agenda lecture radicals 7.17.3 review quiz 9

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135 week 10..notebook March 29, 2017 AGENDA Lecture Radicals 7.17.3 Review Quiz 9 Radicals 3*3=9 square root of 9 is 3. number that if multiplied by itself you get the number inside the radical 9 =3 ALWAYS POSITIVE cubed root = number multiplied by itself 3 times 3 * 3* 3 = 27

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135 week 10..notebook March 29, 2017

AGENDA

Lecture Radicals 7.1­7.3

Review Quiz 9

Radicals3 * 3 = 9    square root of 9 is 3.

number that if multiplied by itself you get the number inside the radical

√ 9 = 3 ALWAYS POSITIVE

cubed root = number multiplied by itself 3 times   3 *  3* 3 = 27

135 week 10..notebook March 29, 2017

simpilfy 

135 week 10..notebook March 29, 2017

always positive AS IS

  could be negative!!!

not real!

=3

4

absolute value to the rescue

135 week 10..notebook March 29, 2017

no absolute value| 3 ­ y | need absolutes to be +

can't take the square root of a negative number!!!x­4 > 0 x > 4

­x + 5 > 0 x < 5

all numbers

x ­ 4 > 0 

135 week 10..notebook March 29, 2017

135 week 10..notebook March 29, 2017

135 week 10..notebook March 29, 2017

NO

135 week 10..notebook March 29, 2017

135 week 10..notebook March 29, 2017

135 week 10..notebook March 29, 2017

135 week 10..notebook March 29, 2017

135 week 10..notebook March 29, 2017

135 week 10..notebook March 29, 2017

F O I L

x ­ 2 conjugates

x                  + 18

F O I L

135 week 10..notebook March 29, 2017

sloppy is bad!

Review Quiz 9

135 week 10..notebook March 29, 2017

LCD:(u­2)(u­1)

6(u­2)(u­1)+5(u­1)=­2(u­2)

6(u2­3u+2)+5u­5=­2u+4

6u2­18u+12 +5u­5+2u­4=0

6u2 ­ 11u +3 =0

AC=18<

6u^2 ­9u ­2u +3

3u(2u­3) ­1(2u­3)

(3u ­ 1) ( 2u ­ 3) = 0