review for unit 4 assessment. write the formula for the following compounds? l.t. #5 carbon...
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Review for Unit 4 Assessment
Write the formula for the following compounds? L.T. #5
Carbon tetrabromide
Dioxygen tetranitride
Heptasulfur pentaiodide
Triphosporus monoselenide
CBr4
O2N4
S7I5
P3Se
Name the following compounds L.T. #4
Br2O6
C3N5
S8P4
NCl
Dibromine hexaoxide
Tricarbon pentanitride
Octasulfur tetraphosphide
Nitrogen monochloride
How many moles are in 100 g of C3N5? L.T. = #10, 11
100 g (___________)
= 0.94 moles C3N5
1 mole
From periodic table: (C3N5)
C = 12.01 g (3) = 36.03 g
N= 14.01 g (5) = + 70.05 g
molar mass = 106.08 g
106.08 g
How many molecules are in 4.1 moles of Br2O6 ? L.T. = #10, 11
= 2.468 x 1024 mc
4.1 mol (____________)6.02 x 1023 mc1 mol
What is the percent composition of each element in triphosphorus pentachloride?
/ 270.16 = 34.4 % P
From periodic table:
P = 30.97 g (3) = 92.91 g
Cl= 35.45 g (5) = + 177.25 g
molar mass = 270.16 g
P3Cl 5
/ 270.16 = 65.6 % Cl
L.T. = #8
What is the bond type for each compound?
C = 2.5 Br = 2.8
Difference = 0.3
Bond type = nonpolar covalent
CBr4
Al2S3
LiF
Al = 1.5 S = 2.5
Bond type = Polar covalent
Li = 1.0 F = 4.0
Bond type = Ionic
L.T. = #3
What might be the properties for each compound?
Nonpolar = liquid or gas, low m.p., low b.p., soluble in nonpolar substances
CBr4
LiF Ionic = solid, high m.p., high b.p., soluble in ionic substances, excellent conductor
L.T. = #2
What is the molecular shape for each compound?
tetrahedralCBr4
SO2
PCl3
AlBr3
angular
triangular pyramidal
triangular planar
L.T. = #6,7
What is the percent composition the salt in the following hydrate compound; CuSO4 * 5H2O?
Cu = 63.55 g (1) = 63.55 g
S= 32.07 g (1) = 32.07 g
O = 16.00 g (4) = + 64.00 g
molar mass salt = 159.62 g/mol / 249.72 =
63.69 % salt
L.T. = #9
H2O = 18.02 (5) = + 90.10 g/ mol
molar mass hydrate = 249.72 g/mol
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