basic engineering circuit analysis chapter 6 solution

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Irwin, Basic Engineering Circuit Analysis, 9/E 1

Chapter 6: Capacitance and Inductance Problem 6.FE-1

SOLUTION:

The correct answer is a. Yes. The capacitors should be connected as shown.

F2 F4

F6

eqC

FCeq

366

)6(6

Irwin, Basic Engineering Circuit Analysis, 9/E 1

Chapter 6: Capacitance and Inductance Problem 6.FE-2

SOLUTION:

The correct answer is c.

dttitq )()(

stC

stCt

tC

tq

1,6

10,6

0,0

)(

C

tqtv

)()(

stV

stVtx

tV

tv

1,6

10,106

0,0

)( 6

)(2

1)( 2 tvCtw

stJ

stJtx

tJ

tw

1,18

10,1018

0,0

)( 26

Irwin, Basic Engineering Circuit Analysis, 9/E 1

Chapter 6: Capacitance and Inductance Problem 6.FE-3

SOLUTION:

The correct answer is b.

The voltage across the unknown capacitor Cx is (using KVL):

xV 824

VVx 16vCq

The capacitors are connected in series and the charge is the same.Cq 480)8(60

Fv

qCx

3016

480

Irwin, Basic Engineering Circuit Analysis, 9/E 1

Chapter 6: Capacitance and Inductance Problem 6.FE-4

SOLUTION:

mH6

eqL

mH12

mH3

mH3 mH9

mH2

The correct answer is d. mmmmmmLeq 2]36]12)93[([

mmmmmLeq 2]36]12)12[([

mmmmLeq 2]366[

mmmLeq 2]33[

mmLeq 25.1

mHLeq 5.3

Irwin, Basic Engineering Circuit Analysis, 9/E 1

Chapter 6: Capacitance and Inductance Problem 6.FE-5

SOLUTION:

The correct answer is a.

dt

tdiLtv

)()(

tttt teeetedt

tdi 2222 402020)2(20)(

tt teemtv 22 402010)(

0,4.02.0

0,0)(

22 tVtee

tVtv

tt