amcat programming - program 3_1432437424716

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Ques:ChoosethecorrectanswerAnkitatakesasinput2integernumbers,aandb,whosevaluecanbebetween0and31.Hestoresthemas5bitnumbers.Hewritesthefollowingcodetoprocessthesenumberstoproduceathirdnumberc.

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c=2*(ab)

InhowmanyminimumbitsshouldAnkitastorec?Option1:6bitsOption2:7bitsOption3:8bitsOption4:9bits

AskedInAMCAT Aashu(1yearago)

Unsolved ReadSolution(9)

IsthisPuzzlehelpful? Yes (5) No (2) SubmitYourSolutionProgram

c=2*(ab)lowestnumberwillbegeneratedwhena=0andb=31c=2*(031)=64highestnumberwillbegeneratedwhena=31andb=0c=2*(310)=64range=64to64bitsrequired=7

IsthissolutionHelpfull?Yes(36)|No(4)

ANKITGUPTA(8MONTHSAGO)

Option1sinceoverflowofonly1biti.e.5+1=6


AJAYYADAV(1YEARAGO)

ans:6bits.2power5=32maxvalueofab=31.2*31=62.2power6=64so6bitswillbetheanswer.


VIPUL(1YEARAGO)

7bitsa=0b=31c=621bitwillbrequiredtostorethe""andtostorethenumber626bitswillbrequired.


MANAVAGGARWAL(10MONTHSAGO)

option2isthecorrectanswerbczc=2*32=64means2^6bitsrequired..sowehavetoadd1bitasasignbitsototal6+1=7

IsthissolutionHelpfull?Yes(4)|No

GOWRI(5MONTHSAGO)

c=2*(ab)Forlowestnumberwhena=0andb=31c=2*(031)=62

Forhighestnumberwhena=31andb=0c=2*(310)=62range=62to62

SoItwillfiton(64to63)i.e2^7BitsRequired=7


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2*(310)=622*(031)=6262to62arerangebetweenthe2pow6=64bitsatifiedthebitansis6


Ithink2*(031)=62Soweneedtostorethemnearestdatabitslike64,128,256.rightSofor62thebestoptionis64,64wecanwrittenitas2^6.Sotherequiredbitsare6.letmesuggestforthebetterAns

IsthissolutionHelpfull?Yes|No

TRINADH(4MONTHSAGO)

Adminplscanuexplainmethisquestionalongwiththeanswer..


ANTARAROY(3MONTHSAGO)

Ques:ChoosethecorrectanswerPrashanttakesasinput2integernumbers,aandb,whosevaluecanbebetween0and127.Hestoresthemas7bitnumbers.Hewritesthefollowingcodetoprocessthesenumberstoproduceathirdnumberc.

c=ab

InhowmanyminimumbitsshouldPrashantstorec?Option1:6bitsOption2:7bitsOption3:8bitsOption4:9bits

AskedInAMCAT Aashu(1yearago)

Unsolved ReadSolution(10)

IsthisPuzzlehelpful? Yes (10) No (5) SubmitYourSolutionProgram

MAXc=127(Whena=127&b=0)MINc=127(Whena=0&b=127)ToStore127,WeRequire"7Bits"&AccordingtoSignMagnitudeRepresentation"1ExtraBit"isRequired(forveValues)Therefore,inall7+1=8bitsistheAnswer.


ANKITJAIN(1YEARAGO)

Option3=8bitsincemaximumvalueofc=127andminimumvalue=127hence8bitswillbeusedd


AJAYYADAV(1YEARAGO)

Intheaboveproblemhedidnotmentionedanyvevaluesandvaluesbetween0to127.Maxvalueofc=1270=127.so2^7=128.Butincasec=0127=127.Sotostorethisvaluewewant8bytes.


ANILREDDY(1YEARAGO)

2^7=128,ithink7bits.minvalueofccanbe127andmaxwillbe+127.


AVIGYAN(1YEARAGO)

VERTIKASRIVASTAV(11MONTHSAGO)

KEEP AN EYE (#M40031699) AMCAT QUESTION



wecanttake0and1asquessaysb/wthem............guysjustseetoit


VERTIKASRIVASTAV(11MONTHSAGO)

pleasetellmethecorrectreason


MAHESH(6MONTHSAGO)

127(127)=254(oneofthepossiblecases)forstoring256werequire8bitswhichistheanswer


VIRJESHPATEL(2MONTHSAGO)

Inquestionitisgiven

whosevaluecanbebetween0and127.not127to127so2^7=128ansis7


MR.X(2MONTHSAGO)

Whyiseveryonesayingmaxtobe127wudntitbe127+127=254.soshuoudnttheanswerbe9bits.1forsignedbitand8bitfor254


SURBHIJAIN(2MONTHSAGO)

maxvalueofc=127ndminvalueofc=127totalvalue=127(127)=2542^7


PUSHPANK(1MONTHAGO)

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