Problems Amplitude Modulation6. For an AM DSBFC modulator with a carrier frequenc of !""#$% and a ma&imum modulatin' si'nal of (#$%) determine*a+ Frequenc limits for the upper and lower sidebandsb+ Bandwidthc+ ,pper and lower frequencies produced b a modulatin' si'nal of -#$%..i/en* fc0 !""#$% 1fm2ma&+0 (#$% 3equired*a.+ 4SB 5 ,SBb.+ Bc.+ fusf 5 flsfSolution*a.+ 4SB 0 6fc 7 fm2ma&+8 to fc 0 6!""#$% (#$%8 to !""#$%4SB 0 9(#$% to !""#$%a.+ ,SB 0 fc to 6fc : fm2ma&+80 !""#$% to 6!""#$% : (#$%8 ,SB 0 !""#$% to !"(#$%b.+ B0 ;fm2ma&+0 ;2(#$% + B 0 !"#$?panda minimumpea#/olta'eof;?p) compute for*a+ ,pperandlowerpea#amplitudeside frequenciesb+ Pea#amplitudeoftheunmodulated carrierc+ Pea#chan'eintheamplitudeofthe en/eloped+ Modulation inde&e+ Percent modulation.i/en* ?ma&0 !>?p?min0 ;?p3equired*a.+ @usf 5 @lsfb.+ @cc.+ @md.+ me.+ MSolution*a.+ @usf 0 @lsf 0 0 @usf 0 @lsf 0 A?b.+ @c 0 0 @c 0 !"?Solution*c.+ @m 0 0 0 @c 0 >?d.+ m 00 m 0 ".>e.+ M 0& !""C0& !""CM 0 >"C>.ForanAMDSBFCtransmitterwith anunmodulatedcarrierpowerPc0 !""Dthatismodulated simultaneouslbthreemodulatin' si'nals with coeEcients of modulation* ".;) ".A) ".(. Determine* a+ Fotal coeEcient of modulationb+ ,pper and lower sideband powerc+ Fransmitted power.i/en*Pc 0 !""D m! 0 ".;m; 0 ".Am- 0 ".(3equired *a.+ mtb.+ Psbtc.+ PtSolution*a.+mt0 0 mt 0 ".6=b.+Psbt0 0 Psbt0 c.+Pt 0 Pc 2 ! 0 !""D 2 ! : +Pt 0 !;;.A(D9.For thema&imumpositi/een/elope /olta'e of !;? and a minimum positi/e en/elopeamplitudeofA?.Determine the modulation coeEcient and percent modulation. .i/en* ?ma& 0 !;?1?min 0 A?3equired*m 5 MSolution*m 0 0 m 0 ".(M 0& !""C0G !""CM 0 ("C!".Dhatisthema&imummodulatin' si'nal frequenc that can be used with AMDSBFCsstemwitha;"#$% bandwidthH.i/en* B 0 ;"#$%3equired* fm2ma&+Solution*B 0 ;fm2ma&+fm2ma&+ 0 BI; 0 ;"#$% I ;fm2ma&+ 0 !"#$%!!.ForanAMDSBFCwa/ewithan unmodulatedcarrier/olta'eof!>?p andloadresistanceof=;Janda modulationcoeEcientof".6 Determine*a+ ,nmodulated carrier powerb+ Fotal sideband powerc+ ,pper and lower sideband powerd+ Fotal transmitted power..i/en* ?c 0 !>?p 340 =;J3equired*a+ Pcb+ Psbc+ Pusb 5 Plsbd+ PtSolution*a.+Pc 0 ?c; I ;310 2!>?+; I ;2=;J+Pc 0 ;.;(Db.+ Psb 0 m;Pc I ;0 2".6+;2;.;(D+ I ; Psb0 ".A"( Dc.+Pusb 0 Plsb 0 m;Pc I A0 2".6+;2;.;(D+ I APusb 0 Plsb 0 ".;";( Dd.+ Pt 0 Pc 2 !: m;I;+0 Pc 2 !: m;I;+0 2;.;(D+ 2!: ".6;I;+Pt 0 ;.6((D