Physics Ranking Tasks 9 Mechanics

Position Time Graphs—Displacement 8

In the position vs. time graphs below, all the times are in seconds (s), and all the positions are in meters(m). Rank these graphs on the basis of which graph indicates the greatest displacement from beginning toend of motion. Give the highest rank to the one(s) with the greatest displacement, and give the lowestrank to the one(s) indicating the least displacement. If two graphs indicate the same displacement, givethem the same rank. Note: Zero is greater than negative, and ties are possible.

t t t

x x x

t t t

x x x

30

3

5

10 5

5

10

2

308

10

A B C

D E F10

10 10

10

Greatest 1 2 3 4 5 6 Least

Or, none of these graphs indicate any displacement at all. ____________

Or, all of the displacements are the same. _____________

Please carefully explain your reasoning.

How sure were you of your ranking? (Circle one)Basically Guessed Sure Very Sure1 2 3 4 5 6 7 8 9 10

8 K. W. Nicholson

✓ ✓ ✓=⇒ E €85.MG?9o

C had displacement of IOM AD had displacement of 3m

ABF had Zero displacement IE0

Physics Ranking Tasks 11 Mechanics

Position Time Graphs—Average Speed 10

In the position vs. time graphs below, all the times are in seconds (s), and all the positions are in meters(m). Rank these graphs on the basis of which graph indicates the greatest average speed, where theaverage speed is calculated from the beginning to the end of motion. Give the highest rank to the one(s)with the greatest average speed, and give the lowest rank to the one(s) indicating the least average speed.If two graphs indicate the same average speed, give them the same rank.

t t t

x x x

t t t

x x x

30

3

5

10 5

5

10

2

308

10

A B C

D E F10

10 10

10

Greatest 1 2 3 4 5 6 Least

Or, none of these are moving at all. _____________

Or, the average speed is the same for all of these. ____________

Please carefully explain your reasoning.

How sure were you of your ranking? (circle one)Basically Guessed Sure Very Sure1 2 3 4 5 6 7 8 9 10

10 K. W. Nicholson

lmls' slope

Omls omls §

€50.345 3ns 1.6ms

E F C D AB

.

Pg . 30*9.

w <¥→E Nghthis positive

H

Giv= E = 2.90 mf. [ ST

I = - 2.90mW [n]E = 5.72 s

I = Omls

Required, (initial velocity)

Analysis : oi=TtISteps Isolate I

Et = is . I8

,= To it

Et =/,

at iii=v%# -8,

It Az = -8,

⇒at in =P,

Ba - Et Iv ,

0%- ( -2.90 ⇒[n](s⇒ If

0%+490 ;⇒[D(sm¥r,

0 Mls t 16.

588 m/s[Div

i. T ,= 16.6 m↳[N]

Pg.

30 # 5 .

v ,= 10 mls [ N]

✓ 2 = 10 mls [ S ]

constant speed?

T= Vz :

÷nls [ D . 10m1s[D

= 10m/s[s] - fund [§= 20ns [ s ]

Pg . 30*8Gilda

, 0.5343

Isig digsI :O .68§[n]it :O .89÷[D

Required time =t

Analysis k=I.¥Sleepy Isolate t

t=J-

t.0.am/sCf.O.68n1sfN=53m/s2[ N ]

t.ge#Edxt=o*

.

53 's

t = 0.396=

÷ 396 s

t = 0.40 s

Read pgs .31 - 35

Carefully go over

examples .