properties of solutions chapter 13 blb 11 th. expectations: g ↔ mol (using molar mass) g ↔ ml...

Properties of SolutionsChapter 13 BLB 11th

Expectations: g ↔ mol (using molar mass) g ↔ mL (using density) Other conversions: temp., pressure, etc. Solve for any variable in a formula. Distinguish between molecular and ionic

compounds. Convert between different concentration

units. Describe the properties of solutions.

13.1 The Solution Process Solution – homogeneous mixture

Solute – present in smaller quantity Solvent – present in larger quantity

Intermolecular forces are rearranged when a solute and solvent are mixed.

Making a Solution

1. Solute molecules separate (endothermic)

2. Solvent molecules separate (endothermic)

3. Formation of solute-solvent interactions (exothermic)

ΔHsoln = total energy

ΔHsoln – enthalpy change for the formation of a solution; exothermic – usually favorable; endothermic – usually unfavorable

Will a solution form? Solute-solvent interaction must be stronger or

comparable to the separation of solute and solvent particles.

Intermolecular forces play a key role. Entropy (disorder) is also a factor.

Disorder is favorable. (2nd law of thermodynamics) Solution formation increases entropy.

Dissolve vs. react (p. 533-4)

Entropy in Solution Formation

Ionic compoundvery ordered

As the ionic compound dissolves, itbecomes more disordered.

13.2 Saturated Solutions and Solubility Saturated solution – solution is in equilibrium

with undissolved solute.

Solute + solvent ⇌ solution

Unsaturated – less solute than saturated Supersaturated – more solute than saturated

dissolution

crystallization

A Saturated Solution

A dynamic equilibrium – ions continually exchange between the solid and solution form.

13.3 Factors Affecting Solubility

1. Like dissolves like, i.e. same polarity. Polar solutes are soluble in polar solvents. Nonpolar solutes are soluble in nonpolar solvents. If two liquids: miscible or immiscible

Examples:

✔ water + alcohol, NaCl + water, hexane + pentane

✘ water + hexane, NaCl + benzene, oil + water

Fat- and Water-Soluble Vitamins

13.3 Factors Affecting Solubility

2. Pressure Effects (for gases in any liquid solvent)

Solubility increases as the partial pressure above the solution increases.

Henry’s Law: Sg = kPg

Sg – solubility of gas

k – Henry’s Law constant; conc./pressure units

Pg – partial pressure of gas above solution

The partial pressure of O2 in your lungs varies from 25 to 40 torr. What molarity of O2 can dissolve in water at each pressure? The Henry’s Law constant for O2 is 6.02 x 10-5 M/torr.

13.3 Factors Affecting Solubility

3. Temperature Effects For solids: Solubility ↑ as temperature ↑ - usually.

If ΔHsoln > 0 (endothermic)

If ΔHsoln < 0 (exothermic)

For gases: Solubility ↓ as temperature ↑ - always. Kinetic energy plays a primary role. Entropy is also a factor.

Ioniccompounds

Gases(In liquids)

13.4 Ways of Expressing Concentration

Mass %, volume %, and ppm

610solutiong

solutegppm

100%solutionmL

solutemL%volume

100%solutiong

soluteg%mass

13.4 Ways of Expressing Concentration, cont.

Mole fraction, molarity, and molality

solventkg

solutemol

solutionL

solutemol

solutionmol

solutemol

m

M

X

44. A solution contains 80.5 g ascorbic acid (C6H8O6) in 210 g water and has a density of 1.22 g/mL at 55°C.Calculate mass %, X, m, and M.

51. Commercial aqueous nitric acid has a density of 1.42 g/mL and is 16 M. Calculate mass % of HNO3.

43. A sulfuric acid solution containing 571.6 g of H2SO4 per liter of solution has a density of 1.329 g/cm3. Calculate the mass %, mole fraction, molality, and molarity.

Concentration Problems Practice! See Figure 13.19, p. 545, for conversion map. Several examples on pp. 544-6.

13.5 Colligative Properties The addition of a solute to a pure solvent:

1. Lowers the vapor pressure

2. Lowers the freezing point

3. Raises the boiling point

4. Causes movement through a semipermeable membrane (osmosis)

Depends on the number of solute particles (moles), not the identity; more particles the greater the effect

Ionic compounds cause an even greater effect.

1. Lowering the vapor pressure Addition of solute blocks the solvent from

evaporation. More solute, less vapor, lower vapor pressure Raoult’s Law (for a nonvolatile solute):

PA = XAPA° PA – solvent v. p. over solution

(PA < PA°) PA° – pure solvent v. p.

XA – mole fraction of solvent

1. Lowering the vapor pressure, cont. When a volatile solute is added, both the

solvent and solute contribute to the vapor pressure.

“Expanded” Raoult’s Law:

Ptotal = PA + PB = XAPA° + XBPB° If a solution obeys Raoult’s Law, it is an ideal

solution. Nonideal solutions have strong intermolecular

interactions which lower the vapor pressure of the solution even further.

Vapor Pressure Lowering

62a. Calculate the vapor pressure above a solution of 32.5 g C3H8O3 (glycerin-nonvolatile) in 125 g water at 343 K. The vapor pressure of water at 343 K is 233.7 torr.

63. A solution is made from equal masses of water and ethanol (C2H5OH). Calculate the vapor pressure above the solution at 63.5°C. The vapor pressures of water and ethanol are 175 and 400. torr, respectively, at 63.5°C.

2. Boiling point elevation3. Freezing point depression

Since a solution has a lower vapor pressure: A higher temperature is needed to boil solution A lower temperature is needed to freeze solution.

To calculate effect:

b.p. ↑ ΔTb = Kb·m solution − solvent

f.p. ↓ ΔTf = Kf·m solvent − solution ΔT – difference between boiling or freezing points of the pure

solvent and solution K – boiling or freezing pt. dep. constant (specific to solvent) m – molality

69a. Calculate the freezing and boiling points of a solution that is 0.40 m glucose in ethanol.For ethanol: f.p. -114.6°C, b.p. 78.4°C, Kf = 1.99 °C/m, Kb = 1.22 °C/m

72. Calculate the molar mass of lauryl alcohol when 5.00 g of lauryl alcohol is dissolved in 0.100 kg benzene (C6H6). The freezing point of the solution is 4.1°C. For benzene: f.p. 5.5°C, Kf = 5.12 °C/m

4. Osmosis

Osmosis – movement of solvent molecules through a semipermeable membrane from a region of lower solute concentration to a region of higher solute concentration

Driving force – to dilute the higher concentration Continues until:

Equilibrium is reached between two solutions, or External pressure prevents further movement.

Osmosis in red blood cells

Hypertonic solution Hypotonic solution

4. Osmosis, cont.

Osmotic pressure

P = M R T P – osmotic pressure (atm)

M – molarity

R – 0.08206 L∙atom/mol∙K

T – temperature (K)

Good technique for measuring molar mass of large molecules like proteins

4. Osmosis, cont. Applications:

Kidney dialysis Intercellular transport

Reverse osmosis – apply external pressure to reverse the flow of solvent molecules Water purification – alternative to salt ion exchange Desalination – purification of salt water

78. A dilute aqueous solution of an organic compound is formed by dissolving 2.35 g in water to form 0.250 L of solution. The resulting solution has an osmotic pressure of 0.605 atm at 25°C. Calculate the molar mass of the compound.

13.6 Colloids Colloid or colloidal dispersion

Intermediate between a solution and a suspension Dispersing medium – analogous to solvent Dispersing phase – analogous to solute; typically

large molecules with high molar masses Does not settle Tyndall effect – particles scatter light

Tyndall Effect

Types of Colloids

Surfactants Change the surface properties so that two

things that would not normally mix do Emulsifying agent Soap Detergent

Hydrophobic – water-fearing (nonpolar)Hydrophilic – water-loving (polar)

Action of soap on oil