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    MICROWAVE NETWORKS

    Dr L.Anjaneyulu

    NIT, Warangal

    [email protected]

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    Network ports

    What is the difference between the port of

    low frequency network and microwave

    frequency network ?

    For low frequency network a port is a pair

    of terminals where as for a microwave

    network a port is reference planetransverse to the length of microwave

    transmission line

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    Network Parameters

    Z, h, Y and ABCD parameters are difficultto measure for microwave networkbecause at microwave frequencies the

    physical length of the component or line iscomparable to or much greater than thewavelength.

    so the voltage and current are not welldefined at a given point for a microwavecircuit

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    Why Z, Y,h and ABCD parameters are

    difficult to measure for MW circuit ?

    1) Non- availability of terminal voltage and

    current measuring equipment

    2) Short circuit and open circuits are not

    easily achieved for a wide range of

    frequencies

    3) Presence of active devices makes the

    circuit unsuitable for short and open circuit

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    A photograph of the Hewlett-

    Packard HP8510B Network

    Analyzer. This test instrument

    is used to measure the

    scattering parameters

    (magnitude and phase) of a

    one- or two-port microwave

    network from 0.05 GHz to

    26.5 GHz. Built-in

    microprocessors provideerror correction, a high

    degree of accuracy, and a

    wide choice of display

    formats. This analyzer can

    also perform a fast Fourier

    transform of the frequencydomain data to provide a time

    domain response of the

    network under test.

    Courtesy of Agilent

    Technologies.

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    Properties of S - Parameters

    a) Zero diagonal elements for perfectmatched network

    For an ideal N-port network with matchedtermination sii= 0 since there is no reflectionfrom any port

    so under perfect patched conditions thediagonal elements of [S] are zero

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    Properties .

    b) Symmetry of [S] for a reciprocal network

    A reciprocal device has the same

    transmission characteristics in eitherdirection of a pair of ports ischaracerized by a symmetric matrix

    Sij = Sji ( i not equal to j)

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    Properties

    c)Unitary property for a lossless junctionFor any lossless network the sum of theproducts of each term of any row or of any

    column of the S matrix multiplied by itsconjugate is unity

    If all

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    Phase shift property

    Device S

    1 1 2 2

    2221

    1211

    SS

    SSS

    Complex S-parameters of anetwork defined with respect tothe positions of the port orreference planes

    For unprimed reference planes the Sparameters havedefinite complex values

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    Phase shift property cont..

    222

    111

    l

    l

    Device S

    1 1 2 2

    If reference planes 1 and 2are shifted outward to 1and 2 by electrical phase

    shifts

    2

    1

    2

    1

    0

    0

    0

    0'

    j

    j

    j

    j

    e

    eS

    e

    eS

    The new S matrix is given by

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    Several Losses in Microwave

    circuits

    The losses in a microwave circuit can be

    expressed in terms of S-parameters

    Insertion Loss

    (dB)

    Pi = Power fed at Port 1; Pr = Power reflected at the same port

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    Losses

    Transmission Loss

    or Attenuation (dB)

    Reflection Loss

    (dB)

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    Losses ..

    Return Loss (dB)

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    S parameters for some microwave

    components

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    Wave guide sections

    01

    10S

    The S-Matrix for

    ideal sections are

    Examples of S matrices: 2-ports (1)

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    Bends

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    Adopters

    Between series adapter (WR-51 to WR-42)

    Waveguide to coax adapter

    (WR-62 to type N)

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    Flexguide (non-twistable)

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    Examples of S matrices: 2-ports (2)

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    Examples of S matrices: 2-ports (3)

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    S Matrix for Wave guide - Tees

    Wave guide tees are three port

    components. They are used to

    connect a branch or sections of the

    waveguide in series or parallel with

    the main waveguide transmission line

    for providing means of splitting andalso of combining power in a

    waveguide system

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    Two basic types of Tees

    E-plane T H-plane T

    S t f E l d H

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    S-parameters of E-plane and H-

    plane -T

    E-plane H-plane

    Because of the

    symmetry Sij = Sjij = 1.2

    332313

    231112

    131211

    SSS

    SSS

    SSS

    S

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    E l T

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    E-plane T

    S31 = S13= - S23 = -S32

    S12=S21

    ai = incident power

    bi = reflected power

    02/12/1

    2/12/12/1

    2/12/12/1

    2

    13

    2

    33 2)1( SS If S33 =0 ,S13 = 1/ 2

    I/p power =o/p power

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    H-plane Tee

    In a H-plane tee if two waves arefed into port 1 and port 2 of thecollinear arms the output wave atport 3 will be in phase andadditive.

    Reversely an input wave at port 3 will be equally divided into port1and port 2 in phase.

    02/12/1

    2/12/12/1

    2/12/12/1

    S

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    Hybrid -T

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    Cross guide couplers

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    Directional Coupler

    The coupling factor is defined as:

    http://en.wikipedia.org/wiki/Image:6-4ep2.gifhttp://en.wikipedia.org/wiki/Image:6-4ep2.gif
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    S-parameters of DC

    Insertion Loss (IL) = 10*log(P1/P2)=-

    20*log(S21)

    Coupling Factor (CF) = 10*log(P1/P4)=-

    20*log(S41)

    Isolation (I) = 10*log(P1/P3) = -20*log(S31)

    Directivity (D) = 10*log(P4/P3)=-

    20*log(S31/S41)

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    DC

    COUPLERS

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    COUPLERS

    0 1 1 0

    1 0 0 1.

    1 0 0 12

    0 1 1 0

    jS

    0 1 0

    0 0 111 0 02

    0 1 0

    ,

    j

    jSj

    j

    The quadrature hybrid (or branch-line hybrid) is

    a 3 dB coupler. The quadrature term comesfrom the 90 deg phase difference between the

    outputs at ports 2 and 3.

    The coupling and insertion loss are both equal

    to 3 dB.

    Ring hybrid (or rat-race) couplerQuadrature hybrid Coupler

    A microwave signal fed at port 1 will split evenly

    in both directions, giving identical signals out of

    ports 2 and 3. But the split signals are 180 deg

    out of phase at port 4, the isolated port, so they

    cancel and no power exits port 4.

    The insertion loss and coupling are both equal to

    3 dB. Not only can the ring hybrid split power to

    two ports, but it can add and subtract a pair of

    signals.

    Filters

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    Filters

    Filters are two-port networks used to attenuate undesirable frequencies.

    Microwave filters are commonly used in transceiver circuits.

    The four basic filter types are low-pass, high-pass, bandpass and bandstop.

    Low-pass High-pass

    BandstopBandpass

    Filters

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    A low-pass filter is characterized by the insertion loss

    versus frequency plot in Figure. Notice that there may

    be ripple in the passband (the frequency rangedesired to pass through the filter), and a roll offin

    transmission above the cutoff or corner frequency, fc.

    Simple filters (like series inductors or shunt capacitors)

    feature 20 dB/decade roll off. Sharper roll off is

    available using active filters or multisection filters.

    Active filters employ operational amplifiers that arelimited by performance to the lower RF frequencies.

    Multisection filters use passive components (inductors

    and capacitors), to achieve filtering.

    The two primary types are the Butterworth and the

    Chebyshev. A Butterworth filter has no ripple in the

    passband, while the Chebyshev filter features sharperroll off.

    Low-pass Filters

    Lumped Element Filters

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    Low-pass Filters

    High-pass Filters Band-pass Filters

    p

    Some simple lumped element filter circuits are shown below.

    Lumped Element Filters

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    Low-pass Filter Example

    p

    2

    ,l

    L

    o

    v

    PR

    .2

    o

    l s

    o

    R

    v vR j L

    20log 1 .2

    o

    j LIL

    R

    The 3 dB cutoff frequency, also termed the corner frequency, occurs where

    insertion loss reaches 3 dB.

    1,2

    o

    L

    R

    20log 1

    23

    o

    j L

    R

    3

    201 10 22

    o

    j L

    R

    .oc

    Rf

    L

    2

    2 22

    .4

    s

    l s

    A

    o o o

    v

    v vP

    R R R

    10log L

    A

    ILP

    P

    Power delivered to the load

    Insertion Loss

    Maximum available Power:

    Lumped Element Filters

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    Low-pass Filter Example

    Example 10.12: Let us design a low-pass filter for a 50.0 system using a

    series inductor. The 3 dB cutoff frequency is specified as 1.00 GHz.

    p

    .oc

    Rf

    L

    The 3 dB cutoff frequency is given by

    950

    15.9 .1 10 1

    oR H

    L nHf sx s

    Therefore, the required inductance value is

    Filters

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    The insertion loss for a bandpass filter is shown in

    Figure. Here the passband ripple is desired small.

    The sharpness of the filter response is given by theshape factor, SF, related to the filter bandwidth at 3dB

    and 60dB by

    60

    3

    .dB

    dB

    BWSF

    BW

    A filters insertion loss relates the power delivered to

    the load without the filter in place (PL) to the power

    delivered with the filter in place (PLf):

    10log .L

    Lf

    PIL

    P

    Band-pass Filters

    Amplifier Design

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    p g

    Microwave amplifiers are a common and crucial component of wireless transceivers.

    They are constructed around a microwave transistor from the field effect transistor

    (FET) or bipolar junction transistor (BJT) families.A general microwave amplifier can be represented by the 2-port S-matrix network

    between a pair of impedance-matching networks as shown in the Figure below. The

    matching networks are necessary to minimize reflections seen by the source and to

    maximize power to the output.

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    Example : Output Matching Network

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    Step 1: Plot the reflection coefficient

    Step 3:Intersection points on 1+jb Circle

    Step 4:Open-Circuited Stub Length

    Step 2: Find the Admittance yL

    Shunt Stub Problem:

    Admittance Calculation

    61876.0L

    L

    1

    2

    3

    4

    3

    4

    2 3 4

    Example : Input Matching Network234

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    Step 1: Plot the reflection coefficient

    Step 3:Intersection points on 1+jb Circle

    Step 4:Open-Circuited Stub Length

    Step 2: Find the Admittance ys

    1

    2

    3

    4Shunt Stub Problem:Admittance Calculation

    120.01 d

    5.311 jy

    206.01

    123872.0s

    S

    X

    Ignore

    Treat as a load

    234

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