phy131h1s – class 12 (half-way through the course…)jharlow/teaching/phy131s10/class... ·...

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PHY131H1S – Class 12 (half-way through the course…)

Today: •  Action / Reaction

Pairs •  Newton’s Third Law •  Ropes and Pulleys

Team Homework due in Practicals this week! Please hand to your T.A. at the start of practicals.

•  A cyclist is pushing on his pedals, and therefore accelerating to the left.

•  What is the direction of the force of static friction of the ground on the back wheel?

a A.  Left B.  Right C. Up D. Down E.  zero

At the end of Class 11 I asked:

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•  A cyclist is pushing on his pedals, and therefore accelerating to the left.

•  What is the direction of the force of rolling friction of the ground on the back wheel?

a A.  Left B.  Right C. Up D. Down E.  zero

4 discussion questions in a set. [2 / 4]

•  A cyclist is pushing on his pedals, and therefore accelerating to the left.

•  What is the direction of the force of static friction of the ground on the front wheel?

a A.  Left B.  Right C. Up D. Down E.  zero

4 discussion questions in a set. [3 / 4]

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•  A cyclist is pushing on his pedals, and therefore accelerating to the left.

•  What is the direction of the force of rolling friction of the ground on the front wheel?

a A.  Left B.  Right C. Up D. Down E.  zero

4 discussion questions in a set. [4 / 4]

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•  The entire Earth accelerates toward the Moon, due to this pulling force.

•  To find the total acceleration, you use the force as calculated for the centre-to-centre distance.

•  Since FG = GMm/r2, the force on the ocean nearer to the moon will be greater, so it will accelerate more than the rest of the Earth, bulging out.

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•  Since FG = GMm/r2, the force on the ocean nearer to the moon will be greater, so it will accelerate more than the rest of the Earth, bulging out.

•  Similarly, the force on the ocean further from the moon will be less, so it will accelerate less than the rest of the Earth, remaining behind, forming a bulge.

•  In general, tidal effects tend to stretch objects both toward and away from the object causing the tides.

Identifying Action / Reaction Pairs

•  Consider an accelerating car. •  Action: tire pushes on road. •  Reaction: road pushes on tire

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Identifying Action / Reaction Pairs

•  Consider a rocket accelerating upward. •  Action: rocket pushes on gas. •  Reaction: gas pushes on rocket

Identifying Action / Reaction Pairs

•  Action force: man pulls on rope to the left.

•  Reaction force?

A.  Feet push on ground to the right. B.  Ground pushes on feet to the left. C.  Rope pulls on man to the right. D.  Gravity of Earth pulls man down. E.  Gravity of man pulls Earth up.

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Identifying Action / Reaction Pairs

•  Consider a stationary man pulling a rope. •  Action: man pulls on rope •  Reaction: rope pulls on man

Identifying Action / Reaction Pairs

•  Action force: gravity of Earth pulls ball down.

•  Reaction force?

A.  Feet push ground down. B.  Ground pushes feet up. C.  Gravity of Earth pulls man down. D.  Gravity of ball pulls Earth up. E.  Manager yells at player to the left.

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Identifying Action / Reaction Pairs

•  Consider a basketball in freefall. •  Action: Earth pulls on ball •  Reaction: ball pulls on Earth

Test Question from PHY131 Spring 2009

•  Action force: Bob stands on a bathroom scale. There is an action force on Bob, which is gravity. Gravity pulls Bob down.

•  Reaction force? A.  Feet push down on scale (normal). B.  Scale pushes up on Bob (normal). C.  Earth pulls down on scale. D.  Scale pushes down on Earth. E.  Gravity of Bob pulls up on Earth.

scale

14% of the class got this correct on the test in 2009…

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Identifying Action / Reaction Pairs •  Action force: Bob stands on a

bathroom scale in an elevator, which is accelerating upward. There is an action force on Bob, which is gravity. Gravity pulls Bob down.

•  Reaction force? (equal and opposite)

A.  Feet push down on scale (normal). B.  Scale pushes up on Bob (normal). C.  Earth pulls down on scale. D.  Scale pushes down on Earth. E.  Gravity of Bob pulls up on Earth.

scale

a

The Massless String Approximation

Often in physics problems the mass of the string or rope is much less than the masses of the objects that it connects. In such cases, we can adopt the following massless string approximation:

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Pulleys

A.  Equal to B.  Greater than C.  Less than

All three 50 kg blocks are at rest. Is the tension in rope 2 greater than, less than, or equal to the tension in rope 1?

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In the figure to the right, is the tension in the string greater than, less than, or equal to the weight of block B?

A.  Equal to B.  Greater than C.  Less than

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