5-1 business statistics chapter 5 discrete distributions
TRANSCRIPT
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5-1
Business Statistics
Chapter 5
DiscreteDistributions
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5-2
Learning Objectives
• Distinguish between discrete random variables and continuous random variables.
• Know how to determine the mean and variance of a discrete distribution.
• Identify the type of statistical experiments that can be described by the binomial distribution, and know how to work such problems.
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5-3
Learning Objectives -- Continued
• Decide when to use the Poisson distribution in analyzing statistical experiments, and know how to work such problems.
• Decide when binomial distribution problems can be approximated by the Poisson distribution, and know how to work such problems.
• Decide when to use the hypergeometric distribution, and know how to work such problems.
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5-4
Discrete vs Continuous Distributions• Random Variable -- a variable which contains
the outcomes of a chance experiment• Discrete Random Variable -- the set of all
possible values is at most a finite or a countably infinite number of possible values– Number of new subscribers to a magazine– Number of bad checks received by a restaurant– Number of absent employees on a given day
• Continuous Random Variable -- takes on values at every point over a given interval– Current Ratio of a motorcycle distributorship– Elapsed time between arrivals of bank customers– Percent of the labor force that is unemployed
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5-5
Some Special Distributions
• Discrete– binomial– Poisson– hypergeometric
• Continuous– normal– uniform– exponential– t– chi-square– F
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5-6
Discrete Distribution -- Example
012345
0.370.310.180.090.040.01
Number of Crises Probability
Distribution of Daily Crises
0
0.1
0.2
0.3
0.4
0.5
0 1 2 3 4 5
Probability
Number of Crises
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5-7
Requirements for a Discrete Probability Function
• Probabilities are between 0 and 1, inclusively
• Total of all probabilities equals 1
0 1 P X( ) for all X
P X( )over all x 1
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5-8
Requirements for a Discrete Probability Function -- Examples
X P(X)
-10123
.1
.2
.4
.2
.11.0
X P(X)
-10123
-.1.3.4.3.11.0
X P(X)
-10123
.1
.3
.4
.3
.11.2
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5-9
Mean of a Discrete Distribution
E X X P X( )
X
-10123
P(X)
.1
.2
.4
.2
.1
-.1.0.4.4.31.0
X P X ( )
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5-10
Variance and Standard Deviation of a Discrete Distribution
2.1)(22 XPX
212 110. .
X
-10123
P(X)
.1
.2
.4
.2
.1
-2-1012
X 41014
.4
.2
.0
.2
.41.2
)(2X
2( ) ( )X P X
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5-11
Binomial Distribution• Experiment involves n identical trials• Each trial has exactly two possible outcomes: success
and failure• Each trial is independent of the previous trials
p is the probability of a success on any one trialq = (1-p) is the probability of a failure on any one
trialp and q are constant throughout the experimentX is the number of successes in the n trials
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5-12
Binomial Distribution
• Probability function
• Mean value
• Variance and standard deviation
P Xn
X n XX n
X n Xp q( )!
! !
for 0
n p
2
2
n p q
n p q
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5-13
Binomial Table
n = 20 PROBABILITY
X 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9
0 0.122 0.012 0.001 0.000 0.000 0.000 0.000 0.000 0.0001 0.270 0.058 0.007 0.000 0.000 0.000 0.000 0.000 0.0002 0.285 0.137 0.028 0.003 0.000 0.000 0.000 0.000 0.0003 0.190 0.205 0.072 0.012 0.001 0.000 0.000 0.000 0.0004 0.090 0.218 0.130 0.035 0.005 0.000 0.000 0.000 0.0005 0.032 0.175 0.179 0.075 0.015 0.001 0.000 0.000 0.0006 0.009 0.109 0.192 0.124 0.037 0.005 0.000 0.000 0.0007 0.002 0.055 0.164 0.166 0.074 0.015 0.001 0.000 0.0008 0.000 0.022 0.114 0.180 0.120 0.035 0.004 0.000 0.0009 0.000 0.007 0.065 0.160 0.160 0.071 0.012 0.000 0.000
10 0.000 0.002 0.031 0.117 0.176 0.117 0.031 0.002 0.00011 0.000 0.000 0.012 0.071 0.160 0.160 0.065 0.007 0.00012 0.000 0.000 0.004 0.035 0.120 0.180 0.114 0.022 0.00013 0.000 0.000 0.001 0.015 0.074 0.166 0.164 0.055 0.00214 0.000 0.000 0.000 0.005 0.037 0.124 0.192 0.109 0.00915 0.000 0.000 0.000 0.001 0.015 0.075 0.179 0.175 0.03216 0.000 0.000 0.000 0.000 0.005 0.035 0.130 0.218 0.09017 0.000 0.000 0.000 0.000 0.001 0.012 0.072 0.205 0.19018 0.000 0.000 0.000 0.000 0.000 0.003 0.028 0.137 0.28519 0.000 0.000 0.000 0.000 0.000 0.000 0.007 0.058 0.27020 0.000 0.000 0.000 0.000 0.000 0.000 0.001 0.012 0.122
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5-14
Using the Binomial TableDemonstration Problem 5.4
n = 20 PROBABILITY
X 0.1 0.2 0.3 0.4
0 0.122 0.012 0.001 0.0001 0.270 0.058 0.007 0.0002 0.285 0.137 0.028 0.0033 0.190 0.205 0.072 0.0124 0.090 0.218 0.130 0.0355 0.032 0.175 0.179 0.0756 0.009 0.109 0.192 0.1247 0.002 0.055 0.164 0.1668 0.000 0.022 0.114 0.1809 0.000 0.007 0.065 0.160
10 0.000 0.002 0.031 0.11711 0.000 0.000 0.012 0.07112 0.000 0.000 0.004 0.03513 0.000 0.000 0.001 0.01514 0.000 0.000 0.000 0.00515 0.000 0.000 0.000 0.00116 0.000 0.000 0.000 0.00017 0.000 0.000 0.000 0.00018 0.000 0.000 0.000 0.00019 0.000 0.000 0.000 0.00020 0.000 0.000 0.000 0.000
n
p
P X C
20
40
10 0117120 1010 10
40 60
.
( ) .. .
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5-15
Binomial Distribution using Table: Demonstration Problem 5.3
n
p
q
P X P X P X P X
20
06
94
2 0 1 2
2901 3703 2246 8850
.
.
( ) ( ) ( ) ( )
. . . .
P X P X( ) ( ) . . 2 1 2 1 8850 1150
n p ( )(. ) .20 06 1 202
2
20 06 94 1 128
1 128 1 062
n p q ( )(. )(. ) .
. .
n = 20 PROBABILITYX 0.05 0.06 0.070 0.3585 0.2901 0.23421 0.3774 0.3703 0.35262 0.1887 0.2246 0.25213 0.0596 0.0860 0.11394 0.0133 0.0233 0.03645 0.0022 0.0048 0.00886 0.0003 0.0008 0.00177 0.0000 0.0001 0.00028 0.0000 0.0000 0.0000
… … …20 0.0000 0.0000 0.0000
…
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5-16
Excel’s Binomial Function
n = 20
p = 0.06
X P(X)
0 =BINOMDIST(A5,B$1,B$2,FALSE)
1 =BINOMDIST(A6,B$1,B$2,FALSE)
2 =BINOMDIST(A7,B$1,B$2,FALSE)
3 =BINOMDIST(A8,B$1,B$2,FALSE)
4 =BINOMDIST(A9,B$1,B$2,FALSE)
5 =BINOMDIST(A10,B$1,B$2,FALSE)
6 =BINOMDIST(A11,B$1,B$2,FALSE)
7 =BINOMDIST(A12,B$1,B$2,FALSE)
8 =BINOMDIST(A13,B$1,B$2,FALSE)
9 =BINOMDIST(A14,B$1,B$2,FALSE)
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5-17
Poisson Distribution
• Describes discrete occurrences over a continuum or interval
• A discrete distribution• Describes rare events• Each occurrence is independent any other
occurrences.• The number of occurrences in each interval
can vary from zero to infinity.• The expected number of occurrences must
hold constant throughout the experiment.
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5-18
Poisson Distribution: Applications
• Arrivals at queuing systems– airports -- people, airplanes, automobiles,
baggage– banks -- people, automobiles, loan applications– computer file servers -- read and write
operations• Defects in manufactured goods
– number of defects per 1,000 feet of extruded copper wire
– number of blemishes per square foot of painted surface
– number of errors per typed page
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5-19
Poisson Distribution
• Probability function
P XX
X
where
long run average
e
X e( )!
, , , ,...
:
. ...
for
(the base of natural logarithms )
0 1 2 3
2 718282
Mean valueMean value
Standard deviationStandard deviation VarianceVariance
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5-20
Poisson Distribution: Demonstration Problem 5.7
3 2
6 4
1010
0 05286 4
.
!
!.
.
customers / 4 minutes
X = 10 customers / 8 minutes
Adjusted
= . customers / 8 minutes
P(X) =
( = ) =
X
106.4
e
eX
P X
3 2
6 4
66
0 15866 4
.
!
!.
.
customers / 4 minutes
X = 6 customers / 8 minutes
Adjusted
= . customers / 8 minutes
P(X) =
( = ) =
X
66.4
e
eX
P X
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5-21
Poisson Distribution: Probability Table
X 0.5 1.5 1.6 3.0 3.2 6.4 6.5 7.0 8.00 0.6065 0.2231 0.2019 0.0498 0.0408 0.0017 0.0015 0.0009 0.00031 0.3033 0.3347 0.3230 0.1494 0.1304 0.0106 0.0098 0.0064 0.00272 0.0758 0.2510 0.2584 0.2240 0.2087 0.0340 0.0318 0.0223 0.01073 0.0126 0.1255 0.1378 0.2240 0.2226 0.0726 0.0688 0.0521 0.02864 0.0016 0.0471 0.0551 0.1680 0.1781 0.1162 0.1118 0.0912 0.05735 0.0002 0.0141 0.0176 0.1008 0.1140 0.1487 0.1454 0.1277 0.09166 0.0000 0.0035 0.0047 0.0504 0.0608 0.1586 0.1575 0.1490 0.12217 0.0000 0.0008 0.0011 0.0216 0.0278 0.1450 0.1462 0.1490 0.13968 0.0000 0.0001 0.0002 0.0081 0.0111 0.1160 0.1188 0.1304 0.13969 0.0000 0.0000 0.0000 0.0027 0.0040 0.0825 0.0858 0.1014 0.1241
10 0.0000 0.0000 0.0000 0.0008 0.0013 0.0528 0.0558 0.0710 0.099311 0.0000 0.0000 0.0000 0.0002 0.0004 0.0307 0.0330 0.0452 0.072212 0.0000 0.0000 0.0000 0.0001 0.0001 0.0164 0.0179 0.0263 0.048113 0.0000 0.0000 0.0000 0.0000 0.0000 0.0081 0.0089 0.0142 0.029614 0.0000 0.0000 0.0000 0.0000 0.0000 0.0037 0.0041 0.0071 0.016915 0.0000 0.0000 0.0000 0.0000 0.0000 0.0016 0.0018 0.0033 0.009016 0.0000 0.0000 0.0000 0.0000 0.0000 0.0006 0.0007 0.0014 0.004517 0.0000 0.0000 0.0000 0.0000 0.0000 0.0002 0.0003 0.0006 0.002118 0.0000 0.0000 0.0000 0.0000 0.0000 0.0001 0.0001 0.0002 0.0009
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5-22
Poisson Distribution: Using the Poisson Tables
X 0.5 1.5 1.6 3.00 0.6065 0.2231 0.2019 0.04981 0.3033 0.3347 0.3230 0.14942 0.0758 0.2510 0.2584 0.22403 0.0126 0.1255 0.1378 0.22404 0.0016 0.0471 0.0551 0.16805 0.0002 0.0141 0.0176 0.10086 0.0000 0.0035 0.0047 0.05047 0.0000 0.0008 0.0011 0.02168 0.0000 0.0001 0.0002 0.00819 0.0000 0.0000 0.0000 0.002710 0.0000 0.0000 0.0000 0.000811 0.0000 0.0000 0.0000 0.000212 0.0000 0.0000 0.0000 0.0001
1 6
4 0 0551
.
( ) .P X
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5-23
Poisson Distribution: Using the Poisson Tables
X 0.5 1.5 1.6 3.00 0.6065 0.2231 0.2019 0.04981 0.3033 0.3347 0.3230 0.14942 0.0758 0.2510 0.2584 0.22403 0.0126 0.1255 0.1378 0.22404 0.0016 0.0471 0.0551 0.16805 0.0002 0.0141 0.0176 0.10086 0.0000 0.0035 0.0047 0.05047 0.0000 0.0008 0.0011 0.02168 0.0000 0.0001 0.0002 0.00819 0.0000 0.0000 0.0000 0.002710 0.0000 0.0000 0.0000 0.000811 0.0000 0.0000 0.0000 0.000212 0.0000 0.0000 0.0000 0.0001
1 6
5 6 7 8 9
0047 0011 0002 0000 0060
.
( ) ( ) ( ) ( ) ( )
. . . . .
P X P X P X P X P X
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5-24
Poisson Distribution: Using the Poisson Tables
1 6
2 1 2 1 0 1
1 2019 3230 4751
.
( ) ( ) ( ) ( )
. . .
P X P X P X P X
X 0.5 1.5 1.6 3.00 0.6065 0.2231 0.2019 0.04981 0.3033 0.3347 0.3230 0.14942 0.0758 0.2510 0.2584 0.22403 0.0126 0.1255 0.1378 0.22404 0.0016 0.0471 0.0551 0.16805 0.0002 0.0141 0.0176 0.10086 0.0000 0.0035 0.0047 0.05047 0.0000 0.0008 0.0011 0.02168 0.0000 0.0001 0.0002 0.00819 0.0000 0.0000 0.0000 0.002710 0.0000 0.0000 0.0000 0.000811 0.0000 0.0000 0.0000 0.000212 0.0000 0.0000 0.0000 0.0001
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5-25
Poisson Distribution: Graphs
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
0 1 2 3 4 5 6 7 8
1 6.
0.00
0.02
0.04
0.06
0.08
0.10
0.12
0.14
0.16
0 2 4 6 8 10 12 14 16
6 5.
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5-26
Excel’s Poisson Function
= 1.6
X P(X)
0 =POISSON(D5,E$1,FALSE)
1 =POISSON(D6,E$1,FALSE)
2 =POISSON(D7,E$1,FALSE)
3 =POISSON(D8,E$1,FALSE)
4 =POISSON(D9,E$1,FALSE)
5 =POISSON(D10,E$1,FALSE)
6 =POISSON(D11,E$1,FALSE)
7 =POISSON(D12,E$1,FALSE)
8 =POISSON(D13,E$1,FALSE)
9 =POISSON(D14,E$1,FALSE)
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5-27
Poisson Approximation of the Binomial Distribution
• Binomial probabilities are difficult to calculate when n is large.
• Under certain conditions binomial probabilities may be approximated by Poisson probabilities.
• Poisson approximation
If and the approximation is acceptable.n n p 20 7,
Use n p.
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5-28
Poisson Approximation of the Binomial Distribution
X Error
0 0.2231 0.2181 -0.0051
1 0.3347 0.3372 0.0025
2 0.2510 0.2555 0.0045
3 0.1255 0.1264 0.0009
4 0.0471 0.0459 -0.0011
5 0.0141 0.0131 -0.0010
6 0.0035 0.0030 -0.0005
7 0.0008 0.0006 -0.0002
8 0.0001 0.0001 0.0000
9 0.0000 0.0000 0.0000
Poisson
1 5.
Binomial
n
p
50
03.X Error
0 0.0498 0.0498 0.0000
1 0.1494 0.1493 0.0000
2 0.2240 0.2241 0.0000
3 0.2240 0.2241 0.0000
4 0.1680 0.1681 0.0000
5 0.1008 0.1008 0.0000
6 0.0504 0.0504 0.0000
7 0.0216 0.0216 0.0000
8 0.0081 0.0081 0.0000
9 0.0027 0.0027 0.0000
10 0.0008 0.0008 0.0000
11 0.0002 0.0002 0.0000
12 0.0001 0.0001 0.0000
13 0.0000 0.0000 0.0000
Poisson
3 0.
Binomial
n
p
10 000
0003
,
.