4 eso academics - unit 01 - real numbers and percentages
TRANSCRIPT
Unit 01 September
1. RATIONAL NUMBERS.
A Rational number is any number that can be expressed as the quotient ππππ
of
two integers, where the denominator b is not equal to zero. ππ,ππ β β€; ππ β ππ
12 ,β
34
NOTE: A set is a collection of objects, these objects are called elements.
The set of all rational numbers is usually denoted β (for quotient). Natural
numbers, whole numbers, integers and fractions are rational numbers.
A Decimal number is a rational number if it can be written as a fraction. Those
are decimals that either terminate or have a repeating block of digits.
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Terminating decimals: 4.8; 3.557; 24.997897
Recurring decimals: 4.888888..; 34.345345345...
NOTE: We can write a recurring decimal in different ways:
13 = 0.333 β¦ = 0. 3Μ = 0. 3οΏ½
All the rational numbers can be shown in a number line. To do this we generally
divide each segment using the theorem of Thales.
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MATH VOCABULARY: Rational number, Integer, Denominator, Set, Elements, Decimal
number, Terminating decimals, Recurring decimals, Number line, ThalesΒ΄ theorem,
Theorem, Segment.
2. IRRATIONAL NUMBERS.
An Irrational number is a number that cannot be written as a simple fraction.
Equivalently, irrational numbers cannot be represented as terminating or recurring
decimals (the decimal part goes on forever without repeating). There are infinite
irrational numbers. Here you are some of the most interesting ones:
2.1. NUMBER Ο.
Ο (pi) is an irrational number. The value of Ο is
3.1415926535897932384626433832795 (and moreβ¦). There is no pattern to the
decimals, and you cannot write down a simple fraction that equals Ο. Remember that
Ο is the ratio of the circumference to the diameter of a circle. In other words, if you
measure the circumference, and then divide by the diameter of the circle you get the
number Ο.
MATH VOCABULARY: Irrational Numbers, Ratio, Circumference, Diameter, Circle,
Pattern.
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2.2. THE SQUARE ROOT OF 2.
Pythagoraβs theorem shows that the diagonal of a square with sides of one unit
of length is equal to β2:
π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· = οΏ½12 + 12 = 2
The computer says that β2 = 1.414213562373095048801688724. .. , but
this is not the full story! It actually goes on and on, with no pattern to the numbers.
You cannot write down a simple fraction that equals β2 .
How can we prove that β2 is an irrational number? The proof that β2 is indeed
irrational is a βproof by contradictionβ (if β2 WERE a rational number, then we would
get a contradiction):
PROOF:
Letβs suppose β2 were a rational number. Then we can write it as a quotient of
two integer numbers:
β2 =π·π·ππ
We also suppose that is the simplest fraction, that is, a and b have no common
factors. Squaring on both sides gives:
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οΏ½β2οΏ½2
= οΏ½π·π·πποΏ½
2β 2 =
π·π·2
ππ2 β 2ππ2 = π·π·2 β π·π·2 π·π·ππ π·π·π·π· πππππππ·π· π·π·ππππππππππ
If π·π· 2 is an even number, then π·π· is also an even number. If π·π· were an odd
number, then π·π· = 2π·π· + 1.
π·π·2 = (2π·π· + 1)2 = (2π·π·)2 + 2 β 2π·π· β 1 + 12 = 4π·π·2 + 4π·π· + 1 = 2(2π·π·2 + π·π·) + 1
π·π·2 = 2(2π·π·2 + π·π·) + 1
β π·π·2 π€π€π·π·πππ·π·π€π€ ππππ π·π·π·π· π·π·π€π€π€π€ π·π·ππππππππππ, π·π·π·π·π€π€ π‘π‘βπ·π·ππ π·π·ππ π·π· ππππππππππππππππππππππππππ
So we have that π·π· is an even number, that is, we can write π·π· = 2ππ
2 =π·π·2
ππ2 β 2 =(2ππ)2
ππ2 β 2 =4ππ2
ππ2 β 2ππ2 = 4ππ2 β ππ2 = 2ππ2
ππ2 = 2ππ2 β ππ2 π·π·ππ π·π·π·π· πππππππ·π· π·π·ππππππππππ β ππ π·π·ππ π·π·π·π· πππππππ·π· π·π·ππππππππππ
Therefore, π·π· and ππ are both even numbers. This is a contradiction because we
started our proof saying that π·π· and ππ have no common factors.
Then β2 is an irrational number.
Many square roots, cube roots, etc. are also irrational numbers. If ππ is not a
square number, then οΏ½ππ is an irrational number. In general, if ππ is not an exact nth
power, then οΏ½ππππ is an irrational number.
β3, β11, β153 , β105 π·π·ππππ π·π·πππππ·π·π‘π‘π·π·π·π·π·π·π·π·π·π· π·π·ππππππππππππ
MATH VOCABULARY: Pythagoraβs theorem, Diagonal, Square, To Prove, Proof, Proof
by contradiction, Simplest fraction, Even number, Odd number, Square root, Cube root.
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2.3. THE GOLDEN NUMBER.
In a regular pentagon the ratio between a diagonal and a side is the irrational
number:
Ξ¦ =β5 + 1
2
This number is called π½π½, the Golden number (or the Golden ratio).
If you divide a line into two parts so that: βThe whole length divided by the
longest part is equal to the longest part divided by the smallest part, then you will have
the golden numberβ.
In this case we say that a and ππ are in the Golden ratio. The golden ratio
appears many times in geometry, art, architecture and other areas.
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A rectangle, in which the ratio of the longest side to the shortest is the golden
ratio, is called Golden rectangle. A golden rectangle can be cut into a square and a
smaller rectangle that is also a golden rectangle.
Some artists and architects believe the golden ratio makes the most pleasing
and beautiful shape. Many buildings ant artworks have the Golden Ratio in them, such
as the Parthenon in Greece, but it is not really known if it was designed that way.
MATH VOCABULARY: Pentagon, Side, Golden ratio, Golden number, Length, Geometry,
Rectangle, Shape.
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2.4. THE NUMBER e.
The number e is a famous irrational number, and one of the most important
numbers in mathematics. It is often called Eulerβs number, after Leonhard Euler. The
first few digits are:
ππ.ππππππππππππππππππππππππππππβ¦
There are many ways of calculating the value of ππ, but none of them ever give
an exact answer. Nevertheless, it is known to over 1 trillion digits of accuracy. For
example, the value of
οΏ½ππ
ππ+ πποΏ½ππ
approaches ππ as ππ gets bigger and bigger.
MATH VOCABULARY: Eulerβs number, Accuracy, To Approach.
3. REAL NUMBERS.
The set of the rational numbers and the irrational numbers is called the set of
the Real numbers. It is usually denoted β.
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Natural numbers are a subset of integers. Integers are a subset of rational
numbers. Rational numbers are a subset of real numbers.
MATH VOCABULARY: Real numbers, Subset.
3.1. THE REAL NUMBER LINE.
The real number system can be visualized as a horizontal line that extends from
a special point called the origin in both directions towards infinity. Also associated with
the line is a unit of length. The origin corresponds to the number ππ. A positive number
ππ corresponds to a point ππ ππππππππππ away from the origin to the right, and a negative
number β ππ corresponds to a point on the line ππ ππππππππππ away from the origin to the
left.
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This horizontal line is called the Real number line. Any point on the number line
is a real number and vice versa, any real number is a point on the number line. To plot
irrational numbers like βπ·π·, we use the Pythagoraβs theorem. For irrational numbers
like ππ, ππ, β¦ we plot them approximately.
MATH VOCABULARY: Horizontal, To Extend, Point, Origin, Real number line.
4. APPROXIMATION AND ROUNDING.
Rounding a number is another way of writing a number approximately. We
often donβt need to write all the figures in a number, as an approximate one will do.
The population of Villanueva de la Serena is 28,789. Since populations change
frequently, we use a rounded number instead of the exact number. It is better to
round up and say 29,000.
To round a number to a given place:
β’ Find the place you are rounding to.
β’ Look at the digit to its right.
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β’ If the digit is less than 5, round down.
β’ If the digit is 5 or greater, round up.
Round 83,524 to the nearest ten:
The digit to the right is 4. 4 < 5. Round down to 83,520
Round 83,524 to the nearest hundred:
The digit to the right is 2. 2 < 5. Round down to 83,500
Round 83,524 to the nearest thousand:
The digit to the right is 5. 5 = 5. Round up to 84,000
To round 718.394 to 2 decimal places, look at the thousandths digit.
The thousandths digit is 4, so round down to 718.39. 718.394 β 718.39 (π‘π‘π·π· 2 π€π€πππππ·π·πππ·π·π·π· πππ·π·π·π·ππππππ)
Numbers can be rounded:
β’ To decimal places 4.16 = 4.2 to 1 decimal place
β’ To the nearest unit, 10, 100, 1000, β¦
Remember that a method of giving an approximate answer to a problem is to
round off using significant figures. The first non-zero digit in a number is called the
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first significant figure βit has the highest value in the number. When rounding to
significant figures, count from the first non-zero digit.
54.76 β 55 (π‘π‘π·π· 2 πππ·π·π·π·π·π·π·π·π π π·π·πππ·π·π·π·π‘π‘ π π π·π·π·π·ππππππππ)
0.00405 β 0.0041 (π‘π‘π·π· 2 πππ·π·π·π·π·π·π·π·π π π·π·πππ·π·π·π·π‘π‘ π π π·π·π·π·ππππππππ) 6.339 β 6.34 (π‘π‘π·π· 3 πππ·π·π·π·π·π·π·π·π π π·π·πππ·π·π·π·π‘π‘ π π π·π·π·π·ππππππππ)
0.000000338754 β 0.000000339 (π‘π‘π·π· 3 πππ·π·π·π·π·π·π·π·π π π·π·πππ·π·π·π·π‘π‘ π π π·π·π·π·ππππππππ)
You can estimate the answer to a calculation by rounding the numbers:
Estimate the answer to
6.23 β 9.8918.7
You can round each of the numbers to 1 significant figure:
6 β 1020 = 3 β
6.23 β 9.8918.7 β 3
dp and sf are abbreviations for βdecimal placesβ and βsignificant figuresβ. When
a measurement is written, it is always written to a given degree of accuracy. The real
measurement can be anywhere within Β± half a unit.
A man walks 23 km (to the nearest km). Write the maximum and minimum distance he could have walked.
Because the real measurement has been rounded, it can lie anywhere between
22.5 km (minimum) and 23.5 (maximum).
Another way of approximating a number is called Truncating a number, is a
method of approximating a decimal number by dropping all decimal places past a
certain point without rounding.
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3.14159265... can be truncated to 3.1415
MATH VOCABULARY: Rounding, Approximation, Population, Frequently, Exact number,
Round up, Round down, Thousandths, First significant figure, Estimate, Truncate.
5. APPROXIMATION ERRORS.
Absolute and Relative error are two types of error. The differences are
important.
Absolute error is the amount of physical error in a measurement, period. Given
some value ππ and its approximation ππππππππππππππ, the Absolute error is:
π¨π¨πππππππ¨π¨ππππππ ππππππππππ = βππ = ππ = οΏ½ππ β πππππππππππππποΏ½
Relative error gives an indication of how good a measurement is relative to the
size of the thing being measured. The Relative error is:
πΉπΉπππ¨π¨ππππππππππ ππππππππππ = πΌπΌ =ππ
|ππ| =οΏ½ππ β πππππππππππππποΏ½
|ππ| = οΏ½ππ βππππππππππππππ
ππ οΏ½
This error can be converter in a percentage by multiplying by 100
called Percent Error:
πΉπΉ = πΌπΌ β ππππππ
In words, the Absolute error is the magnitude of the difference between the
exact value and the approximation. The Relative error is the absolute error divided by
the magnitude of the exact value. The Percent error is the relative error expressed in
terms of per 100.
If the exact value is 50 and its approximation 49.9, then the absolute error is:
Ο΅ = |50 β 49.9| = |0.1| = 0.1
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and the relative error is:
Ξ· =Ο΅
|v| =0.150 = 0.002
so the percent error is:
πΏπΏ = ππ β 100 = 0.002 β 100 = 0.2%
Sometimes a maximum assumable error is given; this error is called
βError boundβ. This error can be absolute or relative.
Absolute error bound is 0.005 cm Relative error bound is 5 %
An upper bound for the absolute error is half a unit of the last significant figure
in the approximate value.
3.14 is the approximation of the number ππ to 3 significant figures, that is, to the hundredths. An upper bound for the absolute error of this approximation is: half one
hundredth, that is:
0.012 = 0.005 β |ππ β 3.14| < 0.005
MATH VOCABULARY: Error, Absolute error, Relative error, Percent error, Error bound.
6. INTERVALS.
An Interval is a set formed by the real numbers between, and sometimes
including, two numbers. They can also be non-ending intervals as we are going to see.
It can also be thought as a segment of the real number line. An endpoint of an interval
is either of the two points that mark end on the line segment. An interval can include
either endpoint, both endpoints, or neither endpoint.
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There are different notations for intervals:
Let ππ and ππ be real numbers such that ππ < ππ:
β’ The Open interval (ππ,ππ) is the set of real numbers between ππ and ππ, excluding
ππ and ππ.
β’ The Closed interval [ππ,ππ] is the set of real numbers between ππ and ππ, including
ππ and ππ.
β’ The Left half-open interval (ππ,ππ] is the set of real numbers between ππ and ππ,
including ππ but not a.
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β’ The Right half-open interval [ππ,ππ) is the set of real numbers between ππ and ππ,
including ππ but not ππ.
β’ The Infinite intervals are those that do not have an endpoint in either the
positive or negative direction, or both. The interval extends forever in that
direction.
Examples:
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MATH VOCABULARY: Interval, Endpoint, Square bracket, Round bracket, Notation,
Open interval, Closed interval, Left half-open interval, Right half-open interval, Infinite
interval.
6.1. UNION AND INTERSECTION.
We can to join two sets using "Union" (and the symbol βͺ). There is also
"Intersection" which means "has to be in both". Think "where do they overlap?". The
Intersection symbol is "β©".
Example: π₯π₯ β€ 2 π·π·ππ π₯π₯ > 3. On the number line it looks like this:
And interval notation looks like this:
(ββ, 2] ππ (3, +β) Example: (ββ, 6] β© (1,β). The first interval goes up to (and including) 6. The second interval goes from (but not including) 1 onwards.
The Intersection (or overlap) of those two sets goes from 1 to 6 (not including
1, including 6):
MATH VOCABULARY: Union, Intersection.
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7. PERCENTAGES.
7.1. FINDING A PERCENTAGE OF A QUANTITY.
You often need to calculate a Percentage of a quantity πΈπΈ:
ππ% ππππ πΈπΈ = ππππππππ β πΈπΈ
Example: 9% of 24 m.
9% π·π·π π 24 =9
100 β 100 = 2.16 ππ
7.2. PERCENTAGE INCREASE AND DECREASE.
Percentages are used in real life to show how much an amount has increased
or decreased.
β’ To calculate a Percentage increase, work out the increase and add it to the
original amount.
β’ To calculate a Percentage decrease, work out the decrease and subtract it from
the amount.
Alan is paid Β£940 a month. His employer increases his wage by 3%. Calculate the new wage Alan is paid each month.
Increase in wage = 3% of Β£940 = 0.03 Γ Β£940 = Β£28.20 Alanβs new wage = Β£940 + Β£28.20 = Β£968.20 A new car costs Β£19 490. After one year the car depreciates in value by 8.7%.
What is the new value of the car? Depreciation = 8.7% of Β£19 490 = 0.087 Γ Β£19490 = Β£1695.63 New value of car = Β£19490 β Β£1695.63 = Β£17 794.37
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You can also calculate a percentage increase or decrease in a single calculation:
π·π·πππππππππππππππ·π·ππ π°π°ππππππππππππππ ππ% ππππππππ πΈπΈ = πΈπΈ β οΏ½ππππππ+ ππππππππ οΏ½
π·π·πππππππππππππππ·π·ππ π«π«ππππππππππππππ ππ% ππππππππ πΈπΈ = πΈπΈ β οΏ½ππππππ β ππππππππ οΏ½
In a sale all prices are reduced by 16%. A pair of trousers normally costs Β£82. What is the sale price of the pair of trousers?
πππ·π·π·π·ππ πππππ·π·ππππ = Β£82 β οΏ½100β 16
100 οΏ½ = Β£82 β 0.84 = Β£68.88
MATH VOCABULARY: Percentage increase, Percentage decrease.
7.3. MULTIPLE PERCENTAGES.
Sometimes we need to calculate Multiple percentages simultaneously. We
have to apply the above formulas several times:
π΄π΄πππ¨π¨πππππππ¨π¨ππ πππππππππππππππππ·π·ππππ ππππππππ πΈπΈ = πΈπΈ β οΏ½ππππππΒ± ππππππππππ οΏ½ β οΏ½
ππππππ Β± ππππππππππ οΏ½β¦
During Christmas, a phone shop prices up 21%. On January, during sales, prices fell 19%. Before Christmas a phone cost 645β¬. How much cost in January?
January cost = 645 β οΏ½100 + 21
100 οΏ½ β οΏ½100β 19
100 οΏ½ = 632.16 β¬
MATH VOCABULARY: Multiple percentages, Formulae.
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8. SIMPLE INTEREST.
You earn Interest when you invest in a savings account at a bank. However, you
pay Interest if you borrow money for a mortgage. The original sum you invest is called
the principal.
Simple interest is money you can earn by initially investing some money (the
principal). A percentage (the interest) of the principal is added to the principal, making
your initial investment grow!
To calculate simple interest, use the interest rate to work out the amount
earned. If simple interest is paid for several years, the amount paid each time stays the
same, because the interest is paid elsewhere and the principal stays the same.
π°π° = π·π· β πΉπΉ β π»π»
π°π° = π°π°ππππππππππππππ ππππππππππππ; π·π· = π·π·πππππππππππππππ¨π¨; πΉπΉ = π°π°ππππππππππππππ ππππππππ; π»π» = π»π»πππ»π»ππ
Usually:
πΉπΉ =ππππππππ ,ππππππππππ ππ ππππ ππππππ πππππππππππππππππ·π·ππ ππππππππππππ ππππππ ππππππππ
Calculate the interest when Β£1,000 is invested for 4 years at a 5% simple
interest (I).
πΌπΌ = 1,000 β5
100 β 4 = Β£200
πππ·π·π‘π‘π·π·π·π· = πππππ·π·π·π·πππ·π·πππ·π·π·π· + πΌπΌ = Β£1,000 + Β£200 = Β£1200
MATH VOCABULARY: Interest, Saving account, to Invest, Mortgage, Principal, Simple
interest.
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9. COMPOUND INTEREST.
The addition of interest to the principal sum of a loan or deposit is called
compounding. Compound interest is interest on interest. It is the result of reinvesting
interest, rather than paying it out, so that interest in the next period is then earned on
the principal sum plus previously-accumulated interest. Compound interest is standard
in finance and economics.
To calculate compound interest, work out the interest in the same way, but
add the interest earned to the principal. If compound interest is paid for several years,
the amount of interest earned each year increases, because the principal increases.
π¨π¨ = π·π· β οΏ½ππ +πΉπΉπποΏ½
ππβππ
π¨π¨ = π¨π¨π»π»ππππππππ;
π·π· = π·π·πππππππππππππππ¨π¨;
πΉπΉ = πππππππππππ¨π¨ πππππ»π»πππππππ¨π¨ ππππππππππππππππ ππππππππ;
ππ = πππππ»π»ππππππππππ πππππ»π»ππππ ππππππ ππππππππππππππππ ππππ πππππ»π»ππππππππππππππ ππππππ ππππππππ;
ππ = πππππ»π»ππππππ ππππ ππππππππππ
Β£2,000 is invested at 6.5% compound interest. Find the principal after 15 years.
A = 2,000 β οΏ½1 +0,065
1 οΏ½1β15
= 2,000 β (1,065)15 = Β£5,143.68
If you have a bank account whose principal is $1,000, and your bank
compounds the interest twice a year at an interest rate of 5%, how much money do you have in your account at the year's end?
A = 1,000 β οΏ½1 +0,05
2 οΏ½2β1
= 1,000 β (1,025)2 = $1,050.63
MATH VOCABULARY: Compound interest, to Reinvest.
Axel CotΓ³n GutiΓ©rrez Mathematics 4ΒΊ ESO 1.21