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Aptitude: Problems On Ages for [clerk andp.o]

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Aptitude: Problems On Ages for [clerk and p.o]

Problems on ages is really a complicated part in aptitude test since they take

more time compared to that of the other problems we see. Normally peoplesolve these problems with a direct method or they just skip this question. Yet

every problems have a shortcut solution method to solve them, so do this.here i gonna give some formula and along with some examples to solve

them.lets see it below..

Before we start, there are four formulas used for these problems based on their type. all you have to do is

to identify the question type and apply the formula to get the answers in time..

Type 1:

't' years earlier, the father's age was x times that of his son.

At present the father's age is Y times that of his son. what are the

present ages of father and his son? .

Shortcut Formula: for son's age = t (x-1) / x-y

for father's age = y t (x-1) / x-y , that's it

TYPE 1 EXAMPLE :

10 years ago, my mother was four times older than me . now

my mother will be twice older than me. what is my present age.?

shortcut method:

son's age = 10 (4-1)/ 4-2 = 10 / ans

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Type 2: The present age of father is 'Y' times the age of his son. After

't' years, the father's age is 'z' times the age of his son. present age

of father and son?

Shortcut formula : son's age = (z-1)t / y-z

father's age = y t (z-1)/ y-z

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Aptitude:Problems OnAges for[cle...

TYPE 2 EXAMPLE :

The age of a man is 4 times of his son. 5 years ago , the man was

nine times as old as his son. calculate their ages ?

Shortcut method : z=9 , t=5 , y=4

son's age is = 5(9-1)/ 9-4 = 8

father's age is = (4*5)(9-1)/(9-4)= 32

(or)

since father's age is 9 times as son's age, therfore 4*8= 32 .

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Type 3: 't2' years earlier the age of the father was 'X' times the

age of his son. 't2' years later, the age of the father becomes

'Z' times the age of son. what is the present age of father and

son?

Shortcut Formula:

son's age = [t2(z-1)+ t1(x-1)] / (x-z)

Father's age = t1(z-1) + t1 (x-1)

TYPE 3 EXAMPLE :

Five years before the fathers age was 7 times of his son's age. 5

years hence , father's age 3 times the age of his son. find their

present age?

Short cut method : t1= 5, t2=5, x= 7, z= 3

son's age = [5(3-1)]+5(7-1)] / 7-3 = 10

father's age = 10(7-3) = 40

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Type 4:

The ratio of both father and son's age at the present is X:Y . 't' years before theratio was A:B what is their present age?

Shortcut Formula:

son's age = y*[t(a-b)/x*b-a*y]

Father's age = x*[t(a-b)/x*b-a*y]

TYPE 4 EXAMPLE :

the age of you and me are in the ratio 9:4. seven years hence

ratio of our ages will be 5:3. find our present age?

Short cut method :

son's age = 4*[7(5-3) / (9*3) - (5*4)] = 8

father's age = 9*[7(5-3) / (9*3) - (5*4)] = 18

Categories aptitude, problems on ages, qap

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Malik_Vibhor said:May 11, 2012 at 11:39 AM

Hi,Can you please mention type 3 clearly. how you wrote 10(7-3) in the type 3 example.and I have a question which I am not able to take the answer with your type 3 method.question: rohit was 4 times his son 8 years ago. after 8 years rohit twice his son. presentages?ans : son 16, rohit:40but by your method rohit is coming 32 years.please help. I am about to give an exam.please email me if possible. malik.guitar@gmail.com

Thanks a lot.

Malik_Vibhor said:May 11, 2012 at 1:20 PM

Hi,I deep;y studied your formula and got to know the mistake you did in the formula oftype 3.

The type 3 formula is :son's age: {t1(y-1) + t2(y-1)}/x-yfather's age: x*son's age.

these ages are t1 years ago.so present ages areson's age + t1father's age + t1

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