jones polynomial

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Jones Polynomial. Ty Callahan. Historical Background. Lord Kelvin thought that atoms could be knots Mathematicians create table of knots Organization sparks knot theory. Background. Knot A loop in R 3 Unknot Arc Portion of a knot Diagram Depiction of a knot’s projection to a plane. - PowerPoint PPT Presentation

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JONES POLYNOMIALTy Callahan

Historical Background Lord Kelvin thought

that atoms could be knots

Mathematicians create table of knots

Organization sparks knot theory

Background Knot

A loop in R3

Unknot

Arc Portion of a knot

Diagram Depiction of a knot’s

projection to a plane

Diagram OK NOT OK

Equivalence Two knots are equivalent if there is an

isotopy that deforms one link into the other

Isotopy Continuous deformation of ambient space Able to distort one into the other without breaking

Nothing more than trial and error can demonstrate equivalence Can mathematically distinguish between

nonequivalence

Figure 8 Knot

Orientation Choice of the sense in which a knot can

be traversed

Crossings Orientation results in two possible crossings

Right and Left

Jones Polynomial Two Principles

1) Assign a value of 1 to any diagram representing an unknot

2) Skein Relation: Whenever three oriented diagrams differ at only one crossing, the Jones Polynomial is governed by the following equation

t−1R[t] − tL[t] = (t12 − t

−12)Q[t]

Ex. Trefoil Knots

1) Skein Relation for Right Trefoil

t−1R1[t] − t = (t12 − t

−12)Q1[t]

R1[t] = (t32 − t

12)Q1[t]+ t

2

2) Skein Relation for Link

t−1R2[t] − tL2[t] = (t12 − t

−12)

R2[t] = t2L2[t]+ t

32 − t

12

3) Skein Relation for Twisted Unknot

t−1 − t = (t12 − t

−12)Q3[t]

t−12 − t

32 = (t −1)Q3[t]

(t −1)(−t12 − t

−12 ) = (t −1)Q3[t]

Q3[t] = −t12 − t

−12

4) Substitute and Simplify

L2[t] =Q3[t] = −t12 − t

−12

R2[t] = t2(−t

12 − t

−12) + t

32 − t

12

R2[t] = −t52 − t

32 + t

32 − t

12

R2[t] = −t52 − t

12

4) Continued..

Q1[t] = R2[t] = −t52 − t

12

R1[t] = (t32 − t

12)(−t

52 − t

12) + t 2

R1[t] = −t4 − t 2 + t 3 + t + t 2

R1[t] = −t4 + t 3 + t

5) Compare to Left Trefoil

R1[t] = −t−4 + t−3 + t−1

R1[t] = −t4 + t 3 + tRight

Left

Conclusion The Jones Polynomial of the Right Trefoil

knot does not equal that of the Left Trefoil knot

The knots aren’t isotopes

“KNOT” EQUAL!!

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