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Bo DengUNL

B. Blaslus, et al Nature1999

B. Blaslus, et al Nature1999

Mark O’Donoghue, et al Ecology 1998

Mark O’Donoghue, et al Ecology 1998

An empirical data of a physical process P is a set of

observation time and quantities:

with

The aim of mathematical modeling is to fit a mathematical form to

the data by one of two ways:

1. phenomenologically without a conceptual model

2. mechanistically with a conceptual model

We will consider only mathematical models of differential equations:

with t having the same time dimension as t i j , x the state

variables, and p the parameters.

ljkiyt jjiji ,...,2,1,,...,2,1),,(

.0)1( jiji tt

)0(

),(

0xx

pxFdt

dx

Inverse Problem : Let be the predicted states by the model to the

observed states, Then the inverse problem is to fit the model

to the data with the least dimensionless error between the predicted

and the observed:

The least error of the model for the process is

with the minimizer being the best fit of the model to

the data.

The best model for the process F satisfies

for all proposed models G .

)),,,(( 0 ppxtxf ijj

).,( ijij yt

l

j

k

iijijjijfF

j

yppxtxfwxpE1 1

2

02

0),( )),,,((),(

),(),(min),( 00),(),( 0

xpExpEfF fFxp

),( 0 xp

),(),( fGfF

Gradient Search Method for Local Minimizers: In the parameter and initial state space , a search path

satisfies the gradient search equation:

A local minimizer is found as

My belief: The fewer the local minima,

the better the model.

),( 0xp

))(,( 0 sxp

),())0(),0((

)),,,(()),,,((2

),(),(

0,000

1 10),(0

2

020

0

xpxp

ppxtxfDyppxtxfw

xpEs

xp

l

j

k

iijjxpijijjij

j

))(,(lim),( 00 sxpxps

Dimensional Analysis by the Buckingham Theorem:

Old Dimension = m + nOld Dimension = m + n

New Dimension = (m – n – 1) + n + l + 1 = n + m – ( n – l ) New Dimension = (m – n – 1) + n + l + 1 = n + m – ( n – l )

Degree of Freedom for the Best Fit = Old Dimension – New Dimension = n – l Degree of Freedom for the Best Fit = Old Dimension – New Dimension = n – l A best fit by the dimensionless model corresponds to a (n – l )-dimensional surface of the same least error fit, i.e., best fit in general is not unique.

Example: Logistic equation with Holling Type II harvesting

where n = 1, m = 4, and m – n – 1 = 2.

With best fit to l = 1 data set, there is zero, n – l = 0, degree of freedom.

Example: Logistic equation with Holling Type II harvesting

where n = 1, m = 4, and m – n – 1 = 2.

With best fit to l = 1 data set, there is zero, n – l = 0, degree of freedom.

,

with 1

)1('

1

)1(' Kh

r

Ka

x

xxxx

xh

xa

K

xrxx

Solve it for the per-predator Predation Rate:

Holling’s Type II Form (Can. Ent. 1959)

where T = given time a = encounter probability rate h = handling time per prey

For One Predator:

X

XC

1/hhaX

aX

T

X C

1

XaXhTX CC ) (

Prey captured during T period of time

Type I Form, h = 0

Type II Form, h > 0

Dimensional ModelDimensional Model

Dimensionless ModelDimensionless Model

By Method of Line Search for local extrema

By Method of Line Search for local extrema

iv 1iv

kvv ii

1 chiralityright , 0

chiralityleft , 0

Left Chirality and Right Chirality :

By Taylor,s expansion:

Best-Fit Sensitivity : ,

By Taylor,s expansion:

Best-Fit Sensitivity : ,

20

2

)(

),(

2

1

ii

p pp

xpES

i 20,0,

02

)(

),(

2

10,

ii

x xx

xpES

i

...)(

),(

2

1

)(

),(

2

1),(),(

2

0,

0,0,2

0,0,

022

20

2

00

i

ii

iii

ii

ii x

xx

xx

xpE

p

pp

pp

xpExpExpE

Best-Fit Sensitivity : ,

Best-Fit Sensitivity : ,

20

2

)(

),(

2

1

ii

p pp

xpES

i2

0,0,

02

)(

),(

2

10,

ii

x xx

xpES

i

All models are constructed to fail against the test of time. All models are constructed to fail against the test of time.

S. Ellner & P. TurchinAmer. Nat.1995

Is Hare-Lynx Dynamics Chaotic? Rate of Expansion along Time Series ~ exp()Lyapunov Exponent > 0 Chaos

N.C. StensethScience1995

1844 -- 1935

Alternative Title:

Holling made trappers to drive hares to eat lynx

Dimension: n + m Dimension: n + m

Dimension: n + m - n - 1 + l +1 = n + m - n + l Dimension: n + m - n - 1 + l +1 = n + m - n + l

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