chapter 19 gas stoichiometry. if an excess of chlorine gas reacts with a solution containing 20.0g...

Post on 11-Jan-2016

214 Views

Category:

Documents

1 Downloads

Preview:

Click to see full reader

TRANSCRIPT

Chapter 19

Gas Stoichiometry

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many

cm3 of bromine gas can be produced at STP?

2KBr + Cl2 → Br2 + 2KCl

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many

cm3 of bromine gas can be produced at STP?

2KBr + Cl2 → Br2 + 2KCl

20.0g KBr

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many

cm3 of bromine gas can be produced at STP?

2KBr + Cl2 → Br2 + 2KCl

20.0g KBr119g KBrmol KBr

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many

cm3 of bromine gas can be produced at STP?

2KBr + Cl2 → Br2 + 2KCl

20.0g KBr119g KBrmol KBr

2 mol KBr1 mol Br2

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many

cm3 of bromine gas can be produced at STP?

2KBr + Cl2 → Br2 + 2KCl

20.0g KBr119g KBrmol KBr

2 mol KBr1 mol Br2

1 mol Br2

22.4 dm3

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many

cm3 of bromine gas can be produced at STP?

2KBr + Cl2 → Br2 + 2KCl

20.0g KBr119g KBrmol KBr

2 mol KBr1 mol Br2

1 mol Br2

22.4 dm3

1 dm3

1000 cm3

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many

cm3 of bromine gas can be produced at STP?

2KBr + Cl2 → Br2 + 2KCl

20.0g KBr119g KBrmol KBr

2 mol KBr1 mol Br2

1 mol Br2

22.4 dm3

1 dm3

1000 cm3

= 1880 cm3

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with

5.00 dm3 of oxygen at STP?

4Al + 3O2 → 2Al2O3

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with

5.00 dm3 of oxygen at STP?

4Al + 3O2 → 2Al2O3

5.00 dm3 O2

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with

5.00 dm3 of oxygen at STP?

4Al + 3O2 → 2Al2O3

5.00 dm3 O2

22.4 dm3

mol O2

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with

5.00 dm3 of oxygen at STP?

4Al + 3O2 → 2Al2O3

5.00 dm3 O2

22.4 dm3

mol O2

3 mol O2

4 mol Al

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with

5.00 dm3 of oxygen at STP?

4Al + 3O2 → 2Al2O3

5.00 dm3 O2

22.4 dm3

mol O2

3 mol O2

4 mol Almol Al27.0 g

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with

5.00 dm3 of oxygen at STP?

4Al + 3O2 → 2Al2O3

5.00 dm3 O2

22.4 dm3

mol O2

3 mol O2

4 mol Almol Al27.0 g = 8.04 g

How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP?

H2 + Cl2 → 2HCl

How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP?

H2 + Cl2 → 2HCl

• This is a volume – volume calculation.• We can use a shortcut for these type of calculations.

50.0 cm3 HCl

How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP?

H2 + Cl2 → 2HCl

• This is a volume – volume calculation.• We can use a shortcut for these type of calculations.

50.0 cm3 HCl

2 cm3 HCl

1 cm3 Cl2

= 25.0 cm3

Homework

• Gas Laws Lab (due today).• Worksheet: Ideal Gas Equation (due

tomorrow).• Worksheet: Gas Stoichiometry (due in two

days). • Lab Summary: “Molecular Mass of a Gas”

(due in two days). • Study Guide Chapter 19 (due in two days).

top related