asserting java, ch 7: repetition

Chapter 6

Repetition

Asserting Java

© Rick Mercer

Algorithmic Pattern:

The Determinate loop

We often need to perform some action a specific

number of times:

— Produce 89 paychecks.

— Count down to 0 (take 1 second of the clock).

— Compute grades for 81 students

The determinate loop pattern repeats some action

a specific number of times.

Pattern: Determinate Loop

Problem: Do something exactly n times, where n is known in

advance.

Algorithm determine n repeat the following n times

perform these actions

CodeExample:

public boolean catDog(String str) {

int cats = dogs = 0;

int i = 0;

while(i <= str.length()-3) {

if(str.substring(i, i+3).equals("cat"))

cats = cats + 1;

if(str.substring(i, i+3).equals("dog"))

dogs = dogs + 1;

i++;

}

return cats == dogs;

}

Determinate Loops with while

The determinate loop pattern can be implemented with

the Java while loop

This template repeats a process n times:

int n = /* how often we must repeat the process */int counter = 1;

while ( counter <= n ) {

// the process to be repeated counter = counter + 1;

}

— determinate loops must know the number of repetitions before

they begin: know exactly how many employees, or students, or

whatever that must be processed, for example

Example for loop that produces an

average

Scanner keyboard = new Scanner(System.in);

double sum = 0.0;

double number;

System.out.print("How many do you want to average? ");

int n = keyboard.nextInt();

int counter = 1;

// Do something n times

while (counter <= n) {

System.out.print("Enter number: "); // <- Repeat 3

number = keyboard.nextDouble(); // <- statements

sum = sum + number; // <- n times

counter = counter + 1; // make sure the loop stops

}

double average = sum / n;

System.out.print("Average of "+ n

+ " numbers is "+ average);

Active Learning

What is the output :

int j = 1;

int n = 5;

while(j <= n) {

System.out.print (j + " ");

j = j + 1;

}

j = 0;

while(j <= 2 * n) {

System.out.print (j + " ");

j = j + 2;

}

Indeterminate Loops

Determinate loops have a limitation

— We must know n (the number of repetitions) in

advance

Many situations need us to repeat a set of

statements an unspecified number of times: — Processing report cards for every student in a school

(or paychecks for all employees, or...)

— Allowing 1 to many ATM transactions

— Asking the user for specific input and allowing re-entry

of input after invalid inputs

Some things that terminate

indeterminate loops

An indeterminate loop repeats a process until some

stopping event terminates the repetition

There are many such events, but we'll focus on these:

— User enters a special value indicating end of data

— A logical expression becomes false

— The Grid's mover hits the wall or an edge

— The end of a file is encountered

Indeterminate loops do not need to know n in advance

Indeterminate loops can actually determine n

Pattern Indeterminate loop

Problem Some process must repeat an unknown number

of times so some event is needed to terminate

the loop.

Algorithm while( the termination event has not occurred ) {

execute several actions1

bring the loop closer to termination}

Code while(dog.frontIsClear()) {

dog.turnLeft()

Example myGrid.move();

}

Example Indeterminate Loopneed Grid.java

// Using random robot placement, instruct robot to get to

// the wall in front, turn left, and move to the next wall

public class MoveAroundTheGrid {

public static void main(String[] args) {

Grid g = new Grid(10, 15);

while (g.frontIsClear()) {

g.move();

}

g.turnLeft();

while (g.frontIsClear()) {

g.move();

}

}

}

While loop with a Scanner

Sometimes a stream of input from the

keyboard or a file needs to be read until there

is no more data in the input stream

Consider a Scanner object constructed with a

String argument

— The string represents an input stream

You will need Scanner in ControlFun

These assertions pass

@Test

public void showScanner() {

Scanner scannerWithInts = new Scanner("1 2 3");

assertEquals(1, scannerWithInts.nextInt());

assertEquals(2, scannerWithInts.nextInt());

assertEquals(3, scannerWithInts.nextInt());

Scanner scanner =

new Scanner("There are five words here.");

assertEquals("There", scanner.next());

assertEquals("are", scanner.next());

assertEquals("five", scanner.next());

assertEquals("words", scanner.next());

assertEquals("here.", scanner.next());

}

Write method average to return the

average of the doubles in a Scanner

@Test

public void testNum100s() {

ControlFun cf = new ControlFun();

Scanner scanner1 = new Scanner("80.0 70.0 90.0");

Scanner scanner2 = new Scanner("1.0\t 2\n 3. 4.0");

assertEquals(80.0, cf.average(scanner). 0.01);

assertEquals(2.5, cf.average(scanner). 0.01);

}

@Test

public void testSumOfNegs() {

ControlFun cf = new ControlFun();

Scanner scanner0 = new Scanner("1 2 3");

Scanner scannerA = new Scanner("1 -2 3 -4");

Scanner scannerB = new Scanner("-1 -2 -3 -4");

assertEquals(0, cf.sumOfNegatives(scanner0));

assertEquals(-6, cf.sumOfNegatives(scannerA));

assertEquals(-10, cf.sumOfNegatives(scannerB));

}

Let sumOfNegatives return the sum of the

negative integers in a Scanner

What's wrong with this method?

public int sumOfNegatives(Scanner scanner) {

int result = 0;

while (scanner.hasNextInt()) {

if (scanner.nextInt() < 0) {

result += scanner.nextInt();

}

}

return result;

}