aim: factoring course: adv. alg. & trig. aim: renewing an old friendship some more –...

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Aim: Factoring Course: Adv. Alg. & Trig. Aim: Renewing an old friendship some more – factoring, Algebra! Again! Do Now: Factor: 2m 2 a + 4m 3 b - 2m 4 c 4x 2 – 25 a 2 – 8a + 7 2x 2 + 5x + 3 3x 2 - 6x - 24

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Aim: Factoring Course: Adv. Alg. & Trig.

Aim: Renewing an old friendship some more – factoring, Algebra! Again!

Do Now:

Factor: 2m2a + 4m3b - 2m4c4x2 – 25

a2 – 8a + 72x2 + 5x + 33x2 - 6x - 24

Aim: Factoring Course: Adv. Alg. & Trig.

Factoring: Greatest Common Factor

Factor by finding the greatest common factor: 2m2a + 4m3b - 2m4c

2m2(a + 2mb - m2c)

GCF - 2m2

General Rules for Factoring with GCF

•Find the greatest common monomial that is a factor of each term by:

•finding the greatest common factor of the coefficients•finding the greatest common factor for each of the variables

•Write the original expression as the product of the greatest common factor and the remaining polynomial

3

y2

3y2GCF

3 y2 (1 – 3y)=Factor: 3y2 – 9y3

Aim: Factoring Course: Adv. Alg. & Trig.

Factoring: Difference between Perfect Squares

-4x2 25

+ -2x 2x5 5

-x2 a2

+ -

1. Are both terms perfect squares?2. Are they subtracted?

x xa a

If yes, then in general terms:x2 - a2 = (x - a)(x + a)

Aim: Factoring Course: Adv. Alg. & Trig.

Factoring Trinomials a = 1

( )( )

F L

a2 - 8a + 7

a a 71 --

O

-7a

+I

-1a

-8a

Aim: Factoring Course: Adv. Alg. & Trig.

Factoring Trinomials a 1

Factor: 2x2 + 5x + 3What do you know?1. The product of 2 binomials

( )( )2. 1st Terms (2x )(x )

3. Last Terms ( 1)( 3)

4. Signs ( + )( + )

Possible Combinations:

(2x + 1)(x + 3) or (2x + 3)(x + 1)

1x

6x7x

3x

2x5x

5x = sum of O & IO

Aim: Factoring Course: Adv. Alg. & Trig.

Factor Completely

3x2 - 6x - 243(x2 - 2x - 8)

3(x - 4)(x + 2)

1. Find the GCF

2. Factor the trinomial

Aim: Factoring Course: Adv. Alg. & Trig.

Factoring - Perfect Cubes

Factoring Difference/Sum of Perfect Cubes

u3 – v3 = (u – v)(u2 + uv + v2)

u3 + v3 = (u + v)(u2 – uv + v2)

Factor:

x3 – 27

x9 + 125

x3 and -27 are perfect cubes:

-27 = (-3)3

u = x and v = (-3)

= (x – (-3))(x2 + x(-3) + (-3)2)

= (x + 3)(x2 – 3x + 9)

x9 and 125 are perfect cubes:

x9 = (x3)3

125 = 53

= (x3 + 5) ((x3)2 – x3(5) + 52)

= (x3 + 5)(x6 – 5x3 + 25)

u = x3 and v = 5

Aim: Factoring Course: Adv. Alg. & Trig.

Model Problems

1. 144 - d2

2. 9x2 - 16y2

3. x4 - y6

4. 8x2 - 8y2

(12 - d)(12 + d)

(9x - 4y)(9x + 4y)

(x2 - y3)(x2 + y3)

8(x - y)(x + y)

8(x2 - y2)

5. s8 - t4 (s4 - t2)(s4 + t2)

(s2 - t)(s2 + t)(s4 + t2)

Note: Check your factoring by multiplying the factors to come up with the original expression.

G.C.F.

Aim: Factoring Course: Adv. Alg. & Trig.

Model Problems

Factor Completely

1. 4a2 + a – 3

2. 8m3 - 1

3. r3 + 3r2 – 54r

4. 4x6 – 4x2

5. 5y5 + 135y2