introduction to signals and systems lecture #6 - frequency...
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Introduction to Signals and Systems Lecture #6 - Frequency-Domain Representation of Signals
Guillaume Drion Academic year 2017-2018
1
The complex exponential
2
Transmission of complex exponentials through LTI systems
3
where is the transfer function of the LTI system.
LTI system
Continuous case:
Transmission of complex exponentials through LTI systems
4
Continuous case:
x(t) = a1es1t + a2e
s2t + a3es3t
y(t) = a1H(s1)es1t + a2H(s2)e
s2t + a3H(s3)es3t
would totally define the system input-output properties if
x(t) =X
k
akeskt
H(s)
Transmission of complex exponentials through LTI systems
5
where is the transfer function of the LTI system.
Discrete case:
LTI system
Transmission of complex exponentials through LTI systems
6
Discrete case:
would totally define the system input-output properties if
x[n] = a1zn1 + a2z
n2 + a3z
n3
y[n] = a1H(z1)zn1 + a2H(z2)z
n2 + a3H(z3)z
n3
H(z)
x[n] =X
k
akznk
Outline
Frequency-domain representation of periodic signals: Fourier series.
Frequency-domain representation of aperiodic signals: the Fourier transform
Convergence of the Fourier transform
Properties of the Fourier transform
7
Continuous-time periodic signals
8
x(t) = e
j!0t = e
j 2⇡T t
The complex exponential of period has a set of harmonically related complex exponentials: that are all periodic with period .
T
�k(t) = ejk!0t = ejk2⇡T t, k = 0,±1,±2, . . .
T
So the signalis also periodic with period .
x(t) =k=1X
k=�1ake
jk!0t =k=1X
k=�1ake
jk 2⇡T t
T
Fourier series of a periodic continuous-time signal
9
x(t) =k=1X
k=�1ake
jk!0t =k=1X
k=�1ake
jk 2⇡T t
ak =1
T
Z
Tx(t)e�jk!0t
dt
=1
T
Z
Tx(t)e�jk 2⇡
T tdt
Fourier series coefficients
Example: is the average value over one period.a0 =1
T
Z
Tx(t)dt
Two classes of conditions that a periodic signal can satisfy to guarantee that it can be represented by a Fourier series
10
(i) Signals having finite energy over a period, i.e. are representable through the Fourier series.
Z
T|x(t)|2dt < 1.
When this condition is satisfied, we are guaranteed that the coefficients are finite. Furthermore, we are guaranteed that the energy in the approximation error of converges to 0 as :
ENxN (t) N ! 1
e(t) = x(t)�1X
k=�1ake
jk!0t !Z
T|e(t)|2dt = 0.
Two classes of conditions that a periodic signal can satisfy to guarantee that it can be represented by a Fourier series
11
(ii) The Dirichlet conditions to ensure that a signal equals its Fourier series representation, except at isolated values of time for which the signal is discontinuous: 1. Over a period, must be absolutely integrable, that is, 2. is of bounded variations, i.e. no more than a finite number of maxima and minima during a single period. 3. There are only a finite number of discontinuities, and each of these discontinuities is finite.
x(t)Z
T|x(t)|dt < 1
x(t)
Two classes of conditions that a periodic signal can satisfy to guarantee that it can be represented by a Fourier series
12
(ii) The Dirichlet conditions ensures that
8t 2 [O, T ) : limN!1
xN (t) = x(t)
1X
k=�1ake
jk!0t = x(t) for all where is continuous.t x(t)
How does the Fourier series converges for a periodic signal with discontinuities?
Discrete-time periodic signals
A signal is periodic with a period if .
13
x[n] = x[n+N ] 8nN
with .!0 =2⇡
N
�k[n] = ejk!0n = ejk2⇡N n, k = 0,±1,±2, . . .
The complex exponential of period has a set of harmonically related complex exponentials:
N
In discrete time, there are only N dinstinct harmonic components:
�k[n] = �k+rN [n]
Fourier series of a periodic discrete-time signal
14
Fourier series coefficients
Finite serie!
x[n] =X
k=<N>
akejk!0n =
X
k=<N>
akejk 2⇡
N n
ak =1
N
X
n=<N>
x[n]e�jk!0n
=1
N
X
n=<N>
x[n]e�jk 2⇡N n
Outline
Frequency-domain representation of periodic signals: Fourier series.
Frequency-domain representation of aperiodic signals: the Fourier transform
Convergence of the Fourier transform
Properties of the Fourier transform
15
We start by deriving the Fourier series representation of the continuous-time periodic square wave defined by
Can we derive a frequency representation of aperiodic signals?
16
x(t) =
⇢1, |t| < T1
0, T1 < |t| < T/2
over one period and periodically repeating with period .T
We start by deriving the Fourier series representation of the continuous-time periodic square wave of period .
Can we derive a frequency representation of aperiodic signals?
17
T
Fourier series coefficients: .ak =2 sin(k!0T1)
k!0T
The Fourier series coefficients can be rewritten as:
Tak =2 sin(!T1)
!
����!=k!0
where the function represents the envelope of , and the coefficients are simply equally spaced samples of this envelope. This envelope is independent of .
(2 sin!T1)/! Tak
T
Can we derive a frequency representation of aperiodic signals?
18
Tak =2 sin(!T1)
!
����!=k!0
T
T = 4T1
T = 8T1
T = 16T1
Can we derive a frequency representation of aperiodic signals?
19
Tak =2 sin(!T1)
!
����!=k!0
As the period increases, the envelope is sampled with closer and closer spacing. As :
The periodic square-wave approaches a rectangular pulse (aperiodic).
The set of Fourier series coefficients approaches the envelope function.
TT ! 1
We think of an aperiodic signal (a) as the limit of the periodic signal (b) as the period becomes arbitrarily large, and we examine the limiting behaviour of the Fourier series representation for this signal.
Frequency representation of an aperiodic signal
20
On the interval , we have:
Frequency representation of an aperiodic signal
21
�T/2 t T/2
x̃(t) =+1X
k=�1ake
jk!0t : periodic signalx̃(t)
: aperiodic signalx(t)
ak =1
T
Z T/2
�T/2x̃(t)e�jk!0t
dt
=1
T
Z T/2
�T/2x(t)e�jk!0t
dt
=1
T
Z +1
�1x(t)e�jk!0t
dt
The envelope of is defined as
Frequency representation of an aperiodic signal
22
X(j!) Tak
X(j!) =
Z +1
�1x(t)e�j!t
dt
with ak =1
TX(jk!0)
This gives the Fourier series representation of the periodic signal
x̃(t) =+1X
k=�1
1
T
X(jk!0)ejk!0t
=+1X
k=�1
1
2⇡X(jk!0)e
jk!0t!0
As :
the periodic signal approaches the aperiodic signal: .
the fundamental frequency approaches 0: .
Frequency representation of an aperiodic signal
23
T ! 1x̃(t) ! x(t)
!0 = 2⇡/T ! 0
x̃(t) =+1X
k=�1
1
2⇡X(jk!0)e
jk!0t!0
x(t) =1
2⇡
Z +1
�1X(j!)ej!t
d!
The continuous-time Fourier transform
24
x(t) =1
2⇡
Z +1
�1X(j!)ej!t
d!
X(j!) =
Z +1
�1x(t)e�j!t
dt
Inverse Fourier transform
Fourier transform
is called the frequency spectrum of .
It tells you how to describe as a linear combination of sinusoïdal signals at different frequencies (i.e. what frequencies are “present” in the signal).
X(j!) x(t)
x(t)
The continuous-time Fourier transform: example
25
The continuous-time Fourier transform: example
26
The continuous-time Fourier transform: example
27
Fourier series of periodic signals vs Fourier transform of aperiodic signals
To represent a periodic signals, we use a set of complex exponentials that are harmonically related:
To represent an aperiodic signals, we use a set of complex exponentials that are infinitesimally close in frequency:
x(t) =1
2⇡
Z +1
�1X(j!)ej!t
d!
x̃(t) =+1X
k=�1
1
2⇡X(jk!0)e
jk!0t!0
28
Fourier transform of periodic signals
We can construct the Fourier transform of a periodic signal directly from its Fourier series representation.
The resulting transform is a train of impulses in the frequency domain, with the areas of the impulses proportional to the Fourier series coefficients.
Indeed, the Fourier transform corresponds to the signal
X(j!) = 2⇡�(! � !0)
x(t) =1
2⇡
Z 1
�12⇡�(! � !0)e
j!td!
= e
j!0t
29
Fourier transform of periodic signals
We can construct the Fourier transform of a periodic signal directly from its Fourier series representation.
The resulting transform is a train of impulses in the frequency domain, with the areas of the impulses proportional to the Fourier series coefficients.
If we now take a linear combination of impulses equally spaced in frequency it gives the signal
x(t) =+1X
k=�1ake
jk!0t
X(j!) =+1X
k=�12⇡ak�(! � k!0)
30
Fourier transform of periodic signals: example
Fourier transform of a periodic square wave.
31
Fourier transform of Dirac delta function :
Examples of Fourier transforms
x(t) = �(t)
X(j!) =
Z +1
�1�(t)ej!tdt = 1
32
Fourier transform of Dirac delta function :
Examples of Fourier transforms
x(t) = cos!0t
33
Fourier transform of Dirac delta function :
Examples of Fourier transforms
x(t) = sin!0t
34
Examples of Fourier transforms
35
Outline
Frequency-domain representation of periodic signals: Fourier series.
Frequency-domain representation of aperiodic signals: the Fourier transform
Convergence of the Fourier transform
Properties of the Fourier transform
36
Convergence of Fourier transforms
The Fourier transform remain valid for an extremely broad class of signals of infinite duration. The convergence criteria are similar to the Fourier series:
There is no energy in the difference between a signal and the reconstruction of a signal from its Fourier representation if the signal has finite energy:
Z +1
�1|x(t)|2dt < +1
The Dirichlet conditions ensure that a signal equals its Fourier representation, except at isolated values of time for which the signal is discontinuous (see Fourier series).
37
Outline
Frequency-domain representation of periodic signals: Fourier series.
Frequency-domain representation of aperiodic signals: the Fourier transform
Convergence of the Fourier transform
Properties of the Fourier transform
38
Properties of the Fourier transform: linearity
x(t)F ! X(j!)
y(t)F ! Y (j!)
ax(t) + by(t)F ! aX(j!) + bY (j!)
If
and
then
39
Properties of the Fourier transform: time shifting
x(t)F ! X(j!)
If
then
x(t� t0)F ! e
�j!t0X(j!)
It is very useful when taking time delays into account in systems.
40
Properties of the Fourier transform: differentiation and integration
dx(t)
dt
F ! j!X(j!)
Z t
�1x(⌧)d⌧
F ! 1
j!
X(j!) + ⇡X(0)�(!)
41
Properties of the Fourier transform: time and frequency scaling
x(t)F ! X(j!)
If
then
Example: playing an audio signal faster sounds higher in frequency.
x(at)F ! 1
|a|X(j!
a
)
42
Properties of the Fourier transform: time and frequency scaling
x(t)F ! X(j!)If then x(at)
F ! 1
|a|X(j!
a
)
A signal that is localized in time is not localized in frequency, and conversely!
Time domain Frequency domain
Example: incertitude principle in physics.
43
Properties of the Fourier transform: the convolution property
y(t) = x(t) ⇤ h(t) F ! Y (j!) = X(j!)H(j!)
If
then
x(t)F ! X(j!)
y(t)F ! Y (j!)
h(t)F ! H(j!)
44
The discrete-time Fourier transform
45
Synthesis equation
Analysis equation
x[n] =1
2⇡
Z
2⇡X(ej!)ej!n
d!
X(ej!) =+1X
n=�1x[n]e�j!n
The discrete-time Fourier transform: example
46
Transmission of complex exponentials through LTI systems
47
where is the Fourier transform of the impulse response of the system.
LTI system
u(t) = ej!t
y(t) = h(t) ⇤ u(t)
=
Z +1
�1h(⌧)ej!(t�⌧)d⌧
= ej!t
Z +1
�1h(⌧)e�j!⌧d⌧
= ej!tH(j!)
H(j!) =
Z +1
�1h(⌧)e�j!⌧d⌧
u(t) = ej!t
y(t) = ej!tH(j!)
Transmission of complex exponentials through LTI systems
48
where is the discrete-time Fourier transform of the impulse response of the system.
LTI system
u[n] = ej!n
y[n] = h[n] ⇤ u[n]
=X
k2Zh[k]ej!(n�k)
= ej!nX
k2Zh[k]e�j!k
= ej!nH(ej!)
H(ej!) =X
k2Zh[k]e�j!k
u[n] = ej!n
y[n] = ej!nH(ej!)
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