alexis carulli ccb project
DESCRIPTION
Notch Regulation of Intestinal Crypt Dynamics. Alexis Carulli CCB Project. The Intestinal Crypt: Proliferative Zone. Transit-Amplifying Progenitor(TA). Notch?. Stem Cell. Experimental Observations. Hypothesis. Asymmetric Cell Division. 5 day Notch inhibition. 1 day Notch inhibition. - PowerPoint PPT PresentationTRANSCRIPT
Alexis CarulliCCB Project
Notch Regulation of Intestinal Crypt Dynamics
The Intestinal Crypt: Proliferative Zone
Transit-AmplifyingProgenitor(TA)
Stem CellNotch?
Experimental Observations HypothesisAsymmetric Cell Division
Symmetric Cell Division
Notch Inhibition
5 day Notch inhibition1 day Notch inhibition
Continuous Compartmental Model of Crypt Dynamics
α1
α2
α3
β1
β2
β3
γ
apoptosis apoptosis
renewal renewal
differentiation differentiation sloughing-off N0Stem
N1TA
N2Diff
WITH FEEDBACK: = (α3 – α1 – α2)N0 –
k0N20
1 + m0N0
dN0
dt
k0N20
1 + m0N0 = (β3 – β1 – β2)N1 –
k1N21
1 + m1N1
dN1
dt + α2N0 +
= – γN2 + β2N1 + k1N2
1 1 + m1N1
dN2
dt
Johnston et al. PNAS 2007
Continuous Compartmental Model of Crypt Dynamics
α1
α2
α3
β1
β2
β3
γ
apoptosis apoptosis
renewal renewal
differentiation differentiation sloughing-off N0Stem
N1TA
N2Diff
WITH FEEDBACK: = (α3 – α1 – α2)N0 –
k0N20
1 + m0N0
dN0
dt
k0N20
1 + m0N0 = (β3 – β1 – β2)N1 –
k1N21
1 + m1N1
dN1
dt + α2N0 +
= – γN2 + β2N1 + k1N2
1 1 + m1N1
dN2
dt
Johnston et al. PNAS 2007
Continuous Model: α2 and α3 analysis
1 day Notch inhibition 5 day Notch inhibition
α2 = 1α3 = 0
α2 = 3α3 = 0.586
Homeostatic rates: α2 = 0.3, α3 = 0.586
α2 = 5α3 = 0.001
N2
N0
N1
Continuous Compartmental Model of Crypt Dynamics
α1
α2
α3
β1
β2
β3
γ
apoptosis apoptosis
renewal renewal
differentiation differentiation sloughing-off N0Stem
N1TA
N2Diff
Even if N0=0 there is still a population of N1 and N2 cells:
Johnston et al. PNAS 2007
N2
N0
N1
Continuous Model: β3 analysisHomeostatic rate: β3 = 0.732
1 day Notch inhibition 5 day Notch inhibition
Β3 = 0α2 = 1α3 = 0.3
D(t+1) = D + 0.6T2 – γ
T1(t+1) = 3XS TT(t+1) = T1 + T2
T2(t+1) = 4T1
S(t+1) = S + (1-X)S + R
Discrete Compartmental Model of Crypt Dynamics
X
R
γ
ASSUMPTION: When crypt is in homeostasis, apoptosis is negligible in S and T compartments
renewal
differentiation amplification Sloughoff S
Stem T1TA
DDiff
T2TA
differentiation
X= Stem cell division symmetryX=0: completely symmetric, towards SX=1: completely asymmetric, equal S and TTX=2: completely symmetric, towards TT
Discrete Model: X analysis
X=0
X=1
X=2Maximum is 60% increased from TTi
NOTE: In my experiment I saw a 60% increase in proliferating cells after 1 day of Notch inhibition
S grows exponentially, TT crashes
Homeostasis
TTS
Discrete Model; x=1.5 1 day Notch inhibition 5 day Notch inhibition
No stem cell renewal
Constant stem cell renewal
Notch-dependent stem cell renewal
TTS
Discrete Model: Alternate hypothesis
Notch inhibition may result in stem cell apoptosis and the rebound stem cell overpopulation, without affecting differentiation rate of
STT
1 day Notch inhibition 5 day Notch inhibitionTTS
Stem cell loss
Stem cell rebound
Future Directions
X
R
γS
Stem T1TA
DDiff
T2TA
T3TA
T4TA
1) Test different permutations of amplification scheme
2) Design hybrid model- Neither discrete nor continuous is likely correct - Adapt discrete model to ODEs with feedback, but maintain dependence on S compartment
3) Do more experiments!- Check intermediate time points for proliferation drop
Thanks!Many thanks to the course instructors
(Especially Greg!) and the TAs.
It was great to meet all of you. Safe travels home and may you have many Science/Nature/Cell
publications in the future