8.2 integration by parts. start with the product rule:

11
8.2 Integration By Parts

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Page 1: 8.2 Integration By Parts. Start with the product rule:

8.2 Integration By Parts

Page 2: 8.2 Integration By Parts. Start with the product rule:

Start with the product rule:

d dv duuv u v

dx dx dx

d uv u dv v du

d uv v du u dv

u dv d uv v du

u dv d uv v du

u dv d uv v du

u dv uv v du

Page 3: 8.2 Integration By Parts. Start with the product rule:

u dv uv v du

The Integration by Parts formula is a “product rule” for integration.

u differentiates to zero (usually).

dv is easy to integrate.

Choose u in this order: LIPET

Logs, Inverse trig, Polynomial, Exponential, Trig

Integration by Parts

Page 4: 8.2 Integration By Parts. Start with the product rule:

cos x x dxpolynomial factor u x

du dx

cos dv x dx

sinv x

u dv uv v du LIPET

sin cosx x x C

u v v du

sin sin x x x dx

Example

Page 5: 8.2 Integration By Parts. Start with the product rule:

ln x dxlogarithmic factor lnu x

1du dx

x

dv dx

v x

u dv uv v du LIPET

lnx x x C

1ln x x x dx

x

u v v du

Example

Page 6: 8.2 Integration By Parts. Start with the product rule:

This is still a product, so we need to use integration by parts again.

2 xx e dx u dv uv v du LIPET 2u x xdv e dx

2 du x dx xv e

u v v du 2 2 x xx e e x dx 2 2 x xx e xe dx

u x xdv e dx

du dx xv e 2 2x x xx e xe e dx 2 2 2x x xx e xe e C

Example

Page 7: 8.2 Integration By Parts. Start with the product rule:

2 xx e dx & deriv.f x & integralsg x

2x

2x

2

0

xexexexe

2 xx e 2 xxe 2 xe C

Example

Page 8: 8.2 Integration By Parts. Start with the product rule:

Tabular integration works for integrals of the form:

f x g x dx

where: Differentiates to 0 in several steps.

Integrates repeatedly.

A Shortcut: Tabular Integration

3 sin x x dx3 cosx x 2 3 sinx x 6 cosx x 6sin x + C

Example:

3x

23x

6x

6

sin x

cos x

sin xcos x

0

sin x

Page 9: 8.2 Integration By Parts. Start with the product rule:

cos xe x dxxu e sin dv x dx

xdu e dx cosv x

u v v du sin sinx xe x x e dx

sin cos cos x x xe x e x x e dx

xu e cos dv x dx xdu e dx sinv x

sin cos cos x x xe x e x e x dx

This is the expression we started with!uv v du

cos xe x dx 2 cos sin cosx x xe x dx e x e x

sin coscos

2

x xx e x e xe x dx C

This is called “solving for the unknown integral.”

It works when both factors integrate and differentiate forever.

Example

Page 10: 8.2 Integration By Parts. Start with the product rule:

• Try to choose u so that du (its derivative) becomes easier to integrate than u. – If ln is present, then u must be ln.– Oftentimes, let u be the powers of x.

• Also, choose dv so that it is easy to integrate dv.– If ex is present, let dv = ex dx– Oftentimes, let dv be the sin or cos.

• After integrating by parts, you should wind up with the integral that is “easier” to integrate.

How to choose u and dv

Page 11: 8.2 Integration By Parts. Start with the product rule:

dxxx )2sin(

dxxx ln5 dxx)9arctan(

dxex x43

dxxe x sin25

1ln dtt

Examples