8.3 ratios in right triangles
DESCRIPTION
8.3 Ratios in Right Triangles. To find trig ratios using right triangles To solve problems using trig ratios. Background. A. hypotenuse. Adjacent. B. C. opposite. trigonometry- the word comes from 2 Greek words trigon-meaning triangle metron meaning measure. - PowerPoint PPT PresentationTRANSCRIPT
8.3 Ratios in Right Triangles
To find trig ratios using right triangles
To solve problems using trig ratios
trigonometry- the word comes from 2 Greek words trigon-meaning triangle
metron meaning measure.
Sinopposite
hypotenuse Cos
adjacent
hypotenuse Tan
opposite
adjacent
A ratio of the lengths of sides of a right triangle .
hypotenuse
A
BCA
djac
ent
opposite
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IN
pposi te
ypotenuse
OS
djacent
AN
ypotenuse
pposi te
djacent
Find sin A, cos A, tan A, sin B, cos B, and tan B. Express each ratio as a fraction and as a decimal
A
B
C 12
13
5
sin .A 5
130 385 cos .A
12
13923 tan .A
5
12417
sin .B 12
13923 cos .B
5
13385 tan .B
12
52 4
Find the value of each ratio to the nearest ten-thousandth
sin 7o = .1219 cos 30o = .8660
Find the measure of each angle to the nearest tenth degree
sin A = .7245
A = sin-1 .7245A = 46.4o
tan C = 9.4618
C = 84o
Find x
63o
20
x
determine the relationship between the given angle and the sides
sin6320
x
.891
1
20x
cross multiply
.891x = 20
solve for x
x = 22.45
Homework
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