allen 0 1 3 1 4 0 7 1 clas amme · (academ sessio 2014-2015) ... sd iz'u esa pkj fodyi (a),...

Ïi;k bu fun sZ'kks a dks /;ku ls i<+ sA vkidks 5 feuV fo'ks"k :i ls bl dke ds fy, fn;s x;s gS aAPlease read the instructions carefully. You are allotted 5 minutes specifically for this purpose.

A. lkekU; / General :1. ;g iqfLrdk vkidk iz'u&i= gSA bldh eqgj rc rd u rksM+s tc rd fujh{kd ds }kjk bldk funZs'k u fn;k tk;sA

This booklet is your Question Paper. Do not break the seal of this booklet before being instructed to do so by theinvigilator.

2. iz'u&i= dk dksM (CODE) bl i`"B ds Åijh nk;sa dkSus ij Nik gSAThe question paper CODE is printed on the right hand top corner of this sheet.

3. dPps dk;Z ds fy, [kkyh i`"B vkSj [kkyh LFkku bl iqfLrdk esa gh gSaA dPps dk;Z ds fy, dksbZ vfrfjDr dkxt ugha fn;k tk;sxkABlank spaces and blank pages are provided in the question paper for your rough work. No additional sheets willbe provided for rough work.

4. dksjs dkxt] fDyi cksMZ] ykWx rkfydk] LykbM :y] dSYdqysVj] dSejk] lsyQksu] istj vkSj fdlh Hkh izdkj ds bysDVªkWfud midj.k dhijh{kk d{k esa vuqefr ugha gSaABlank papers, clipboards, log tables, slide rules, calculators, cameras, cellular phones, pagers and electronicgadgets of any are NOT allowed inside the examination hall.

5. bl iqfLrdk ds fiNys i`"B ij fn, x, LFkku esa viuk uke vkSj QkWeZ uEcj fyf[k,AWrite your name and Form number in the space provided on the back cover of this booklet.

6. mÙkj i=] ,d ; a=&Js.khdj.k ;ksX; i= (ORS) gS tks fd vyx ls fn;s tk;saxsAThe answer sheet, a machine-readable Optical Response Sheet (ORS), is provided separately.

7. vks-vkj-,l-(ORS) ;k bl iqfLrdk esa gsj&Qsj@foÏfr u djsa / DO NOT TAMPER WITH/MUTILATE THE ORS OR THIS BOOKLET.8. bl iqfLrdk dh eqgj rksM+us ds i'pkr d`i;k tk¡p ysa fd blesa 48 i`"B gSa vkSj izR;sd fo"k; ds lHkh 21 iz'u vkSj muds mÙkj fodYi Bhd

ls i<+ s tk ldrs gSaA lHkh [kaMksa ds izkjEHk esa fn;s gq, funsZ'kksa dks /;ku ls i<+ sAOn breaking the seal of the booklet check that it contains 48 pages and all the 21 questions in each subject andcorresponding answer choices are legible. Read carefully the instructions printed at the beginning of each section.

B. vks-vkj-,l- (ORS) dk Hkjko / Filling the ORS :9. ijh{kkFkhZ dks gy fd;s x;s iz'u dk mÙkj ORS mÙkj iqfLrdk esa lgh LFkku ij dkys ckWy ikbUV dye ls mfpr xksys dks xgjk djds nsuk gSA

A candidate has to write his / her answers in the ORS sheet by darkening the appropriate bubble with the help ofBlack ball point pen as the correct answer(s) of the question attempted.

10. ORS ds (i`"B la[;k 1) ij ekaxh xbZ leLr tkudkjh /;ku iwoZd vo'; Hkjsa vkSj vius gLrk{kj djsaAWrite all information and sign in the box provied on part of the ORS (Page No. 1).

C. iz'ui= dk izk:i / Question Paper Formate :bl iz'u&i= ds rhu Hkkx (HkkSfrd foKku] jlk;u foKku vkSj xf.kr) gSaA gj Hkkx dk ,d [kaM gSaAThe question paper consists of 3 parts (Physics, Chemistry and Mathematics). Each part consists of one section.

11. [kaM–I / SECTION – I(i) Hkkx esa 8 cgqfodYi iz'u gSaA gj iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesa ls dsoy ,d lgh gSaA

Contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of whichONLY ONE is correct.

(ii) Hkkx esa 5 cgqfodYi iz'u gSaA gj iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesa ls ,d ;k vf/kd lgh gSaAContains 5 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of whichONE or MORE are correct.

(iii) Hkkx esa fl¼kUrksa] iz;ksxksa vkSj vk¡dM+ksa vkfn dks n'kkZus okys 2 vuqPNsn gSA nksuksa vuqPNsnksa ls lacfU/kr pkj iz'u gSaA ftuesa ls gjvuqPNsn ij nks iz'u gSaA fdlh Hkh vuqPNsn esa gj iz'u ds pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesa ls dsoy ,d lgh gSaAContains 2 paragraphs each describing theory, experiment, data etc. Four questions relate to two paragraphswith two questions on each paragraph. Each question of a paragraph has ONLY ONE correct answer amongthe four choices (A), (B), (C) and (D)

(iv) [kaM–I ds Hkkx esa 4 cgqfodYi iz'u gSaA izR;sd iz'u esa lqesyu lwpha gSA lwfp;ksa ds fy, dksM ds fodYi (A), (B), (C) vkSj(D) gSa ftuesa ls dsoy ,d lgh gSaAContains 4 multiple choice questions. Each question has matching lists. The codes for the lists have choices(A), (B), (C) and (D) out of which ONLY ONE is correct

funs Z'k / INSTRUCTIONS

Path to Success

ALLENCAREER INSTITUTEKOTA (RAJASTHAN)

CLASSROOM CONTACT PROGRAMME(ACADEMIC SESSION 2014-2015)

Ïi;k 'ks"k funs Z'kks a ds fy;s bl iqfLrdk ds vfUre i`"B dks i<+ sA / Please read the last page of this booklet for rest of the instructions

PAPER CODE 0 1 C T 3 1 4 0 7 1

DO N

OT B

REAK

THE

SEA

LS W

ITHO

UT B

EIN

G IN

STRU

CTED

TO

DO S

O BY

THE

INVI

GILA

TOR

\ fuj

h{kd

ds v

uqns'k

ksa ds fc

uk e

qgjsa u

rksM

+s

le; : 3 ?k.Vs egÙke vad : 204Time : 3 Hours Maximum Marks : 204

DATE : 09 - 04 - 2015ALLEN JEE (Advanced ) TEST

TARGET : JEE (Advanced) 2015 ENTHUSIAST & LEADER COURSE : SCORE

T M

isij – 2PAPER – 2

fo"k; [k.M i`"B la[;kSubject Section Page No.

Hkkx-1 HkkSfrd foKku I(i) dsoy ,d lgh fodYi izdkj 03 - 07Part-1 Physics Only One Options Correct Type

I(ii) ,d ;k vf/kd lgh fodYi izdkj 08 - 12One or More Options Correct Type

I(iii) vuqPNsn izdkj 13 - 15Paragraph Type

I(iv) lqesyu lwpha izdkj 16 - 21Matching List Type

Hkkx-2 jlk;u foKku I(i) dsoy ,d lgh fodYi izdkj 22 - 25Part-2 Chemistry Only One Options Correct Type




Hkkx-3 xf.kr I(i) dsoy ,d lgh fodYi izdkj 35 - 37Part-3 Mathematics Only One Options Correct Type




SOME USEFUL CONSTANTSAtomic No. H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16, Cl = 17,

Br = 35, Xe = 54, Ce = 58,Atomic masse s : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,

Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,Xe = 131, Ba=137, Ce = 140,

Kota/01CT3140712/48

Target : JEE (Advanced) 2015/09-04-2015/Paper-2

· Boltzmann constant k = 1.38 × 10–23 JK–1

· Coulomb's law constant pe9

0

1 = 9×104

· Universal gravitational constant G = 6.67259 × 10–11 N–m2 kg–2

· Speed of light in vacuum c = 3 × 108 ms–1

· Stefan–Boltzmann constant s = 5.67 × 10–8 Wm–2–K–4

· Wien's displacement law constant b = 2.89 × 10–3 m–K· Permeability of vacuum µ0 = 4p × 10–7 NA–2

· Permittivity of vacuum Î0 = 20

1

cm· Planck constant h = 6.63 × 10–34 J–s

Enthusiast & Leader Course/Score/09-04-2015/Paper-2

PHYS

ICS

3/48Kota/01CT314071

PART-1 : PHYSICS Hkkx-1 : HkkSfrd foKku

SECTION–I : (i) Only One options correct Type [k.M-I : (i) dsoy ,d lgh fodYi izdkj

This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONLY ONE is correct.

bl [k.M esa 8 cgqfodYi iz'u gSaA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa] ftuesa ls dsoy ,d

lgh gSA1. Suppose you are anchored near the shore of a channel in which there is steady current, and you are

going to run your (motor) boat at constant throttle to a dock directly across the channel on the oppositeshore. The way in which one might steer the boat to the dock is POINTING method. In pointingmethod keep the nose of the boat pointed directly at the dock. Velocity of boat with respect to water is‘v’ and velocity of water is ‘u’. Width of water channel is ‘b’. The time taken by boat to reach the dockis :-

dYiuk dhft;s fd vkius fdlh unh ds fdukjs ij vkidh cksV dks yaxj }kjk jksd j[kk gSA unh esa LFkk;h /kkjk cg jgh gS

rFkk vki unh ds ikj nwljs fdukjs ij fLFkr canjxkg ij viuh eksVj cksV ls fu;r rsth ls tkus dh rS;kjh dj jgs gSaA og

rjhdk ftlds }kjk vki uko dks canjxkg dh rjQ ys tk ldrs gS] POINTING fof/k dgykrh gSA bl fof/k esa uko dk

eqag lhèkk canjxkg dh rjQ bafxr gksrk gSA ikuh ds lkis{k uko dk osx ‘v’ gS rFkk ikuh dk osx ‘u’ gSA unh dh pkSM+kbZ ‘b’

gSA uko }kjk canjxkg rd igq¡pus esa yxk le; gksxk%&

(A) 2 2

bvv u-

(B) 2 2

bv u-

(C) 2

buv (D) 2

bvu

BEWARE OF NEGATIVE MARKINGHAVE CONTROL ¾® HAVE PATIENCE ¾® HAVE CONFIDENCE Þ 100% SUCCESS

Space for Rough Work / dPps dk;Z ds fy, LFkku

4/48

PHYS

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Kota/01CT314071


2. Four lamps are connected in the way shown in the figure. When switch S2 is open and switch S

1 is on

position -2, Lamp-b is the brightest, and lamp-c and lamp-d are the dimmest and are of the same brightness.Now S

2 is closed and S

1 is on position-1, the sequence in brightness of the lamps is _____, with the first

in the sequence being the brightest.

pkj ysEiksa dks fp=kuqlkj tksM+k tkrk gSA tc fLop S2 [kqyk gS rFkk fLop S

1 fLFkfr -2 ij gksrk gS rks ysEi-b lcls vf/kd

pedrk gS rFkk ysEi-c o ysEi-d leku ped ds lkFk lcls de pedrs gSaA vc S2 dks can dj nsrs gSa rFkk S

1 dks fLFkfr-

1 ij ys vkrs gSaA ;fn lokZf/kd pedus okys ysEi dks Øe esa izFke LFkku ij j[kk tk, rks bu ysEiksa dks budh ped ds vk/

kkj ij O;ofLFkr dhft,A

c

da

bS2

S1

21

(A) c, d, b, a (B) a, d, b, c (C) a, b, c, d (D) a, d,c, b3. Three identical small electric dipoles are arranged parallel to each other at equal separation a as shown

in the figure. Their total interaction energy is U. Now one of the end dipole is gradually reversed, howmuch work is done by the electric forces.

rhu leku NksVs oS|qr f}/kqzoksa dks fp=kuqlkj ,d nwljs ds lekUrj leku nwjh a ij j[kk x;k gSA mudh dqy vU;ksU; ÅtkZ U

gSA vc fdukjs okys fdlh ,d f}/kqzo dks /khjs ls ?kqekdj foijhr fd;k tkrk gS rks fo|qr cyksa }kjk dqy fdruk dk;Z fd;k

x;k\

a a

+ + +

(A) 17U

8(B)

16U

17(C)

16U

8(D)

18U

17


PHYS

ICS

5/48Kota/01CT314071


4. A smooth insulating ring of radius R, with a bead having charge q is placed horizontally and in a

uniform magnetic field of strength B0 and perpendicular to the ring plane. Starting from t = 0, the

magnetic field is changed to B (t) = B0 + at, where a is a positive constant. The contact force between

the ring and bead as a function of time is (Neglect gravity)

f=T;k R okyh ,d fpduh dqpkyd oy; esa ,d eksrh yxk gqvk gS rFkk bl eksrh ij vkos'k q fo|eku gSA bl oy; dks

ry ds yEcor~ fLFkr lkeF;Z B0 okys le:i pqEcdh; {ks= esa {kSfrt :i ls j[kk x;k gSA t = 0 ls izkjEHk djds pqEcdh;

{ks= dks B (t) = B0 + at rd ifjofrZr fd;k tkrk gS tgk¡ a /kukRed fu;rkad gSA le; ds Qyu ds :i esa oy; rFkk

eksrh ds e/; lEidZ cy gksxk%& (xq:Ro dks ux.; ekus)

(A) ( )2

0q Rt 2B tm

a+ a (B) ( )

2

0q Rt 2B t4m

a+ a (C) ( )

2

0q Rt B t4m

a+ a (D) ( )

2

04 q Rt 2B t

ma

+ a

5. Sound waves of frequency 320Hz are sent into the top of a vertical tube containing water at a level that

can be adjusted. Standing waves are produced at two successive water levels 44cm and 74cm from

open end. The distance of nearest displacement antinode from open end (in cm) is.

vkofr 320Hz okyh /ofu rjaxksa dks ,d Å/okZ/kj uyh ds 'kh"kZ ls uyh esa Hkstk tkrk gSA bl uyh esa Hkjs ikuh ds Lrj dks

O;ofLFkr fd;k tk ldrk gSA vizxkeh rjaxs uyh ds [kqys fljs ls nks Øekxr ty Lrjksa 44cm rFkk 74cm ij mRiUu gksrh

gSA [kqys fljs ls fudVre foLFkkiu izLian dh nwjh (cm esa) gksxh%&

water

44cm

74cm

(A) 1 (B) 2 (C) 3 (D) 4

6/48

PHYS

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Kota/01CT314071

6. A bulb hangs from a bracket whose three arms each have one end fixed in the wall, the other ends

meeting at a point. The two upper arms form an isosceles triangle with an angle of 60º between the arms.

The plane of this triangle is at right angles to the third arm, which makes an angle of 30º with the wall.

The bulb and shade weight 1N. The force in the arm AC is :-

,d cYc dks cszdsV ls yVdk;k x;k gSA czsdsV dh rhuksa Hkqtkvksa esa ls izR;sd dk ,d&,d fljk nhokj esa fLFkj gS rFkk nwljs

fljs ,d fcUnq ij vkdj feyrs gSA Åij dh nks Hkqtk;sa ,d lef¼ckgq f=Hkqt cukrh gS rFkk buds e/; 60º dk dks.k gSA

bl f=Hkqt dk ry rhljh Hkqtk ds lkFk ledks.k ij gS] tks fd nhokj ds lkFk 30º dk dks.k cukrh gSA cYc rFkk mlds 'ksM

dk Hkkj 1N gSA Hkqtk AC esa cy gksxk%&

(A) 3 2 N (B) 1 N

2 3 (C) 1 N

3 2 (D) 2 3 N



PHYS

ICS

7/48Kota/01CT314071

7. A spherical black body of radius r at absolute temperature T is surrounded by a thin spherical andconcentric shell of radius R, black on both sides. The factor by which this radiation shield reduces therate of cooling of the body (consider space between spheres evacuated, with no thermal conductionlosses) is given by the following expression : aR2/(R2 + br2). a and b are numerical coefficient. The ratio

ab is :-

ije rki T ij f=T;k r dk ,d xksyh; d`".k fi.M] f=T;k R ds ,d irys xksyh; rFkk ladsUnzh; dks'k ds }kjk pkjksa vksj

ls f?kjk gqvk gS rFkk ;g nksuksa vksj ls dkyk iqrk gqvk gSA bl fofdj.k ifjj{k.k }kjk fi.M ds 'khryu dh nj O;atd

aR2/(R2 + br2) }kjk fn;s tkus okys ?kVd }kjk ?kVrh tkrh gSA xksyksa ds chp dk LFkku fuokZfrr gS] rFkk rkih; pkyu ds

dkj.k Å"ek gkfu ugah gksrh gSA a o b la[;kRed xq.kkad gSaA vuqikr ab gS %&

(A)1 (B) 2 (C) 3 (D) 48. From a point P located at height H above inclined plane, beads are released in all possible directions

along frictionless wires. One of the beads reaches the incline in minimum time . The minimum time is :-

fdlh urry ds Åij H Å¡pkbZ ij fLFkr fcUnq P ls d.kksa dks ?k"kZ.k jfgr rkjksa ds vuqfn'k lHkh laHkkfor fn'kkvksa esa

fojkekoLFkk ls NksM+k tkrk gSA buesa ls ,d d.k urry rd U;wure le; esa igq¡prk gSA U;wure le; gS%&///////////////////////////////////

P

(A) sec 2aæ ö

ç ÷è ø

2H cosg

a(B) sec 2

aæ öç ÷è ø

2Hg

(C) 2H cos

ga

(D)2Hg


8/48

PHYS

ICS


Kota/01CT314071

(ii) One or more options correct Type

(ii) ,d ;k vf/kd lgh fodYi izdkjThis section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) and

(D) out of which ONE or MORE are correct.

bl [k.M esa 5 cgqfodYi iz'u gSaA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa] ftuesa ls ,d ;k

vf/kd lgh gSA

9. An electron typically spends about 10–8 s in an excited state before it drops to a lower state by emittinga photon. An electron is in n = 2 Bohr orbit :-(A) Number of revolutions made by an electron in n = 2 Bohr orbit in 10–8 s (to the nearest integer) is

8 × 106

(B) Frequency of photon emitted when an electron in an n = 2 orbit drops to n = 1 orbit (to the nearestinteger) is 3 × 1015 Hz

(C) The de-Broglie wavelength associated with an electron in n = 2 orbit is equal to the circumferenceof that orbit

(D) The angular momentum of an electron in n = 2 orbit (to the nearest integer) is 2 × 10–34 kg m2/s

,d bysDVªkWu QksVksu ds mRltZu }kjk fuEurj d{kk esa fxjus ls iwoZ fdlh mÙksftr voLFkk esa yxHkx 10–8 s rd jgrk gSA

,d bysDVªkWu n = 2 cksgj d{kk esa gS %&

(A) n = 2 cksgj d{kk esa bysDVªkWu }kjk 10–8 s esa yxk;s x;s pDdjksa dh la[;k (yxHkx fudVre iw.kk±d esa) 8 × 106

gksxhA

(B) tc n = 2 d{kk esa fLFkr bysDVªkWu n = 1 d{kk esa dwnrk gS rks mRlftZr gq, QksVksu dh vkofÙk (yxHkx fudVre iw.kk±d

esa)3 × 1015 Hz gksxhA

(C) n = 2 d{kk esa fLFkr bysDVªkWu ls lEcfU/kr Mh&czksXyh rjaxnS/; Z ml d{kk dh ifjf/k ds rqY; gksxhA

(D) n = 2 d{kk esa bysDVªkWu dk dks.kh; laosx (yxHkx fudVre iw.kk±d esa) 2 × 10–34 kg m2/s gksxkA



PHYS

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9/48Kota/01CT314071

10. As shown, a uniform block of mass m and with equilateral triangular cross-section (side l) is placed atthe edge of a step on a car floor which is under constant acceleration a (< g) to the right. A horizontal

force on the apex of the triangle Fr

is large enough to just tilt the block

(A) Force F is m(g a)

3+

(B) Contact force at A in horizontal direction is m2 (g – a)

(C) Contact force at A in vertical direction is mg(D) Moment of inertia of triangular block about an axis through A & perpendicular to the cross section

of block is 25 m

12l

fp= esa æO;eku m rFkk leckgq f=Hkqtkdkj vuqizLFkdkV (Hkqtk l) okyk ,d le:i CykWd fdlh dkj ds Q'kZ ij fLFkr

,d lh<+h ds fdukjs ij j[kk gqvk gSA ;g dkj nka;h vksj fu;r Roj.k a (< g) ls xfr'khy gSA bl f=Hkqt ds 'kh"kZ ij ,d

{kSfrt cy Fr

yxk;k tkrk gS tks bruk i;kZIr gS fd ;g CykWd iyV tk;s%&

(A) cy F dk eku m(g a)

3+

gSA

(B) {kSfrt fn'kk esa A ij lEidZ cy dk eku m2 (g – a) gSA

(C) Å/okZ/kj fn'kk esa A ij lEidZ cy dk eku mg gSA

(D) CykWd ds vuqizLFkdkV ds yEcor~ rFkk A ls xqtjus okyh v{k ds lkis{k f=Hkqtkdkj CykWd dk tM+Ro vk?kw.kZ

25 m12

l gSA


10/48

PHYS

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Kota/01CT314071

11. In an experiment to determine the Young’s modulus of a metal, two identical wires are suspended usinga vernier arrangement as shown in figure. The left wire is held taut with a fixed mass. Different loadscan be applied to the right wire and stretching of the wire can be measured by using the vernier scaleattached to the wire on right. The test wire has a length of 2.2 m between support and vernier and auniform diameter of 0.42 mm. Take g = 10ms–2 and give your answer in appropriate significant digits.(A) The strain produced in the wire is 0.0010(B) The Young’s modulus of the material is 1.4 × 1011 Nm–2

(C) If the wire is loaded statically, then the increase in internal energy of the wire is 0.022 J(D) If the wire is loaded statically, then the increase in internal energy of the wire is 0.22 J

1010

00

0 0

1 1

cm cm

0kg2kg

Vernier

fdlh /kkrq dk ;ax izR;kLFkrk xq.kkad Kkr djus ds fy;s fd;s x;s ,d iz;ksx esa nks ,dleku rkjksa dks fp=kuqlkj ofuZ;j

O;oLFkk }kjk yVdk;k x;k gSA ck¡;s rkj dks ,d fLFkj æO;eku dh lgk;rk ls ruk gqvk j[kk x;k gSA nka;s rkj ij fofHkUu

Hkkj yxk;s tk ldrs gS rFkk rkj ds foLrkj dks nk¡;h vksj rkj ls tqM+s ofuZ;j iSekus ds mi;ksx }kjk ekik tk ldrk gSA vkèkkj

rFkk ofuZ;j ds e/; yxs ijh{k.k rkj dh yEckbZ 2.2 m gS rFkk bl rkj dk le:i O;kl 0.42 mm gSA

g = 10ms–2 yhft;s rFkk vius mÙkj dks mi;qZDr lkFkZd vadks esa nhft;sA

(A) rkj esa mRiUu fodfr 0.0010 gSA

(B) inkFkZ dk ;ax izR;kLFkrk xq.kkad 1.4 × 1011 Nm–2 gSA

(C) ;fn rkj dks LFkk;h :i ls Hkkfjr (loaded) dj fn;k tkrk gS rks rkj dh vkarfjd ÅtkZ esa o`f¼ 0.022 J gksxhA

(D) ;fn rkj dks LFkk;h :i ls Hkkfjr (loaded) dj fn;k tkrk gS rks rkj dh vkarfjd ÅtkZ esa o`f¼ 0.22 J gksxhASpace for Rough Work / dPps dk;Z ds fy, LFkku


PHYS

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11/48Kota/01CT314071

12. In the circuit shown, switch S is first pushed up to charge the capacitor. Swtich S is then pushed down.(A) Maximum value of energy stored in the inductor is 250 × 10–6 J(B) Maximum value of energy stored in the capacitor is 250 × 10–6 J(C) Maximum current in the circuit is 100 mA(D) Maximum charge on the capacitor is 5 µC

10V

S

50mH

iznf'kZr ifjiFk esa la/kkfj= dks vkosf'kr djus ds fy;s fLop S dks igys Åij dh vksj nck;k tkrk gSA vc fLop S dks

uhps dh vksj nck;k tkrk gSA

(A) izsjd dq.Myh esa lafpr ÅtkZ dk vf/kdre eku 250 × 10–6 J gSA

(B) la/kkfj= esa lafpr ÅtkZ dk vf/kdre eku 250 × 10–6 J gSA

(C) ifjiFk esa vf/kdre /kkjk 100 mA gSA

(D) la/kkfj= ij vf/kdre vkos'k 5 µC gSASpace for Rough Work / dPps dk;Z ds fy, LFkku

12/48

PHYS

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Kota/01CT314071

13. A massless frame is present in uniform magnetic field and a block of mass m hangs on the frame as

shown in figure. When a constant current I > mg

Bl is mantained in the frame, it gets displaced by ‘h’ in

some time interval. If e is the emf of battery then which of the following is/are CORRECT ?(A) Work done by magnetic force is IlBh(B) Work done by battery is IlBh

(C) Velocity of block when it gets displacement by h is 2(I B mg)h

m-l

(D) Force on charges in the segment PQ while the frame moves up is in the vertical direction

m

masslessframe

Imagneticfield (B)

× × × ×

× × ×× × × ×× × × ×

P Q

S R

,d æO;ekughu Ýse le:i pqEcdh; {ks= esa mifLFkr gS rFkk m æO;eku okyk ,d CykWd fp=kuqlkj Ýse ij yVdk gqvk

gSA tc ,d fu;r /kkjk I > mg

Bl dks Ýse esa izokfgr fd;k tkrk gS rks Ýse dqN le;kUrjky esa ‘h’ nwjh rd foLFkkfir gks

tkrk gSSA ;fn e cSVjh dk fo|qr okgd cy gS rks fuEu esa ls dkSulk@dkSuls dFku lgh gS\(A) pqEcdh; cy }kjk fd;k x;k dk;Z IlBh gkssxkA(B) cSVjh }kjk fd;k x;k dk;Z IlBh gksxkA

(C) tc CykWd h nwjh rd foLFkkfir gks tkrk gS rks CykWd dk osx 2(I B mg)h

m-l

gksxkA

(D) tc Ýse Åij dh vksj xfr djrk gS rks Hkkx PQ esa vkos'kksa ij cy Å/okZ/kj fn'kk esa yxrk gS



PHYS

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13/48Kota/01CT314071

(iii) Paragraph Type

(iii) vuqPNsn izdkjThis section contains 2 paragraphs each describing theory, experiment, data etc. Four questions relateto two paragraphs with two questions on each paragraph. Each question of a paragraph has only onecorrect answer among the four choices (A), (B), (C) and (D).bl [k.M esa fl¼kUrksa] iz;ksxksa vkSj vk¡dM+ksa vkfn dks n'kkZus okys 2 vuqPNsn gSA nksuksa vuqPNsn ls lacaf/kr pkj iz'ugSa] ftuesa ls gj vuqPNsn ij nks iz'u gSaA vuqPNsn esa gj iz'u ds pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesals dsoy ,d lgh gSA

Paragraph for Questions 14 and 15iz'u 14 ,oa 15 ds fy;s vuqPNsn

A rocket is launched from point A on earth. It reaches point B on earth with its velocity antiparallel to itsinitial velocity. The angle subtended by straight line joining AB at the center is 2q. The satellite movingclose to surface of earth has time period of revolution T

0. Radius of earth is R.

,d jkWdsV dks i`Foh ij fLFkr fcUnq A ls iz{ksfir fd;k tkrk gSA ;g vius izkjfEHkd osx ds izfrlekUrj osx ls i`Foh ij

fLFkr fcUnq B ij igq¡prk gSA AB dks tksM+us okyh ljy js[kk }kjk dsUæ ij varfjr dks.k 2q gSA i`Foh dh lrg ds utnhd

xfr dj jgs mixzg dk ifjØe.k dky T0 gSA i`Foh dh f=T;k R gSA

14. The time of flight of the rocket is :-jkWdsV dk mMM~;u dky gksxk%&

(A) 0T2 (B) 0

1 3T2 2

æ ö+ç ÷ç ÷

è ø(C) 0

1 1T2 2

æ ö+ç ÷pè ø(D) 0

1 3T2 2

æ ö+ç ÷ç ÷pè ø

15. Maximum height attained by the rocket is :-jkWdsV }kjk izkIr dh xbZ vf/kdre Å¡pkbZ gksxh%&

(A) R (B) R2 (C)

R 32

(D) 3R


14/48

PHYS

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Kota/01CT314071

Paragraph for Questions 16 and 17

iz'u 16 ,oa 17 ds fy;s vuqPNsn

A student wants to find the specific heat of a dark oil. She pours 100 grams of the oil into a glass beakerof negligible mass, and then submerges a small 50 watt light bulb in the oil. Before the student turns onthe light bulb, the oil is 20ºC, room temperature. The student then seals the top of the beaker and turnson the light bulb, at time t = 0. She can see some light coming from the bulb, though it looks muchdimmer than usual. A small magnetic stirrer ensures that the oil has a uniform temperature throughoutthe beaker, at all times. A thermometer keeps track of the oil’s temperatue. After the light bulb has beenon for 40 seconds, the student switches it off. The oil’s temperature at that moment is 30ºC. The studentimmediately unseals the top of the beaker and removes the light bulb. When the top of the beaker issealed, assume that negligible heat is absorbed by the beaker or escapes into the environment.

,d fo|kFkhZ rsy (dark oil) dh fof'k"V Å"ek Kkr djuk pkgrh gSA og ux .; æO;eku okys ,d dk¡p ds chdj esa

100 xzke rsy Mkyrh gS rFkk fQj rsy esa ,d NksVk 50 okWV dk izdk'k cYc Mwcksrh gSA cYc dks pkyw djus ls igys rsy

20ºC (dejs ds rki) ij gSA vc fo|kFkhZ chdj ds Åijh fljs dks lhyc¼ dj nsrh gS rFkk t = 0 ij cYc dks pkyw djrh

gSA og cYc ls vk jgs dqN izdk'k dks ns[k ldrh gS] tks fd lkekU; izdk'k dh rqyuk esa cgqr vf/kd ean gSA ,d NksVk

pqEcdh; foMksyd ;g lqfuf'pr djrk gS fd rsy chdj eas lnSo ,dleku rki ij jgsA ,d rkiekih rsy ds rki dks ntZ

djrk jgrk gSA cYc ds 40 lsd.M rd pkyw jgus ds i'pkr~ fo|kFkhZ bls can dj nsrh gSA ml le; rsy dk rki 30ºC

gSA vc fo|kFkhZ rqjUr chdj ds Åijh fljs dks [kksyrh gS rFkk cYc dks ckgj fudky ysrh gSA tc chdj dk Åijh fljk

lhyc¼ fd;k tkrk gS rks ;g ekfu;s fd chdj }kjk ux.; Å"ek vo'kksf"kr dh tkrh gS vFkok ifjos'k esa iykf;r gksrh gSA

to electricaloutlet

light bulb

stirrer

thermomenter



PHYS

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15/48Kota/01CT314071

16. Which of these graphs best shows the temperature of the oil as a function of time?

le; ds Qyu ds :i esa rsy ds rki dks fuEu esa ls dkSulk vkjs[k Js"B rjhds ls iznf'kZr djrk gS\

(A)

time(s)

temperature

30

(B)

time(s)

temperature

30

(C)

time(s)

temperature

30

(D)

time(s)

temperature

30

17. Starting again from room temperature, the experiment is repeated. But this time, the student uses a100watt light bulb, and leaves it on for 60 seconds. The temperature of the oil after those 60 seconds willbe about :-

iqu% dejs ds rki ls izkjEHk djds iz;ksx dks nksgjk;k tkrk gSA ijUrq bl le; fo|kFkhZ 100 okWV ds cYc dk iz;ksx djrh gS

rFkk cYc dks 60 lsd.M ds fy;s pkyw NksM + nsrh gSA mu 60 lsd.Mksa ds i'pkr~ rsy dk rki yxHkx gksxk%&(A) 40ºC (B) 50ºC (C) 60ºC (D) 90ºC


16/48

PHYS

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Kota/01CT314071

(iv) Matching List Type (iv) lqesyu lwpha izdkj

This Section contains 4 multiple choice questions. Each question has matching lists. The codes for the

lists. have choices (A), (B), (C) and (D) out of which ONLY ONE is correct.

bl [k.M esa 4 cgqfodYi iz'u gSaA izR;sd iz'u esa lqesyu lwpha gSA lwfp;ksa ds fy, dksM ds fodYi (A), (B), (C) vkSj (D)

gSa ftuesa ls dsoy ,d lgh gSA

18. A block slides down a smooth inclined plane & then moves on to a rough horizontal surface.List-I gives quantities related to block. List-II gives corresponding graphs of physical quantities versustime :-

,d CykWd fpdus urry ij uhps dh vksj xfr djrk gS rFkk fQj ,d [kqjnjh {kSfrt lrg ij xfr djrk gSA lwph-I esa

CykWd ls lEcfU/kr jkf'k;k¡ nh x;h gSA lwph-II esa HkkSfrd jkf'k;ksa rFkk le; ds e/; laxr vkjs[k n'kkZ;s x;s gS%&

List-I/lwph-I List-II/lwph-II

(P) Velocity (osx) (1) time

(Q) Acceleration (Roj.k) (2) time

(R) Mechanical energy (;kaf=d ÅtkZ) (3) time

(S) Kinetic energy (xfrt ÅtkZ) (4) time

Codes/dwV :P Q R S

(A) 1 2 3 4(B) 4 3 2 1(C) 2 3 1 4(D) 3 2 4 1



PHYS

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17/48Kota/01CT314071

19. List-I shows different configurations of charge distribution. List-II gives the corresponding expressionsof physical quantities mentioned in list-I :-

List-I List-II

(P) (1)26kq

R

Four point charges are kept at the vertices of a regular tetrahedronof side R.Total electrostatics energy of the configuration.

(Q) (2)26kq 9

R 40æ öç ÷è ø

Two thin spherical uniformly charged shells having charge q areseparated by distance 4R. Total electrostatics energy of the configuration.

(R) (3)26kq

6R

A solid non-conducting sphere of radius R having uniform charge qis kept inside a thin spherical non-conducting shell of radius 2Rhaving uniform charge q. Total electrostatics energy of the configuration.

(S) (4) 26kq (3)

40R

Work done in contracting the sphere having uniform chargeq from radius 4R to R

Codes :P Q R S

(A) 1 3 4 2(B) 4 2 3 1(C) 3 2 1 4(D) 1 3 2 4


18/48

PHYS

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Kota/01CT314071

19. lwph-I esa vkos'k forj.k ds fofHkUu foU;kl n'kkZ;s x;s gSA lwph-II esa HkkSfrd jkf'k;ksa ds laxr O;atd fn;s x;s gS%&lwph-I lwph-II

(P) (1)26kq

R

pkj fcUnq vkos'k Hkqtk R ds ,d leprq"Qyd ds 'kh"kks± ij j[ks x;s gSAbl foU;kl dh dqy fLFkjoS|qr ÅtkZ gS

(Q) (2)26kq 9

R 40æ öç ÷è ø

vkos'k q okys nks irys xksyh; ,dleku vkosf'kr dks'k nwjh 4R }kjk i`Fkd gSAbl foU;kl dh dqy fLFkjoS|qr ÅtkZ gS

(R) (3)26kq

6R

f=T;k R rFkk le:i vkos'k q okys ,d Bksl vpkydh; xksys dks] f=T;k 2R

rFkk le:i vkos'k q ds irys vpkydh; xksyh; dks'k ds vUnj j[kk x;k gSAbl foU;kl dh dqy fLFkjoS|qr ÅtkZ gS

(S) (4) 26kq (3)

40R

,dleku vkos'k q okys xksys dks f=T;k 4R ls R rd ladqfpr djus esafd;k x;k dk;Z gksxk

dwV :P Q R S

(A) 1 3 4 2(B) 4 2 3 1(C) 3 2 1 4(D) 1 3 2 4



PHYS

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19/48Kota/01CT314071

20. List-I gives different lens configurations. The radius of curvature of each surface is R. Rays of lightparallel to the axis of lens from left of lens traversing through the lens get focused at distance f from thelens. List-II gives corresponding values of magnitudes of f (m represent refractive index) :-lwph-I esa fofHkUu ySal foU;kl fn;s x;s gSA izR;sd lrg dh oØrk f=T;k R gSA ySal dh cka;h vksj ls ySal ds v{k dslekUrj izdk'k fdj.ksa ySal ls xqtjus ds i'pkr~] ySal ls nwjh f ij Qksdflr gksrh gSA lwph-II, f ds ifjek.k ds laxr ekuksadks n'kkZrh gSA (m viorZukad gS):-


(P) (1) 13 R

(Q) (2)13R

4

Lens is silvered (ySal jtfrr gS)

(R) (3)7R3

Plano concave lens (leryksory ySal)

(S) (4)7R16

Codes/dwV :P Q R S

(A) 1 3 2 4(B) 1 2 3 4(C) 2 3 4 1(D) 3 4 1 2


20/48

PHYS

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Kota/01CT314071

21. List-I gives different situations in which bodies are floating in liquid. Bodies are slightly displaced in

vertical plane & released. List-II gives corresponding time periods of oscillation. The value of H is 5m.

lwph-I esa fofHkUu fLFkfr;k¡ n'kkZ;h x;h gS ftuesa fi.M æo esa rSj jgs gSA fi.Mksa dks Å/okZ/kj ry esa vYi foLFkkfir dj NksM+

fn;k tkrk gSA lwph-II esa nksyu ds laxr vkorZdky fn;s x;s gSA H dk eku 5m gS%&


(P) (1) p

A cylinder floating in liquid

æo esa rSjrk gqvk csyu

(Q) (2)2

3p

A cone floating in liquid

æo esa rSjrk gqvk 'kadq



PHYS

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21/48Kota/01CT314071

(R) (3)2

6p

A sphere floating in liquid

æo esa rSjrk gqvk xksyk

(S)

H

(4) 6p

A cube floating in liquid

æo esa rSjrk gqvk ?ku

Codes/dwV :

P Q R S

(A) 3 4 2 1

(B) 1 3 4 2

(C) 2 3 1 4

(D) 4 3 2 1


CHEM

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Kota/01CT31407122/48

PART-2 : CHEMISTRY

Hkkx-2 : jlk;u foKkuSECTION–I : (i) Only One options correct Type

[k.M-I : (i) dsoy ,d lgh fodYi izdkjThis section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONLY ONE is correct.


lgh gSA1. Correct expression for determining packing fraction (PF) of NaCl type unit cell, if ions along an edge

diagonal are absentwhere r

+ = cationic radius, r

– = anionic radius

edge diagonal

(A) P.F. =

3 3

3

4 (r r )3

16 2 r

+ -

-

p +(B)

3 3

3

4 7 r 4r3 2

16 2 r

+ -

-

æ öp +ç ÷è ø (C)

3 3

3

4 5 r 4r3 2

16 2 r

+ -

-

æ öp +ç ÷è ø (D)

3 3

3

4 5 r 4r3 2

16 2 r

+ -

+

æ öp +ç ÷è ø

NaCl izdkj dh bdkbZ lsy dk ladqyu izHkkt (PF) Kkr djus ds fy, lgh O;atd gksxk] ;fn fdukjs ds fod.kZ okys

vk;u vuqifLFkr gks

tgk¡ r+

= /kuk;fud f=T;k , r–

= ½.kk;fud f=T;kfdukjs dk fod.kZ

(A) P.F. =

3 3

3

4 (r r )3

16 2 r

+ -

-

p +(B)

3 3

3

4 7 r 4r3 2

16 2 r

+ -

-

æ öp +ç ÷è ø (C)

3 3

3

4 5 r 4r3 2

16 2 r

+ -

-

æ öp +ç ÷è ø (D)

3 3

3

4 5 r 4r3 2

16 2 r

+ -

+

æ öp +ç ÷è ø



CHEM

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Kota/01CT314071 23/48


2. 7 moles of tetra-atomic, non linear ideal gas A at TK temperature are mixed with 6 moles of another

ideal gas B at T K3

in a closed rigid vessel without heat loss with surrounding. If final temperature of

mixture is 5T K6 , the gas B should be (assuming all modes of energy is active)

(A) Mono-atomic (B) Di-atomic (C) Tri-atomic (D) Tetra-atomic

TK rki ij prq"d&ijekf.o; vjs[kh; vkn'kZ xSl A ds 7 eksy dks ,d can n`< ik= esa T K3

ij vU; vkn'kZ xSl B ds

6 eksyksa ds lkFk ifjos'k esa dksbZ Å"ek gkfu fd;s fcuk] fefJr fd;k x;kA ;fn feJ.k dk vafre rki 5T K6 gS] rks xSl B

gksuh pkfg,A (eku fyft;s ÅtkZ ds lHkh izdkj lfØ; gS)

(A) ,dy&ijek.kqd (B) f}&ijek.kqd (C) f=&ijek.kqd (D) prq"d&ijek.kqd

3. Select the correct statement about white ppt of PbSO4 :

(A) The white ppt dissolves in excess of NaOH

(B) The white ppt dissolves in dil. HCl

(C) The white ppt dissolves in dil. H2SO

4

(D) The white ppt dissolves in all of these

PbSO4 ds 'osr vo{ksi ds lUnHkZ esa lgh dFku pqfu, :

(A) 'osr vo{ksi] NaOH ds vkf/kD; esa ?kqy tkrk gS

(B) 'osr vo{ksi ruq HCl esa ?kqy tkrk gS

(C) 'osr vo{ksi ruq H2SO

4 esa ?kqy tkrk gS

(D) 'osr vo{ksi mijksDr lHkh esa ?kqy tkrk gS

CHEM

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Kota/01CT31407124/48


4. Which of the following molecule has only two identical P–O bond length :

(A) Sodium pyrophosphate (B) Sodium phosphate

(C) Sodium hydrogenphosphite (D) Sodium phosphite

fuEu esa ls dkSuls v.kq esa dsoy nks leku P–O ca/k yEckbZ;k¡ mifLFkr gS :

(A) lksfM;e ik;jksQkWLQsV (B) lksfM;e QkWLQsV

(C) lksfM;e gkbMªkstuQkWLQkbV (D) lksfM;e QkWLQkbV

5. Organic product obtained in following reaction is :

fuEu vfHkfØ;k esa izkIr dkcZfud mRikn gS&

OPCl5

(A) CH —CH3

Cl

Cl(B) CH —CH2 2

Cl Cl

(C) CH —CH2 2

OH Cl

(D) CH —CH3

O6. Organic product obtained in following reaction is :

fuEu vfHkfØ;k esa izkIr dkcZfud mRikn gS&

OC

OBr2Fe

(A)

CO

O

Br

(B)

CO

O Br

(C)

CO

O

Br(D) None of these / buesa ls dksbZ ugha


CHEM

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Kota/01CT314071 25/48

7. Least acidic compound is :

U;wure vEyh; ;kSfxd gS&

(A)

COOH

(B)

COOH

OH

(C)

COOHOH

(D)

COOH

NO2

8. The action of Br2 water (excess) on salicylic acid results in the formation of :

lsfyflfyd vEy ij Br2 ty (vkf/kD;) dh fØ;k ds ifj.kkeLo:i fuEu esa ls fdldk fuekZ.k gksrk gS&

(A)COOH

OH

Br(B)

COOH

OH

Br

Br

(C)Br

OH

Br

Br

(D)

COOH

OH

Br

BrSpace for Rough Work / dPps dk;Z ds fy, LFkku

CHEM

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Kota/01CT31407126/48


(ii) ,d ;k vf/kd lgh fodYi izdkjThis section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONE or MORE are correct.


vf/kd lgh gSA

9. Consider the reaction 2CO(g) + O2(g)

�� 2CO

2(g) + Heat, under what conditions shift is

undeterminable(A) Addition of O

2 and decrease in volume

(B) Addition of CO and removal of CO2 at constant volume

(C) Increase in temperature along with decrease in volume(D) Addition of CO with increase in temperature at constant volume.

fuEu vfHkfØ;k ij fopkj dhft;s 2CO(g) + O2(g)

�� 2CO

2(g) + Å"ek, fdl fLFkfr esa foLFkkiu vKkr gksrk gS

(A) O2 dks feykuk rFkk vk;ru esa deh djus ij

(B) fu;r vk;ru ij CO dks feykus rFkk CO2 dks gVkus ij

(C) vk;ru esa deh ds lkFk rki eas o`f¼ djus ij

(D) fu;r vk;ru ij rki esa o`f¼ ds lkFk CO dks feykus ij10. Degree of hydrolysis for a salt of strong acid and weak base is -

(A) Independent of dilution and Kb both

(B) Increases with increase in Kb and dilution both

(C) Increases with decreases in Kb but increase in dilution.

(D) dependent on dilution

izcy vEy rFkk nqcZy {kkj ds ,d yo.k ds fy;s ty vi?kVu dh ek=k -

(A) ruqdj.k rFkk Kb nksuksa ls Lora= gksrh gS

(B) Kb rFkk ruqdj.k nksuksa esa o`f¼ ds lkFk c<+rh gS

(C) Kb esa deh ijUrq ruqdj.k esa o`f¼ ds lkFk c<+rh gS

(D) ruqdj.k ij fuHkZj djrh gS



CHEM

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Kota/01CT314071 27/48

11. Which of the following molecules are trigonal bipyramidal :

fuEu esa ls dkSuls v.kq f=Hkqth; f}fijkfefM; gSa :

(A) SbBr5

(B) XeO3F

2(C) SF

+

5(D) PF

5

12. The smelting step of extraction of iron in a blast furnace involves the following processes

(A) Combustion (B) Reduction (C) Slag formation (D) Self reduction

okR;k HkV~Vh esa ^vk;ju fu"d"kZ.k* ds izxyu in esa ] fuEu esa ls dkSuls izØe lfEefyr gksrs gS

(A) ngu (B) vip;u (C) /kkrqey dk fuekZ.k (D) Lovip;u

13. Compound(s) which on reaction with NaBH4 gives optically active alcohol :

,sls ;kSfxd tks NaBH4 ds lkFk vfHkfØ;k ij izdkf'kd lfØ; ,sYdksgkWy nsrs gSa&

(A)

O

(B)

O

(C)

O

O(D)

CHO


CHEM

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Kota/01CT31407128/48


(iii) vuqPNsn izdkjThis section contains 2 paragraphs each describing theory, experiment, data etc. Four questions relateto two paragraphs with two questions on each paragraph. Each question of a paragraph has only onecorrect answer among the four choices (A), (B), (C) and (D).

bl [k.M esa fl¼kUrksa] iz;ksxksa vkSj vk¡dM+ksa vkfn dks n'kkZus okys 2 vuqPNsn gSA nksuksa vuqPNsn ls lacaf/kr pkj iz'u

gSa] ftuesa ls gj vuqPNsn ij nks iz'u gSaA vuqPNsn esa gj iz'u ds pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesa

ls dsoy ,d lgh gSAParagraph for Questions 14 and 15

Lowering of vapour pressure is determined by ostwald and walker dynamic method. It is based on theprinciple, when air is allowed to pass through a solvent or solution , it takes up solvent vapour with itto get itself saturated at that temperature. As shown in figure container I and II are weighted separatelybefore and after passing dry air. Adjustment of loss in mass of each set-gives the lowering of vapourpressure. The temperature of air, solution and solvent is kept constant.

Liquid solution

Puresolvent

AnhydrousCaCl2

Dryair

Dryair

I II III

14. Loss in the mass of solvent (WII) and Gain in mass of anhydrous CaCl

2 are respectively proportional

to (where Pº = vapour pressure of pure solventP = vapour pressure of pure solution)

(A) P – Pº , P (B) Pº – P , Pº (C) Pº – P , P (D) P ,Pº PPº

-

15. Relative lowering in vapour pressure is equal toGiven : W

I = loss in weight of solution

WII = loss in weight of solvent

W = gain in weight of anhydrous CaCl2

(A) II

I

WW (B) I

I II

WW W+

(C) II

I II

WW W+ (D)

II

WW



CHEM

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Kota/01CT314071 29/48


ok;qnkc ds voueu dks vksLVokYV RkFkk okYdj xfrdh fof/k }kjk Kkr fd;k tkrk gSA ;g ml fl¼kUr ij vk/kkfjr

gksrk gS] tc ok;q dks ,d foyk;d ;k foy;u ls xqtkjk tkrk gS] ;g Lo;a dks fn;s x;s bl rki ij lar`Ir j[kus ds

fy;s vius lkFk foyk;d ok"i dks xzg.k djrk gSA fp= esa fn[kk;s vuqlkj ik=-I rFkk ik=-II dk i`Fkd&i`Fkd Hkkj

ekiu ok;q dks izokfgr djus ls igys rFkk i'pkr~ fd;k x;kA izR;sd voLFkk ds nzO;eku esa gkfu ds larqyu dks ok;q

nkc esa voueu ls fd;k tkrk gSA ok;q ] foy;u rFkk foyk;d dk rki fu;r j[kk tkrk gSA

futZyCaCl2

'kq"dok;q

I II III

nzo foy;u

'kq¼foyk;d

'kq"dok;q

14. foyk;d ds nzO;eku esa gkfu (WII) rFkk futZy CaCl

2 ds nzO;eku esa o`f¼ Øe'k% lekuqikrh gksrh gS

(tgk¡ Pº = 'kq¼ foyk;d dk ok"inkc

P = 'kq¼ foy;u dk ok"i nkc)

(A) P – Pº , P (B) Pº – P , Pº (C) Pº – P , P (D) P ,Pº PPº

-

15. ok;q nkc esa lkis{k voueu cjkcj gksrk gS

fn;k gS : WI = foy;u ds Hkkj esas gkfu

WII = foyk;d ds Hkkj esa gkfu

W = futZy CaCl2 esa Hkkj esa o`f¼

(A) II

I

WW (B) I

I II

WW W+

(C) II

I II

WW W+ (D)

II

WW


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Compound (A)(soluble)

dil. H SO2 4 gas(B) + (C)

Milkyappearance

White pptLimewater

H2S gas on passing through aq. solution of gas 'B' produces 'C'

;kSfxd (A)( )foys;

ruq H SO2 4 xSl(B) + (C)

nwf/k;k jax

'osr vo{ksipwus dkikuh

xSl 'B' ds tyh; foy;u esa H2S xSl dks izokfgr djus ij 'C' izkIr gksrk gSA

16. Compound 'A' may be :

(A) BaS2O

3(B) BaSO

3(C) CaS

2O

3(D) Both (A) and (C)

;kSfxd 'A' gks ldrk gS :

(A) BaS2O

3(B) BaSO

3(C) CaS

2O

3(D) (A) rFkk (C) nksuksa

17. Gas 'B' on reaction with (Al + Conc. NaOH) will produce :

(A) Solid compound having oxidation state 6 of central atom

(B) Gas having rotten fish smell

(C) Gas having rotten egg smell

(D) White ppt of sulphur

xSl 'B', (Al + lkUæ NaOH) ds lkFk fØ;k djkus ij nsxk :

(A) Bksl ;kSfxd ftlds dsUæh; ijek.kq dh vkWDlhdj.k voLFkk 6 gS

(B) xSl ftldh xa/k] lM+h gqbZ eNyh tSlh gS

(C) xSl ftldh xa/k] lM+s gq, vaMs ds leku gS

(D) lYQj dk 'osr vo{ksi



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(iv) Matching List Type

(iv) lqesyu lwpha izdkj




gSa ftuesa ls dsoy ,d lgh gSA

18. Match list-I with list-II

List-I List-II

(P) Pt|Fe3+, Fe2+ (1) Metal-metal ion half cell

(Q) Pt|H2| H+ (2) Gas-gas ion half cell

(R) Pt|Hg| Hg2

2+ (3) Oxidation reduction half cell

(S) Ag|AgCl| Cl– (4) Metal sparingly soluble salt half cell

lwpha-I rFkk lwpha -II dks lqesfyr dhft;s

lwpha-I lwpha-II

(P) Pt|Fe3+, Fe2+ (1) /kkrq&/kkrq vk;u v/kZ lSy

(Q) Pt|H2| H+ (2) xSl&xSl vk;u v/kZ lSy

(R) Pt|Hg| Hg2

2+ (3) vkWDlhdj.k vip;u v/kZ lSy

(S) Ag|AgCl| Cl– (4) /kkrq vYi foys; yo.k v/kZ lSy

Codes :P Q R S

(A) 2 3 1 4

(B) 3 2 1 4

(C) 3 2 4 1

(D) 2 4 1 3


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19. List-I (Metal) List-II (Properties)

(P) Al (1) Does not dissolve completely in conc. HNO3

(Q) Pt (2) Produces NH4NO

3 with both dil.HNO

3 and very

dil.HNO3

(R) Zn (3) Does not dissolve in conc. H2SO

4

(S) Sn (4) Produces H2 gas on reaction with dil. H

2SO

4

lwpha-I (/kkrq) lwpha-II (xq.k)

(P) Al (1) lkUæ HNO3 esa iw.kZr;k foys; ugha gksrk gS

(Q) Pt (2) ruq HNO3 rFkk vfr ruq HNO

3 , nksuksa ds lkFk NH

4NO

3

cukrk gS

(R) Zn (3) lkUæ H2SO

4 esa foys; ugha gksrk gS

(S) Sn (4) ruq H2SO

4 ds lkFk fØ;k djkus ij H

2 xSl mRikfnr djrk gS

Codes :

P Q R S

(A) 1, 3 1, 4 4 2, 3

(B) 1, 4 1, 3 4 2, 4

(C) 1, 3 2, 3 3, 4 2, 4

(D) 1, 2 3, 4 2, 3 1, 3



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20. List- I List- II

(P)

Cl

(1) SN1 reaction may takes place

(Q)Cl

(2) SN2 reaction may takes place

(R)

Cl

(3) SN1 is not possible

(S)Cl

(4) SN2 is not possible

lwpha- I lwpha- II

(P)

Cl

(1) SN1 vfHkfØ;k gks ldrh gSA

(Q)Cl

(2) SN2 vfHkfØ;k gks ldrh gSA

(R)

Cl

(3) SN1 lEHko ugha gSA

(S)Cl

(4) SN2 lEHko ugha gSA

Codes :P Q R S

(A) 3, 4 1, 2 3, 4 3, 4

(B) 3, 4 2, 2 1, 2 4, 4

(C) 4, 4 2, 2 1, 1 3, 3

(D) 4, 4 1, 1 2, 2 3, 3


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21. List- I (lwpha - I) List- II (lwpha- II)

(Alkanes) (Number of structural isomers)

(, sYdsu) (lajpukRed leko;oh dh la[;k)

(P) C4H

10(1) 2

(Q) C5H

12(2) 3

(R) C6H

14(3) 5

(S) C7H

16(4) 9

Codes :

P Q R S

(A) 2 4 1 3

(B) 2 3 4 1

(C) 1 2 3 4

(D) 1 4 3 2



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PART-3 : MATHEMATICS Hkkx-3 : xf.kr

SECTION–I : (i) Only One options correct Type [k.M-I : (i) dsoy ,d lgh fodYi izdkj

This section contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONLY ONE is correct.


lgh gSA1. The number of solutions of the equation |ln|x|| = |sinx|, is-

(A) 0 (B) 2 (C) 4 (D) infinite

lehdj.k |ln|x|| = |sinx| ds gyksa dh la[;k gksxh -

(A) 0 (B) 2 (C) 4 (D) vuUr

2. The number of solutions of the equation 2[x] = x + 2{x} (where [.] & {.} represent greatest integer and

fractional part function respectively), is-

lehdj.k 2[x] = x + 2{x} ds gyksa dh la[;k gksxh (tgk¡ [.] rFkk {.} Øe'k% egÙke iw.kk±d Qyu rFkk fHkUukRed HkkxQyu dks n'kkZrs gS -

(A) 0 (B) 2 (C) 3 (D) 5

3. For the curve represented implicitly as px – ey = p, the value of x

dylim

dx®¥

æ öç ÷è ø

is -

(A) 1 (B) 0 (C) lnp (D) does not exist

vLi"V :i ls iznf'kZr oØ px – ey = p ds fy,] x

dylim

dx®¥

æ öç ÷è ø

dk eku gksxk -

(A) 1 (B) 0 (C) lnp (D) fo|eku ugha gSA


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4. ( )4 4 4 2 4 2sin x cos x sin x cos x cos x sin x dx+ - -ò is-

(A) 7 7sin x cos x

C7 7

+ + (B) 5x 3

sin 4x C8 32

- +

(C) 5x 3

sin 4x C8 32

+ + (D) 7 7sin x cos x

C7 7

- +

(where 'C' is constant of integration)

( )4 4 4 2 4 2sin x cos x sin x cos x cos x sin x dx+ - -ò cjkcj gksxk -

(A) 7 7sin x cos x

C7 7

+ + (B) 5x 3

sin 4x C8 32

- +

(C) 5x 3

sin 4x C8 32

+ + (D) 7 7sin x cos x

C7 7

- +

(tgk¡ 'C' lekdyu vpj gS)

5. The value of 1

k kk 1

C . Cg-

a bg-

=å is (where a,b,k,g Î N, a > g, b > g & nCr = -

n!

(n r)!r!)

1

k kk 1

C . Cg-

a bg-

=å dk eku gksxk (tgk¡ a,b,k,g Î N, a > g, b > g rFkk nCr = -

n!

(n r)!r! gS)

(A) a+bCg (B) abCg

(C) a+bCg – (aCg + bCg) (D) (–1)g. a+bCg


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6. Let X,Y and Z be three events such that events X and Y are mutually exclusive, if P(X È Y) = 1,

P(X Ç Z)1

5= and ( ) 7

P Z15

= , then P(Y Ç Z) is equal to-

ekuk X,Y rFkk Z rhu ?kVuk;sa bl izdkj gS fd ?kVuk X rFkk Y ijLij viothZ gSA ;fn P(X È Y) = 1, P(X Ç Z)1

5=

rFkk ( ) 7P Z

15= gks] rks P(Y Ç Z) dk eku gksxk -

(A) 4

15(B)

2

3(C)

7

25(D)

11

15

7. The ratio of distance of center to a focus and center to the corresponding vertex for a curve represented

parametrically by the equation t2 – 4t + 1 – tx = 0 and t2 + 4t – 1 – ty = 0, (t ¹ 0), is-

lehdj.k t2 – 4t + 1 – tx = 0 and t2 + 4t – 1 – ty = 0, (t ¹ 0) }kjk izkpfyd :i ls iznf'kZr oØ ds fy, dsUæ ls ,dukfHk dh nwjh rFkk dsUæ ls laxr 'kh"kZ dh nwjh dk vuqikr gksxk -

(A) 3 (B) 1

3(C) 2 (D)

1

2

8. A(–4,0) & B(4,0) are two fixed points in argand plane then the set of values of m for which two another

points C & D in argand plane satisfying Im(Z) = mRe(Z) + 8 are such that AC AD

Arg ArgBC BD 2

pæ ö æ ö= =ç ÷ ç ÷è ø è ø

is-

A(–4,0) rFkk B(4,0) vkxZ.M lery esa nks fuf'pr fcUnq gks] rks m ds ekuksa dk leqPp; ftlds fy, vkxZ.M lery esa

nks vU; fcUnq C rFkk D, Im(Z) = mRe(Z) + 8 dks bl izdkj lUrq"V djrs gS fd AC AD

Arg ArgBC BD 2

pæ ö æ ö= =ç ÷ ç ÷è ø è ø

gS] gksxk -

(A) 3, 3é ù-ë û (B) ( ) ( ), 3 3,-¥ - È ¥

(C) ( ) ( ) { }, 3 3, 2,2-¥ - È ¥ - - (D) ( ) ( ) { }, 1 1, 2,2-¥ - È ¥ - -

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(ii) ,d ;k vf/kd lgh fodYi izdkjThis section contains 5 multiple choice questions. Each question has four choices (A), (B), (C) and

(D) out of which ONE or MORE are correct.


vf/kd lgh gSA

9. Consider ( ) ( ) ( )( )x

2

2

ƒ x t 2 t 2 t 4 dt-

= - + -ò , then-

(A) ƒ(x) increases in ( ) ( )x , 2 4,Î -¥ - È ¥ (B) ƒ(x) decreases in x Î (–2,4)

(C) ƒ"(2) = 0 (D) ƒ(–2) = 0

ekuk ( ) ( ) ( )( )x

2

2

ƒ x t 2 t 2 t 4 dt-

= - + -ò gks] rks -

(A) ƒ(x), ( ) ( )x , 2 4,Î -¥ - È ¥ esa o/kZeku gksxkA (B) ƒ(x), x Î (–2,4) esa Îkleku gksxkA

(C) ƒ"(2) = 0 (D) ƒ(–2) = 0

10. Consider all possible permutations of the word CONTINUITY, then the number of permutations

(A) which have COUNT in all of them is 6 (B) which have COUNT in all of them is 3 5

(C) which have all vowels separated is 15 7 (D) which have all vowels separated is 6 7

'kCn CONTINUITY ds lHkh laHko Øep;ksa esa ls mu Øep;ksa dh la[;k ftuesa

(A) lHkh esa COUNT vkrk gks 6 gksxhA (B) lHkh esa COUNT vkrk gks 3 5 gksxhA

(C) lHkh Loj vyx&vyx gks] 15 7 gksxhA (D) lHkh Loj vyx&vyx gks] 6 7 gksxhA

11. If the equation in x, x2 + 2(1 + l)x + (3l2 + 2) = 0 has imaginary roots, then -

;fn x esa lehdj.k x2 + 2(1 + l)x + (3l2 + 2) = 0 ds dkYifud ewy gks] rks -

(A) l = 1 (B) 1

2l = - (C) l = 0 (D) l = –1



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12. If 1vr

& 2vr

are two non collinear non zero vectors and XYZ is a triangle with side lengths x,y,z satisfying

( ) ( ) ( ) ( )1 2 1 2200x 150y v 150y 120z v 120z 200x v v 0- + - + - ´ =r r r r

, then-

(A) Triangle XYZ is a right angled triangle (B) 2

2 2zx , , y

2 are in AP

(C) orthocenter of DXYZ is vertex Z (D) 1 1y x

sin tanz y 2

- - æ ö pæ ö + =ç ÷ç ÷è ø è ø

;fn 1vr

rFkk 2vr

nks vlajs[kh; v'kwU; lfn'k gS rFkk XYZ ,d f=Hkqt gS ftldh Hkqtkvksa dh yEckbZ x,y,z,z

( ) ( ) ( ) ( )1 2 1 2200x 150y v 150y 120z v 120z 200x v v 0- + - + - ´ =r r r r

dks lUrq"V djrh gS] rc -

(A) f=Hkqt XYZ ledks.k f=Hkqt gksxkA (B) 2

2 2zx , , y

2 lekUrj Js.kh esa gksaxsA

(C) f=Hkqt XYZ dk yEcdsUæ] 'kh"kZ Z gksxkA (D) 1 1y xsin tan

z y 2- - æ ö pæ ö + =ç ÷ç ÷

è ø è ø

13. Consider ( )sin x 0 x

2g x

cos x x2

pì £ <ïï= í pï ³ïî

and a continuous function y = ƒ(x) satisfies ( )5dy5y g x

dx+ = ,

ƒ(0) = 0, then-

ekuk ( )sin x 0 x

2g x

cos x x2

pì £ <ïï= í pï ³ïî

rFkk ,d larr~ Qyu y = ƒ(x), ( )5dy5y g x

dx+ = dks lUrq"V djrk gS] ,oa

ƒ(0) = 0 gS] rc

(A) / 4e

ƒ4 10

-ppæ ö =ç ÷è ø

(B) -pp -æ ö =ç ÷

è ø

/ 4e 1ƒ

4 10

(C) / 2e 1

ƒ2 10

-pp +æ ö =ç ÷è ø

(D) / 2ƒ e2

-ppæ ö =ç ÷è ø


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(iii) vuqPNsn izdkjThis section contains 2 paragraphs each describing theory, experiment, data etc. Four questions relateto two paragraphs with two questions on each paragraph. Each question of a paragraph has only onecorrect answer among the four choices (A), (B), (C) and (D).bl [k.M esa fl¼kUrksa] iz;ksxksa vkSj vk¡dM+ksa vkfn dks n'kkZus okys 2 vuqPNsn gSA nksuksa vuqPNsn ls lacaf/kr pkj iz'ugSa] ftuesa ls gj vuqPNsn ij nks iz'u gSaA vuqPNsn esa gj iz'u ds pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesals dsoy ,d lgh gSA



Consider A(1,2,–3), B(4,–1,7) and line x 10 y 1 z 6

L :9 1 3

- - += =

- -. Let image of A in plane P is point B..

ekuk A(1,2,–3), B(4,–1,7) rFkk js[kk x 10 y 1 z 6L :

9 1 3

- - += =

- - gSA ekuk lery P esa A dk izfrfcEc B gSA

14. Equation of the plane P is-

P dk lehdj.k gksxk -

(A) 3x + 3y + 8z – 26 = 0 (B) 3x – 3y + 10z – 25 = 0

(C) 3x – 3y – 10z – 26 = 0 (D) 3x – 3y + 10z – 26 = 0

15. If L' is image of line L in plane P, then the distance between L & L' is -

;fn lery P esa js[kk L dk izfrfcEc L' gks] rks L rFkk L' ds e/; nwjh gksxh -

(A) 0 (B) 118

2(C) 118 (D) 2 118



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Consider ( ){ } { }{ } { }x x

x Iƒ x x x

cos x x I

ì - -Ïï= + -í

ï p Îî

, (where {.} denotes fractional part function)

ekuk ( ){ } { }{ } { }x x

x Iƒ x x x

cos x x I

ì - -Ïï= + -í

ï p Îî

gS] ( tgk¡ {.} fHkUukRed Hkkx Qyu dks n'kkZrk gS )A

16. The number of points of discontinuity of ƒ(x) in x Î [–2,2] is-

x Î [–2,2] esa ƒ(x) ds vlarr~rk ds fcUnqvksa dh la[;k gksxh -

(A) 4 (B) 5 (C) 9 (D) 10

17. The value of ( )2

2

ƒ x dx-ò is-

( )2

2

ƒ x dx-ò dk eku gksxk -

(A) 2 (B) 4 (C) 8 (D) 16


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(iv) Matching List Type (iv) lqesyu lwpha izdkj




gSa ftuesa ls dsoy ,d lgh gSA18. Consider a line L : lx – y = |l|, l Î R

Match List-I with List-II and select the correct answer using the code given below the list.List-I List-II

(P) The positive value of l for which sum of intercepts of (1) 1L on axes is zero, is

(Q) If L is tangent to y = ex–2 + x2 at x =2, then the value (2)15

8of l is

(R) If L is tangent to py + tanpx = 0 (3) –1at x =–1, then the value of l is

(S) The positive value of l for which L touches the circle (4) 5x2 + y2 – 4x – 8y + 19 = 0, is

ekuk js[kk L : lx – y = |l|, l Î R gSA

lwph-I dks lwph-II ls lqesfyr dhft, rFkk lwfp;ksa ds uhps fn, u, dksM dk iz;ksx djds lgh mÙkj pqfu;s %

lwph-I lwph-II

(P) l dk /kukRed eku ftlds fy, v{kksa ij L ds vUr %[k.Mksa dk (1) 1

;ksxQy 'kwU; gks] gksxk

(Q) ;fn L, y = ex–2 + x2 ij x = 2 ij Li'kZjs[kk gks] (2)15

8rks l dk eku gksxk

(R) ;fn L, py + tanpx = 0 ij x = –1 ij Li'kZjs[kk gks] (3) –1

rks l dk eku gksxk

(S) l dk /kukRed eu ftlds fy, L, o`Ùk x2 + y2 – 4x – 8y + 19 = 0 (4) 5

dks Li'kZ djrh gks] rksCodes :

P Q R S(A) 1 4 3 2(B) 1 3 4 2(C) 2 3 1 4(D) 4 1 2 3



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19. Match List-I with List-II and select the correct answer using the code given below the list.List-I List-II

(P) The number of solutions of sin3x – cosx = 0 in x ,2 2

p pé ùÎ -ê úë û, is (1) 1

(Q) The value of x for which ( ) ( )22 21 1sin x cos x

4- - p

- = , is (2) 2

(R) For an event A, P(A) = 6

15, ( ) 4

P A B15

Ç = , (3) 3

( ) 8 BP A B , P

15 A 6

æ ö lÈ = =ç ÷

è ø, then l is

(S) The number of points where ƒ(x) = [sin 5p[x]], is (4) 0not differentiable in x Î [–2,2](where [.] represents greatest integer function)


lwph-I lwph-II

(P) x ,2 2

p pé ùÎ -ê úë û esa sin3x – cosx = 0 ds gyksa dh la[;k gksxh (1) 1

(Q) x dk eku ftlds fy, ( ) ( )22 21 1sin x cos x

4- - p

- = gks] gksxk (2) 2

(R) ?kVuk A ds fy, P(A) = 6

15, ( ) 4

P A B15

Ç = , (3) 3

( ) 8 BP A B , P

15 A 6

æ ö lÈ = =ç ÷

è ø gks] rks l dk eku gksxk

(S) fcUnqvksa dh la[;k ƒ(x) = [sin 5p[x]], x Î [–2,2] esa vodyuh; (4) 0

ugha gks] gksxh

(tgk¡ [.] egÙke iw.kk±d Qyu dks n'kkZrk gS)Codes :

P Q R S(A) 3 4 2 1(B) 2 1 4 3(C) 3 1 2 4(D) 1 4 2 3



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21. Match List-I with List-II and select the correct answer using the code given below the list.


List-I / lwph-I List-II / lwph-II

(P)( )

n

22r 1

2r 1

r r=

+

+å (1) ( )

n 2

2 n 1

++

(Q)( )( )

n

2n 2r 1

2r 1lim

r r®¥=

+

+å (2)

( )( )2

n n 2

n 1

+

+

(R)( )

n k

22r 1k 1

2r 1

r r==

æ ö+ç ÷ç ÷+è øåÕ (3) 1

(S)( )

n k

2n 2r 1k 1

2r 1lim

r r®¥==

æ ö+ç ÷ç ÷+è øåÕ (4)

1

2

Codes :

P Q R S

(A) 1 3 2 4

(B) 2 3 1 4

(C) 3 2 1 4

(D) 2 3 4 1


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47/48Kota/01CT314071


D. vadu ;kstuk / Marking scheme :

12. [kaM-I (i, iii & iv) ds gj iz'u esa dsoy lgh mÙkjksa (mÙkj) okys lHkh cqycqyksa (cqycqys) dks dkyk djus ij 3 vad vkSj dksbZ Hkh cqycqyk

dkyk ugha djus ij 'kwU; (0) vad iznku fd;k tk;sxkA vU; lHkh fLFkfr;ksa esa ½.kkRed ,d (–1) vad iznku fd;k tk;sxkA

For each question in Section-I (i, iii & iv), you will be awarded 3 marks if you darken all the bubble(s) corresponding to

only the correct answer(s) and zero mark if no bubbles are darkened. In all other cases minus one (–1) mark will be awarded

13. [kaM-I (ii) esa gj iz'u esa dsoy lgh mÙkj okys cqycqys (BUBBLE) dks dkyk djus ij 4 vad vkSj dksbZ Hkh cqycqyk dkyk ugha djus ij

'kwU; (0) vad iznku fd;k tk;sxk bl [ akM ds iz'uksa esa xyr mÙkj nsus ij dksbZ ½.kkRed vad ugha fn;s tk;saxsaA

For each question in Section-I (ii), you will be awarded 4 marks if you darken the bubble corresponding to the correctanswer and zero mark if no bubbles are darkened No negative marks will be awarded for incorrect answers inthis section.

14. g = 10 m/s2 iz;qDr djsa ] tc rd fd vU; dksbZ eku ugha fn;k x;k gksA

Take g = 10 m/s2 unless otherwise stated.

Name of the Candidate / ijh{kkFkhZ dk uke

I have read all the instructions and shall abide by them.eSusa lHkh vuqns'kksa dks i<+ fy;k gS vkSj eSa mudk vo'; ikyu d:¡xk@d:¡xhA

Signature of the Candidate / ijh{kkFkhZ ds gLrk{kj

Form Number / QkWeZ la[;k

I have verified all the information filled in by the Candidate.ijh{kkFkhZ }kjk Hkjh xbZ tkudkjh dks eSus a tk¡p fy;k gSA

Signature of the Invigilator / fujh{kd ds gLrk{kj


Corporate Office : ALLEN CAREER INSTITUTE, “SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005

+91-744-2436001 [email protected]

Appropriate way of darkening the bubble for your answer to be evaluatedvkids mÙkj ds ewY;kadu ds fy, cqycqys dk s dkyk djus dk mi;qDr rjhdk

a

a

a

a

a

a

The one and the only acceptable,d vkSj dsoy ,d Lohdk;Z

Part darkeningvkaf'kd dkyk djuk

Darkening the rimfje dkyk djuk

Cancelling after darkeningdkyk djus ds ckn jn~n djuk

Erasing after darkeningdkyk djus ds ckn feVkuk

Answer will not be evaluated -no marks, no negative marks

mÙkj dk ewY;kadu ugha gksxk&dksbZ vad ugha] dksbZ ½.kkRed vad ugha

Figure-1 : Correct way of bubbling for valid answer and a few examplex of invalid answers fp=&1 % oS/k mÙkj ds fy, cqycqyk Hkjus dk lgh rjhdk vkSj voS/k mÙkjks a ds dqN mnkgj.kAAny other form of partial marking such as ticking or crossing the bubble will be invalidvkaf'kd vadu ds vU; rjhds tSls cqycqys dks fVd djuk ;k ØkWl djuk xyr gksxkA

10

234

6789

4 2 0 0 0 20

2

0

2 2 23 3 3 3 3

0

4 4 4 45 5 5 5 56 6 6 6 6 67 7 7 7 7 78 8 8 8 8 89 9 9 9 9 9

1 1 1 1 1

20

456789

1

54

5

3

1

3

Figure-2 : Correct Way of Bubbling your Form Number on the ORS. (Example Form Numebr : 14200022)fp=&2 % vks-vkj-,l (ORS) ij vkids QkWeZ uEcj ds ccy dks Hkjus dk lgh rjhdkA (mnkgj.k QkWeZ uEcj : 14200022)

Kota/01CT314071Your Target is to secure Good Rank in JEE 201548/48

allen 0 1 3 1 4 0 7 1 clas amme · (academ sessio 2014-2015) ... sd iz'u esa pkj fodyi (a),...

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