chapter 19 gas stoichiometry. if an excess of chlorine gas reacts with a solution containing 20.0g...
Post on 11-Jan-2016
214 Views
Preview:
TRANSCRIPT
Chapter 19
Gas Stoichiometry
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
20.0g KBr
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
20.0g KBr119g KBrmol KBr
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
20.0g KBr119g KBrmol KBr
2 mol KBr1 mol Br2
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
20.0g KBr119g KBrmol KBr
2 mol KBr1 mol Br2
1 mol Br2
22.4 dm3
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
20.0g KBr119g KBrmol KBr
2 mol KBr1 mol Br2
1 mol Br2
22.4 dm3
1 dm3
1000 cm3
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
20.0g KBr119g KBrmol KBr
2 mol KBr1 mol Br2
1 mol Br2
22.4 dm3
1 dm3
1000 cm3
= 1880 cm3
In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with
5.00 dm3 of oxygen at STP?
4Al + 3O2 → 2Al2O3
In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with
5.00 dm3 of oxygen at STP?
4Al + 3O2 → 2Al2O3
5.00 dm3 O2
In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with
5.00 dm3 of oxygen at STP?
4Al + 3O2 → 2Al2O3
5.00 dm3 O2
22.4 dm3
mol O2
In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with
5.00 dm3 of oxygen at STP?
4Al + 3O2 → 2Al2O3
5.00 dm3 O2
22.4 dm3
mol O2
3 mol O2
4 mol Al
In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with
5.00 dm3 of oxygen at STP?
4Al + 3O2 → 2Al2O3
5.00 dm3 O2
22.4 dm3
mol O2
3 mol O2
4 mol Almol Al27.0 g
In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with
5.00 dm3 of oxygen at STP?
4Al + 3O2 → 2Al2O3
5.00 dm3 O2
22.4 dm3
mol O2
3 mol O2
4 mol Almol Al27.0 g = 8.04 g
How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP?
H2 + Cl2 → 2HCl
How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP?
H2 + Cl2 → 2HCl
• This is a volume – volume calculation.• We can use a shortcut for these type of calculations.
50.0 cm3 HCl
How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP?
H2 + Cl2 → 2HCl
• This is a volume – volume calculation.• We can use a shortcut for these type of calculations.
50.0 cm3 HCl
2 cm3 HCl
1 cm3 Cl2
= 25.0 cm3
Homework
• Gas Laws Lab (due today).• Worksheet: Ideal Gas Equation (due
tomorrow).• Worksheet: Gas Stoichiometry (due in two
days). • Lab Summary: “Molecular Mass of a Gas”
(due in two days). • Study Guide Chapter 19 (due in two days).
top related