chapter 5 branching and looping

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Chapter 5 Branching and Looping. 5.1 Unconditional Jumps. jmp Instruction. Like a goto in a high-level language Format: jmp StatementLabel The next statement executed will be the one at StatementLabel:. Program Design: Calculate 1+2+3+…. number := 0; sum := 0; forever loop - PowerPoint PPT Presentation

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Chapter 5Branching and Looping

5.1 Unconditional Jumps

jmp Instruction

• Like a goto in a high-level language• Format: jmp StatementLabel • The next statement executed will be the

one at StatementLabel:

Program Design: Calculate 1+2+3+…

number := 0;sum := 0;forever loop

add 1 to number;add number to sum;

end loop;

Program Code: Calculate 1+2+3+…

; program to find sum 1+2+...+n for n=1, 2, ....586.MODEL FLAT.STACK 4096.DATA.CODEmain PROC mov ebx,0 ; number := 0 mov eax,0 ; sum := 0 forever: inc ebx ; add 1 to number add eax, ebx ; add number to sum jmp forever ; repeat main ENDPEND

Program Stopped at Breakpoint

jmp Encoding• Relative short encodes a single byte signed

displacement telling how far forward or backward to jump for the next instruction to execute – the assembler uses this format if possible

• Relative near encodes a signed doubleword displacement – this allows a forward or backward jump essentially anywhere in memory

• Indirect forms that encode the address of the destination in a register or memory are not often used

5.2 Conditional Jumps, Compare Instructions and if Structures

Conditional Jump Instructions• Format: j-- targetStatement• The last part of the mnemonic identifies the

condition under which the jump is to be executed– If the condition holds, then the jump takes place and

the next statement executed is at targetStatement:– Otherwise, the next instruction (the one following the

conditional jump) is executed• Used to implement if structures, other selection

structures, and loop structures in 80x86 assembly language

Conditional Jumps and Flags

• Most “conditions” considered by the conditional jump instructions are settings of flags in the EFLAGS register.

• Examplejz endWhile

means to jump to the statement with label endWhile if the zero flag ZF is set to 1

• Conditional jump instructions don’t modify flags; they react to previously set flag values

cmp Instructions

• Most common way to set flags for conditional jumps

• Format: cmp operand1, operand2 – Flags are set the same as for the subtraction

operation operand1 – operand2– Operands are not changed

Conditional Jumps To Use After Signed Operand Comparison

mnemonic jumps if

jg jump if greater SF=OF and ZF=0 jnle jump if not less or equal

jge jump if greater or equal SF=OF jnl jump if not less jl jump if less SFOF jnge jump if not above or equal jle jump if less or equalSFOF or ZF=1 jng jump if not greater

Conditional Jumps To Use After Unsigned Operand Comparison

mnemonic jumps if

ja jump if aboveCF=0 and ZF=0 jnbe jump if not below or equal

jae jump if above or equal CF=0jnb jump if not below jb jump if below CF=1jnae jump if not above or equal jbe jump if below or equal CF=1 or ZF=1 jna jump if not above

Some Other Conditional Jumps

mnemonic jumps if

je jump if equal ZF=1 jz jump if zero

jne jump if not equal ZF=0 jnz jump if not zero js jump if sign (negative) SF=1 jc jump if carry CF=1

jo jump if overflow OF=1

Example Usage

cmp eax, nbrjle smaller

• The jump will occur if the value in EAX is less than or equal than the value in nbr, where both are interpreted as signed numbers

if Example 1Design

if value < 10then

add 1 to smallCount;else

add 1 to largeCount;end if;

Code

cmp ebx, 10 jnl elseLarge inc smallCount jmp endValueCheckelseLarge: inc largeCountendValueCheck:

Assumptions• value in EBX• smallCount and largeCount in memory

if Example 2Design

if (total 100) or (count = 10)

thenadd value to total;

end if;

Code cmp total, 100 jge addValue cmp ecx, 10 jne endAddCheckaddValue: mov ebx, value add total, ebx

endAddCheck:

Assumptions• total and value in memory• count in ECX

5.3 Implementing Loop Structures

while Loops• while pseudocode design

while continuation condition loop... { body of loop }end while;

• Typical while implementation

while1: . ; code to check Boolean expression . .body: . ; loop body . . jmp while1 ; go check condition againendWhile1:

Continuation Condition• A Boolean expression• Checked before the loop body is executed

– Whenever it is true the loop body is executed and then the continuation condition is checked again

– When it is false execution continues with the statement following the loop.

• It may take several 80x86 statements to evaluate and check a continuation condition

while Example

Design

while (sum < 1000) loopadd count to sum;add 1 to count;

end while;

Code

whileSum: cmp sum, 1000 jnl endWhileSum add sum, ecx inc ecx jmp whileSum endWhileSum:

Assumptions• sum in memory• count in ECX

for Loops

• Counter-controlled loop• for pseudocode design

for index := initialValue to finalValue loop... { body of loop }

end for;• Loop body executed once for each value

of the loop index in the given range

for Implementation

• Convert for loop to equivalent while loopindex := initialValue;while index ≤ finalValue loop

... { body of loop }add 1 to index;

end while;• Implement while loop in 80x86 code• Section 5.4 shows another implementation

until Loops• until pseudocode design

repeat... { body of loop }

until termination condition;• Termination condition checked after the

loop body is executed– If true execution continues with the statement

following the until loop– If false the loop body is executed again

until Example

Designrepeat

add 2*count to sum;add 1 to count;

until (sum > 1000);

CoderepeatLoop: add sum, ecx add sum, ecx inc ecx cmp sum, 1000 jng repeatLoopendUntilLoop:

Assumptions• sum in memory• count in ECX

5.4 for Loops in Assembly Language

for Loops

• Can be implemented by converting into while loops

• 80x86 loop instruction designed to implement “backward” counter-controlled loops:

for index := count downto 1 loop... { body of loop }

end for;

loop Instruction• format: loop statementLabel

– statementLabel is the label of a statement which is a short displacement from the loop instruction

• execution– The value in ECX is decremented– If the new value in ECX is zero, then execution

continues with the statement following the loop instruction

– If the new value in ECX is non-zero, then a jump to the instruction at statementLabel takes place

for Example

Design

sum := 0for count := 20 downto 1 loop

add count to sum;end for;

Code mov eax, 0 mov ecx, 20forCount: add eax, ecx loop forCount

Assumptions• sum in EAX• count in ECX

Cautions

• If ECX is initially 0, then 00000000 will be decremented to FFFFFFFF, then FFFFFFFE, etc., for a total of 4,294,967,296 iterations

• The jecxz (“jump if ECX is zero”) instruction can be used to guard a loop implemented with the loop instruction

5.5 Arrays

Defining an Array• Typically declare a collection of contiguous

elements in the data section• Examples

– array1 DWORD 25, 47, 15, 50, 32creates an array of 5 doublewords with initial values

– array2 DWORD 1000 DUP (?)creates an array of 1000 logically uninitialized doublewords

Sequential Array Access

• Put the address of the first element in a register (typically with a lea instruction)

• Register indirect addresssing allows the register to “point at” the array element to be used

• Add the element size to the register to point at the next element

Example: Using Sequential Access to Add 50 Doublewords in an ArraynbrArr DWORD 50 DUP (?) ... mov eax, 0 ; sum := 0 lea esi, nbrArr ; load array address mov ecx, 50 ; number of elementsaddElt: add eax, [esi] ; add array element add esi, 4 ; point at next element loop addElt ; repeat

Random Array Access

• Use indexed addressing• Example nbrArray[4*ecx]

where nbrArray references the array, ECX is the index of the element to be accessed and scaling factor 4 gives doubleword element size

Example: Using Random Access to Add 50 Doublewords in an Array

nbrArr DWORD 50 DUP (?) ... mov eax, 0 ; sum := 0 mov ecx, 50 ; number of elements mov esi, 0 ; array indexaddElt: add eax, nbrArr[4*esi] ; add element inc esi ; increment array index loop addElt ; repeat

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