH/IITD

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    Solid An le for a Hemisphere2/ 2/2

    srs ns nw0 0h 0

    ===

    MECH/IITD

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    Spectral Intensit I

    ,e(,,)=dq/(dA1cos .d.d) I

    ,e

    is the rate at which radiant energy is emitted at the wave length

    in the (, ) direction, per unit area of emitting surface normal to thisdirection, per unit solid angle about this direction and per unit

    wavelength interval d about .

    MECH/IITD

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    Heat Flux dq=dq/drate at which radiation of wavelength leaves dA1 and

    passes through dAn (unit: W/m)

    dq= I,e(,, ) dA1cos d 1

    = ddsincos),,(Idq e,"

    Spectral heat flux associated with emission into hypothetical

    hemisphere above dA1 is

    =2/2

    " ddsincos,,I

    Total heat flux associated with emissions in all directions and

    at all wavelengths is then

    0

    ,

    0

    MECH/IITD

    =0

    "" d)(qq

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    Emissive Power

    emitted per unit surface area

    ,

    E()(W/m2.m)=

    2/

    e,

    2

    ddsincos),,(I

    Ebased on actual surface area

    I based on projected surface area

    00

    ,

    Total hemispherical Emissive power:

    MECH/IITD

    =

    d)(EE

    0

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    Relation between Emissive Power

    2/2

    E= 0 e,0 ddsincos),,(I

    For a diffuse surface, I(,,)= I

    ()

    2/2

    E=

    00

    e, ddsincos)(I

    ,e

    =

    MECH/IITD